An iron ring of mean circumference 80 cm is uniformly wound with 500 turns of wire and carries 0.8A. Find the magnetic field strength.

An iron ring of mean circumference 80 cm is uniformly wound with 500 turns of wire and carries 0.8A. Find the magnetic field strength. 
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Ans: Magnetic field strength H = NI /l = 500 x 0.8 / 80 x 10-2 = 500 AT/m

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