Description : 876 °R = _____ °F a. 335 b. 416 c. 400 d. None of the above
Last Answer : 416
Description : 746 °R = ______ °F a. 254 b. 345 c. 286 d. None of the above
Last Answer : 286
Description : What is the formula to convert °F to °C? a) °C = °F + 273 b) °C = 5/9 (°F - 32) c) °C = 9/5 (°F)+32 d) None of the above
Last Answer : °C = 5/9 (°F - 32)
Description : What is the formula to convert °C to °F? a) °F = °C + 273 b) °F = 5/9 (°C - 32) c) °F = 9/5 (°C)+32 d) None of the above
Last Answer : momentum
Description : A certain gas, with cp = 0.529Btu/ lb. °Rand R = 96.2ft.lb/lb. °R, expands from 5 cu ft and 80°F to 15 cu ft while the pressure remains constant at 15.5psia. Compute for T2. a.1520°R b. 1620°R c. 1720°R d. 1820°R formula: T2= T1V2/V1
Last Answer : 1620°R
Description : A certain gas, with cp = 0.529Btu/lb.°R and R = 96.2 ft.lb/lb.°R, expands from 5 cu ft and 80°F to 15 cu ft while the pressure remains constant at 15.5 psia. Compute for T2. (Formula: T2= T1V2/V1) a. 460°R b. 270°R c. 1620 °R d. None of the above
Last Answer : 1620 °R
Description : 710°R= ______ °C a. 214 b. 121 c. 213 d. None of the above
Last Answer : 121
Description : 3.0 lbm of air are contained at 25 psia and 100 ˚F. Given that Rair = 53.35 ft-lbf/lbm- ˚F, what is the volume of the container? A.10.7 ft^3 B.14.7 ft^3 C.15 ft^3 D.24.9 ft^3 Formula: use the ideal gas law pV = mRT T = (100 +460) ˚R V = mRT/p
Last Answer : 24.9 ft^3
Description : A wall of the firebrick has an inside temperature of 313ºF and an outside temperature of 73ºF. What is the difference in the surface temperature in Rankin? a. 70 b. 68 c. 72 d. 94 ºR = ºF + 460
Last Answer : 70
Description : 212 °F = _____R a. 567 b. 672 c. 700 d. None of the above
Last Answer : 672
Description : 212 °F = _____ °C a. 200 b. 150 c. 100 d. None of the above
Last Answer : 100
Description : What is the SI unit of specific heat capacity? A. J/kg B. J/kg °F ∙ C. J/kg °C ∙ D. J/°C
Last Answer : J/kg °C
Description : What is the force required to accelerate amass of 30kg at a rate of 15m/s². a. 460 N b. 380 N c. 560 N d. 450 N F = ma
Last Answer : 450 N
Description : Optimum preheating temperature for pitch creosote mixture (PCM) which is also termed as C.T.F-200, before atomisation through burners is (A) 200 °F (B) 200 °C (C) 200 °K (D) 200 °R
Last Answer : (A) 200 °F
Description : Melting point & boiling points of liquid oxygen are respectively - 218.8°C & - 183°C, while the same for liquid nitrogen is - 210°C & - 195.8°C respectively. The difference in melting points of liquid oxygen & liquid nitrogen is not equal to 8.8 (A) °C (B) °F (C) °K (D) °R
Last Answer : (B) °F
Description : The heat absorbed by a unit mass of a material at its holding point in order to convert the material into a gas at the same temperature. a. Latent Heat of Sublimation b. Latent Heat of Vaporization c. Latent Heat of Fusion d. Latent Heat Of Condensation
Last Answer : Latent Heat of Vaporization
Description : Convert the change of temperature from 20˚C to 30˚C to Kelvin scale. a. 10 K b. 293 K c. 303 K d. 273 K
Last Answer : 10 K
Description : Which of the following is the correct statement of the second law of thermodynamics? A. It is impossible to construct an engine working on a cyclic process, whose sole purpose is to convert heat energy ... energy, which can be obtained from a given quantity of heat energy. D. all of the above
Last Answer : Answer: D
Description : The value for the ΔU of a system is -120 J. If the system is known to have absorbed 420 J of heat, how much work was done? a. -540 J b. -640 J c. -740 J d. -840 J formula: ΔU = q +w
Last Answer : -540 J
Description : Twenty grams of oxygen gas are compressed at a constant temperature of 30 ˚C to 5%of their original volume. What work is done on the system. A.824 cal B.924 cal C.944 cal D.1124 cal Formula: W = -mRTln (V2/V1) Where R = (1.98 cal/gmole·K) (32 g/gmole)
Last Answer : 1124 cal
Description : What is the equation for the work done by a constant temperature system? A. W = mRTln(V2-V1) B. W = mR( T2-T1 ) ln( V2/V1) C. W = mRTln (V2/V1) D. W = RT ln (V2/V1) Formula : W=∫ pdV lim1,2 ∫ = mRT / V
Last Answer : W = mRTln (V2/V1)
Description : Two thick slices of bread, when completely oxidized by the body, can supply 200,000 cal of heat. How much work is this equivalent to? a) 4,190,000 joules b) 8,390,000 joules c) 839, ... d) 419 000 joules Formula: J =Work/Heat J = mechanical equivalent of heat whose value is 4.19 joules/calorie
Last Answer : 419 000 joules
Description : How many joules of work is the equivalent of 15000 cal of heat? a) 62850 joules b) 3579.95 joules c) 14995.81 joules d) 15004.19 joules Formula: J =Work/Heat J = mechanical equivalent of heat whose value is 4.19 joules/calorie
Last Answer : 62850 joules
Description : A perfect gas has a value of R= 319.2 J/ kf.K and k= 1.26. If 120 kJ are added to 2.27 kf\g of this gas at constant pressure when the initial temp is 32.2°C? Find T2. a. 339.4 K b. 449.4 K c. 559.4K d. 669.4K formula: cp = kR/ k-1 Q= mcp(T2-T1)
Last Answer : 339.4 K
Description : The volume of a gas under standard atmospheric pressure & 76 cmHg is 200m³. What is the volume when pressure is 80 cmHg if the temperature is unchanged? a) 180 in³ b) 170 in³ c) 160 in³ d) 190 in³ Formula: P2V2 = P1V1
Last Answer : 190 in³
Description : A 1-kg steam-water mixture at 1.0 MPa is contained in an inflexible tank. Heat is added until the pressure rises to 3.5 MPa and the temperature to 400°. Determine the heat added. a) 1378.7 kJ b) 1348.5 kJ c) 1278,7 kJ d) 1246,5 kJ Formula: Q = (h2 – p2v2) –(h1 –p1v1)
Last Answer : 1378.7 kJ
Description : Utilizing the answer to the previous problem, estimate the overall or average increase in temperature ( ΔT) of the concrete roof from the energy absorbed from the sun during a12hour day. Assume that all of the radiation absorbed goes into ... °C b. 8.9°C c. 9.9°C d. 10.9°C formula: ΔQ = m c ΔT
Last Answer : 7.9 °C
Description : Water (specific heat cv= 4.2 kJ/ kg ∙ K ) is being heated by a 1500 W h eater. What is the rate of change in temperature of 1kg of the water? A. 0.043 K/s B. 0.179 K/s C. 0.357 K/s D. 1.50 K/s Formula: Q = mcv ( T)
Last Answer : 0.179 K/s
Description : Find the change in internal energy of 5 lb. of oxygen gas when the temperature changes from 100 ˚F to 120 ˚F. CV = 0.157 BTU/lbm-˚R A.14.7 BTU B.15.7 BTU C. 16.8 BTU D. 15.9 BTU Formula: U= mcv T
Last Answer : 15.7 BTU
Description : If air is at pressure, p, of 3200 lbf/ft2 , and at a temperature, T, of 800 ˚R, what is the specific volume, v? (R=5303 ft-lbf/lbm-˚R, and air can be modeled as an ideal gas.) A.9.8 ft^3/lbm B.11.2 ft^3/lbm C.13.33 ft^3/lbm D.14.2 ft^3/lbm Formula: pv = RT v = RT / p
Last Answer : 13.33 ft^3/lbm
Description : According to Kelvin-Planck's statement of second law of thermodynamics, A. it is impossible to construct an engine working on a cyclic process, whose sole purpose is to convert heat energy into work B. it ... other than the transfer of heat from a cold body to a hot body D. none of the above
Last Answer : Answer: A
Description : To convert volumetric analysis to gravimetric analysis, the relative volume of each constituent of the flue gases is (a) divided by its molecular weight (b) multiplied by its molecular weight (c) ... by its density (d) multiplied by its specific weight (e) divided by its specific weight.
Last Answer : Answer : b
Description : The flow energy of 5 ft3 of a fluid passing a boundary to a system is 80,000 ft-lb. Determine the pressure at this point. a. 222 psi b. 333 psi c. 444 psi d. 111 psi formula: Ef= pV
Last Answer : 111 psi
Description : Let a closed system execute a state change for which the heat is Q = 100 J and work is W = -25 J. Find E. ∆ (Formula: E = Q- W) ∆ a. 125 J b. 123 J c. 126 J d. None of the above
Last Answer : 125 J
Description : Gas is enclosed in a cylinder with a weighted piston as the stop boundary. The gas is heated and expands from a volume of 0.04 m^3 to 0.10 m^3 at a constant pressure of 200kPa.Calculate the work done by the system. A. 8 kJ B. 10 kJ C.12 kJ D.14 kJ Formula: W = p(V2-V1)
Last Answer : 12 kJ
Description : A system weighing 2kN. Determine the force that accelerate if to 12 m/s^2. a. vertically upward when g = 9.7 m/s^2 A. 4474.23 N B.5484.23 N C.4495.23 N D.5488.23 N Formula: F = m/k (a +g)
Last Answer : 4474.23 N
Description : A 10m^3 vessel initially contains 5 m^3 of liquid water and 5 m^3 of saturated water vapor at 100 kPa. Calculate the internal energy of the system using the steam table. A. 5 x10^5 kJ B. 8x10^5 kJ C. 1 ... 3 kJ/kg ug= 2506kJ/kg formula: Mvap = V vap/vg M liq = Vliq/ vƒ u =uƒM liq + ug M vap
Last Answer : 2 x10^6 kJ
Description : Extensive property of a system is one whose value (a) depends on the mass of the system like volume (b) does not depend on the mass of the system, like temperature, pressure, etc. (c) is not ... the state (d) is dependent on the path followed and not on the state (e) is always constant.
Last Answer : Answer : a
Description : Intensive property of a system is one whose value (a) depends on the mass of the system, like volume (b) does not depend on the mass of the system, like temperature, pressure, etc. (c) is not ... on the state (d) is dependent on the path followed and not on the state (e) remains constant.
Description : Calculate the power output in horsepower of an 80-kg man that climbs a flight of stairs 3.8 m high in 4.0 s. a) 744.8 hp b) 0.998 hp c) 746 hp d) 1.998 hp Formula: Power = Fd/t = mgh/t F = W = mg d = h
Last Answer : 0.998 hp
Description : How many Newton’s (N) in 900,000 dynes? a) 8 Newton’s b) 9 Newton’s c) 7 Newton’s d) 6 Newton’s Formula: 1Newton (N)=100,000dynes
Last Answer : 9 Newton’s
Description : 3 horsepower (hp) = _____________watts? a) 1492 watts b) 2238 watts c) 746 watts d) 2238 kilowatts Formula: 1hp= 746 watts
Last Answer : 2238 watts
Description : While swimming at depth of120m in a fresh water lake, A fish emits an air bubbles of volume 2.0mm³ atmospheric pressure is 100kPa. What is the pressure of the bubble? a) 217.7 kPa b) 317.7 kPa c) 417.7 kPa d) 517.7 kPa Formula: P= δh
Last Answer : 217.7 kPa
Description : Assuming compression is according to the Law PV = C, Calculate the initial volume of the gas at a pressure of 2 bars w/c will occupy a volume of 6m³ when it is compressed to a pressure of 42 Bars. a) 130m³ b) 136m³ c) 120m³ d) 126m³ Formula: P1V1/T1 =P2V2/T2
Last Answer : 126m³
Description : The pressure gauge on a 2000 m³ tank of oxygen gas reads 600 kPa. How much volumes will the oxygen occupied at pressure of the outside air 100 kPa? a) 14026.5 m³ b) 15026.5 m³ c) 13026.5 m³ d) 16026.5 m³ Formula: P1V1/T1 =P2V2/T2
Last Answer : 14026.5 m³
Description : A steam calorimeter receives steam from a pipe at 0.1 MPa and 20°SH. For a pipe steam pressure of 2 MPa, what is the quality of the steam? a) 95.56% b) 70.10% c) 95.20% d) 85.10% Formula: h1 = hf1 + x1hfg1
Last Answer : 265.4°C, 430.7kJ/kg, 71.4kJ/kg, 1.0327kJ/(kg)(K),502.1 kJ/kg
Description : What mass of nitrogen is contained in a10 ft3 vessel at a pressure of 840atm and 820°R? Make a computation by using ideal gas equation. a. 194lb b. 214lb c. 394 lb d. 413lb formula: m=pV /RT
Last Answer : 394 lb
Description : Find ∫ for steam at 100 psia and 600°F.If h = 1329.6 and v = 6.216 a. 1214 Btu / lb b. 1234 Btu /lb c. 1342 Btu / lb d. 1324 Btu /lb formula: ∫ = h– pv/ J
Last Answer : 1214Btu / lb
Description : Two masses, one of the 10kg and the other unknown, are placed on a scale in a region where g = 9.67 m/sec2 . The combined weight of these two masses is 174.06 N. Find the unknown mass in kg. a. 20 kg b. 19 kg c. 18 kg d. 17 kg formula: m=Fg k / g
Last Answer : 18 kg
Description : A car whose mass is 2 metric tons is accelerated uniformly from stand hill to 100 kmph in 5 sec. Find the driving force in Newton’s. a. 11,120 N b. 11,320 N c. 11,420 N d. 11520 N formula: F= ma / k
Last Answer : 11,120N