Twenty grams of oxygen gas are
compressed at a constant temperature
of 30 ˚C to 5%of their original volume.
What work is done on the system.
 A.824 cal
 B.924 cal
 C.944 cal
 D.1124 cal
Formula:
W = -mRTln (V2/V1)
Where R = (1.98 cal/gmole·K) (32
g/gmole)

1 Answer

Answer :

1124 cal

Related questions

Description : What is the equation for the work done by a constant temperature system?  A. W = mRTln(V2-V1)  B. W = mR( T2-T1 ) ln( V2/V1)  C. W = mRTln (V2/V1)  D. W = RT ln (V2/V1) Formula : W=∫ pdV lim1,2 ∫ = mRT / V

Last Answer : W = mRTln (V2/V1)

Description : Helium ( R= 0.4698 BTU/lbm-˚R ) is compressed isothermally from 14.7 psia and 68 ˚F. The compression ratio is 1:4. Calculate the work done by the gas.  A. –1454 BTU/lbm  B. -364 BTU/lbm  C.-187BTU/lbm  D.46.7 BTU/lbm Formula: W = RT ln (V2/V1)

Last Answer : -364 BTU/lbm

Description : Gas is enclosed in a cylinder with a weighted piston as the stop boundary. The gas is heated and expands from a volume of 0.04 m^3 to 0.10 m^3 at a constant pressure of 200kPa.Calculate the work done by the system.  A. 8 kJ  B. 10 kJ  C.12 kJ  D.14 kJ Formula: W = p(V2-V1)

Last Answer : 12 kJ

Description : A certain gas with cp = 0.529Btu/lb°R and R = 96.2ft/lbºR expands from 5 ft and 80ºF to 15 ft while the pressure remains constant at 15.5 psia.  a. T2=1.620ºR, ∫H = 122.83 Btu  b. T2 = 2°R, ∫H = 122.83 Btu  c. ... , ∫H = 122.83 Btu  d. T2 = 1°R, ∫H = 122.83 Btu T2= V2(t2)/V1 and ∫H = mcp (T2-T1)

Last Answer : T2=1.620ºR, ∫H = 122.83 Btu

Description : From the steam table, determine the average constant pressure specific heat (c) of steam at 10 kPa and45.8 ˚C  A.1.79 kJ/ kg-˚C  B.10.28 kJ/ kg-˚C  C.30.57 kJ/ kg-˚C  D. 100.1 kJ/ kg-˚C Formula: h = c T ∆ ∆ From the steam table At 47.7 ˚C h= 2588.1 kJ/ kg At 43.8 ˚C h= 2581.1 kJ/ kg

Last Answer : 1.79 kJ/ kg-˚C

Description : A gas is compressed in a cylinder by a movable piston to a volume onehalf its original volume. During the process 300 kJ heat left the gas and internal energy remained same. The work done on gas in Nm will be  (a) 300 Nm  (b) 300,000 Nm  (c) 30 Nm  (d) 3000 Nm  (e) 30,000 Nm.

Last Answer : Answer : b

Description : A cylinder contains oxygen at a pressure of 10 atm and a temperature of 300 K. The volume of the cylinder is 10 liters. What is the mass of the oxygen in grams? Molecular weight (MW) of oxygen is 32 g/mole?  a. 125.02  b. 130.08  c. 135.05  d. 120.04

Last Answer : 130.08 {(10atm)(10)(32)/(0.0821) (300K)}

Description : A certain gas, with cp = 0.529Btu/ lb. °Rand R = 96.2ft.lb/lb. °R, expands from 5 cu ft and 80°F to 15 cu ft while the pressure remains constant at 15.5psia. Compute for T2.  a.1520°R  b. 1620°R  c. 1720°R  d. 1820°R formula: T2= T1V2/V1

Last Answer : 1620°R

Description : A certain gas, with cp = 0.529Btu/lb.°R and R = 96.2 ft.lb/lb.°R, expands from 5 cu ft and 80°F to 15 cu ft while the pressure remains constant at 15.5 psia. Compute for T2. (Formula: T2= T1V2/V1)  a. 460°R  b. 270°R  c. 1620 °R  d. None of the above

Last Answer : 1620 °R

Description : A perfect gas has a value of R= 319.2 J/ kf.K and k= 1.26. If 120 kJ are added to 2.27 kf\g of this gas at constant pressure when the initial temp is 32.2°C? Find T2.  a. 339.4 K  b. 449.4 K  c. 559.4K  d. 669.4K formula: cp = kR/ k-1 Q= mcp(T2-T1)

Last Answer : 339.4 K

Description : Which of the following is the mathematical representation of the Charles’s law?  A. V1/V2= P2/P1  B. V1/T1=V2/T2  C. V1/T2=V2/T1  D. V1/V2=√P2/√P1

Last Answer : V1/T1=V2/T2

Description : Assuming compression is according to the Law PV = C, Calculate the initial volume of the gas at a pressure of 2 bars w/c will occupy a volume of 6m³ when it is compressed to a pressure of 42 Bars.  a) 130m³  b) 136m³  c) 120m³  d) 126m³ Formula: P1V1/T1 =P2V2/T2

Last Answer : 126m³

Description : If the initial volume of an ideal gas is compressed to one-half its original volume and to twice its original temperature, the pressure:  a. doubles  b. halves  c. quadruples  d. triples

Last Answer : quadruples

Description : Oxygen at 15ºC and 10.3 Mpa gauge pressure occupies 600L. What is the occupied by the oxygen at 8.28 Mpa gauge pressure and 35ºC?  a. 789.32 L  b. 796.32 L  c. 699 L  d. 588 L V2= P1V1/T1P2

Last Answer : 796.32 L

Description : Twenty grams of ice at 0˚C melts to water at 0˚C. How much does the entropy of the 20g change in this process?  a. 30.5 J/K  b. 24.6 J/K  c. 21.3 J/K  d. 15.7 J/K

Last Answer : 24.6 J/K

Description : There are 1.36 kg of gas, for which R = 377 J/kg.k and k = 1.25, that undergo a nonflow constant volume process from p1 = 551.6 kPa and t1 = 60°C to p2 = 1655 kPa. During the process the gas is internally stirred and ... (Formula: T2= T1p2/ p1)  a. 999 K  b. 888 K  c. 456 K  d. One of the above

Last Answer : 999 K

Description : An ideal gas is compressed in a cylinder so well insulated that there is essentially no heat transfer. The temperature of gas  a. Remains constant  b. increases  c. decreases  d. is basically zero

Last Answer : increases

Description : If air is at pressure, p, of 3200 lbf/ft2 , and at a temperature, T, of 800 ˚R, what is the specific volume, v? (R=5303 ft-lbf/lbm-˚R, and air can be modeled as an ideal gas.)  A.9.8 ft^3/lbm  B.11.2 ft^3/lbm  C.13.33 ft^3/lbm  D.14.2 ft^3/lbm Formula: pv = RT v = RT / p

Last Answer : 13.33 ft^3/lbm

Description : Two thick slices of bread, when completely oxidized by the body, can supply 200,000 cal of heat. How much work is this equivalent to?  a) 4,190,000 joules  b) 8,390,000 joules  c) 839, ... d) 419 000 joules Formula: J =Work/Heat J = mechanical equivalent of heat whose value is 4.19 joules/calorie

Last Answer : 419 000 joules

Description : How many joules of work is the equivalent of 15000 cal of heat?  a) 62850 joules  b) 3579.95 joules  c) 14995.81 joules  d) 15004.19 joules Formula: J =Work/Heat J = mechanical equivalent of heat whose value is 4.19 joules/calorie

Last Answer : 62850 joules

Description : According to which law, all perfect gases change in volume by l/273th of their original volume at 0°C for every 1°C change in temperature when pressure remains constant  (a) Joule’s law  (b) Boyle’s law  (c) Regnault’s law  (d) Gay-Lussac law  (e) Charles’ law.

Last Answer : Answer : e

Description : The heat supplied to the gaS at constant volume is (where m = Mass of gas, cv = Specific heat at constant volume, cp = Specific heat at constant pressure, T2 – T1 = Rise in temperature, and R = Gas constant)  A. mR(T2 – T1)  B. mcv(T2 – T1)  C. mcp(T2 – T1)  D. mcp(T2 + T1)

Last Answer : Answer: B

Description : A gas is enclosed in a cylinder with a weighted piston as the top boundary. The gas is heated and expands from a volume of 0.04 m3 to 0.10 m3 at a constant pressure of 200 kPa. Find the work done on the system.  a. 5 kJ  b. 15 kJ  c. 10 kJ  d. 12 kJ

Last Answer : 12 kJ

Description : The mass of one mole of a substance in grams is known as ______.  A. Molar weight  B. Molar mass  C. Molar volume  D. Molar constant

Last Answer : Molar mass

Description : If a gas is heated against a pressure, keeping the volume constant, then work done will be equal to  (a) + v  (b) – ve  (c) zero  (d) pressure x volume  (e) any where between zero and infinity.

Last Answer : Answer : c

Description : Addition of heat at constant pressure to a gas results in  (a) raising its temperature  (b) raising its pressure  (c) raising its volume  (d) raising its temperature and doing external work  (e) doing external work.

Last Answer : Answer : d

Description : Find the change in internal energy of 5 lb. of oxygen gas when the temperature changes from 100 ˚F to 120 ˚F. CV = 0.157 BTU/lbm-˚R  A.14.7 BTU  B.15.7 BTU  C. 16.8 BTU  D. 15.9 BTU Formula: U= mcv T

Last Answer : 15.7 BTU

Description : The value for the ΔU of a system is -120 J. If the system is known to have absorbed 420 J of heat, how much work was done?  a. -540 J  b. -640 J  c. -740 J  d. -840 J formula: ΔU = q +w

Last Answer : -540 J

Description : The volume of a gas under standard atmospheric pressure & 76 cmHg is 200m³. What is the volume when pressure is 80 cmHg if the temperature is unchanged?  a) 180 in³  b) 170 in³  c) 160 in³  d) 190 in³ Formula: P2V2 = P1V1

Last Answer : 190 in³

Description : If a system absorbs 500 cal of heat at the same time does 400J of work, find the change in internal energy of the system.  a. 1400 J  b. 1700 J  c. 1900 J  d. 1500 J

Last Answer : 1700 J

Description : Ten cu. ft of air at 300psia and 400°F is cooled to 140°F at constant volume. What is the transferred heat?  a.-120Btu  b. -220Btu  c.-320Btu  d. -420Btu formula: Q= mcv(T2-T1)

Last Answer : -420Btu

Description : Ten cu ft. of air at 300 psia 400°F is cooled to 140°F at constant volume. What is the final pressure? (formula: p2 = p1T2/T1)  a. 0  b. 209 psia  c. - 420 psia  d. None of the above

Last Answer : 209 psia

Description : What is the resulting pressure when one pound of air at 15 psia and 200 ˚F is heated at constant volume to 800 ˚F?  A.15 psia  B. 28.6 psia  C. 36.4 psia.  D. 52.1 psia Formula : T1/p1 = T2/p2 p2= p1T2 / T1

Last Answer : 28.6 psia

Description : Work done is zero for the following process  (a) constant volume  (b) free expansion  (c) throttling  (d) all Of the above  (e) none of the above.

Last Answer : Answer : d

Description : The volume of a gas under constant pressure increases or decrease with temperature.  a. Gay- Lussac’s Law  b. Ideal Gas Law  c. Charles’ Law  d. Boyle’s Law

Last Answer : Charles’ Law

Description : What Law states that the pressure of gas is inversely proportional to its volume at constant temperature?  a. Charles’ law  b. Gay-Lussac’s Law  c. Boyle’s Law  d. Dalton’s Law

Last Answer : Boyle’s Law

Description : The volume of a confined gas is held constant, the pressure is directly proportional to the absolute temperature.  a. Charle’s Law  b. Boyle’s Law  c. Joule’s Law  d. Specific Heat

Last Answer : Boyle’s Law

Description : The pressure of the confined gas is held constant, the volume directly proportional to the absolute temperature.  a. Charle’s Law  b. Boyle’s Law  c. Zeroth Law  d. Gas Law

Last Answer : Charle’s Law

Description : “If the temperature o f a fixed quantity of a gas is held constant during a change of state, the volume varies inversely with the absolute pressure.  a. Charle’s Law  b. Boyle’s Law  c. Dalton’s Law  d. Amagat’s Law

Last Answer : Boyle’s Law

Description : A gas having a volume of100 ft³ at 27ºC is expanded to 120 ft³by heated at constant pressure to what temperature has it been heated to have this new volume?  a. 87°C  b. 85°C  c. 76°C  d. 97°C t2= T2–T1

Last Answer : 87°C

Description : An ideal gas is maintained at constant temperature. If the pressure on the gas is doubled, the volume is  a. increased fourfold  b. doubled  c. reduced by half  d. decreased by a quarter

Last Answer : reduced by half

Description : The gas in a constant gas thermometer cooled to absolute zero would have _________.  a. no volume  b. no pressure  c. zero temperature at all scales  d. none of the above

Last Answer : no pressure

Description : What gas thermometer is based on the principle that at low pressure, the temperature of a gas is proportional to its pressure at constant volume?  A. Constant-pressure gas thermometer  B. Isobaric gas thermometer  C. Isometric gas thermometer  D. Constant-volume gas thermometer

Last Answer : Constant-volume gas thermometer

Description : The temperatures of the ideal gas temperature scale are measured by using a ______.  A. Constant-volume gas thermometer  B. Constant-mass gas thermometer  C. Constant-temperature gas thermometer  D. Constant-pressure gas thermometer

Last Answer : Constant-volume gas thermometer

Description : For a perfect gas, according to Boyle’s law (where p = Absolute pressure, v = Volume, and T = Absolute temperature)  A. p v = constant, if T is kept constant  B. v/T = constant, if p is kept constant  C. p/T = constant, if v is kept constant  D. T/p = constant, if v is kept constant

Last Answer : Answer: A

Description : The specific heat at constant volume is  A. the amount of heat required to raise the temperature of unit mass of gas through one degree, at constant pressure  B. the amount of heat required to raise ... to raise the temperature of 1 kg of water through one degree  D. any one of the above

Last Answer : Answer: B

Description : The absolute pressure of a given mass of a perfect gas varies inversely as its volume, when the temperature remains constant. This statement is known as Charles’ law.  A. Yes  B. No

Last Answer : Answer: B

Description : According to Gay-Lussac law, the absolute pressure of a given mass of a perfect gas varies __________ as its absolute temperature, when the volume remains constant.  A. directly  B. indirectly

Last Answer : Answer: A

Description : The amount of heat required to raise the temperature of the unit mass of gas through one degree at constant volume, is called  A.specific heat at constant volume  B.specific heat at constant pressure  C.kilo Joule  D.none of these

Last Answer : Answer: A

Description : A perfect gas at 27°C is heated at constant pressure till its volume is double. The final temperature is  (a) 54°C  (b) 327°C  (c) 108°C  (d) 654°C  (e) 600°C

Last Answer : Answer : b