Find the change in internal energy of 5 lb. of oxygen gas when the temperature changes from 100 ˚F to 120 ˚F. CV = 0.157 BTU/lbm-˚R  A.14.7 BTU  B.15.7 BTU  C. 16.8 BTU  D. 15.9 BTU Formula: U= mcv T

Find the change in internal energy
of 5 lb. of oxygen gas when the
temperature changes from 100 ˚F to 120
˚F. CV = 0.157 BTU/lbm-˚R
 A.14.7 BTU
 B.15.7 BTU
 C. 16.8 BTU
 D. 15.9 BTU
Formula: U= mcv T
by

1 Answer

Answer :

15.7 BTU
by

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Description : General gas equation is  (a) PV=nRT  (b) PV=mRT  (d) PV = C  (c) PV=KiRT  (e) Cp-Cv = Wj

Last Answer : Answer : b

A cylinder contains oxygen at a pressure of 10 atm and a temperature of 300 K. The volume of the cylinder is 10 liters. What is the mass of the oxygen in grams? Molecular weight (MW) of oxygen is 32 g/mole?  a. 125.02  b. 130.08  c. 135.05  d. 120.04

Description : A cylinder contains oxygen at a pressure of 10 atm and a temperature of 300 K. The volume of the cylinder is 10 liters. What is the mass of the oxygen in grams? Molecular weight (MW) of oxygen is 32 g/mole?  a. 125.02  b. 130.08  c. 135.05  d. 120.04

Last Answer : 130.08 {(10atm)(10)(32)/(0.0821) (300K)}

Calculate the power output in horsepower of an 80-kg man that climbs a flight of stairs 3.8 m high in 4.0 s.  a) 744.8 hp  b) 0.998 hp  c) 746 hp  d) 1.998 hp Formula: Power = Fd/t = mgh/t F = W = mg d = h

Description : Calculate the power output in horsepower of an 80-kg man that climbs a flight of stairs 3.8 m high in 4.0 s.  a) 744.8 hp  b) 0.998 hp  c) 746 hp  d) 1.998 hp Formula: Power = Fd/t = mgh/t F = W = mg d = h

Last Answer : 0.998 hp

A fluid flows in a steady manner between two section in a flow line at section 1: A 1 = 1ft², V1 = 100fpm, volume1 of 4ft³/lb. at sec2: A2 = 2 ft², p= 0.20 lb/ft³ calculate the velocity at section 2.  a. 625 fpm  b. 567 fpm  c. 356 fpm  d. None of the above

Description : A fluid flows in a steady manner between two section in a flow line at section 1: A 1 = 1ft², V1 = 100fpm, volume1 of 4ft³/lb. at sec2: A2 = 2 ft², p= 0.20 lb/ft³ calculate the velocity at section 2.  a. 625 fpm  b. 567 fpm  c. 356 fpm  d. None of the above

Last Answer : 625 fpm

One kg of carbon monoxide requires __________ kg of oxygen to produce 11/7 kg of carbon dioxide gas.  A. All  B. 4/7  C. 11/4  D. 9/7

Description : One kg of carbon monoxide requires __________ kg of oxygen to produce 11/7 kg of carbon dioxide gas.  A. All  B. 4/7  C. 11/4  D. 9/7

Last Answer : Answer: B

In a non-flow reversible process for which p = (- 3V+ 15) x 105N/m2,V changes from 1 m to 2 m3. The work done will be about  (a) 100 xlOO5 joules  (b) lxlO5 joules  (c) 10 xlO5 joules  (d) 10 xlO5 kilo joules  (e) 10xl04ki\ojoules.

Description : In a non-flow reversible process for which p = (- 3V+ 15) x 105N/m2,V changes from 1 m to 2 m3. The work done will be about  (a) 100 xlOO5 joules  (b) lxlO5 joules  (c) 10 xlO5 joules  (d) 10 xlO5 kilo joules  (e) 10xl04ki\ojoules.

Last Answer : Answer : c

The mechanical equivalent of heat is  a. joule  b. calorie  c. Btu  d. Specific heat

Description : The mechanical equivalent of heat is  a. joule  b. calorie  c. Btu  d. Specific heat

Last Answer : joule

1 British thermal unit (BTU) is equivalent to how many joules?  A. 1016  B. 1043  C. 1023  D. 1054

Description : 1 British thermal unit (BTU) is equivalent to how many joules?  A. 1016  B. 1043  C. 1023  D. 1054

Last Answer : 1054

The value for the ΔU of a system is -120 J. If the system is known to have absorbed 420 J of heat, how much work was done?  a. -540 J  b. -640 J  c. -740 J  d. -840 J formula: ΔU = q +w

Description : The value for the ΔU of a system is -120 J. If the system is known to have absorbed 420 J of heat, how much work was done?  a. -540 J  b. -640 J  c. -740 J  d. -840 J formula: ΔU = q +w

Last Answer : -540 J