Principal planes are subjected to
(A) Normal stresses only
(B) Tangential stresses only
(C) Normal stresses as well as tangential stresses
(D) None of these
Description : The total strain energy for a unit cube subjected to three principal stresses is given by? a) U= [(σέ) 1 + (σέ) 2+ (σέ) 3]/3 b) U= [(σ12+σ22+σ32)/2E] – (σ1σ2+σ2σ3+σ3σ1)2μ c) U= [(σέ) 1 + (σέ) 2+ (σέ) 3]/4 d) None of the mentioned
Last Answer : b) U= [(σ12+σ22+σ32)/2E] – (σ1σ2+σ2σ3+σ3σ1)2μ
Description : In case of an eccentric loading on a bracket subjected to moment M, the tangential force developed in any rivet, at right angles to its radius vector r is (A) Mr/ r² (B) r²/Mr (C) Mr²/ r² (D) Mr/ r²
Last Answer : (A) Mr/ r²
Description : Angle of obliquity is defined as a. Angle between the plane on which stresses are evaluated and one of the given planes b. Angle between resultant stress and the plane of given normal stress c. Angle between resultant stress and shear stress d. Angle between resultant stress and normal stress
Last Answer : d. Angle between resultant stress and normal stress
Description : On the planes of maximum shear, there are (a) Normal stresses (b) Bending stresses (c) Bucking stresses (d) None
Last Answer : (a) Normal stresses
Description : Principal planes are those planes on which a. Normal stress is maximum b. Normal stress is minimum c. Normal stress is either maximum or minimum d. Shear stress is maximum
Last Answer : c. Normal stress is either maximum or minimum
Description : For finding out the bending moment for the arm (spoke) of flywheel the arm is assumed as 1. a cantilever beam fixed at the rim and subjected to tangential force at the hub 2. a simply ... tangential force at the rim 4. a fixed beam fixed at hub and rim and carrying uniformly distributed load
Last Answer : 3. a cantilever hub fixed at the rim and subjected to tangential force at the rim
Description : For finding out the bending moment for the arm (spoke) of flywheel, the arm is assumed as, (A) A cantilever beam fixed at the rim and subjected to tangential force at the hub (B) A simply ... tangential force at the rim (D) A fixed beam fixed at hub and rim and carrying uniformly distributed load
Last Answer : (C) A cantilever beam fixed at the hub and subjected to tangential force at the rim
Description : Which of the following formulae is used to calculate tangential stress, when a member is subjected to stress in mutually perpendicular axis and accompanied by a shear stress? a. [(σ x - σ y )/2 ]sin θ - τ cos 2θ b. [(σ x - ... τ cos 2θ c. [(σ x - σ y )/2 ]sin θ - τ 2 cos θ d. None of the above
Last Answer : c. [(σ x – σ y )/2 ]sin θ – τ 2 cos θ
Description : Maximum shear stress is (a) Average sum of principal stresses (b) Average difference of principal stresses (c) Average sum as well as difference of principal stresses (d) None
Last Answer : (b) Average difference of principal stresses
Description : Principal stresses are a. Firstly Maximum and minimum shear stresses b. Secondly Maximum and minimum normal stresses c. Both (a) & (b) d. None
Last Answer : b. Secondly Maximum and minimum normal stresses
Description : A pressure conduit laid underground, may not be subjected to (A) Internal pressure of water (B) Pressure due to external load (C) Longitudinal temperature stress (D) Longitudinal stresses due to unbalanced pressure to bends
Last Answer : (C) Longitudinal temperature stress
Description : A compound bar consists of two bars of equal length. Steel bar cross-section is 3500 mm2 and that of brass bar is 3000 mm2 . These are subjected to a compressive load 100,000 N. If Eb = 0.2 MN/mm2 and Eb = 0.1 ... 6 N/mm2 s = 12 N/mm2 (D) b = 5 N/mm2 s = 10 N/mm
Last Answer : (A) b = 10 N/mm2 s = 20 N/mm
Description : When the distance between centers of two adjacent rivets connecting the members subjected to either compression or tension exceeds the maximum pitch, then the additional rivets which are not subjected to the ... (a) Packing rivets (b) Long-grip rivets (c) Tacking rivets (d) Auxiliary rivets
Last Answer : (c) Tacking rivets
Description : A concrete block subjected to shear stresses, then the failure may result by [ A ] Diagonal tension [ B ] Longitudinal tension [ C ] Diagonal compression [ D ] None of the above
Last Answer : [ A ] Diagonal tension
Description : The principal stresses at a point are 100, 100 and -200 kgf/cm2 , the octahedral shear stress at the point is: (A) 100 kg/cm2 (B) 200 kg/cm2 (C) 300 kg/cm2 (D) 400 kg/cm2
Last Answer : (A) 100 kg/cm2
Description : In non-cohesive soil in passive state of plastic equilibrium (A) Major principal stress is horizontal (B) Minor principal stress is vertical (C) Major principal stress is vertical (D) Minor and major principal stresses are equally inclined to the horizontal
Last Answer : (B) Minor principal stress is vertical
Description : In active state of plastic equilibrium in a non cohesive soil with horizontal ground surface (A) Major principal stress is horizontal (B) Minor principal stress is vertical (C) Major principal stress is vertical (D) Minor and major principal stresses are equally inclined to horizontal
Last Answer : Answer: Option C
Description : The locus of the end point of the resultant of the normal and tangential components of the stress on an inclined plane, is (A) Circle (B) Parabola (C) Ellipse (D) Straight line
Last Answer : (C) Ellipse
Description : In a general two dimensional stress system, there are a. Two principal planes b. Only one plane c. Three principal planes d. No principal plane
Last Answer : a. Two principal planes
Description : Along the principal plan subjected to maximum principal stress (A) Maximum shear stress acts (B) Minimum shear stress acts (C) No shear stress acts (D) None of these
Last Answer : (C) No shear stress acts
Description : Pick up the correct statement from the following: (A) An unconfined compression test is a special case of triaxial compression test (B) An unconfined compression test is a special case of direct ... subjected to major principal stress till it fails due to shearing along the plane of the failure
Last Answer : Option A
Description : The equations for principal stresses are valid only when (a)σ x and σ y are both tensile (b) σ x is compressive and σ y is tensile (c) σ x is tensile and σ y is compressive (d) None
Last Answer : (a)σ x and σ y are both tensile
Description : In a general two dimensional stress system, planes of maximum shear stress are inclined at ___ with principal planes. a. 90 degree b. 180 degree c. 45 degree d. 60 degree
Last Answer : c. 45 degree
Description : Principal planes are mutually inclined at a. 45 degree b. 60 degree c. 90 degree d. 180 degree
Last Answer : c. 90 degree
Description : There are in all (a) Two principal planes (b) Three principal planes (c) Four principal planes (d) None
Last Answer : (b) Three principal planes
Description : The helical spring ad wire of helical torsion spring, both are subjected to torsional shear stresses. a) True b) False
Last Answer : b) False
Description : Cotter joint is employed when the members are subjected to which sort of stresses? a) Axial tensile b) Axial compressive c) Axial tensile or compressive d) None of the above
Last Answer : c) Axial tensile or compressive
Description : Cotter joint is used when the members are subjected to which type of stresses? a) Axial tensile b) Axial compressive c) Axial tensile or compressive d) None of the mentioned
Description : During transverse vibrations, shaft is subjected to which type of stresses? A) Tensile stresses B) Torsional shear stress C) Bending stresses D) All of the above
Last Answer : C) Bending stresses
Description : During transverse vibrations, shaft is subjected to which type of stresses? a. Tensile stresses b. Torsional shear stress c. Bending stresses d. All of the above
Last Answer : c. Bending stresses
Description : Pick out the correct statement. (A) Hot worked materials are subjected to annealing to remove internal stresses (B) Annealing of steel hardens it slightly (C) Normalising of a material induces stresses (D) Tempering of a material improves ductility & toughness but reduces hardness & brittleness
Last Answer : (D) Tempering of a material improves ductility & toughness but reduces hardness & brittleness Share
Description : Pick out the wrong statement. (A) Both annealing and normalising release the internal stresses of the material besides improving the mechanical properties (B) Low carbon steel does not respond to ... are also used for surface hardening (D) Martempering of a material is a hardening process
Last Answer : Option C
Description : In a static fluid (A) Resistance to shear stress is small (B) Fluid pressure is zero (C) Linear deformation is small (D) Only normal stresses can exist
Last Answer : Answer: Option D
Description : Under complex loading, principal stresses exist as (a) Firstly σ 1 > σ 2 =σ 3 (b) Secondly σ 1 = σ 2 =σ 3 (c) Thirdly σ 1 > σ 2 < σ 3 (d) None
Last Answer : (d) None
Description : Symbols for principal stresses are a. Firstly σ, τ & γ b. Secondly σ 1 , σ 2 & σ 3
Last Answer : b. Secondly σ 1 , σ 2 & σ 3
Description : The maximum number of principal stresses is a. 1 b. 3 c. 5 d. None
Last Answer : b. 3
Description : The maximum number of principal stresses is a. 2 b. 4 c. 6 d. None
Last Answer : d. None
Description : Why do we determine principal stresses? a. Failure is due to simple stress or strain b. Failure is due to complex stress or strain c. Both (a) & (b) d. None
Last Answer : a. Failure is due to simple stress or strain
Description : Shear strain energy under principal tensile stresses σ1 and σ2 is (a) (1/12E) (σ1 — σ2) 2 + σ2 2 — σ1 2 ) (b) (1/12G) (σ1 — σ2) 2 + σ2 2 + σ1 2 ) (c) (1/12K) (σ1 — σ2) 2 + σ2 2 + σ1 2 ) (d) None
Last Answer : (b) (1/12G) (σ1 — σ2) 2 + σ2 2 + σ1 2 )
Description : Resilience under principal tensile stresses σ1 and σ2 is (a) (1/2E)( σ1 2 + σ2 2 –μ σ1 σ2) (b) (1/2E)( σ1 2 + σ2 2 –4μ σ1 σ2) (c) (1/2E)( σ1 2 + σ2 2 –2μ σ1 σ2) (d) None
Last Answer : (c) (1/2E)( σ1 2 + σ2 2 –2μ σ1 σ2)
Description : Resilience under principal tensile stresses σ1 and σ2 is (a) (1/2E)( σ1 2 + σ2 2 –3μ σ1 σ2) (b) (1/2E)( σ1 2 + σ2 2 –4μ σ1 σ2) (c) (1/2E)( σ1 2 + σ2 2 –5μ σ1 σ2) (d) None
Description : Principal stresses are found by a. Analytical method b. Graphical method c. Analytical & graphical methods d. None
Last Answer : c. Analytical & graphical methods
Description : Maximum shear stress in terms of principal stresses is a. Firstly (σ 1 +σ 2 )/2 b. Secondly (σ 1 /σ 2 ) c. Thirdly (σ 1 –σ 2 )/2 d. None
Last Answer : c. Thirdly (σ 1 –σ 2 )/2
Description : In the analysis, all the principal stresses are assumed as a. Shear stresses b. Compressive stresses c. Tensile stresses d. None
Last Answer : c. Tensile stresses
Description : In a body under pure shear, the magnitude and nature of the two principal stresses are a. Firstly Equals shear stress, opposite nature b. Secondly Equals shear stress, same nature c. Both (a) & (b) d. None
Last Answer : a. Firstly Equals shear stress, opposite nature
Description : How many maximum shear stresses are there with three principal stresses? a. 1 b. 2 c. 3 d. None
Last Answer : c. 3
Description : Nature of the three principal stresses is a. Firstly All tensile b. Secondly All compressive c. Thirdly All shear d. None
Last Answer : a. Firstly All tensile
Description : The order of magnitude of the principal stresses is a. Firstly σ 1 >σ 2 >σ 3 b. Secondly σ 2 >σ 3 >σ 1 c. Thirdly σ 1 >σ 3 >σ 2 d. None
Last Answer : a. Firstly σ 1 >σ 2 >σ 3
Description : All the principal stresses are at an angle of (a)90 0 (b) 45 0 (c) 135 0 (d) None
Last Answer : (a)90 0