From the steam table, determine the average constant pressure specific heat (c) of steam at 10 kPa and45.8 ˚C
A.1.79 kJ/ kg-˚C
B.10.28 kJ/ kg-˚C
C.30.57 kJ/ kg-˚C
D. 100.1 kJ/ kg-˚C
Formula: h = c T ∆ ∆
From the steam table
At 47.7 ˚C h= 2588.1 kJ/ kg
At 43.8 ˚C h= 2581.1 kJ/ kg
A.1.79 kJ/ kg-˚C
B.10.28 kJ/ kg-˚C
C.30.57 kJ/ kg-˚C
D. 100.1 kJ/ kg-˚C
Formula: h = c T ∆ ∆
From the steam table
At 47.7 ˚C h= 2588.1 kJ/ kg
At 43.8 ˚C h= 2581.1 kJ/ kg