A certain gas with cp =
0.529Btu/lb°R and R = 96.2ft/lbºR
expands from 5 ft and 80ºF to 15 ft while
the pressure remains constant at 15.5
psia.
 a. T2=1.620ºR, ∫H = 122.83 Btu
 b. T2 = 2°R, ∫H = 122.83 Btu
 c. T2 = 2.620ºR, ∫H = 122.83 Btu
 d. T2 = 1°R, ∫H = 122.83 Btu
T2= V2(t2)/V1 and ∫H = mcp (T2-T1)

1 Answer

Answer :

T2=1.620ºR, ∫H = 122.83 Btu

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