Description : Find the Laplace equation value of the following potential field V = r cos θ + φ a) 3 b) 2 c) 1 d) 0
Last Answer : d) 0
Description : Calculate the emf of a material having flux density 5sin t in an area of 0.5 units. a) 2.5 sin t b) -2.5 cos t c) -5 sin t d) 5 cos t
Last Answer : d) 5 cos t
Description : Find the electric field when the magnetic field is given by 2sin t in air. a) 8π x 10 -7 cos t b) 4π x 10 -7 sin t c) -8π x 10 -7 cos t d) -4π x 10 -7 sin t
Last Answer : a) 8π x 10 -7 cos t
Description : Given the potential V = 25 sin θ, in free space, determine whether V satisfies Laplace’s equation. a) Yes b) No c) Data sufficient d) Potential is not defined
Last Answer : a) Yes
Description : The scalar factor of spherical coordinates is a) 1, r, r sin θ b) 1, r, r c) r, r, 1 d) r, 1, r
Last Answer : a) 1, r, r sin θ
Description : Find the current density on the conductor surface when a magnetic field H = 3cos x i + zcos x j A/m, for z>0 and zero, otherwise is applied to a perfectly conducting surface in xy plane. a) cos x i b) –cos x i c) cos x j d) –cos x j
Last Answer : b) –cos x i
Last Answer : We hold theta = A. sin2A + cos2 (PM / OP) 2+ (OM / OP) 2 PM2 / OP2 + OM2OP2 (PM2 + OM2) / OP2 OP2 / OP2 => 1 So sin2A + cos2A = 1
Description : In trapezoidal threads, f (coefficient of friction) can be taken as a) f sec θ b) f cos θ c) f sin θ d) f cosec θ
Last Answer : a) f sec θ
Description : Which of the following formulae is used to calculate tangential stress, when a member is subjected to stress in mutually perpendicular axis and accompanied by a shear stress? a. [(σ x - σ y )/2 ]sin θ - τ cos 2θ b. [(σ x - ... τ cos 2θ c. [(σ x - σ y )/2 ]sin θ - τ 2 cos θ d. None of the above
Last Answer : c. [(σ x – σ y )/2 ]sin θ – τ 2 cos θ
Description : Work done by a uniform magnetic field in moving a charged particle in a circular path is a) qvB sin θ b) mg sin θ c) zero d) mg cos θ
Last Answer : Zero
Description : The torque of a conductor is defined only in the case when a) The field is perpendicular to the loop b) The plane of the loop is parallel to the field c) The plane of the loop is perpendicular to the current direction d) The field and the current direction are same
Last Answer : b) The plane of the loop is parallel to the field
Description : Consider the conductor to be a coil of turns 60 and the flux density to be 13.5 units, current 0.12A and area 16units. The torque will be a) 1555.2 b) 1222.5 c) 525.1 d) 255.6
Last Answer : a) 1555.2
Description : The torque on a conductor with flux density 23 units, current 1.6A and area 6.75 units will be a) 248.4 b) 192.6 c) 175.4 d) 256.9
Last Answer : a) 248.4
Description : Identify the polarisation of the wave given, Ex = cos wt and Ey = sin wt. The phase difference is -90 0 . a) Left hand circularly polarised b) Right hand circularly polarised c) Left hand elliptically polarised d) Right hand elliptically polarised
Last Answer : b) Right hand circularly polarised
Description : Identify the polarisation of the wave given, Ex = 2 cos wt and Ey = 2 sin wt. The phase difference is +90 0 . a) Left hand circularly polarised b) Right hand circularly polarised c) Left hand elliptically polarised d) Right hand elliptically polarised
Last Answer : a) Left hand circularly polarised
Description : Identify the polarisation of the wave given, Ex = 2 cos wt and Ey = sin wt. The phase difference is -90 0 . a) Left hand circularly polarised b) Right hand circularly polarised c) Left hand elliptically polarised d) Right hand elliptically polarised
Last Answer : d) Right hand elliptically polarised
Description : Identify the polarisation of the wave given, Ex = Exo cos wt and Ey = Eyo sin wt. The phase difference is +90 0 . a) Left hand circularly polarised b) Right hand circularly polarised c) Left hand elliptically polarised d) Right hand elliptically polarised
Last Answer : c) Left hand elliptically polarised
Description : The Snell’s law is given by a) N1 sin θi = N2 sin θt b) N2 sin θi = N1 sin θt c) sin θi = sin θt d) N1 cos θi = N2 cos θt
Last Answer : a) N1 sin θi = N2 sin θt
Description : Numerical aperture is expressed as the a) NA = sin θa b) NA = cos θa c) NA = tan θa d) NA = sec θa
Last Answer : a) NA = sin θa
Description : Find the area of a right angled triangle with sides of 90 degree unit and the functions described by L = cos y and M = sin x. a) 0 b) 45 c) 90 d) 180
Last Answer : d) 180
Description : Given D = e -x sin y i – e -x cos y j Find divergence of D. a) 3 b) 2 c) 1 d) 0
Description : Find the gradient of the function sin x + cos y. a) cos x i – sin y j b) cos x i + sin y j c) sin x i – cos y j d) sin x i + cos y j
Last Answer : a) cos x i – sin y j
Description : Find the Lorentz force due to a conductor of length 2m carrying a current of 1.5A and magnetic flux density of 12 units. a) 24 b) 36 c) 32 d) 45
Last Answer : c) 32
Description : Find the flux density due to a conductor of length 6m and carrying a current of 3A(in 10 -7 order) a) 1 b) 10 c) 100 d) 0.1
Last Answer : a) 1
Description : Find the height of an infinitely long conductor from point P which is carrying current of 6.28A and field intensity is 0.5 units. a) 0.5 b) 2 c) 6.28 d) 1
Last Answer : b) 2
Description : The expression for velocity of a wave in the conductor is a) V = √(2ω/μσ) b) V = √(2ωμσ) c) V = (2ω/μσ) d) V = (2ωμσ)
Last Answer : a) V = √(2ω/μσ)
Description : The maximum tangential stress σ t = (σ x sin 2θ)/2 is maximum if, θ is equal to ________ a. 45 o b. 90 o c. 270 o d. all of the above
Last Answer : a. 45 o
Description : If the potential is given by, V = 10sin θ cosφ/r, find the density at the point P(2, π/2, 0) (in 10 -12 units) a) 13.25 b) 22.13 c) 26.31 d) 31.52
Last Answer : b) 22.13
Description : Find the potential of the function V = 60cos θ/r at the point P(3, 60, 25). a) 20 b) 10 c) 30 d) 60
Last Answer : b) 10
Description : Find the potential of V = 60sin θ/r 2 at P(3,60,25) a) 5.774 b) 6.774 c) 7.774 d) 8.774
Last Answer : a) 5.774
Description : Evaluate Gauss law for D = 5r 2 /4 i in spherical coordinates with r = 4m and θ = π/2 as volume integral. a) 600 b) 588.9 c) 577.8 d) 599.7
Last Answer : b) 588.9
Description : Evaluate Gauss law for D = 5r 2 /4 i in spherical coordinates with r = 4m and θ = π/2. a) 600 b) 599.8 c) 588.9 d) 577.8
Last Answer : c) 588.9
Description : Given B= (10/r)i+( rcos θ) j+k in spherical coordinates. Find Cartesian points at (- 3,4,0) a) -2i + j b) 2i + k c) i + 2j d) –i – 2k
Last Answer : a) -2i + j
Description : Transform the spherical system B = (10/r)i + (10cos θ)j + k into cylindrical form at (5, π/2, -2) a) 2.467i + j + 1.167k b) 2.467i – j + 1.167k c) 2.467i – j – 1.167k d) 2.467i + j – 1.167k
Last Answer : a) 2.467i + j + 1.167k
Description : he work done of vectors force F and distance d, separated by angle θ can be calculated using, a) Cross product b) Dot product c) Addition of two vectors d) Cannot be calculated
Last Answer : b) Dot product
Description : The magnetic moment and torque are related as follows a) T = BM b) B = TM c) M = TB d) T = M
Last Answer : a) T = BM
Description : State the expression for the magnetic force on straight current carrying conductor placed in uniform magnetic field
Last Answer : State the expression for the magnetic force on straight current carrying conductor placed in uniform magnetic field
Description : The equation, X = A cos(wt + f) (read: X equals A times the cosine of omega t + phi (fee)), can represent an expression for: w) accelerating due to gravity x) uniform straight line motion y) dc current z) a simple harmonic oscillator
Last Answer : ANSWER: Z -- A SIMPLE HARMONIC OSCILLATOR
Description : Find the magnetic field intensity at the centre O of a square of the sides equal to 5m and carrying 10A of current. a) 1.2 b) 1 c) 1.6 d) 1.8
Last Answer : d) 1.8
Description : What is a conical pendulum? Show that its time period is given by 2π √(l cos θ)/g, where l is the length of the string,
Last Answer : What is a conical pendulum? Show that its time period is given by 2π\(\sqrt{\frac{l\,cos\, ... the vertical and g is the acceleration due to gravity.
Description : According to D' Alembert's principle, m (d 2 x/ dt 2 ) + c (dx/dt) + Kx =0 is the differential equation for damped free vibrations having single degree of freedom. What will be the solution to this differential equation if the system is ... Φ) C x = (A - Bt) e - ωt D x = X e - ξωt (cos ω d t + Φ)
Last Answer : A x = (A + Bt) e – ωt
Description : According to D' Alembert's principle, m (d 2 x/ dt 2 ) + c (dx/dt) + Kx =0 is the differential equation for damped free vibrations having single degree of freedom. What will be the solution to this differential equation if the system is ... ) C. x = (A - Bt) e - ωt D. x = X e - ξωt (cos ω d t + Φ
Last Answer : A. x = (A + Bt) e – ωt
Description : According to D' Alembert's principle, m (d 2 x/ dt 2 ) + c (dx/dt) + Kx =0 is the A differential equation for damped free vibrations having single degree of freedom. What will be the solution to this differential equation if the system is ... (C)x = (A - Bt) e - ωt ( D )x = X e - ξωt (cos ω d t + Φ
Last Answer : ( A ) x = (A + Bt) e – ωt
Description : According to D' Alembert's principle, m (d 2 x/ dt 2 ) + c (dx/dt) + Kx =0 is the differential equati damped free vibrations having single degree of freedom. What will be the solution to this differ equation if the system is critically ... c. x = (A - Bt) e - ωt d. x = X e - ξωt (cos ω d t + Φ)
Last Answer : a. x = (A + Bt) e – ωt
Description : The analog signal m(t) is given below m(t) = 4 cos 100 pt + 8 sin 200 pt + cos 300 pt, the Nyquist sampling rate will be: (1) 1/100 (2) 1/200 (3) 1/300 (4) 1/600
Last Answer : The analog signal m(t) is given below m(t) = 4 cos 100 pt + 8 sin 200 pt + cos 300 pt, the Nyquist sampling rate will be: 1/300
Description : The loss tangent refers to the a) Power due to propagation in conductor to that in dielectric b) Power loss c) Current loss d) Charge loss
Last Answer : a) Power due to propagation in conductor to that in dielectric
Description : Calculate the flux density due to a circular conductor of radius 100nm and current 5A in air. a) 10 b) 100 c) 0.1 d) 1
Last Answer : a) 10
Description : Find the maximum force of the conductor having length 60cm, current 2.75A and flux density of 9 units. a) 14.85 b) 18.54 c) 84.25 d) 7.256
Last Answer : a) 14.85
Description : The force on a conductor of length 12cm having current 8A and flux density 3.75 units at an angle of 300 is a) 1.6 b) 2 c) 1.4 d) 1.8
Description : Find the flux density of a conductor in the square of the centre of the loop having current 3.14A and radius is 1.414m in air. a) 8π x 10 -7 b) 4π x 10 -7 c) 6π x 10 -7 d) 2π x 10 -7
Last Answer : c) 6π x 10 -7