A simple steam engine receives steam from the boiler at 180˚C and exhausts directly into the air at 100˚C. What is the upper limit of its efficiency?  a. 11.28 %  b. 36.77 %  c. 20.36 %  d. 17.66 %

A simple steam engine receives steam from the boiler at 180˚C and exhausts directly into the air at 100˚C. What is the upper limit of its efficiency?  a. 11.28 %  b. 36.77 %  c. 20.36 %  d. 17.66 %
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17.66 %
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Last Answer : increases

The efficiency of Carnot cycle is maximum for  (a) gas engine  (b) well lubricated engine  (c) petrol engine  (d) steam engine  (e) reversible engine.

Description : The efficiency of Carnot cycle is maximum for  (a) gas engine  (b) well lubricated engine  (c) petrol engine  (d) steam engine  (e) reversible engine.

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What is the resulting pressure when one pound of air at 15 psia and 200 ˚F is heated at constant volume to 800 ˚F?  A.15 psia  B. 28.6 psia  C. 36.4 psia.  D. 52.1 psia Formula : T1/p1 = T2/p2 p2= p1T2 / T1

Description : What is the resulting pressure when one pound of air at 15 psia and 200 ˚F is heated at constant volume to 800 ˚F?  A.15 psia  B. 28.6 psia  C. 36.4 psia.  D. 52.1 psia Formula : T1/p1 = T2/p2 p2= p1T2 / T1

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A steam calorimeter receives steam from a pipe at 0.1 MPa and 20°SH. For a pipe steam pressure of 2 MPa, what is the quality of the steam?  a) 95.56%  b) 70.10%  c) 95.20%  d) 85.10% Formula: h1 = hf1 + x1hfg1

Description : A steam calorimeter receives steam from a pipe at 0.1 MPa and 20°SH. For a pipe steam pressure of 2 MPa, what is the quality of the steam?  a) 95.56%  b) 70.10%  c) 95.20%  d) 85.10% Formula: h1 = hf1 + x1hfg1

Last Answer : 265.4°C, 430.7kJ/kg, 71.4kJ/kg, 1.0327kJ/(kg)(K),502.1 kJ/kg

The thermodynamic difference between a Rankine cycle working with saturated steam and the Carnot cycle is that  (a) carnot cycle can’t work with saturated steam  (b) heat is supplied to water at temperature below the maximum temperature of the cycle  (c) a rankine cycle receives heat at two places  (d) rankine cycle is hypothetical  (e) none of the above.

Description : The thermodynamic difference between a Rankine cycle working with saturated steam and the Carnot cycle is that  (a) carnot cycle can't work with saturated steam  (b) heat is supplied to water at temperature ... heat at two places  (d) rankine cycle is hypothetical  (e) none of the above.

Last Answer : Answer : b

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Description : A 600kg hammer of a pile driver is lilted 2m the pilling head. What is the change of potential energy? If the hammer is realest. What will be its velocity and the instant if it sticks the pilling?  a. 10,772 N-m and 5.26m/s ...  c. 11,772 N-m and 6.26m/s  d. 11,77 2N-m and5.26m/s ∫PE = mgo(∫Z)/gc

Last Answer : 11,772 N-m and 6.26m/s

From the steam table, determine the average constant pressure specific heat (c) of steam at 10 kPa and45.8 ˚C  A.1.79 kJ/ kg-˚C  B.10.28 kJ/ kg-˚C  C.30.57 kJ/ kg-˚C  D. 100.1 kJ/ kg-˚C Formula: h = c T ∆ ∆ From the steam table At 47.7 ˚C h= 2588.1 kJ/ kg At 43.8 ˚C h= 2581.1 kJ/ kg

Description : From the steam table, determine the average constant pressure specific heat (c) of steam at 10 kPa and45.8 ˚C  A.1.79 kJ/ kg-˚C  B.10.28 kJ/ kg-˚C  C.30.57 kJ/ kg-˚C  D. 100.1 kJ/ kg-˚C Formula: h = c T ∆ ∆ From the steam table At 47.7 ˚C h= 2588.1 kJ/ kg At 43.8 ˚C h= 2581.1 kJ/ kg

Last Answer : 1.79 kJ/ kg-˚C

On volume basis, air contains following parts of oxygen  (a) 21  (b) 23  (c) 25  (d) 77  (e) 79.

Description : On volume basis, air contains following parts of oxygen  (a) 21  (b) 23  (c) 25  (d) 77  (e) 79.

Last Answer : Answer : a

on analyzing the result of an competitive exam the teacher found that the average for the entire the class was 69 marks. If we say that average of 10 % of the students scored 77 marks and average of 28 % of the students scored 66 marks, then calculate average marks of the remaining students of the class A) 67.54 B) 68.26 C) 66.91 D) 69.06

Description :  on analyzing the result of an competitive exam the teacher found that the average for the entire the class was 69 marks. If we say that average of 10 % of the students scored 77 marks and average of 28 % of the ... marks of the remaining students of the class A) 67.54 B) 68.26 C) 66.91 D) 69.06 

Last Answer : D) average of entire class = 69marks average of 28 % of the students = 66 marks average of 10% of the students = 77 marks then % of remaining students = (100- 10 - 28) = 62% let the average of 62% of the ... (62*x)+770+1848= 6900 62 * x = 6900-770-1848 62*x = 4282 x = 69.06

Which of the following represents the perpetual motion of the first kind  (a) engine with 100% thermal efficiency  (b) a fully reversible engine  (c) transfer of heat energy from low temperature source to high temperature source  (d) a machine that continuously creates its own energy  (e) production of energy by temperature differential in sea water at different levels.

Description : Which of the following represents the perpetual motion of the first kind  (a) engine with 100% thermal efficiency  (b) a fully reversible engine  (c) transfer of heat energy from low ... its own energy  (e) production of energy by temperature differential in sea water at different levels.

Last Answer : Answer : d

The efficiency and work ratio of a simple gas turbine cycle are  A.low  B.very low  C.high  D.very high

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For heat engine operating between two temperatures (T1>T2), what is the maximum efficiency attainable?  A. Eff = 1 – (T2/T1)  B. Eff = 1 - (T1/T2)  C. Eff = T1 - T2  D. Eff = 1 - (T2/T1)^2

Description : For heat engine operating between two temperatures (T1>T2), what is the maximum efficiency attainable?  A. Eff = 1 – (T2/T1)  B. Eff = 1 - (T1/T2)  C. Eff = T1 - T2  D. Eff = 1 - (T2/T1)^2

Last Answer : Eff = 1 – (T2/T1)

What is the highest efficiency of heat engine operating between the two thermal energy reservoirs at temperature limits?  A. Ericson efficiency  B. Otto efficiency  C. Carnot efficiency  D. Stirling efficiency

Description : What is the highest efficiency of heat engine operating between the two thermal energy reservoirs at temperature limits?  A. Ericson efficiency  B. Otto efficiency  C. Carnot efficiency  D. Stirling efficiency

Last Answer : Carnot efficiency

The efficiency of a Carnot engine depends on  (a) working substance  (b) design of engine  (c) size of engine  (d) type of fuel fired  (e) temperatures of source and sink.

Description : The efficiency of a Carnot engine depends on  (a) working substance  (b) design of engine  (c) size of engine  (d) type of fuel fired  (e) temperatures of source and sink.

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An actual engine is to be designed having same efficiency as the Carnot cycle. Such a proposition is  (a) feasible  (b) impossible  (c) possible  (d) possible, but with lot of sophistications  (e) desirable.

Description : An actual engine is to be designed having same efficiency as the Carnot cycle. Such a proposition is  (a) feasible  (b) impossible  (c) possible  (d) possible, but with lot of sophistications  (e) desirable.

Last Answer : Answer : d

Carnot cycle efficiency depends upon  (a) properties of the medium/substance used  (b) condition of engine  (c) working condition  (d) temperature range of operation  (e) effectiveness of insulating material around the engine.

Description : Carnot cycle efficiency depends upon  (a) properties of the medium/substance used  (b) condition of engine  (c) working condition  (d) temperature range of operation  (e) effectiveness of insulating material around the engine.

Last Answer : Answer : d

Carnot cycle has maximum efficiency for  (a) reversible engine  (b) irreversible engine  (c) new engine  (d) petrol engine  (e) diesel engine.

Description : Carnot cycle has maximum efficiency for  (a) reversible engine  (b) irreversible engine  (c) new engine  (d) petrol engine  (e) diesel engine.

Last Answer : Answer : a

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Description : The more effective way of increasing efficiency of Carnot engine is to  (a) increase higher temperature  (b) decrease higher temperature  (c) increase lower temperature  (d) decrease lower temperature  (e) keep lower temperature constant.

Last Answer : Answer : d

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Description : Steam is throttled to 0.1 MPa with 20 degrees of superheat. (a) What is the quality of throttled steam if its pressure is 0.75 MPa (b) What is the enthalpy of the process?  a) 97.6%,2713 kJ/kg  b) -97.6%, 2713 kJ/kg  c) 87.6%,3713 kJ/kg  d) -87.6%, 3713 kJ/kg

Last Answer : 97.6%,2713 kJ/kg

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Description : Two masses, one of the 10kg and the other unknown, are placed on a scale in a region where g = 9.67 m/sec2 . The combined weight of these two masses is 174.06 N. Find the unknown mass in kg.  a. 20 kg  b. 19 kg  c. 18 kg  d. 17 kg formula: m=Fg k / g

Last Answer : 18 kg

What horse power is required to isothermally compress 800 ft^3 of Air per minute from 14.7 psia to 120 psia?  A. 28 hp  B.108 hp  C.256 hp  D.13900 hp Formula: W= p1V1 ln (p1/p2) Power = dW / dt

Description : What horse power is required to isothermally compress 800 ft^3 of Air per minute from 14.7 psia to 120 psia?  A. 28 hp  B.108 hp  C.256 hp  D.13900 hp Formula: W= p1V1 ln (p1/p2) Power = dW / dt

Last Answer : 108 hp

A locomotive of weight 100 tonnes is attached to train of wagons weighing 1000 tonnes. The locomotive pulls the wagons with a constant velocity of 36 km/hour. When the coupling between the train and wagons breaks, the wagons roll on 95 m in 10 sec. The distance between the locomotive and the wagons at this instant assuming that the forces acting on the train are unaltered would be a.0.36 m b.0.44 m c.0.77 m. d.0.5 m e.0.66 m

Description : A locomotive of weight 100 tonnes is attached to train of wagons weighing 1000 tonnes. The locomotive pulls the wagons with a constant velocity of 36 km/hour. When the coupling between the train and wagons breaks, the wagons roll on 95 m in ... would be a.0.36 m b.0.44 m c.0.77 m. d.0.5 m e.0.66 m

Last Answer : d. 0.5 m

Producer gas is obtained by  A. partial combustion of coal, coke, anthracite coal or charcoal in a mixed air steam blast  B. carbonisation of bituminous coal  C. passing steam over incandescent coke  D. passing air and a large amount of steam over waste coal at about 650°C

Description : Producer gas is obtained by  A. partial combustion of coal, coke, anthracite coal or charcoal in a mixed air steam blast  B. carbonisation of bituminous coal  C. passing steam over incandescent coke  D. passing air and a large amount of steam over waste coal at about 650°C

Last Answer : Answer: A

Producer gas is obtained by  A. partial combustion of coal, coke, anthracite coal or charcoal in a mixed air steam blast  B. carbonisation of bituminous coal  C. passing steam over incandescent coke  D. passing air and a large amount of steam over waste coal at about 650°C

Description : Producer gas is obtained by  A. partial combustion of coal, coke, anthracite coal or charcoal in a mixed air steam blast  B. carbonisation of bituminous coal  C. passing steam over incandescent coke  D. passing air and a large amount of steam over waste coal at about 650°C

Last Answer : Answer: A

Water gas is obtained by passing air and a large amount of steam over waste coal at about 650°C.  A.Correct  B.Incorrect

Description : Water gas is obtained by passing air and a large amount of steam over waste coal at about 650°C.  A.Correct  B.Incorrect

Last Answer : Answer: B

Which of the following can be regarded as gas so that gas laws could be applicable, within the commonly encountered temperature limits.  (a) 02, N2, steam, C02  (b) Oz, N2, water vapour  (c) S02, NH3, C02, moisture  (d) 02, N2, H2, air  (e) steam vapours, H2, C02.

Description : Which of the following can be regarded as gas so that gas laws could be applicable, within the commonly encountered temperature limits.  (a) 02, N2, steam, C02  (b) Oz, N2, water vapour  (c) S02, NH3, C02, moisture  (d) 02, N2, H2, air  (e) steam vapours, H2, C02.

Last Answer : Answer : d

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Description : While swimming a depth of 13m in a fresh water lake a fish emits an air bubble of volume 2 mm² atmospheric pressure is 100kpa what is the original pressure of the bubble.  a. 217.17 kpa  b. 119 kpa  c. 326.15 kpa  d. 210 kap Pabs = Pg + Patm

Last Answer : 217.17 kpa

The ratio of two specific heats of air is equal to  (a) 0.17  (b) 0.24  (c) 0.1  (d) 1.41  (e) 2.71.

Description : The ratio of two specific heats of air is equal to  (a) 0.17  (b) 0.24  (c) 0.1  (d) 1.41  (e) 2.71.

Last Answer : Answer : d

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Description : Specific heat of air at constant pressure is equal to  (a) 0.17  (b) 0.21  (c) 0.24  (d) 1.0  (e) 1.41

Last Answer : Answer : c

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Description : What is the weight of a66-kgm man at standard condition? (Formula: Fg= mg / k)  a. 66 kgf  b. 66 kgm  c. 66 lbm  d. 66 gf

Last Answer : 66 kgf

A manufacturer claims to have a heat engine capable of developing 20 h.p. by receiving heat input of 400 kcal/mt and working between the temperature limits of 227° C and 27° C. His claim is  (a) justified  (b) not possible  (c) may be possible with lot of sophistications  (d) cost will be very high  (e) theroretically possible.

Description : A manufacturer claims to have a heat engine capable of developing 20 h.p. by receiving heat input of 400 kcal/mt and working between the temperature limits of 227° C and 27° C. His claim is  ( ... be possible with lot of sophistications  (d) cost will be very high  (e) theroretically possible.

Last Answer : Answer : b

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Description : It is the unbalanced force developed in a turbo jet engine that is caused by the difference in the momentum of the low-velocity air entering the engine and the high velocity exhaust gases leaving the engine.  a. Fall  b. Lift  c. Drag  d. Thrust

Last Answer : Thrust

A 0.064 kg of octane vapor (MW = 114) is mixed with0.91 kg of air (MW = 29.0) in the manifold of an Engine. The total pressure in the manifold is 86.1 kPa, and a temperature is 290 K. assume octane behaves ideally. What is the partial pressure of the air in the mixture in KPa?  a. 46.8  b. 48.6  c. 84.6  d. 64.8

Description : A 0.064 kg of octane vapor (MW = 114) is mixed with0.91 kg of air (MW = 29.0) in the manifold of an Engine. The total pressure in the manifold is 86.1 kPa, and a temperature is 290 K. assume octane behaves ideally. What is ... of the air in the mixture in KPa?  a. 46.8  b. 48.6  c. 84.6  d. 64.8

Last Answer : 84.6

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Description : If air is at pressure, p, of 3200 lbf/ft2 , and at a temperature, T, of 800 ˚R, what is the specific volume, v? (R=5303 ft-lbf/lbm-˚R, and air can be modeled as an ideal gas.)  A.9.8 ft^3/lbm  B.11.2 ft^3/lbm  C.13.33 ft^3/lbm  D.14.2 ft^3/lbm Formula: pv = RT v = RT / p

Last Answer : 13.33 ft^3/lbm

The boiling of water into steam in an open container is an example of a/an _________ process.  a. adiabatic  b. isochoric  c. isobaric  d. zero work

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Last Answer : 796.32 L

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Description : The value of gas constant (R) in S. I. units is  A. 0.287 J/kgK  B. 2.87 J/kgK  C. 28.7 J/kgK  D. 287 J/kgK

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For a certain gas R = 320 J/kg.K and cv= 0.84kJ/kg.K. Find k?  a. 1.36  b. 1.37  c. 1.38  d. 1.39 formula: k= R / cv+1

Description : For a certain gas R = 320 J/kg.K and cv= 0.84kJ/kg.K. Find k?  a. 1.36  b. 1.37  c. 1.38  d. 1.39 formula: k= R / cv+1

Last Answer : 1.38

There are 1.36 kg of gas, for which R = 377 J/kg.k and k = 1.25, that undergo a nonflow constant volume process from p1 = 551.6 kPa and t1 = 60°C to p2 = 1655 kPa. During the process the gas is internally stirred and there are also added 105.5 kJ of heat. Determine t2. (Formula: T2= T1p2/ p1)  a. 999 K  b. 888 K  c. 456 K  d. One of the above

Description : There are 1.36 kg of gas, for which R = 377 J/kg.k and k = 1.25, that undergo a nonflow constant volume process from p1 = 551.6 kPa and t1 = 60°C to p2 = 1655 kPa. During the process the gas is internally stirred and ... (Formula: T2= T1p2/ p1)  a. 999 K  b. 888 K  c. 456 K  d. One of the above

Last Answer : 999 K

At steam point, the temperature of water and its vapor at standard pressure are:  a. Extremes or maximum  b. unity  c. in equilibrium  d. undefined

Description : At steam point, the temperature of water and its vapor at standard pressure are:  a. Extremes or maximum  b. unity  c. in equilibrium  d. undefined

Last Answer : in equilibrium

1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16, 17, 18, 19, 20, 21, 23, 24, 25, 26, 27, 28, 29, 30, 31, 32, 33, 34, 35, 36, 37, 38, 39, 40, 41, 42, 43, 44, 45, 46, 47, 48, 49, 50'. What number is missing? -Riddles

Description : 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16, 17, 18, 19, 20, 21, 23, 24, 25, 26, 27, 28, 29, 30, 31, 32, 33, 34, 35, 36, 37, 38, 39, 40, 41, 42, 43, 44, 45, 46, 47, 48, 49, 50'. What number is missing? -Riddles

Last Answer : 22

Which of the following is the other term used for enthalpy-entropy diagram?  a. Enthalpy diagram  b. Mollier diagram  c. Steam diagram  d. Entropy chart

Description : Which of the following is the other term used for enthalpy-entropy diagram?  a. Enthalpy diagram  b. Mollier diagram  c. Steam diagram  d. Entropy chart

Last Answer : Mollier diagram

What is the temperature when water and vapor are in equilibrium with the atmospheric pressure?  a. Ice point  b. Steam point  c. Critical point  d. Freezing point

Description : What is the temperature when water and vapor are in equilibrium with the atmospheric pressure?  a. Ice point  b. Steam point  c. Critical point  d. Freezing point

Last Answer : Steam point

What is the temperature when water and vapor are in the equilibrium with the atmospheric pressure?  a. Ice point  b. Steam point  c. Critical point  d. Freezing point

Description : What is the temperature when water and vapor are in the equilibrium with the atmospheric pressure?  a. Ice point  b. Steam point  c. Critical point  d. Freezing point

Last Answer : Steam point

Wet steam at 1 MPa flowing through a pipe is throttled to a pressure of 0.1 MPa. If the throttling temperature is110°C, What is the quality of the steam in the pipe?  a) 96%  b) 86%  c) 76%  d) 66%

Description : Wet steam at 1 MPa flowing through a pipe is throttled to a pressure of 0.1 MPa. If the throttling temperature is110°C, What is the quality of the steam in the pipe?  a) 96%  b) 86%  c) 76%  d) 66%

Last Answer : 96%

Water vapor at 100 KPa and 150°C is compressed isothermally until half the vapor has condensed. How much work must be performed on the steam in this compression process per kilogram?  a) -1384.7 kJ  b) 1384.7 kJ  c) -2384.7 kJ  d) 2384.7 kJ

Description : Water vapor at 100 KPa and 150°C is compressed isothermally until half the vapor has condensed. How much work must be performed on the steam in this compression process per kilogram?  a) -1384.7 kJ  b) 1384.7 kJ  c) -2384.7 kJ  d) 2384.7 kJ

Last Answer : -1384.7 kJ

A 1-kg steam-water mixture at 1.0 MPa is contained in an inflexible tank. Heat is added until the pressure rises to 3.5 MPa and the temperature to 400°. Determine the heat added.  a) 1378.7 kJ  b) 1348.5 kJ  c) 1278,7 kJ  d) 1246,5 kJ Formula: Q = (h2 – p2v2) –(h1 –p1v1)

Description : A 1-kg steam-water mixture at 1.0 MPa is contained in an inflexible tank. Heat is added until the pressure rises to 3.5 MPa and the temperature to 400°. Determine the heat added.  a) 1378.7 kJ  b) 1348.5 kJ  c) 1278,7 kJ  d) 1246,5 kJ Formula: Q = (h2 – p2v2) –(h1 –p1v1)

Last Answer : 1378.7 kJ

Find ∫ for steam at 100 psia and 600°F.If h = 1329.6 and v = 6.216  a. 1214 Btu / lb  b. 1234 Btu /lb  c. 1342 Btu / lb  d. 1324 Btu /lb formula: ∫ = h– pv/ J

Description : Find ∫ for steam at 100 psia and 600°F.If h = 1329.6 and v = 6.216  a. 1214 Btu / lb  b. 1234 Btu /lb  c. 1342 Btu / lb  d. 1324 Btu /lb formula: ∫ = h– pv/ J

Last Answer : 1214Btu / lb

Calculate the entropy of steam at 60psiawith a quality of 0.8  A. 0.4274 BTU/lbm-˚R  B. 0.7303 BTU/lbm-˚R  C. 1.1577 BTU/lbm-˚R  D. 1.2172 BTU/lbm-˚R Formula: fromthe steamtable at 60 psia: sƒ = 0.4274 BTU/lbm-˚R sƒg = 1.2172 BTU/lbm-˚R) s = sƒ + x sƒg where x = is the quality

Description : Calculate the entropy of steam at 60psiawith a quality of 0.8  A. 0.4274 BTU/lbm-˚R  B. 0.7303 BTU/lbm-˚R  C. 1.1577 BTU/lbm-˚R  D. 1.2172 BTU/lbm-˚R Formula: fromthe steamtable at 60 psia: sƒ = 0.4274 BTU/lbm-˚R sƒg = 1.2172 BTU/lbm-˚R) s = sƒ + x sƒg where x = is the quality

Last Answer : 1.1577 BTU/lbm-˚R

A vessel with a volume of cubic meter contains liquid water and water vapor ion equilibrium at 600 kPa. The liquid water has mass of1kg. Using the steam table, calculate the mass of the water vapor.  A. 0.99kg  B. 1.57 kg  C. 2.54 kg  D. 3.16 kg Formula: from the steam table at 600kPa vƒ = 0.001101 m^3 / kg vg = 0.3157 m^3 / kg Vtot = mƒ vƒ + mg vg mg = (tot-mƒ vƒ) / vg

Description : A vessel with a volume of cubic meter contains liquid water and water vapor ion equilibrium at 600 kPa. The liquid water has mass of1kg. Using the steam table, calculate the mass of the water vapor.  A. 0.99kg  B. 1.57 kg  C ... / kg vg = 0.3157 m^3 / kg Vtot = mƒ vƒ + mg vg mg = (tot-mƒ vƒ) / vg

Last Answer : 3.16 kg