The ratio of the moments of resistance of a solid circular shaft of diameter D and a hollow shaft
(external diameter D and internal diameter d), is
(A) D
4
/(D
4 - d
4
)
(B) D
3
/(D
3 - d
3
)
(C) (D
4 - d
4
)/D
4
(D) (D
3 - d
3
)/D
3

1 Answer

Answer :

(A) D
4
/(D
4 - d
4
)

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