10, 221, ____, 44443, 555554 a) 3333 b) 3321 c) 3332 d) 3341 e) 332

10, 221, ____, 44443, 555554
a) 3333
b) 3321
c) 3332
d) 3341
e) 332
by

1 Answer

Answer :

This series is formed by subtracting 1 from the series of 11, 222, 3333, 44444, 555555 and so on. So the missing tam is 3333-1 = 3332. Answer: c)
by

Related questions

6, 15, 35, ____, 143, 221, 323 a) 97 b) 112 c) 77 d) 75 e) 128

Description : 6, 15, 35, ____, 143, 221, 323 a) 97 b) 112 c) 77 d) 75 e) 128

Last Answer : Number in each term is the product of the successive prime numbers starting from two, for first term 2×3 = 6, for second term 3×5 = 15, for third term 5×7 = 35, so missing term is 7×11 = 77. Answer: c)

(3333÷30) + (665 ÷ 25) + (3771 ÷ 27) = ? a) 357.637 b) 458.558 c) 229.357 d) 277.367 e) 498.627

Description : (3333÷30) + (665 ÷ 25) + (3771 ÷ 27) = ? a) 357.637 b) 458.558 c) 229.357 d) 277.367 e) 498.627

Last Answer : (3333÷30) + (665 ÷ 25) + (3771 ÷ 27) = ? Sol: 111.1 + 26.6 + 139.667 = ? ? = 277.367 Answer: d)

(3333÷30) + (665 ÷ 25) + (3771 ÷ 27) = ? a) 357.637 b) 458.558 c) 229.357 d) 277.367 e) 498.627

Description : (3333÷30) + (665 ÷ 25) + (3771 ÷ 27) = ? a) 357.637 b) 458.558 c) 229.357 d) 277.367 e) 498.627

Last Answer : (3333÷30) + (665 ÷ 25) + (3771 ÷ 27) = ? Sol: 111.1 + 26.6 + 139.667 = ? ? = 277.367 Answer: d)

5, 8, 12, 18, 24, 30, 36, 42, ____ a) 52 b) 46 c) 48 d) 54 e) 56

Description : 5, 8, 12, 18, 24, 30, 36, 42, ____ a) 52 b) 46 c) 48 d) 54 e) 56

Last Answer : Each term in the series is the addition of successive prime numbers. Like Prime numbers are2, 3, 5, 7, 11, 13, 17, 19, 23, 29 and so on. So first term is addition of (2 + 3). Ie 5, then second term is (3 + 5) ie ... +17)ie. 30, then (17+19)ie.36, then (19+23)ie., 42, then (23+29)i.e. 52. Answer: a)

Find the resistivity of a material having resistance 20kohm, area 2 units and length of 12m. a) 6666.6 b) 3333.3 c) 1200 d) 2000

Description : Find the resistivity of a material having resistance 20kohm, area 2 units and length of 12m. a) 6666.6 b) 3333.3 c) 1200 d) 2000

Last Answer : b) 3333.3

Maximum permissible concentration (i.e. TLV) of DDT in public water supply system is __________ micro gram (μ g)/litre. (A) 22 (B) 42 (C) 332 (D) 1050

Description : Maximum permissible concentration (i.e. TLV) of DDT in public water supply system is __________ micro gram (μ g)/litre. (A) 22 (B) 42 (C) 332 (D) 1050

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In a college of 1335 students, 60 % are boys. Find the number of girls and number of boys in the college? a) 924,221 b) 691,404 c) 802,333 d) 441,564 e) 534,801

Description : In a college of 1335 students, 60 % are boys. Find the number of girls and number of boys in the college? a) 924,221 b) 691,404 c) 802,333 d) 441,564 e) 534,801

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Description : What is 332 of an inch to decimal?

Last Answer : It is 332 inches. A decimal representation does not imply achange in the measurement units. If this is required then you needto specify the units into which the quantity is to beconverted.

What is 332 divided by 321?

Description : What is 332 divided by 321?

Last Answer : 1.0343

0.332 round to nearest hundred?

Description : 0.332 round to nearest hundred?

Last Answer : Rounded to the nearest hundredth would be 0.33

0.332 round to nearest hundred?

Description : 0.332 round to nearest hundred?

Last Answer : Rounded to the nearest hundredth would be 0.33

In which Article of the Constitution of India was the provision for reservation of scheduled castes in the Lok Sabha made? (1) Article 330 (2) Article 331 (3) Article 332 (4) Article 333

Description : In which Article of the Constitution of India was the provision for reservation of scheduled castes in the Lok Sabha made? (1) Article 330 (2) Article 331 (3) Article 332 (4) Article 333

Last Answer : (1) Article 330 Explanation: In the Indian Constitution, seats have been reserved in the Lok Sabha for Scheduled Castes and Scheduled Tribes in Article -330.

When a voltage of 95 VDC is applied to the circuit illustrated with a resistance of 237 ohms the current will be________. EL-0018 A. 1.40 amps B. 2.49 amps C. 332 milliamps D. 400.8 milliamps

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Last Answer : Answer: D

Which article of Indian constitution deals with Constitutional Amendments? (a) Article 332 (b) Article 386 (c) Article 368 (d) None of the above

Description : Which article of Indian constitution deals with Constitutional Amendments? (a) Article 332 (b) Article 386 (c) Article 368 (d) None of the above

Last Answer : (c) Article 368

A prokaryotic mRNA that consists of 999 nucleotides will code for how many amino acids? a. 332 b. 333 c. 666 d. 999

Description : A prokaryotic mRNA that consists of 999 nucleotides will code for how many amino acids? a. 332 b. 333 c. 666 d. 999

Last Answer : a. 332

What is the latent heat of fusion of water at 1 atm?  A. 331.1 kJ/kg  B. 332.6 kJ/kg  C. 333.7 kJ/kg  D. 330.7 kJ/kg

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How much space will be required to store the bit map of a 1.3 GB disk with 512 bytes block size ? (A) 332.8 KB (B) 83.6 KB (C) 266.2 KB (D) 256.6 KB

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Last Answer : (A) 332.8 KB

What is 221.5584 rounded to the nearest tenth?

Description : What is 221.5584 rounded to the nearest tenth?

Last Answer : The answer is 221.6

How many years is it from 221 bc to 206 bc?

Description : How many years is it from 221 bc to 206 bc?

Last Answer : 15 years

Insulin receptors are decreased in number in (A) Obesity (B) Starvation (C) Hyperinsulinism (D) Kwashiorkor HORMONE METABOLISM 221

Description : Insulin receptors are decreased in number in (A) Obesity (B) Starvation (C) Hyperinsulinism (D) Kwashiorkor HORMONE METABOLISM 221

Last Answer : Answer : A

Provision for the representation of Anglo - Indian Community in the Lok sabha has been made in the Constitution under the article - (1) 331 (2) 221 (3) 121 (4) 139

Description : Provision for the representation of Anglo - Indian Community in the Lok sabha has been made in the Constitution under the article - (1) 331 (2) 221 (3) 121 (4) 139

Last Answer : (1) 331 Explanation: Representation of the AngloIndian community in the Lok Sabha or Lower House of parliament is mentioned in the Article 331 of the Indian Constitution.

221 For non-scouring velocity 5 m/sec, the type of sewers generally preferred to, is A. Cast iron sewers B. Cement concrete sewers C. Glazed bricks sewers D. Stone ware sewers

Description : 221 For non-scouring velocity 5 m/sec, the type of sewers generally preferred to, is A. Cast iron sewers B. Cement concrete sewers C. Glazed bricks sewers D. Stone ware sewers

Last Answer : ANS: C

What is the critical point of steam generation in a “once through” boiler? a) 221.5 bar b) 221.4 bar c) 221.3 bar d) 221.2 bar

Description : What is the critical point of steam generation in a “once through” boiler? a) 221.5 bar b) 221.4 bar c) 221.3 bar d) 221.2 bar

Last Answer : d) 221.2 bar

Two cards are drawn at random from a pack of 52 cards. What is the probability that both of them are either black or queen cards? a) 55/442 b) 54/221 c) 55/221 d) 51/221

Description : Two cards are drawn at random from a pack of 52 cards. What is the probability that both of them are either black or queen cards? a) 55/442 b) 54/221 c) 55/221 d) 51/221

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Suppose that we have numbers between 1 and 1000 in a binary search tree and want to search for the number 364. Which of the following sequences could not be the sequence of nodes examined? (A) 925, 221, 912, 245, 899, 259, 363, 364 (B) 3, 400, 388, 220, 267, 383, 382, 279, 364 (C) 926, 203, 912, 241, 913, 246, 364 (D) 3, 253, 402, 399, 331, 345, 398, 364

Description : Suppose that we have numbers between 1 and 1000 in a binary search tree and want to search for the number 364. Which of the following sequences could not be the sequence of nodes examined? (A) 925, 221, 912, 245, 899, ... 926, 203, 912, 241, 913, 246, 364 (D) 3, 253, 402, 399, 331, 345, 398, 364 

Last Answer : (C) 926, 203, 912, 241, 913, 246, 364

Two cards are drawn at random from a pack of 52 cards.what is the probability that either both are Red or both are king? A) 52/221 B) 55/190 C) 55/221 D) 19/221

Description :  Two cards are drawn at random from a pack of 52 cards.what is the probability that either both are Red or both are king? A) 52/221 B) 55/190 C) 55/221 D) 19/221

Last Answer : Answer: C) We have n(s) = 52C2 = 1326. Let A = event of getting both red cards B = event of getting both king A∩B = event of getting king of red cards n(A) = 26C2 = 325, n(B)= 4C2= 6 and n(A∩B) = 2C2 = 1 P(A ... S) = 1/1326 P(A∪B) = P(A) + P(B) - P(A∩B) = (325+6-1) / 1326 = 330/1326 = 55/221

Rosy buys Oats at Rs.10/kg and sell it in order to earn a profit of 40%. However, her faulty balance shows 1000gm when it is actually 800gm. What is her actual gain percentage? a) 35% b) 70% c) 75% d) 25% e) None of the Above

Description : Rosy buys Oats at Rs.10/kg and sell it in order to earn a profit of 40%. However, her faulty balance shows 1000gm when it is actually 800gm. What is her actual gain percentage? a) 35% b) 70% c) 75% d) 25% e) None of the Above

Last Answer : Let price of 1 kg rice = Rs.10. CP of 800 gm rice = Rs.8. She wants to earn a profit of 40% on per Kg SP = 10 + 40% of 10 = Rs. 14 per kg. Faulty balance shows 800 gm = 1000 gm (1 kg) She sells 800 gm for Rs.14. Profit = 14 – 8 = Rs. 6. Profit(%) = 6/8 * 100 = 75%. Answer: c)

In 10 years time, Ram will be 2 times older than his son. 5 years ago he was 9 times as old as his son. What will be the sum of the ages of Ram and his son 3 years from now? a) 46 b) 66 c) 86 d) 76 e) None of these

Description : In 10 years time, Ram will be 2 times older than his son. 5 years ago he was 9 times as old as his son. What will be the sum of the ages of Ram and his son 3 years from now? a) 46 b) 66 c) 86 d) 76 e) None of these

Last Answer : Let current age of Ram and his son be R,S (R + 10) = 3(S + 10) [2 times older = 3 times the age] R = 3S + 20 (R - 5) = 9(S - 5) 3S + 20 – 5= 9S – 45 3S + 15 = 9S – 45 or S = 10., R = 50 sum of ages 3 years from now = 10 + 3 + 50 + 3 = 66. Answer: b)

Pipe A usually fills a tank in 2 hours. On account of a leak at the bottom of the tank, it takes pipe A 30 more minutes to fill the tank. How long will the leak take to empty a full tank if pipe A is shut? a) 4 hours b) 3 hours c) 6 hours d) 8 hours e) 10 hours

Description : Pipe A usually fills a tank in 2 hours. On account of a leak at the bottom of the tank, it takes pipe A 30 more minutes to fill the tank. How long will the leak take to empty a full tank if pipe A is shut? a) 4 hours b) 3 hours c) 6 hours d) 8 hours e) 10 hours

Last Answer : portion of the tank filled by the pipe A in 1 hour = ½ of the tank let the portion of the tank emptied because of the leak in 1 hour be 1/x of the tank therefore, in 1 hour , portion of the tank filled = 1/2 - 1 ... 1/2 - 1/x = 1/2.5 or x = 10 hence, it takes 10 hours to empty a full tank Answer: e)

An amount becomes 160% of itself in 5 years through simple interest. At the same rate of interest, how long will it take for the amount to more than double itself if we use compound interest? a) 7 b) 8 c) 9 d) 10 e) cannot be determined

Description : An amount becomes 160% of itself in 5 years through simple interest. At the same rate of interest, how long will it take for the amount to more than double itself if we use compound interest? a) 7 b) 8 c) 9 d) 10 e) cannot be determined

Last Answer : Answer: a)

0.003 × ? × 0.0003 = 0.00009 a) 10 b) 3 c) 0.03 d) 0.003 e) None of these

Description : 0.003 × ? × 0.0003 = 0.00009 a) 10 b) 3 c) 0.03 d) 0.003 e) None of these

Last Answer : ? = 0.00009 / 0.003 × 0.0003 = 100 Answer: e)

3 1/7 + 4 2/5 - ? = -2 3/5 a) a) 10 1/7 b) b) 7 1/10 c) c) 8 8/7 d) d) 9 8/7 e) None of these

Description : 3 1/7 + 4 2/5 - ? = -2 3/5 a) a) 10 1/7 b) b) 7 1/10 c) c) 8 8/7 d) d) 9 8/7 e) None of these

Last Answer : 3 1/7 + 4 2/5 - ? = -2 3/5 22/7 + 22/5 + 13/5 = 355/35 = 71/7 = 10 1/7 Answer: a)

In a class there are 15 boys and 10 girls. Three students are selected at random. The difference between the probability that 2 boys and 1 girl are selected compared to 1 boy and 2 girls are selected is: a) 23/78 b) 19/88 c) 15/92 d) 4/23 e) 7/46

Description : In a class there are 15 boys and 10 girls. Three students are selected at random. The difference between the probability that 2 boys and 1 girl are selected compared to 1 boy and 2 girls are selected is: a) 23/78 b) 19/88 c) 15/92 d) 4/23 e) 7/46

Last Answer : 2 boys, 1 gi(Prl = (15c2×10c1) / 25c3 = 1050/2300 1 boy, 2 girls = (15c1×10c2) / 25c3 = 675/2300 Difference = (1050 - 675)/2300 = 375/2300 = 15/92 Answer: c)

What is the size of the longest pencil that can fit in a box with dimensions 12 cm× 10 cm× 8cm? a) 15 b) 15.5 c) 17 d) 17.5 e) 18

Description : What is the size of the longest pencil that can fit in a box with dimensions 12 cm× 10 cm× 8cm? a) 15 b) 15.5 c) 17 d) 17.5 e) 18

Last Answer : Answer: d)

A man can row 15 km/hr in still water. It takes him twice as long to row upstream as to row downstream. Find the rate of stream? a) 5 km/hr b) 10 km/hr c) 7.5 km/hr d) 6 km/hr e) 8 km/hr

Description : A man can row 15 km/hr in still water. It takes him twice as long to row upstream as to row downstream. Find the rate of stream? a) 5 km/hr b) 10 km/hr c) 7.5 km/hr d) 6 km/hr e) 8 km/hr

Last Answer : Let the man’s upstream speed be x km/hour and downstream speed will be 2x km/hour Speed in still water = 1/2 (2x + x) = 3x/2 km/hour 3x/2 = 15 X = 10 Hence, his downstream speed = 20km/hour Rate of stream = 1/2 (20-10) = 5km/hour Answer: a)

15 30 ? 40 8 48 a) 10 b) 20 c) 18 d) 12 e) None of these

Description : 15 30 ? 40 8 48 a) 10 b) 20 c) 18 d) 12 e) None of these

Last Answer : The series is ×2, ÷3, ×4, ÷5, ... Answer: a)

Three pipes A, B and C can fill a tank in 6 hours. After working at it together for 2 hours, C is closed and A and B can fill the remaining part in 7 hours. The number of hours taken by C alone to fill the tank is: a) 10 b) 14 c) 12 d) 13 e) 15

Description : Three pipes A, B and C can fill a tank in 6 hours. After working at it together for 2 hours, C is closed and A and B can fill the remaining part in 7 hours. The number of hours taken by C alone to fill the tank is: a) 10 b) 14 c) 12 d) 13 e) 15

Last Answer : (A+B+C) - (A+B) (A+B+C) =1/6 and (A+B+C) in 2hrs=2/6 and remaining part 1-2/6=2/3. So (A+B) in 7 hrs is 2/ (3*7) =2/21. 1/6-2/21=1/14 so answer is 14. Answer: b)

The width of a rectangular park is 10/21 of its length. If the area of the park is 3360 sq m, then what is the difference between the length and the width of the park? a) 40m b) 44m c) 48m d) 52m e) 56m

Description : The width of a rectangular park is 10/21 of its length. If the area of the park is 3360 sq m, then what is the difference between the length and the width of the park? a) 40m b) 44m c) 48m d) 52m e) 56m

Last Answer : Let the length of the park be x metres. Width = x × 10 / 21 = 10x / 21 Area = x × 10x / 21 = 3360 or, x^2 = 3360 × 21 / 10 = 7056 or, x = 84 Hence, length = x = 84m and width = 84 × 10 / 21 = 40 metres Difference = 84 – 40 = 44 metres Answer: b)

5 10 17 27 37 50 65 a) 10 b) 17 c) 27 d) 37 e) 50

Description : 5 10 17 27 37 50 65 a) 10 b) 17 c) 27 d) 37 e) 50

Last Answer : The series is +5, +7, +9, +11, .... Answer: c)

6 men and 8 women can complete a work in 10 days. 26 men and 48 women can finish the same work in 2 days. 15 men and 20 women can do the same work in - days. a) 4 days b) 6 days c) 2 days d) 8 days e) 7 days

Description : 6 men and 8 women can complete a work in 10 days. 26 men and 48 women can finish the same work in 2 days. 15 men and 20 women can do the same work in - days. a) 4 days b) 6 days c) 2 days d) 8 days e) 7 days

Last Answer : Let work done by 1 man in 1 day = m and work done by 1 woman in 1 day = b Work done by 6 men and 8 women in 1 day = 1/10 => 6m + 8b = 1/10 => 60m + 80b = 1 --- (1) Work done by 26 men and 48 ... 1 day = 15/100 + 20/200 =1/4 => Time taken by 15 men and 20 women in doing the work = 4 days Answer: a)

A mixture contains milk and water in the ratio of 3:2 litter of water is added to the mixture, milk, milk and water in the mixture become equal find the quantities of milk and water in the mixture . a) 12, 8 litter b) 4,3 litter c) 12, 6 litres d) 10,8 litres e) None of these

Description : A mixture contains milk and water in the ratio of 3:2 litter of water is added to the mixture, milk, milk and water in the mixture become equal find the quantities of milk and water in the mixture . a) 12, 8 litter b) 4,3 litter c) 12, 6 litres d) 10,8 litres e) None of these

Last Answer : Let quantities of milk and water in the mixture be 3x and 2x. Then if 4 litres of water is added to the mixture the ratio of milk and water become 1:1. It can be written as (3x): (2x + 4) = 1 ... Therefore, the milk in the mixture is 4x3 = 12 litres and quantity of water = 4x2 = 8 liters Answer: a)

A,B and C can do piece of work in 11 days,20 days and 55 days respectively, working alone. How soon can the work be done if a is assisted by B and C on alternate days/ a) 6 b) 7 c) 8 d) 9 e) 10

Description : A,B and C can do piece of work in 11 days,20 days and 55 days respectively, working alone. How soon can the work be done if a is assisted by B and C on alternate days/ a) 6 b) 7 c) 8 d) 9 e) 10

Last Answer : Work done by A and B in one day = 1/11 + 1/20 =31/220 Work done by A and C in one day = 1/11 + 1/55 =6/55 Work done in 2 days = 31 /220+6/55=55/220 = ¼ Hence, 1/4 of the work is done in 2 days Hence, it takes 8 days to finish the work Answer : c

A,B and C can do piece of work in 11 days,20 days and 55 days respectively, working alone. How soon can the work be done if a is assisted by B and C on alternate days/ a) 6 b) 7 c) 8 d) 9 e) 10

Description : A,B and C can do piece of work in 11 days,20 days and 55 days respectively, working alone. How soon can the work be done if a is assisted by B and C on alternate days/ a) 6 b) 7 c) 8 d) 9 e) 10

Last Answer : Work done by A and B in one day = 1/11 + 1/20 =31/220 Work done by A and C in one day = 1/11 + 1/55 =6/55 Work done in 2 days = 31 /220+6/55=55/220 = ¼ Hence, 1/4 of the work is done in 2 days Hence, it takes 8 days to finish the work Answer : c

A man drives from his house to the station. If he drives at the rate of 10 kms per hour, he reaches the station at 6 pm. if he drives at 15 kms per hour, he would reach the station at 4 pm. At what speed, in kms per hour, should he drives so as to reach the station at 5 pm? a) 12 b) 12.33 c) 5√5 d) 12.5 e) 13

Description : A man drives from his house to the station. If he drives at the rate of 10 kms per hour, he reaches the station at 6 pm. if he drives at 15 kms per hour, he would reach the station at 4 pm. At what speed, in kms ... he drives so as to reach the station at 5 pm? a) 12 b) 12.33 c) 5√5 d) 12.5 e) 13

Last Answer : Let x' be the distance between house and station. Time taken to travel a distance of x at the speed of 10km/hr, T1 = x/10 hours Time taken to travel a distance of x at the speed of 15km/hr, T2 = x/15 hours we ... the station at 5 pm, speed = 60/5 = 12 km/hr [12 pm - 5pm, time = 5 hours] Answer: a)

Anjana walked at 4 kmph for a certain part of his journey and took an auto, travelling at 25 kmph for the rest of the journey. If he took 42 minutes for the entire journey, what part of the journey did he walk given that his average speed for the entire journey was 10 kmph? a) 2 km b) 1.5 km c) 3.5 km d) 4 km e) 1 km

Description : Anjana walked at 4 kmph for a certain part of his journey and took an auto, travelling at 25 kmph for the rest of the journey. If he took 42 minutes for the entire journey, what part of the journey did he walk given that his ... journey was 10 kmph? a) 2 km b) 1.5 km c) 3.5 km d) 4 km e) 1 km

Last Answer : Total time = 42 minutes = 0.7 hours. Average speed = 10 kmph Total distance = 0.7×10 = 7 km Let distance walked = W W/4 + (7-W)/25 = 0.7 Solving W = 2 Answer: a)

10 years ago the average age of all the 25 teachers of a college was 45 years. 4 years ago, a teacher retired from the post at the age of 60 years, and was replaced by a new teacher whose age was 54 years. What is the present average age of all the teachers? a) Between 52 and 53 b) Between 53 and 54 c) Between 54 and 55 d) Between 55 and 56 e) None of the above

Description : 10 years ago the average age of all the 25 teachers of a college was 45 years. 4 years ago, a teacher retired from the post at the age of 60 years, and was replaced by a new teacher whose age was 54 years. ... 53 b) Between 53 and 54 c) Between 54 and 55 d) Between 55 and 56 e) None of the above

Last Answer : Let current year be 2015 In 2005, sum of all ages = 25 45 = 1125 In 2015, sum of all ages = 1125 + (25 10) = 1375 Now 60 year old teacher was replaced by a 54 year old teacher. So we need ... all ages in 2015 considering the replacement teacher = 1375 - 6 = 1369 Average = 1369/25 = 54.76 Answer: c)

Five years ago, the age of Arun was 4 times the age of Sarmi after 10 years, Arun will be twice as old as Sarmi. Find the Present ages of Arun and sarmi? a) 30 years, 10.5 years b) 32 years, 11.5 years c) 34 years, 14.5 years d) 35 years, 12.5 years e) None of these

Description : Five years ago, the age of Arun was 4 times the age of Sarmi after 10 years, Arun will be twice as old as Sarmi. Find the Present ages of Arun and sarmi? a) 30 years, 10.5 years b) 32 years, 11.5 years c) 34 years, 14.5 years d) 35 years, 12.5 years e) None of these

Last Answer : Five years ago, x – 5/y – 5 = 4/1 x – 4y = – 15 —-(i) After 10 years, x + 10/y + 10 = 2/1 x – 2y = 10 —–(ii) From eqn (i) and (ii) => x = 35, y = 12.5 Answer: d)

[3/2 + 2(1/5) – 7/10] of ? = 1098 a) 463 b) 326 c) 276 d) 366 e) None of these

Description : [3/2 + 2(1/5) – 7/10] of ? = 1098 a) 463 b) 326 c) 276 d) 366 e) None of these

Last Answer : [15+22-7/10] * x = 1098 X = 1098/3 = 366 Answer: d)

Busses start from a bus terminal with a speed of 20 km/hr at intervals of 10 minutes. What is the speed of a man coming from the opposite direction towards the bus terminal if he meets the buses at intervals of 8 minutes? a) 3 km/hr b) 4 km/hr c) 5 km/hr d) 7 km/hr e) None of these

Description : Busses start from a bus terminal with a speed of 20 km/hr at intervals of 10 minutes. What is the speed of a man coming from the opposite direction towards the bus terminal if he meets the buses at intervals of 8 minutes? a) 3 km/hr b) 4 km/hr c) 5 km/hr d) 7 km/hr e) None of these

Last Answer : Distance covered in 10 minutes at 20 kmph = distance covered in 8 minutes at (20+x) kmph 20× 10/60=8/60(20+x) 200 = 160 + 8x 8x = 40 x=40/8=5 kmph Answer: c)