I. 32a^2 + 52a + 15 = 0 II. 8b^2 + 38b + 35 = 0 1 : if a > b 2 : if a < b 3 : if a ≥ b 4 : if a ≤ b 5 : if a = b or the relation between a and b cannot be established.

I. 32a^2 + 52a + 15 = 0

II. 8b^2 + 38b + 35 = 0

1 : if a > b

2 : if a < b

3 : if a ≥ b

4 : if a ≤ b

5 : if a = b or the relation between a and b cannot be established.
by

1 Answer

Answer :

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3 : if a ≥ b

by

Related questions

I. 12a^2 − a − 6 = 0 II. 8b^2 − 26b + 15 = 0 1 : if a > b 2 : if a < b 3 : if a ≥ b 4 : if a ≤ b 5 : if a = b or the relation between a and b cannot be established.

Description : I. 12a^2 − a − 6 = 0 II. 8b^2 − 26b + 15 = 0 1 : if a > b 2 : if a < b 3 : if a ≥ b 4 : if a ≤ b 5 : if a = b or the relation between a and b cannot be established.

Last Answer : 4 : if a ≤ b

I. 28a^2 + 25a − 8 = 0 II. 5b^2 − 13b − 6 = 0 1 : if a > b 2 : if a < b 3 : if a ≥ b 4 : if a ≤ b 5 : if a = b or the relation between a and b cannot be established.

Description : I. 28a^2 + 25a − 8 = 0 II. 5b^2 − 13b − 6 = 0 1 : if a > b 2 : if a < b 3 : if a ≥ b 4 : if a ≤ b 5 : if a = b or the relation between a and b cannot be established.

Last Answer : 5 : if a = b or the relation between a and b cannot be established.  

I. 2a^2 − 11a + 12 = 0 II. 35b^2 − 18b − 8 = 0 1 : if a > b 2 : if a < b 3 : if a ≥ b 4 : if a ≤ b 5 : if a = b or the relation between a and b cannot be established.

Description : I. 2a^2 − 11a + 12 = 0 II. 35b^2 − 18b − 8 = 0 1 : if a > b 2 : if a < b 3 : if a ≥ b 4 : if a ≤ b 5 : if a = b or the relation between a and b cannot be established.

Last Answer : 1 : if a > b

I. 20a^2 + 51a + 28 = 0 II. 15b^2 − 61b + 56 = 0 1 : if a > b 2 : if a < b 3 : if a ≥ b 4 : if a ≤ b 5 : if a = b or the relation between a and b cannot be established.

Description : I. 20a^2 + 51a + 28 = 0 II. 15b^2 − 61b + 56 = 0 1 : if a > b 2 : if a < b 3 : if a ≥ b 4 : if a ≤ b 5 : if a = b or the relation between a and b cannot be established.

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I. 63x^2 – 275x + 300 = 0 II. 18y^2 – 85y + 100 = 0 1 : if x ≥ y 2 : if x ≤ y 3 : if x > y 4 : if x < y 5 : if x = y or relationship cannot be established

Description : I. 63x^2 – 275x + 300 = 0 II. 18y^2 – 85y + 100 = 0 1 : if x ≥ y 2 : if x ≤ y 3 : if x > y 4 : if x < y 5 : if x = y or relationship cannot be established

Last Answer : 2 : if x ≤ y

I. 20x^2 – 119x + 176 = 0 II. 18y^2 – 123y + 209 = 0 1 : if x ≥ y 2 : if x ≤ y 3 : if x > y 4 : if x < y 5 : if x = y or relationship cannot be established

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Last Answer : 5 : if x = y or relationship cannot be  established

I. 3x^2 – 47x + 184 = 0 II. 3y^2 – 38y + 119 = 0 1 : if x ≥ y 2 : if x ≤ y 3 : if x > y 4 : if x < y 5 : if x = y or relationship cannot be established

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Last Answer : 3 : if x > y

I. 56x^2 – 127x + 72 = 0 II. 6y^2 – 17y + 12 = 0 1 : if x ≥ y 2 : if x ≤ y 3 : if x > y 4 : if x < y 5 : if x = y or relationship cannot be established

Description : I. 56x^2 – 127x + 72 = 0 II. 6y^2 – 17y + 12 = 0 1 : if x ≥ y 2 : if x ≤ y 3 : if x > y 4 : if x < y 5 : if x = y or relationship cannot be established

Last Answer : 4 : if x < y

I. 6x^2 – 71x + 195 = 0 II. 12y^2 – 97y + 195 = 0 1 : if x ≥ y 2 : if x ≤ y 3 : if x > y 4 : if x < y 5 : if x = y or relationship cannot be established

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Last Answer : 1 : if x ≥ y

What is the radius of the circle/ I.Ratio of its area to circumference is >7. II.Diameter of the circle is ≤ 32. If the question can be answered with the help of statement I alone, If the question can be answered with the help of statement II alone, If both,statement I and statement II are needed to answer the question If the question cannot be answered even with the help of both the statements. If the data in either statement I or statement II alone is sufficient to answer the question.

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Last Answer : Let the radius of the circle be r units From statement 1: [πr^2]/ [ 2 πr ] > 7 or r > 14 From statement II: 2r≤32 R ≤ 16 Hence, r can be 15 or 16 units Hence, Answer : d

Naphthenic acid is represented by (A) CnH2n+2O2 (B) CnH2n-2O2 (C) CnH2n+2O2 (n ≥ 6) (D) CnH2n+6O2 (n ≤ 6)

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Last Answer : (B) CnH2n-2O2

. Which of the following relationships between co-efficient of friction (μ) between rock & roll and a (half of the angle of nip) of the particle to be crushed is correct? (A) μ > tan α (B) μ ≥ tan α (C) μ > tan 2α (D) μ ≤ tan α

Description : . Which of the following relationships between co-efficient of friction (μ) between rock & roll and a (half of the angle of nip) of the particle to be crushed is correct? (A) μ > tan α (B) μ ≥ tan α (C) μ > tan 2α (D) μ ≤ tan α

Last Answer : (B) μ ≥ tan α

The grammar with production rules S → aSb |SS|λ generates language L given by: (A) L = {w∈{a, b}* | na(w) = nb(w) and na(v) ≥ nb(v) where v is any prefix of w} (B) L = {w∈{a, b}* | na(w) = nb(w) and na(v) ≤ nb(v) where v is any prefix of w} (C) L = {w∈{a, b}* | na(w) ≠ nb(w) and na(v) ≥ nb(v) where v is any prefix of w} (D) L = {w∈{a, b}* | na(w) ≠ nb(w) and na(v) ≤ nb(v) where v is any prefix of w}

Description : The grammar with production rules S → aSb |SS|λ generates language L given by: (A) L = {w∈{a, b}* | na(w) = nb(w) and na(v) ≥ nb(v) where v is any prefix of w} (B) L = {w∈{a, b}* | na(w) = nb(w) and na(v ... (D) L = {w∈{a, b}* | na(w) ≠ nb(w) and na(v) ≤ nb(v) where v is any prefix of w}

Last Answer : (A) L = {w∈{a, b}* | na(w) = nb(w) and na(v) ≥ nb(v) where v is any prefix of w} 

A set of processors P1, P2, ......, Pk can execute in parallel if Bernstein's conditions are satisfied on a pair wise basis; that is P1 || P2 || P3 || ..... || Pk if and only if: (A) Pi || Pj for all i ≠ j (B) Pi || Pj for all i = j+1 (C) Pi || Pj for all i ≤ j (D) Pi || Pj for all i ≥ j

Description : A set of processors P1, P2, ......, Pk can execute in parallel if Bernstein's conditions are satisfied on a pair wise basis; that is  P1 || P2 || P3 || ..... || Pk if and only if: (A) Pi || Pj for all i ≠ j (B) Pi || Pj for all i = j+1 (C) Pi || Pj for all i ≤ j (D) Pi || Pj for all i ≥ j

Last Answer : (A) Pi || Pj for all i ≠ j Explanation: Bernstein's Condition: 1. If process Pi writes to a memory cell Mi, then no process Pj can read the cell Mi. 2. If process Pi read from a memory ... Mi. 3. If process Pi writes to a memory cell Mi, then no process Pj can write to the cell Mi.

6, 15, 35, ____, 143, 221, 323 a) 97 b) 112 c) 77 d) 75 e) 128

Description : 6, 15, 35, ____, 143, 221, 323 a) 97 b) 112 c) 77 d) 75 e) 128

Last Answer : Number in each term is the product of the successive prime numbers starting from two, for first term 2×3 = 6, for second term 3×5 = 15, for third term 5×7 = 35, so missing term is 7×11 = 77. Answer: c)

3 9 15 ? 35 49 a) 25 b) 30 c) 24 d) 20 e) None of these

Description : 3 9 15 ? 35 49 a) 25 b) 30 c) 24 d) 20 e) None of these

Last Answer : Answer: a) 

Sum of Rs.118 was shared among 50 boys and girls,each girl receive Rs.2.60 and boy receive Rs.1.80.Find the number of girls. A) 15 B)25 C)30 D)35

Description : Sum of Rs.118 was shared among 50 boys and girls,each girl receive Rs.2.60 and boy receive Rs.1.80.Find the number of girls. A) 15 B)25 C)30 D)35

Last Answer : D)35

The Average of marks obtained by 120 candidates in a certain examination is 35. If the average marks of passed candidates is 39 and that of failed candidates is 15, what is the number of candidates who passed the examination? A.90 B.100 C.108 D.115 E.None of these

Description : The Average of marks obtained by 120 candidates in a certain examination is 35. If the average marks of passed candidates is 39 and that of failed candidates is 15, what is the number of candidates who passed the examination? A.90 B.100 C.108 D.115 E.None of these

Last Answer : Answer – B (100) Explanation – Let the number of passed candidates be a Then total marks =>120 x 35 = 39 a + (120 – a) x 15 4200 = 39 a + 1800 – 15 a a = 100

If the compound interest accrued on an amount of Rs.15,000/- in two years is Rs.2,496/-.What is the rate of interest p.c.p.a.? a) 8 b) 12 c) 7.5 d) Cannot be determined e) None of these

Description : If the compound interest accrued on an amount of Rs.15,000/- in two years is Rs.2,496/-.What is the rate of interest p.c.p.a.? a) 8 b) 12 c) 7.5 d) Cannot be determined e) None of these

Last Answer : Let the rate of interest p.c.p.a. be x. 2496 =15000 * x /100 x = 16.64 16.64 is the rate of interest compounded for two year & for one year = 8% 8% C.I. table for two year. I year = 8% II year = 8.64 Total =16.64% Answer: a)

[(3/8) + (8/3)] – [(4/9) + (9/4)] = ? a) 0.5 b) 0.65 c) 0.9 d) 1.25 e) 0.35

Description : [(3/8) + (8/3)] – [(4/9) + (9/4)] = ? a) 0.5 b) 0.65 c) 0.9 d) 1.25 e) 0.35

Last Answer : ? = [(64+9) / 24] – [(81+16)/36] = (73/24) – (97/36) = (219 - 194)/72 = 25/72 = 0.347 = 0.35 Answer: e)

The average age of the students in a class is 14. The average age of half of the students in that class and the class teacher is 16. The average age of the remaining half of the students is 15. What is the number of students in that class? a) 20 b) 70 c) 80 d) Cannot be determined e) None of these

Description : The average age of the students in a class is 14. The average age of half of the students in that class and the class teacher is 16. The average age of the remaining half of the students is 15. What is the number of students in that class? a) 20 b) 70 c) 80 d) Cannot be determined e) None of these

Last Answer : Because total no. of students is not known we cannot find the answer. Answer: d)

Is it more profitable for Company M to produce Q? I. Product R sells at a price four times that of Q II. One unit of Q requires 2 units of labour, while one unit of R requires 5 units of labour. There is a no other constraint on production. If the question can be answered with the help of statement I alone, If the question can be answered with the help of statement II alone, If both,statement I and statement II are needed to answer the question If the question cannot be answered even with the help of both the statements. If the data in either statement I or statement II alone is sufficient to answer the question

Description : Is it more profitable for Company M to produce Q? I. Product R sells at a price four times that of Q II. One unit of Q requires 2 units of labour, while one unit of R requires 5 ... both the statements. If the data in either statement I or statement II alone is sufficient to answer the question

Last Answer : from statement I : Let the price of product Q be P' Then the price of product R is 4P From Statement II: Cost of product Q =2 Cost of product R=5 Therefore, Profit percentage of product ... )=80P-100 Hence, product R is more profitable. Both statements are required to answer the question Answer :c

A man distributed 43 chocolates to his children. How many of his children are more than five years old? I. A child older than five years gets 5 chocolates II. A child 5 years or younger in age gets 6 chocolates. If the question can be answered with the help of statement I alone, If the question can be answered with the help of statement II alone, If both,statement I and statement II are needed to answer the question If the question cannot be answered even with the help of both the statements. If the data in either statement I or statement II alone is sufficient to answer the question

Description : A man distributed 43 chocolates to his children. How many of his children are more than five years old? I. A child older than five years gets 5 chocolates II. A child 5 years or younger ... the statements. If the data in either statement I or statement II alone is sufficient to answer the question

Last Answer : From both statement I and II: Let the number of chocolates received by child older than 5 years be x and that of for child than 5 years or younger be y Therefore, 5x + 6 y = 43 Since x and y has to ... for the above equation will be x=5 and y=3 Hence, 5 children are older than 5 years Answer : c

Is it more profitable for Company M to produce Q? I. Product R sells at a price four times that of Q II. One unit of Q requires 2 units of labour, while one unit of R requires 5 units of labour. There is a no other constraint on production. If the question can be answered with the help of statement I alone, If the question can be answered with the help of statement II alone, If both,statement I and statement II are needed to answer the question If the question cannot be answered even with the help of both the statements. If the data in either statement I or statement II alone is sufficient to answer the question

Description : Is it more profitable for Company M to produce Q? I. Product R sells at a price four times that of Q II. One unit of Q requires 2 units of labour, while one unit of R requires 5 ... both the statements. If the data in either statement I or statement II alone is sufficient to answer the question

Last Answer : from statement I : Let the price of product Q be P' Then the price of product R is 4P From Statement II: Cost of product Q =2 Cost of product R=5 Therefore, Profit percentage of product ... )=80P-100 Hence, product R is more profitable. Both statements are required to answer the question Answer :c

X says to Y,”I am 3 times as old as you were 3 years ago”.How old is X? I. Y ‘s age 17 years from now is same as X’s present age. II. X’s age nine years from now is 3 times Y’s present age. If the question can be answered with the help of statement I alone, If the question can be answered with the help of statement II alone, If both,statement I and statement II are needed to answer the question If the question cannot be answered even with the help of both the statements. If the data in either statement I or statement II alone is sufficient to answer the question

Description : X says to Y, I am 3 times as old as you were 3 years ago .How old is X? I. Y s age 17 years from now is same as X's present age. II. X's age nine years from now is ... with the help of both the statements. If the data in either statement I or statement II alone is sufficient to answer the question

Last Answer : Let the current ages of X and Y be a and b respectively From the question: A=3(a-b) From statement I: A=b + 17 B = a-17 Therefore, a = 3(a-17-3) a=3a-60 2a=60 A=30 Hence, X ... a+9)/3 Substituting this in first equation, A=a+9-9 Hence, no result Therefore, statement I alone is sufficient Answer :a

Nothing is said to be done or believed to be done in good faith which is done or believed without due care & intention - is the definition of good faith contained in (a) Section 29 of IPC (b) Section 29A of IPC (c) Section 52 of IPC (d) Ssection 52A of IPC.

Description : Nothing is said to be done or believed to be done in good faith which is done or  believed without due care & intention - is the definition of good faith contained in (a) Section 29 of IPC (b) Section 29A of IPC (c) Section 52 of IPC (d) Ssection 52A of IPC.

Last Answer : (c) Section 52 of IPC

Five years ago, the age of Arun was 4 times the age of Sarmi after 10 years, Arun will be twice as old as Sarmi. Find the Present ages of Arun and sarmi? a) 30 years, 10.5 years b) 32 years, 11.5 years c) 34 years, 14.5 years d) 35 years, 12.5 years e) None of these

Description : Five years ago, the age of Arun was 4 times the age of Sarmi after 10 years, Arun will be twice as old as Sarmi. Find the Present ages of Arun and sarmi? a) 30 years, 10.5 years b) 32 years, 11.5 years c) 34 years, 14.5 years d) 35 years, 12.5 years e) None of these

Last Answer : Five years ago, x – 5/y – 5 = 4/1 x – 4y = – 15 —-(i) After 10 years, x + 10/y + 10 = 2/1 x – 2y = 10 —–(ii) From eqn (i) and (ii) => x = 35, y = 12.5 Answer: d)

Sum of present ages of A and B is 60 years. 5 years hence, their ages will be in the ratio 3:4. Find A’s present age. a) 25 years b) 30 years c) 35 years d) 40 years e) None of these

Description : Sum of present ages of A and B is 60 years. 5 years hence, their ages will be in the ratio 3:4. Find A’s present age. a) 25 years b) 30 years c) 35 years d) 40 years e) None of these

Last Answer : Sum of their present ages = 60 years sum of their ages, 5 years hence = 60 + (5 × 2) = 70 years. after 5 years, ratio of ages of A and B will be 3 : 4. A’s age after 5 years = (3/7) × 70 = 30 years A’s present age = 30 – 5 = 25 years Answer: a)

The average age of the whole class is 12.05 years. The average age of all girls is 12.5 years and the average age of boys is 11.75 years. If the total number of boys is 45 then what is the total number of girls in the class? a) 20 b) 25 c) 30 d) 35 e) 40

Description : The average age of the whole class is 12.05 years. The average age of all girls is 12.5 years and the average age of boys is 11.75 years. If the total number of boys is 45 then what is the total number of girls in the class? a) 20 b) 25 c) 30 d) 35 e) 40

Last Answer : Let the number of girls be x. The number of boys is 45. :. Total age of boys and girls in the class = (x+45) × 12.05 or, (x+45) × 12.05 = 45 × 11.75 + x × 12.5 or, 12.05x + 542.25 = 528.75 + 12.5x or, 13.5 = 0.45x or, x = 13.5/0.45 = 30 Answer is: c)

Ages of DEEPA and Subha are presently in the ratio of 5 : 6 respectively. Six years hence this ratio will become 6 : 7 respectively. What was Subha’s age 5 years ago? a) 33 years b) 32 years c) 35 years d) 31 years e) None of these

Description : Ages of DEEPA and Subha are presently in the ratio of 5 : 6 respectively. Six years hence this ratio will become 6 : 7 respectively. What was Subha’s age 5 years ago? a) 33 years b) 32 years c) 35 years d) 31 years e) None of these

Last Answer : Present ratio of Deepa&Subha = 5 : 6 Six year hence ratio of Deepa&Subha = 6 : 7 Difference between ratio = 1 Difference in ages between present & future = 6 year. 1 ratio=6 yrs & SUBHA's age = 6 6 =36 year 5 year ago ... = 7 6 = 42 year B's age 5 year ago = 42-6-5 = 42-11 = 31 year Answer: d)

One-fifth of a number is equal to 5/8th of another number. If 35 is added to the first number, it becomes four times of the second number. Find the second number. 1. 39 2. 70 3. 40 4. 25 5. None of these

Description : One-fifth of a number is equal to 5/8th of another number. If 35 is added to the first number, it becomes four times of the second number. Find the second number. 1. 39 2. 70 3. 40 4. 25 5. None of these

Last Answer : Answer- 3(40) Explanation:- (1/5)x =(5/8)y………..1 if 35 is added to first no. , x + 35= 4y so,x= 4y -35 put in eq 1… (1/5)( 4y-35) = (5/8)y y=40 =second number

5, 10, 35, 160, 785, _____. 1 : 2010 2 : 3910 3 : 2525 4 : 2860 5 : None of these

Description : 5, 10, 35, 160, 785, _____. 1 : 2010 2 : 3910 3 : 2525 4 : 2860 5 : None of these

Last Answer : Answer- 2 (3910) Explanationadd 5^1,5^2,5^3,5^4,5^5 and so on in each step.

16, 32, 35, 140, 145, 870, 877, _____ 1 : 7016 2 : 885 3 : 5020 4 : 6018 5 : None of these

Description : 16, 32, 35, 140, 145, 870, 877, _____ 1 : 7016 2 : 885 3 : 5020 4 : 6018 5 : None of these

Last Answer : Answer- 1(7016) Explanation16×2 =32 32+3=35 35×4=140 140+5=145 145×6=870 870+7=877 877×8=7016

A train 125 m long passes a man, running at 5 kmph in the same direction in which the train is going, in 10 seconds. The speed of the train is: A.35 km/hr B.50 km/hr C.48 km/hr D.55 km/hr E.None of these

Description : A train 125 m long passes a man, running at 5 kmph in the same direction in which the train is going, in 10 seconds. The speed of the train is: A.35 km/hr B.50 km/hr C.48 km/hr D.55 km/hr E.None of these

Last Answer : Answer – B (50 km/hr) Explanation – Let speed be S Relative speed = total lengths/time [ in this case man length is neglible compare to train so neglected] (S – 5) x 5/18 = 125 /10 S- 5 = (125/10)x(18/5) S-5 = 45 S=50 km/hr

Present ages of Simmi and Anu are in the ratio of 5 : 4 respectively. Three years hence, the ratio of their ages will become 11 : 9 respectively, What is Anu’s present age in years? A.20 B.24 C.28 D.35 E.None of these

Description : Present ages of Simmi and Anu are in the ratio of 5 : 4 respectively. Three years hence, the ratio of their ages will become 11 : 9 respectively, What is Anu’s present age in years? A.20 B.24 C.28 D.35 E.None of these

Last Answer : Answer – B (24) Explanation – Let the present ages of Simmi and Anu be 5x years and 4x years respectively Then, [5X + 3] / [4X + 3] =11/9 x=6 Anu’s present age = 4X = 24 years

Number of girls enrolled in only Dancing classes is what per cent of the boys enrolled in the same? (Rounded off to two digits after decimal) (1) 38•67 (2) 35•71 (3) 41•83 (4) 28•62 (5) None of these

Description : Number of girls enrolled in only Dancing classes is what per cent of the boys enrolled in the same? (Rounded off to two digits after decimal) (1) 38•67 (2) 35•71 (3) 41•83 (4) 28•62 (5) None of these

Last Answer : (2) 35•71

My brother is 3 years elder to me. My father was 28 years of age when my sister was born while my mother was 26 years of age when I was born. If my sister was 4 years of age when my brother was born, then what was the age my father when my brother was born? a) 35 years b) 34 years c) 33 years d) 32 years e) 30 years

Description : My brother is 3 years elder to me. My father was 28 years of age when my sister was born while my mother was 26 years of age when I was born. If my sister was 4 years of age when my brother was born, ... father when my brother was born? a) 35 years b) 34 years c) 33 years d) 32 years e) 30 years

Last Answer : Let my age = x Then My brother's age = x + 3 My mother's age = x + 26 My sister's age = (x + 3) + 4 = x + 7 My Father's age = (x + 7) + 28 = x + 35 => age my father when my brother was born = x + 35 – (x + 3) = 32. Answer: d)

3.25 × 16 + 7.25 × 8 = ? + 75 a) 83 b) 75 c) 61 d) 53 e) 35

Description : 3.25 × 16 + 7.25 × 8 = ? + 75 a) 83 b) 75 c) 61 d) 53 e) 35

Last Answer : ? + 75 = 52 + 58 = 110 ? = 110 – 75 = 35 Answer: e)

1824 ÷ 32 + 5040 ÷ ? – 5600 ÷ 35 = 37 a) 36 b) 48 c) 60 d) 72 e) 84

Description : 1824 ÷ 32 + 5040 ÷ ? – 5600 ÷ 35 = 37 a) 36 b) 48 c) 60 d) 72 e) 84

Last Answer : 57 + 5040 ÷ ? – 160 = 37 5040 ÷ ? = 37 – 57 + 160 = 140 = 5040 ÷ 140 = 36 Answer: a)

25,?,45,58,73,90,109 a) 33 b) 34 c) 35 d) 38 e) 36

Description : 25,?,45,58,73,90,109 a) 33 b) 34 c) 35 d) 38 e) 36

Last Answer : The series is 3×5+10=25,4×6+10=34,5×7+10=45,6×8+10=58,7×9+10=73,8× 10+10=90,9×11+10=109 Hence missing term=34 Answer: b)

A man on tour travels first 160 km at 64 km/hr and the next 160 km at 80 km/hr. The average speed for the first 320 km of the tour is: a) 35.55 km/hr b) 36 km/hr c) 71.11 km/hr d) 71 km/hr e) 69.69km/hr

Description : A man on tour travels first 160 km at 64 km/hr and the next 160 km at 80 km/hr. The average speed for the first 320 km of the tour is: a) 35.55 km/hr b) 36 km/hr c) 71.11 km/hr d) 71 km/hr e) 69.69km/hr

Last Answer : Total time taken = (160/64) + (160/80) = 9/2 hrs. Avg Speed – 320 × (2/9) km/hr = 71.11km/hr Answer: c)

40 39 32 37 16 ? -8 a) 35 b) 36 c) 33 d) 32 e) 40

Description : 40 39 32 37 16 ? -8 a) 35 b) 36 c) 33 d) 32 e) 40

Last Answer : The series is + (1^2 - 2), – (2^2 + 3), + (3^2 - 4), –(4^2 + 5), ..... Answer: a)

(331/30)+( 661/60) +(704/11) -35.013 + 36.026 =? a) 69 b) 67 c) 83 d) 89 e) 85

Description : (331/30)+( 661/60) +(704/11) -35.013 + 36.026 =? a) 69 b) 67 c) 83 d) 89 e) 85

Last Answer : ?=331/30 + 661/60 + 704/11 – 35.013 + 36.026 =11 + 11 + 64 -1.013 =86-1 ≈ 85 Answer: e)

√80 × (35/6) × (21)2 +343 =? a) 21125 b) 22981 c) 20781 d) 23159 e) 21230

Description : √80 × (35/6) × (21)2 +343 =? a) 21125 b) 22981 c) 20781 d) 23159 e) 21230

Last Answer : ?= √80 × (35/6) × (21)2 + 343 =√(16×5) × (35/6) × 441 + 343 =4√5 × (35/6) × 441 + 343 =2√5 ×35 ×147 + 343 =2 ×2.2 ×35 × 147 +343 = 22981 Answer: b)

987.67 × 123.35 ÷ 9 = ? a) 13411 b) 13621 c) 13489 d) 13551 e) 13721

Description : 987.67 × 123.35 ÷ 9 = ? a) 13411 b) 13621 c) 13489 d) 13551 e) 13721

Last Answer : ? = (987 × 123) / 9 = 13489 Answer: c)

The sum of ages of Mohan and his father is 35 years. When Mohan’s age will be equal to present age of his father, then sum of their ages will be 85 years. Find present age of the father. a) 20 years b) 25 years c) 30 years d) 32 years e) None of these

Description : The sum of ages of Mohan and his father is 35 years. When Mohan’s age will be equal to present age of his father, then sum of their ages will be 85 years. Find present age of the father. a) 20 years b) 25 years c) 30 years d) 32 years e) None of these

Last Answer : Sum of present ages = 35 years sum of their ages will be 85 years after (85-35) / 2 = 25 years from now. the father is 25 years older than his son. Present age of father = (35 + 25)/2 = 30 years. Answer: c)

On selling 25 balls at Rs. 1015, there is a profit equal to the cost price of 10 balls. What is the cost price of a ball? a) Rs. 31 b) Rs. 29 c) Rs. 35 d) Rs. 27 e) Rs. 39

Description : On selling 25 balls at Rs. 1015, there is a profit equal to the cost price of 10 balls. What is the cost price of a ball? a) Rs. 31 b) Rs. 29 c) Rs. 35 d) Rs. 27 e) Rs. 39

Last Answer : b Profit = (S.P of 25 balls) - (C.P of 25 balls) = 1015 - (C.P of 25 balls) Given that Profit = (C.P of 10 balls) => 1015 - (C.P of 25 balls) = (C.P of 10 balls) => (C.P of 25 balls) + (C.P of 10 balls) = 1015 => C.P of 35 balls = 1015 => C.P of 1 ball=1015 / 35 = Rs. 29

Two stations X and Y are 170 km apart on a straight line. One train starts from X at 6 a.m. and travels towards Y at 25 kmph. Another train starts from Y at 8 a.m. and travels towards X at a speed of 35 kmph. At what time will they meet? a) 11. 30 a.m b) 10.30 a.m c) 11 a.m d) 9 a.m e) 10 am

Description : Two stations X and Y are 170 km apart on a straight line. One train starts from X at 6 a.m. and travels towards Y at 25 kmph. Another train starts from Y at 8 a.m. and travels towards X at a speed of 35 kmph. At what time will they meet? a) 11. 30 a.m b) 10.30 a.m c) 11 a.m d) 9 a.m e) 10 am

Last Answer : e Suppose they meet z hours after 6 a.m. Distance covered by X in z hours = 25× z km. Distance covered by Y in (z - 2) hours = 35(z - 2) km. Therefore 25z + 35(z- 2) = 170 60z = 240 x = 4. So, they meet at 10 a.m.

Box A contains wheat worth Rs.30 per kg and box B contains wheat worth Rs.40 per kg.If both A and B are mixed in the the ratio 4:7 then the price of mixture per kg is A)36.36 B)35.80 C)42.50 D)31.30

Description : Box A contains wheat worth Rs.30 per kg and box B contains wheat worth Rs.40 per kg.If both A and B are mixed in the the ratio 4:7 then the price of mixture per kg is A)36.36 B)35.80 C)42.50 D)31.30

Last Answer : A)36.36