2 3 5 8 14 23 41 69 a) 5 b) 8 c) 14 d) 41 e) 69

2 3 5 8 14 23 41 69
a) 5
b) 8
c) 14
d) 41
e) 69
by

1 Answer

Answer :

The series is an alternate series, having
S 1 = 2 5 14 41; ×3 – 1 in each term
S 2 = 3 8 23 69; ×3 – 1 in each term
Answer: e)
by

Related questions

In what ratio must a person mix three kinds of Oats costing him Rs 1.20,Rs 1.44 and Rs 1.74 per Kg so that the mixture may be worth Rs 1.41 per Kg? A)11:77:7 B) 11:45:7 C)25:45:8 D) 27:23:6

Description : In what ratio must a person mix three kinds of Oats costing him Rs 1.20,Rs 1.44 and Rs 1.74 per Kg so that the mixture may be worth Rs 1.41 per Kg? A)11:77:7 B) 11:45:7 C)25:45:8 D) 27:23:6

Last Answer : A)11:77:7

19/14 x 12/72 x 18/29 x 767 = ? (Take 2 digits after the decimal point) a) 110.69 b) 118.78 c) 111.56 d) None e) 108.98

Description : 19/14 x 12/72 x 18/29 x 767 = ? (Take 2 digits after the decimal point) a) 110.69 b) 118.78 c) 111.56 d) None e) 108.98

Last Answer : 19/14 x 12/72 x 18/29 x 767 =? Sol: 1.35 x 0.16 x 0.62 x 767 = ? 102.71 = ? Answer: d)

8 1/4 ×5 2/3 – 4 1/6 × 4 1/5 = ? a) 31 b) 18 c) 14 d) 27 e) 23

Description : 8 1/4 ×5 2/3 – 4 1/6 × 4 1/5 = ? a) 31 b) 18 c) 14 d) 27 e) 23

Last Answer : ? = (33/4) × (27/5) – (25/6) × (21/5) =891/20 -35/2 ≈ 44.5 – 17.5 =27 Answer: d)

(37) 0.75 x [(7056) 0.25] ÷ (64) – 2 = (8) ? (Take 3 digits after the decimal point) a) 95.357 b) 69.567 c) 96.257 d) 78.584 e) 88.598

Description : (37) 0.75 x [(7056) 0.25] ÷ (64) – 2 = (8) ? (Take 3 digits after the decimal point) a) 95.357 b) 69.567 c) 96.257 d) 78.584 e) 88.598

Last Answer : (37) 0.75 x [(7056) 0.25] ÷ (64) – 2 = (8) ? Sol: 27.75 x 1764 ÷ 64 – 2 = 8 x ? 27.75 x 27.5625 – 2 = 8 x ? 762.859/8=? ? = 95.357 Answer: a)

Ravi borrowed some money at the rate of 4 p.c.p.a. for the first three years, at the rate of 8 p.c.p.a. for the next two years and at the rate of 9 p.c.p.a. for the period beyond 5 years. If he pays a total simple interest of 19,550 at the end of 7 years, how much money did he borrow? a) 39,500 b) 42,500 c) 41,900 d) 43,000 e) None of these

Description : Ravi borrowed some money at the rate of 4 p.c.p.a. for the first three years, at the rate of 8 p.c.p.a. for the next two years and at the rate of 9 p.c.p.a. for the period beyond 5 years. If he pays a ... 7 years, how much money did he borrow? a) 39,500 b) 42,500 c) 41,900 d) 43,000 e) None of these

Last Answer : Let the amount borrowed be Rs P Total amount of simple interest = (P×3×4)/100 + (p×2×8)/100 + (p×2×9)/100 = 19550 0.12P + 0.16P + 0.18P = 19550 0.46p= 19550 P = Rs. 42500 Answer: b)

The least number which should be added to 2497 so that the sum is exactly divisible by 5, 6, 4 and 3 is: A.10 B.14 C.23 D.30 E.None of these

Description : The least number which should be added to 2497 so that the sum is exactly divisible by 5, 6, 4 and 3 is: A.10 B.14 C.23 D.30 E.None of these

Last Answer : Answer – C (23) Explanation – L.C.M. of 5, 6, 4 and 3 = 60. On dividing 2497 by 60, the remainder is 37. Number to be added = (60 – 37) = 23

A two digit number is such that the sum of the digits is 11.When the number with the same digits is reversed is subtracted from this number, the difference is 9.What is the number? 1. 23 2. 24 3. 65 4. 14 5. 32

Description : A two digit number is such that the sum of the digits is 11.When the number with the same digits is reversed is  subtracted from this number, the difference is 9.What is the number? 1. 23 2. 24 3. 65 4. 14 5. 32

Last Answer : Answer- 3(65) Explanation:- let the number be written as xy x-ten’s place y units place x+y=11…………………1 (10x+y)-(10y+x)=9 10x+y-10y-x=9 9x-9y=9 x-y=1………………….2 Add (1) & (2) 2x=12 x=6 y=5 the number is 65

The ages of Gaurav and Goutham will be in the ratio 5 : 7 after ten years from now and will be in the ratio 13 : 18 after twelve years from now. Find the ratio of the sum of their ages 10 years hence to the sum of their ages 12 years hence. 1 : 25 : 27 2 : 13 : 15 3 : 14 : 17 4 : 18 : 23 5 : 30 : 31

Description : The ages of Gaurav and Goutham will be in the ratio 5 : 7 after ten years from now and will be in the ratio 13 : 18 after twelve years from now. Find the ratio of the sum of their ages 10 years hence to the sum of their ages 12 ... hence. 1 : 25 : 27 2 : 13 : 15 3 : 14 : 17 4 : 18 : 23 5 : 30 : 31

Last Answer : 5 : 30 : 31

12 22 69 272 1365 ? a) 8196 b) 8184 c) 8195 d) 6830 e) None of these

Description : 12 22 69 272 1365 ? a) 8196 b) 8184 c) 8195 d) 6830 e) None of these

Last Answer : 12 × 2 - 2 = 22 22 × 3 + 3 = 69 69 × 4 - 4 = 272 272 × 5 + 5 = 1365 1365 × 6 - 6 = 8184 Answer: b)

3, 9, 17, 27, 39, 53, ? a) 64 b) 69 c) 74 d) 78 e) 81

Description : 3, 9, 17, 27, 39, 53, ? a) 64 b) 69 c) 74 d) 78 e) 81

Last Answer : Series is 1× 2 + 1, 2 × 3 + 3, 3 × 4 + 5, 4 × 5 + 7, 5 × 6 + 9 Answer: b)

A man on tour travels first 160 km at 64 km/hr and the next 160 km at 80 km/hr. The average speed for the first 320 km of the tour is: a) 35.55 km/hr b) 36 km/hr c) 71.11 km/hr d) 71 km/hr e) 69.69km/hr

Description : A man on tour travels first 160 km at 64 km/hr and the next 160 km at 80 km/hr. The average speed for the first 320 km of the tour is: a) 35.55 km/hr b) 36 km/hr c) 71.11 km/hr d) 71 km/hr e) 69.69km/hr

Last Answer : Total time taken = (160/64) + (160/80) = 9/2 hrs. Avg Speed – 320 × (2/9) km/hr = 71.11km/hr Answer: c)

(331/30)+( 661/60) +(704/11) -35.013 + 36.026 =? a) 69 b) 67 c) 83 d) 89 e) 85

Description : (331/30)+( 661/60) +(704/11) -35.013 + 36.026 =? a) 69 b) 67 c) 83 d) 89 e) 85

Last Answer : ?=331/30 + 661/60 + 704/11 – 35.013 + 36.026 =11 + 11 + 64 -1.013 =86-1 ≈ 85 Answer: e)

1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16, 17, 18, 19, 20, 21, 23, 24, 25, 26, 27, 28, 29, 30, 31, 32, 33, 34, 35, 36, 37, 38, 39, 40, 41, 42, 43, 44, 45, 46, 47, 48, 49, 50'. What number is missing? -Riddles

Description : 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16, 17, 18, 19, 20, 21, 23, 24, 25, 26, 27, 28, 29, 30, 31, 32, 33, 34, 35, 36, 37, 38, 39, 40, 41, 42, 43, 44, 45, 46, 47, 48, 49, 50'. What number is missing? -Riddles

Last Answer : 22

The digits of a two-digit number are in the ratio of 2 : 3 and the number obtained by interchanging the digits is bigger than the original number by 27.What is the original number? 1. 63 2. 48 3. 96 4. 69 5. 66

Description : The digits of a two-digit number are in the ratio of 2 : 3 and the number obtained by interchanging the digits is bigger than the original number by 27.What is the original number? 1. 63 2. 48 3. 96 4. 69 5. 66

Last Answer : Answer- 4 (69) Explanation:- lets digit at tens and ones place be 2x and 3x So,number is 2x*10 + 3x After interchanging number will be 3x*10 +2x so, [3x*10 +2x] – [2x*10 + 3x]27 we get,x=3 so number =69

√730 + √840 - √960 + √1090 - √290 = ? a) 41 b) 33 c) 20 d) 28 e) 55

Description : √730 + √840 - √960 + √1090 - √290 = ? a) 41 b) 33 c) 20 d) 28 e) 55

Last Answer : ? = 27 + 29 – 31 + 33 – 17 = 41 Answer: a)

Number of girls enrolled in only Dancing classes is what per cent of the boys enrolled in the same? (Rounded off to two digits after decimal) (1) 38•67 (2) 35•71 (3) 41•83 (4) 28•62 (5) None of these

Description : Number of girls enrolled in only Dancing classes is what per cent of the boys enrolled in the same? (Rounded off to two digits after decimal) (1) 38•67 (2) 35•71 (3) 41•83 (4) 28•62 (5) None of these

Last Answer : (2) 35•71

What is the difference between money spent by both companies on tax ( in lakh Rs.)? a) 26.8 b) 24.4 c) 24.6 d) 23.8 e) None of these

Description : What is the difference between money spent by both companies on tax ( in lakh Rs.)? a) 26.8 b) 24.4 c) 24.6 d) 23.8 e) None of these

Last Answer : e) None of these

19 + (12 ÷ 4 × (240 × 1 ÷ 180)) × 6 ÷ (101 + 98 ÷ 7 - 113) – (7 ÷ 2 + 14 – 3.5 – 9 × 8.5) × 4 a) 201 b) 241 c) -241 d) -281 e) 281

Description : 19 + (12 ÷ 4 × (240 × 1 ÷ 180)) × 6 ÷ (101 + 98 ÷ 7 - 113) – (7 ÷ 2 + 14 – 3.5 – 9 × 8.5) × 4 a) 201 b) 241 c) -241 d) -281 e) 281

Last Answer : 240 1 180 = 4/3 12 4 (240 1 180) = 3 (4/3) = 4 101 + 98 7 - 113 = 101 + 14 - 113 = 2 19 + (12 4 (240 1 180)) 6 (101 + 98 7 - 113) = 19 + 4 6 2 = 19 + 4 3 = 31 7 2 ... 180)) 6 (101 + 98 7 - 113) - (7 2 + 14 - 3.5 - 9 8.5) 4 = 31 - (-250) = 281 Answer: e)

The sum of 5 natural numbers A, B, C, D, E is 126. It is known that A:B = 7:8, B:C = 2:3, C:D = 4:5, D:E = 5:7.What is the difference between A and E? a) 14 b) 22 c) 24 d) 28 e) 32

Description : The sum of 5 natural numbers A, B, C, D, E is 126. It is known that A:B = 7:8, B:C = 2:3, C:D = 4:5, D:E = 5:7.What is the difference between A and E? a) 14 b) 22 c) 24 d) 28 e) 32

Last Answer : A:B = 7:8 B:C = 2:3 = 8:12 SO, A:B:C = 7:8:12 C:D = 4:5 = 12:15 A:B:C:D = 7:8:12:15 D:E = 5:7 = 15:21 SO, A:B:C:D:E = 7:8:12:15:21 given x(7+8+12+15+21) = 126 or 63x = 126 or x =2 E – A = 21X – 7X = 14X = 28 Answer: d)

The average age of 30 students in a class is 12 years. The average age of a group of 5 of the students is 10 years and that of another group of 5 of them is 14 years. The average of the remaining students is : a) 8 years b) 10 years c) 12 years d) 14 years e) 15 years

Description : The average age of 30 students in a class is 12 years. The average age of a group of 5 of the students is 10 years and that of another group of 5 of them is 14 years. The average of the remaining students is : a) 8 years b) 10 years c) 12 years d) 14 years e) 15 years

Last Answer : Let it be x . Then : 5×10+5×14+20×x=30×12 20x=360-120 or 20x=240 or x = 12 Answer: c)

6 pens and 14 exercise books cost Rs.162. 5pens and 8 exercise books cost Rs.102. The ratio of cost of 1 pen to that of 1 exercise book is : a) 10 : 3 b) 2 : 3 c) 3 : 2 d) 5 : 6 e) None of these

Description : 6 pens and 14 exercise books cost Rs.162. 5pens and 8 exercise books cost Rs.102. The ratio of cost of 1 pen to that of 1 exercise book is : a) 10 : 3 b) 2 : 3 c) 3 : 2 d) 5 : 6 e) None of these

Last Answer : Let cost of 1 pen be Rs.x and that of 1 exercise book be Rs.y. Then 6x +14 y = 162 =>3x + 7y =81……..(1) 5x + 8y =102…………………………………………..(2) (1)× 5 – (2) × 3 =>11y=99=>y=9.Putting y=9 in equation (1),we get : x = 6 x : y =6 : 9 =2 : 3 Answer: b)

A shopkeeper declares that he sells rice at the cost price. However he uses a weight of 425 grams. Instead of 500 grams, what is his percentage of profit? a) a) 16 5/6 b) 15 c) c) 20 7/23 d) 25 e) None of these

Description : A shopkeeper declares that he sells rice at the cost price. However he uses a weight of 425 grams. Instead of 500 grams, what is his percentage of profit? a) a) 16 5/6 b) 15 c) c) 20 7/23 d) 25 e) None of these

Last Answer : % profit = Loss/Actual Weight x 100 = 500 – 425/500 × 100 = 75/500 x 100 = 15% Answer: b)

The population of city S increased from 650,000 in 2000 to 700,000 in 2010, and it is projected that the population will increase by the same number from 2010 to 2020. Approximately what is the projected percent increase in population from 2010 to 2020 ? a) 7.1% b) 7.7% c) 8.3% d) 14.3% e) 15.3%

Description : The population of city S increased from 650,000 in 2000 to 700,000 in 2010, and it is projected that the population will increase by the same number from 2010 to 2020. Approximately what is the projected percent increase in population from 2010 to 2020 ? a) 7.1% b) 7.7% c) 8.3% d) 14.3% e) 15.3%

Last Answer : Required percentage = (750000 - 700000)/700000 * 100 = 7.14% Answer: a)

24+(72 ÷ 48×8+14) × 36 ÷ (3×4) + 36 ÷ 3 ×4 a) 120 b) 140 c) 160 d) 180 e) None of these

Description : 24+(72 ÷ 48×8+14) × 36 ÷ (3×4) + 36 ÷ 3 ×4 a) 120 b) 140 c) 160 d) 180 e) None of these

Last Answer : 72÷48×8+14 = (72/48) × 8 + 14 = (3/2) × 8 + 14 = 12 +14 = 26 24 + (72 ÷ 48 × 8 + 14) ×36 ÷ (3 × 4) + 36 ÷ 3 × 4 = 24 + 26 × 36÷12 + 36 ÷ 3 × 4 = 24 + 26 × 3 + 12 × 4 = 24 + 78 + 48 = 150 Answer: e)

1 ? 27 64 125 a) 14 b) 4 c) 9 d) 8 e) None of these

Description : 1 ? 27 64 125 a) 14 b) 4 c) 9 d) 8 e) None of these

Last Answer : Answer: d)

A two digit number exceeds forty percent of another two digit number by 16. If the sum of these two digit numbers is 72, which of the following is the difference between these two digit numbers ? a) 10 b) 6 c) 8 d) 14 e) None of these

Description : A two digit number exceeds forty percent of another two digit number by 16. If the sum of these two digit numbers is 72, which of the following is the difference between these two digit numbers ? a) 10 b) 6 c) 8 d) 14 e) None of these

Last Answer : c) 8 Let first two digit no. and second two digit no. be x and y respectively. x = y × 40/100 +16 x - 2y/5 = 16....(i) x + y = 72...(ii) From equation (i) and (ii) x = 32, y = 40 Difference = 8 Answer: c)

Suresh and Ramesh are twins. In a form by mistake, Suresh reverses the last 2 digits of his year of birth, and this makes him 9 years older than Ramesh. With this mistake, the sum of their ages in 2015 becomes 43. How old will Ramesh be 2021? a) 17 b) 19 c) 21 d) 23 e) 25

Description : Suresh and Ramesh are twins. In a form by mistake, Suresh reverses the last 2 digits of his year of birth, and this makes him 9 years older than Ramesh. With this mistake, the sum of their ages in 2015 becomes 43. How old will Ramesh be 2021? a) 17 b) 19 c) 21 d) 23 e) 25

Last Answer : Let the correct ages of Ramesh and Suresh be X in 2015 (since they are twins, they will have the same age) Given: 2x + 9 = 43 Or x = 17 years in 2015. Age in 2021 = 17 + 6 = 23 Note: year of birth = 2015 – 17 = 1998. Reversing, Suresh = 1989 or 9 year older. Answer: d)

In a class there are 15 boys and 10 girls. Three students are selected at random. The difference between the probability that 2 boys and 1 girl are selected compared to 1 boy and 2 girls are selected is: a) 23/78 b) 19/88 c) 15/92 d) 4/23 e) 7/46

Description : In a class there are 15 boys and 10 girls. Three students are selected at random. The difference between the probability that 2 boys and 1 girl are selected compared to 1 boy and 2 girls are selected is: a) 23/78 b) 19/88 c) 15/92 d) 4/23 e) 7/46

Last Answer : 2 boys, 1 gi(Prl = (15c2×10c1) / 25c3 = 1050/2300 1 boy, 2 girls = (15c1×10c2) / 25c3 = 675/2300 Difference = (1050 - 675)/2300 = 375/2300 = 15/92 Answer: c)

21, 23, 29, 53, 173, _____ a) 210 b) 893 c) 720 d) 253 e) 293

Description : 21, 23, 29, 53, 173, _____ a) 210 b) 893 c) 720 d) 253 e) 293

Last Answer : Difference between each successive tam is factorial of number starting from 2, like 23-21 = 2, then 29-23 = 6 means 3!, then 53-29 = 24 means 4!, then next difference is 173-53 = 120 means 5!, so next difference would be 6! i.e. 720 so term will be 173+720 = 893. Answer: b)

23.98 × 62.49 × 12.03 = ? × 29.97 a) 500 b) 600 c) 900 d) 450 e) 750

Description : 23.98 × 62.49 × 12.03 = ? × 29.97 a) 500 b) 600 c) 900 d) 450 e) 750

Last Answer : 24× 62.5× 12 = ? × 30 24× 750 = ? × 30 ? = (24× 750) / 30 = 600 Answer: b)

The ratio between two number is 3:4 ,if each number be increased by 9, the ratio becomes 18:23 find the sum of the number a) 135 b) 105 c) 155 d) 165 e) None of these

Description : The ratio between two number is 3:4 ,if each number be increased by 9, the ratio becomes 18:23 find the sum of the number a) 135 b) 105 c) 155 d) 165 e) None of these

Last Answer : Let the two numbers be 3x and 4x. When they are increased by 9 they become 3x + 9 and 4x + 9. It is given that the ratio is 18:23 Thus, 3x + 9/4x + 9 = 18:23 23(3x + 9) = 18(4x + 9) 69x + 207 = 72x ... = -45 X = 15 Thus two numbers are 3x15 = 45 and 4 x 15 = 60 And the sum is 60+45 = 105 Answer: b)

3599 ÷ 224.95 × 23.04 = ? + 16.98 × 11.03 a) 130 b) 210 c) 180 d) 115 e) 155

Description : 3599 ÷ 224.95 × 23.04 = ? + 16.98 × 11.03 a) 130 b) 210 c) 180 d) 115 e) 155

Last Answer : 3600 ÷ 225 × 23 = ? +17 × 11 =>16 × 23 = ? + 187 => ? = 368 – 187 =181 ≈ 180 Answer: c)

Kathir and Anand can do a work in 20 days and 30 days respectively. Kathir started the work and left after 4 days. Anand took over and completed the work. In how many days was the total work completed? a) 28 days b) 20 days c) 23 days d) 25 days e) 26 days

Description : Kathir and Anand can do a work in 20 days and 30 days respectively. Kathir started the work and left after 4 days. Anand took over and completed the work. In how many days was the total work completed? a) 28 days b) 20 days c) 23 days d) 25 days e) 26 days 

Last Answer : a Kathir’s one day’s work= 1/20 Kathir’s 4 day’s work =4* (1/20) = 1/5 Work left= 1-1/5 = 4 /5 Anand’s one day’s work= 1/30 Anand can do work in = (4/5) *(30/ 1) = 24 days So total days = 24+4 = 28 days

Two trains running in opposite directions cross a man standing on the platform in 27 seconds and 17 seconds respectively and they cross each other in 23 seconds. The ratio of their speeds is: A.1 : 3 B.3 : 4 C.3 : 2 D.Data inadequate E.None of these

Description : Two trains running in opposite directions cross a man standing on the platform in 27 seconds and 17 seconds respectively and  they cross each other in 23 seconds. The ratio of their speeds is: A.1 : 3 B.3 : 4 C.3 : 2 D.Data inadequate E.None of these

Last Answer : Answer - C (3 : 2) Explanation - Let the speeds of the two trains be x m/sec and y m/sec respectively. Then, length of the first train = 27x metres, and length of the second train = 17y metres. relative speed = total ... 23x + 23y = 27x + 17 y 27x-23x= 23 y-17y 4x=6y x/y=6/4=3/2= 3:2

What is the ratio between money spent by company Q on tax and money spent by P on salary? a) 23:121 b) 33:144 c) 47:144 d) 144:157 e) None of these

Description : What is the ratio between money spent by company Q on tax and money spent by P on salary? a) 23:121 b) 33:144 c) 47:144 d) 144:157 e) None of these

Last Answer : e) None of these

Three consecutive numbers such that twice the first, 3 times the second and 4 times the third together make 182. The numbers in question are 1. 18, 22 and 23 2. 18, 19 and 20 3. 19, 20 and 21 4. 20, 21 and 22 5. 21, 22 and 23

Description : Three consecutive numbers such that twice the first, 3 times the second and 4 times the third together make 182. The numbers in question are 1. 18, 22 and 23 2. 18, 19 and 20 3. 19, 20 and 21 4. 20, 21 and 22 5. 21, 22 and 23

Last Answer : Answer- 3( 19,20,21) Explanation:- let number be x,x+1,x+2 2x + 3(x+1)+4(x+2)=180 x=19 so numbers are 19,20,21

Two concentric circles have radii of 23 cm and 9 cm. A rectangle has an area equal to the annular space between the above two circles. If the breadth of the rectangle is 22 cm then find its length. 1 : 32 cm 2 : 48 cm 3 : 76 cm 4 : 64 cm 5 : None of these

Description : Two concentric circles have radii of 23 cm and 9 cm. A rectangle has an area equal to the annular space between the above two circles. If the breadth of the rectangle is 22 cm then find its length. 1 : 32 cm 2 : 48 cm 3 : 76 cm 4 : 64 cm 5 : None of these

Last Answer : 4 : 64 cm

What is the total number of literate people in city 'A'? 1) 21.62 lakh 2) 22.18 lakh 3) 23.94 lakh 4) 24.63 lakh 5) 25.02 lakh

Description : What is the total number of literate people in city 'A'? 1) 21.62 lakh 2) 22.18 lakh 3) 23.94 lakh 4) 24.63 lakh 5) 25.02 lakh

Last Answer : 3) 23.94 lakh

Four years ago, the average of a 4 member family was 40 years. 3 years ago, a boy got married to a 23 years old girl, and they had a baby boy last year. what is the average of the family 2 years from now assuming no one joins or leaves from the family in the next 2 years.

Description : Four years ago, the average of a 4 member family was 40 years. 3 years ago, a boy got married to a 23 years old girl, and they had a baby boy last year. what is the average of the family 2 years from now assuming no ... leaves from the family in the next 2 years. a) 40 b) 42.5 c) 36.5 d) 34 e) 35.8

Last Answer : Four years ago, sum of all the family members age = 4× 40 = 160 three years ago, sum of all the family members age = 164 + 23 = 187 last year, sum = 197 (187 + 5 + 5) two years from now, sum = 197 + 18 = 215 hence, average = 215/6 = 35.8 Answer: e)

13.5 × 14 + 22.5 × 18 – 4.7 × 30 = ? a) 405 b) 423 c) 435 d) 453 e) 481

Description : 13.5 × 14 + 22.5 × 18 – 4.7 × 30 = ? a) 405 b) 423 c) 435 d) 453 e) 481

Last Answer : ?=189+405-141 = 453 Answer: d)

Five years ago, the age of Arun was 4 times the age of Sarmi after 10 years, Arun will be twice as old as Sarmi. Find the Present ages of Arun and sarmi? a) 30 years, 10.5 years b) 32 years, 11.5 years c) 34 years, 14.5 years d) 35 years, 12.5 years e) None of these

Description : Five years ago, the age of Arun was 4 times the age of Sarmi after 10 years, Arun will be twice as old as Sarmi. Find the Present ages of Arun and sarmi? a) 30 years, 10.5 years b) 32 years, 11.5 years c) 34 years, 14.5 years d) 35 years, 12.5 years e) None of these

Last Answer : Five years ago, x – 5/y – 5 = 4/1 x – 4y = – 15 —-(i) After 10 years, x + 10/y + 10 = 2/1 x – 2y = 10 —–(ii) From eqn (i) and (ii) => x = 35, y = 12.5 Answer: d)

One year ago the ratio between Sam and Ash’s age was 4:3. One year hence the ratio of their ages will be 5:4. What is the sum of their present ages in years? A.14 B.16 C.18 D.12 E.None of these

Description : One year ago the ratio between Sam and Ash’s age was 4:3. One year hence the ratio of their ages will be 5:4. What is the sum of their present ages in years? A.14 B.16 C.18 D.12 E.None of these

Last Answer : Answer - B (16) Explanation - Let one year ago Sam's age be 4X years And, Ash's age be 3X years Present age of Sam = (4X + 1) years Present age of Ash= (3X + 1) years One year hence Sam's age = (4X + 2) ... = 2 Sum of their present ages = 4X + 1 + 3X + 1 = 7X + 2 = 7 x 2 + 2 = 16 years.

Sush was thrice as old as Poonam 6 years back. Sush will be 5/3 times as old as Poonam 6 years hence. How old is Poonam today? A.20 B.14 C.12 D.15 E.None of these

Description : Sush was thrice as old as Poonam 6 years back. Sush will be 5/3 times as old as Poonam 6 years hence. How old is Poonam today? A.20 B.14 C.12 D.15 E.None of these

Last Answer : Answer – C (12) Explanation – Let Poonam age 6 years back = x. Then, Sush age 6 years back = 3x. (5/3) * (X + 6 + 6) = (3X + 6 + 6) So 5(x+ 12) = 3(3x+ 12), so x=6. Poonam Age = (x+ 6) years = 12 years

Three pipes A, B and C can fill a tank in 6 hours. After working at it together for 2 hours, C is closed and A and B can fill the remaining part in 7 hours. The number of hours taken by C alone to fill the tank is: a) 10 b) 14 c) 12 d) 13 e) 15

Description : Three pipes A, B and C can fill a tank in 6 hours. After working at it together for 2 hours, C is closed and A and B can fill the remaining part in 7 hours. The number of hours taken by C alone to fill the tank is: a) 10 b) 14 c) 12 d) 13 e) 15

Last Answer : (A+B+C) - (A+B) (A+B+C) =1/6 and (A+B+C) in 2hrs=2/6 and remaining part 1-2/6=2/3. So (A+B) in 7 hrs is 2/ (3*7) =2/21. 1/6-2/21=1/14 so answer is 14. Answer: b)

3 ? 113 673 3361 13441 40321 a) 13 b) 14 c) 15 d) 16 e) 17

Description : 3 ? 113 673 3361 13441 40321 a) 13 b) 14 c) 15 d) 16 e) 17

Last Answer : The series is: 3 × 8 – 7 = 17; 17 × 7 – 6 = 113; 113 × 6 – 5 = 673; 673 × 5 – 4 = 3361; 3361 × 4 – 3 = 13441; 13441 × 3 – 2 = 40321 Answer: e)

24 14 26 ? 28 16 30 a) 13 b) 17 c) 15 d) 11 e) 20

Description : 24 14 26 ? 28 16 30 a) 13 b) 17 c) 15 d) 11 e) 20

Last Answer : The series consists of two series 1 and 2: Series 1 : 24 26 28 30 +2 +2 +2 Series 2 : 14 15 16 +1 +1 Answer: c)

By selling 45 lemons for Rs 40, a man loses 20%.How many should he sell for Rs 24 to gain 20% in the transaction? a) 19 b) 22 c) 20 d) 18 e) 14

Description : By selling 45 lemons for Rs 40, a man loses 20%.How many should he sell for Rs 24 to gain 20% in the transaction? a) 19 b) 22 c) 20 d) 18 e) 14

Last Answer : Selling price = Rs. 40 Loss = 20% Therefore, cost price = 40×100 /(100 - 20) = Rs. 50 Therefore, cost price of each lemon = Rs. 50/45 Now, selling price = Rs. 24 Profit = 20% Cost price = 24×100/120 = Rs. 20 Number of lemons for Rs. 20 = 20/(50/45) = 900/50 = 18 Answer: d)

√1369 ×√1444 +√?=1420 a) 14 b) 196 c) 198 d) 194 e) 16

Description : √1369 ×√1444 +√?=1420 a) 14 b) 196 c) 198 d) 194 e) 16

Last Answer : √1369 ×√1444 - √? =1420 Or, √(37)2 ×√(38)2×√? = 1420 Or,37 × 38 ×√? = 1420 Or,1406 + √? =1420 Or, √? = 1420 -1406 =14 ? = 196 Answer: b)

A is 2 years older than B who is twice as old as C. If sum of ages of A, B and C is 37 years, find the age of A. a) 7 years b) 9 years c) 14 years d) 16 years e) None of these

Description : A is 2 years older than B who is twice as old as C. If sum of ages of A, B and C is 37 years, find the age of A. a) 7 years b) 9 years c) 14 years d) 16 years e) None of these

Last Answer : Let the age of C be x years. Then age of B = 2x and age of A = 2x + 2 sum of ages of A, B and C = (2x + 2) + (2x) + x = 37 (5x + 2) = 37  x = 7 Age of A = 2x + 2 = 16 years Answer: d)

Present ages of A and B are 50 years and 18 years respectively. In how many years will A be twice as old as B? a) 14 years b) 15 years c) 16 years d) 18 years e) None of these

Description : Present ages of A and B are 50 years and 18 years respectively. In how many years will A be twice as old as B? a) 14 years b) 15 years c) 16 years d) 18 years e) None of these

Last Answer : Let the required time be x years. then (50+x) = 2 (18 + x) = 50 + x = 36 + 2x  x = 14 years. Alternative method : Double of B’s age = 2 × 18 = 36 years difference between A’s present age and double of B’s age = 50 – 36= 14 years. A will be twice of B’s age after 14 years. Answer: a)