What is a conical pendulum? Show that its time period is given by 2π √(l cos θ)/g, where l is the length of the string,

What is a conical pendulum? Show that its time period is given by 2π √(l cos θ)/g, where l is the length of the string,
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What is a conical pendulum? Show that its time period is given by 2π\(\sqrt{\frac{l\,cos\, ... the vertical and g is the acceleration due to gravity.
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Critical Speed (Nc ) of a ball mill is given by (where R1 and R2 are radii of ball mill and the ball respectively). (A) Nc = (1/4π). √(g/R1 - R2 ) (B) Nc = (1/2π). √(g/R1 - R2 ) (C) Nc = (1/π). √(g/R1 - R2 ) (D) Nc = (1/2π). √(R1 - R2 /g)

Description : Critical Speed (Nc ) of a ball mill is given by (where R1 and R2 are radii of ball mill and the ball respectively). (A) Nc = (1/4π). √(g/R1 - R2 ) (B) Nc = (1/2π). √(g/R1 - R2 ) (C) Nc = (1/π). √(g/R1 - R2 ) (D) Nc = (1/2π). √(R1 - R2 /g)

Last Answer : (B) Nc = (1/2π). √(g/R1 - R2 )

Period of simple harmonic motion of a spiral spring or elastic thread is given by A. T = 2π × (extension produced/gravitational field strength) B. T = 2π × (extension produced/√(gravitational field strength)) C. T = 2π × (√(extension produced)/gravitational field strength) D. T = 2π × √(extension produced/gravitational field strength)

Description : Period of simple harmonic motion of a spiral spring or elastic thread is given by A. T = 2π (extension produced/gravitational field strength) B. T = 2π (extension produced/√( ... (extension produced)/gravitational field strength) D. T = 2π √(extension produced/gravitational field strength)

Last Answer : T = 2π × √(extension produced/gravitational field strength)

Critical speed of rotation, N (in rps - rotation per second) of a trammel is equal to (where, g = acceleration due to gravity = 9.81 m/sec 2 and, r = radius of trammel, metre.) (A) (1/2π). √(g/r) (B) (1/π). √(g/r) (C) ½ √(g/r) (D) 2π. √(g/r)

Description : Critical speed of rotation, N (in rps - rotation per second) of a trammel is equal to (where, g = acceleration due to gravity = 9.81 m/sec 2 and, r = radius of trammel, metre.) (A) (1/2π). √(g/r) (B) (1/π). √(g/r) (C) ½ √(g/r) (D) 2π. √(g/r)

Last Answer : (A) (1/2π). √(g/r)

A stone whirling in a horizontal circle on the end of string depicts A. conical pendulum B. cone C. pendulum D. eclipse

Description : A stone whirling in a horizontal circle on the end of string depicts A. conical pendulum B. cone C. pendulum D. eclipse

Last Answer : conical pendulum

If the length of a simple pendulum is halved then its period of oscillation is - (1) doubled (2) halved (3) increased by a factor √ 2 (4) decreased by a factor √ 2

Description : If the length of a simple pendulum is halved then its period of oscillation is - (1) doubled (2) halved (3) increased by a factor √ 2 (4) decreased by a factor √ 2

Last Answer : (4) decreased by a factor √ 2

. In centrifugal pendulum absorber , the natural frequency in cycle per second can be given by A Fn =N √(R/L) B Fn =1/N √(R/L) C Fn =N/2 √(R/L) D Fn =N2 √(R/L)

Description : . In centrifugal pendulum absorber , the natural frequency in cycle per second can be given by A Fn =N √(R/L) B Fn =1/N √(R/L) C Fn =N/2 √(R/L) D Fn =N2 √(R/L)

Last Answer : A Fn =N √(R/L)

In centrifugal pendulum absorber , the natural frequency in cycle per second can be given by A) Fn =N √(R/L) B) Fn =1/N √(R/L) C) Fn =N/2 √(R/L) D) Fn =N2 √(R/L)

Description : In centrifugal pendulum absorber , the natural frequency in cycle per second can be given by A) Fn =N √(R/L) B) Fn =1/N √(R/L) C) Fn =N/2 √(R/L) D) Fn =N2 √(R/L)

Last Answer : A) Fn =N √(R/L)

Two bodies of mass 6 kg and 9 kg are connected with a light inextensile string passing over a smooth pulley with one of the bodies on a smooth inclined plane (θ = 30°) and the other hanging freely from the other end. Show that the time taken by 9 kg to pull 6 kg up the entire length is half the time taken by 6 kg to pull 9 kg over the same plane.

Description : Two bodies of mass 6 kg and 9 kg are connected with a light inextensile string passing over a smooth pulley with one of the bodies on a smooth inclined plane (θ = 30°) and the other hanging freely from the ... kg up the entire length is half the time taken by 6 kg to pull 9 kg over the same plane.

Last Answer : Given: Mass of body A (mA) = 6 kg Mass of body B (mB) = 9 kg Angle of inclination of the plane (θ) = 30° Let's assume that the acceleration of body A (aA) and body B (aB) are in opposite ... we know that the time taken (t) is given by the formula: t = √(2d/a), where d is the distance travelled

Time period of a simple pendulum depends upon the length of pendulum (l) and acceleration due to gravity (g). Using dimensional analysis

Description : Time period of a simple pendulum depends upon the length of pendulum (l) and acceleration due to gravity (g). Using dimensional analysis

Last Answer : Time period of a simple pendulum depends upon the length of pendulum (l) and acceleration due to ... expression for time period of a simple pendulum.

A simple pendulum consisting of a mass M attached to a string of length L is released from rest at an angle `alpha`. A pin is located at a distance l

Description : A simple pendulum consisting of a mass M attached to a string of length L is released from rest at an angle `alpha`. A pin is located at a distance l

Last Answer : A simple pendulum consisting of a mass M attached to a string of length L is released from rest at an angle `alpha` ... ^(-1) [(L cos alpha-l)/(L+l)]`

The time period of a simple pendulum does not depend upon the mass of the body suspended at the free end of the string. This statement is known as ___________ . (A) law of gravity (B) law of mass (C) law of isochronism (D) law of length

Description : The time period of a simple pendulum does not depend upon the mass of the body suspended at the free end of the string. This statement is known as ___________ . (A) law of gravity (B) law of mass (C) law of isochronism (D) law of length

Last Answer : (B) law of mass

The time `t` of a complete oscillation of a simple pendulum of length `l` is given by the equation `T=2pisqrt(1/g)` where `g` is constant. What is the

Description : The time `t` of a complete oscillation of a simple pendulum of length `l` is given by the equation `T=2pisqrt(1/g)` where `g` is constant. What is the

Last Answer : The time `t` of a complete oscillation of a simple pendulum of length `l` is given by the equation `T= ... error in `T` when `l` is increased by 1%?

The acceleration due to gravity is determined by using a simple pendulum of length l = (100 ± 0.1) cm. If its time period is T = (2 ± 0.01)

Description : The acceleration due to gravity is determined by using a simple pendulum of length l = (100 ± 0.1) cm. If its time period is T = (2 ± 0.01)

Last Answer : The acceleration due to gravity is determined by using a simple pendulum of length l = (100 ... the maximum percentage error in the measurement of g.

The bob of a conical pendulum undergoes ______

Description : The bob of a conical pendulum undergoes ______

Last Answer : The bob of a conical pendulum undergoes ______ (A) Rectilinear motion in horizontal plane ( ... circle (D) Rectilinear motion in vertical circle

The inductance of a coaxial cable with inner radius a and outer radius b, from a distance d, is given by a) L = μd ln(b/a)/2π b) L = 2π μd ln(b/a) c) L = πd/ln(b/a) d) L = 0

Description : The inductance of a coaxial cable with inner radius a and outer radius b, from a distance d, is given by a) L = μd ln(b/a)/2π b) L = 2π μd ln(b/a) c) L = πd/ln(b/a) d) L = 0

Last Answer : a) L = μd ln(b/a)/2π

Which of the following is not a dimension-less group used in catalysis? (Where, D = dispersion co-efficient, cm2 /sec.D1 = diffusion co-efficient; cm2 /sec L = length of the reactor, cm t = time, sec, v = volumetric flow rate, cm3 /sec. V = volume, cm3 .) (A) Reactor dispersion number (D/vL) (B) Reduced time (vt/V) (C) Thiele modulus L √(k/D1 ) (D) None of these

Description : Which of the following is not a dimension-less group used in catalysis? (Where, D = dispersion co-efficient, cm2 /sec.D1 = diffusion co-efficient; cm2 /sec L = length of the reactor, cm t = time, sec, v = volumetric ... (D/vL) (B) Reduced time (vt/V) (C) Thiele modulus L √(k/D1 ) (D) None of these

Last Answer : (D) None of these

As per Taggart's formula, the capacity (kg/hr) of Jaw & Gyratory crushers (for gapes of 10 to 60 cms) is equal to (where, L = Length of feed opening, cms S = Maximum width of discharge opening, cms). (A) LS (B) 93 LS (C) 250 LS (D) √(LS)

Description : As per Taggart's formula, the capacity (kg/hr) of Jaw & Gyratory crushers (for gapes of 10 to 60 cms) is equal to (where, L = Length of feed opening, cms S = Maximum width of discharge opening, cms). (A) LS (B) 93 LS (C) 250 LS (D) √(LS)

Last Answer : (B) 93 LS

The effectiveness factor for large value of Thiele modulus [L√(K/D1 )] of a solid catalysed first order reaction is equal to (where, L = length of the reactor, cm, D1 = diffusion co-efficient, cm2 /second). (A) L √(K/D1 ) (B) 1/[L√(K/D1 )] (C) 1 (D) ∞

Description : The effectiveness factor for large value of Thiele modulus [L√(K/D1 )] of a solid catalysed first order reaction is equal to (where, L = length of the reactor, cm, D1 = diffusion co-efficient, cm2 /second). (A) L √(K/D1 ) (B) 1/[L√(K/D1 )] (C) 1 (D) ∞

Last Answer : (B) 1/[L√(K/D1 )]

A force 2P is acting on the double transverse fillet weld. Leg of weld is h and length l. Determine the shear stress in a plane inclined at θ with horizontal. a) PSinθ(Sinθ+Cosθ)/hl b) P(Sinθ+Cosθ)/hl c) Pcosθ(Sinθ+Cosθ)/hl d) None of the listed

Description : A force 2P is acting on the double transverse fillet weld. Leg of weld is h and length l. Determine the shear stress in a plane inclined at θ with horizontal. a) PSinθ(Sinθ+Cosθ)/hl b) P(Sinθ+Cosθ)/hl c) Pcosθ(Sinθ+Cosθ)/hl d) None of the listed

Last Answer : a) PSinθ(Sinθ+Cosθ)/hl

A force 2P is acting on the double transverse fillet weld. Leg of weld is h and length l. Determine the shear stress in a plane inclined at θ with horizontal. a) PSinθ(Sinθ+Cosθ)/hl b) P(Sinθ+Cosθ)/hl c) Pcosθ(Sinθ+Cosθ)/hl d) None of the listed

Description : A force 2P is acting on the double transverse fillet weld. Leg of weld is h and length l. Determine the shear stress in a plane inclined at θ with horizontal. a) PSinθ(Sinθ+Cosθ)/hl b) P(Sinθ+Cosθ)/hl c) Pcosθ(Sinθ+Cosθ)/hl d) None of the listed

Last Answer : a) PSinθ(Sinθ+Cosθ)/hl

If cos X = a/b, then sin X is equal to: a (b 2 -a 2 )/b b b−a/b c √(b 2 -a 2 )/b d √b−a/b

Description : If cos X = a/b, then sin X is equal to: a (b 2 -a 2 )/b b b−a/b c √(b 2 -a 2 )/b d √b−a/b

Last Answer : c √(b 2 -a 2 )/b

sin ^ 2 θ = cos ^ 2 θ = 1 How is it ?

Last Answer : We hold theta = A. sin2A + cos2 (PM / OP) 2+ (OM / OP) 2 PM2 / OP2 + OM2OP2 (PM2 + OM2) / OP2 OP2 / OP2 => 1 So sin2A + cos2A = 1

In trapezoidal threads, f (coefficient of friction) can be taken as a) f sec θ b) f cos θ c) f sin θ d) f cosec θ

Description : In trapezoidal threads, f (coefficient of friction) can be taken as a) f sec θ b) f cos θ c) f sin θ d) f cosec θ

Last Answer : a) f sec θ

Which of the following formulae is used to calculate tangential stress, when a member is subjected to stress in mutually perpendicular axis and accompanied by a shear stress? a. [(σ x – σ y )/2 ]sin θ – τ cos 2θ b. [(σ x – σ y )/2 ]– τ cos 2θ c. [(σ x – σ y )/2 ]sin θ – τ 2 cos θ d. None of the above

Description : Which of the following formulae is used to calculate tangential stress, when a member is subjected to stress in mutually perpendicular axis and accompanied by a shear stress? a. [(σ x - σ y )/2 ]sin θ - τ cos 2θ b. [(σ x - ... τ cos 2θ c. [(σ x - σ y )/2 ]sin θ - τ 2 cos θ d. None of the above

Last Answer : c. [(σ x – σ y )/2 ]sin θ – τ 2 cos θ

The torque expression of a current carrying conductor is a) T = BIA cos θ b) T = BA cos θ c) T = BIA sin θ d) T = BA sin θ

Description : The torque expression of a current carrying conductor is a) T = BIA cos θ b) T = BA cos θ c) T = BIA sin θ d) T = BA sin θ

Last Answer : c) T = BIA sin θ

Find the Laplace equation value of the following potential field V = r cos θ + φ a) 3 b) 2 c) 1 d) 0

Description : Find the Laplace equation value of the following potential field V = r cos θ + φ a) 3 b) 2 c) 1 d) 0

Last Answer : d) 0

Work done by a uniform magnetic field in moving a charged particle in a circular path is a) qvB sin θ b) mg sin θ c) zero d) mg cos θ

Description : Work done by a uniform magnetic field in moving a charged particle in a circular path is a) qvB sin θ b) mg sin θ c) zero d) mg cos θ

Last Answer : Zero

Torsional rigidity of a shaft is given by a. Gl/θ b. Tθ c. Tl/θ d. T/l

Description : Torsional rigidity of a shaft is given by a. Gl/θ b. Tθ c. Tl/θ d. T/l

Last Answer : c. Tl/θ

The natural frequency (in Hz) of free longitudinal vibrations is equal to a) Square root (k/m) / (2π) b) Square root (g/δ) / (2π) c) 0.4985/δ d) all of the mentioned

Description : The natural frequency (in Hz) of free longitudinal vibrations is equal to a) Square root (k/m) / (2π) b) Square root (g/δ) / (2π) c) 0.4985/δ d) all of the mentioned

Last Answer : d) all of the mentioned

An ordinary clock loses time in summer. This is because (a) The length of the pendulum increases and time period increases (b) The length of the pendulum increases and time period decreases (c) The length of the pendulum decreases and time period increases (d) The length of the pendulum decreases and time period decreases

Description : An ordinary clock loses time in summer. This is because (a) The length of the pendulum increases and time period increases (b) The length of the pendulum increases and time period decreases ... decreases and time period increases (d) The length of the pendulum decreases and time period decreases

Last Answer : Ans:(a)

The acceleration due to gravity on the moon is 1.6 meters per second squared. If a pendulum is whose length is 6.4 meters is placed on the moon, its period will be: w) 1.57 seconds x) 3.14 seconds y) 12.56 seconds z) 25.12 seconds

Description : The acceleration due to gravity on the moon is 1.6 meters per second squared. If a pendulum is whose length is 6.4 meters is placed on the moon, its period will be: w) 1.57 seconds x) 3.14 seconds y) 12.56 seconds z) 25.12 seconds

Last Answer : not real

If the length of a simple pendulum is halved then its period of oscillation is (1) doubled (2) halved (3) increased by a factor 2 (4) decreased by a factor 2

Description : If the length of a simple pendulum is halved then its period of oscillation is (1) doubled (2) halved (3) increased by a factor root 2 (4) decreased by a factor root  2

Last Answer : decreased by a factor root 2

The work done by the string of a simple pendulum during one complete oscillation is equal to (1) Total energy of the pendulum (2) Kinetic energy of the pendulum (3) Potential energy of the pendulum (4) Zero

Description : The work done by the string of a simple pendulum during one complete oscillation is equal to (1) Total energy of the pendulum (2) Kinetic energy of the pendulum (3) Potential energy of the pendulum (4) Zero

Last Answer : (4) Zero Explanation: Work done by the string of the simple pendulum during one complete oscillation is zero. Tension in the string exactly cancels the component parallel to the string. This leaves a net restoring force back toward the equilibrium position as equal to zero.

The work done by the string of a simple pendulum during one complete oscillation is equal to (1) Total energy of the pendulum (2) Kinetic energy of the pendulum (3) Potential energy of the pendulum (4) Zero

Description : The work done by the string of a simple pendulum during one complete oscillation is equal to (1) Total energy of the pendulum (2) Kinetic energy of the pendulum (3) Potential energy of the pendulum (4) Zero

Last Answer : Zero

Calculate the reluctance of a material with length 2π x 10 -4 in air with area 0.5. a) 1 b) 10 c) 100 d) 1000

Description : Calculate the reluctance of a material with length 2π x 10 -4 in air with area 0.5. a) 1 b) 10 c) 100 d) 1000

Last Answer : d) 1000

A particle is moving in Simple Harmonic Motion in a simple pendulum with some period of oscillation. Now in order to double the period of oscillation a.The length of pendulum should be quadrupled b.The length of pendulum should be doubled c.The mass of the bob should be halved d.The length of pendulum should be reduced to one fourth e.The mass of the bob should be doubled

Description : A particle is moving in Simple Harmonic Motion in a simple pendulum with some period of oscillation. Now in order to double the period of oscillation a.The length of pendulum should be quadrupled b.The ... length of pendulum should be reduced to one fourth e.The mass of the bob should be doubled

Last Answer : a. The length of pendulum should be quadrupled

What is the new period of the pendulumThe period of a pendulum is 1.4 seconds. The length of the pendulum is increased by a factor of 4.?

Description : What is the new period of the pendulumThe period of a pendulum is 1.4 seconds. The length of the pendulum is increased by a factor of 4.?

Last Answer : Need answer

A string of length L is fixed between two points. If a standing wave of 5 nodes is produced, what is the relationship between the string's length, L, and its wavelength?

Description : A string of length L is fixed between two points. If a standing wave of 5 nodes is produced, what is the relationship between the string's length, L, and its wavelength?

Last Answer : ANSWER: WAVELENGTH = 1/2 L

What is the highest point on earth? Where is it exactly?

Description : Can you show on a map where the highest point on earth is?

Last Answer : Now everyone would think of Mount Everest. Not at all. It is only the highest above sea level. Farthest from the center of the Earth is the peak of the Chimborazo volcano, which is 6263 meters high ... = '' description = ''] https:///file/2017/05/Volcán_Chimborazo_-El_Taita_Chimborazo-.jpg [/ img]

vcruntime140.dll is missing. Where can I get it?

Description : This program failed to start due to a missing vcruntime140.dll file. Have you ever encountered such an error message?  

Last Answer : Here's a nice little video about the solution: https://www.youtube.com/watch?v=n-CgFu71PTk

msvcp100.dll is missing. Where can I download it?

Description : How do I resolve the error message below? [img alt_text = 'msvcr100.dll' description = ''] https:///wp-content/uploads/2016/11/MSVCP100-1.png [/ img]

Last Answer : Depending on whether your operating system is 64-bit or 32-bit, download the appropriate msvcp100.dll file from there and copy it to C: / windows / System32 / . When asked if you can overwrite the existing file, select yes.      

Drives on a road suitable for parallel traffic where the road markings separating the traffic lanes are not visible. Where can you drive continuously if the traffic on the road is insignificant? (Cross Test)

Description : In the rightmost traffic lane. In a residential area, outside any residential area in the rightmost traffic lane. In any traffic lane.   

Last Answer : In the far right lane. Explanation: This is clear from the right-of-way obligation in this case. This question can be varied in many ways, depending on whether there are road markings or not, whether ... test book! (cross test / Driving on the road / Driving on a road suitable for parallel traffic)

A person of mass ‘m’ kg jumps from a height of ‘h’ meters, he will land on the ground with a velocity equal to: A. √(2 × g × hB. 1/h × √(2 × g)C. 2ghD. 2√(g × h))

Description : A person of mass ‘m’ kg jumps from a height of ‘h’ meters, he will land on the ground with a velocity equal to: A. √(2 × g × h) B. 1/h × √(2 × g) C. 2gh D. 2√(g × h)

Last Answer : √(2 × g × h)

Velocity of escape is equal to A. r × √(2g); where r: radius of Earth or any other planet for that matter, g: gravitational field strength B. g × √(2r); where r: radius of Earth or any other planet for that matter, g: gravitational field strength C. √(2g) ⁄ r; where r: radius of Earth or any other planet for that matter, g: gravitational field strength D. √(2gr); where r: radius of Earth or any other planet for that matter, g: gravitational field strength

Description : Velocity of escape is equal to A. r √(2g); where r: radius of Earth or any other planet for that matter, g: gravitational field strength B. g √(2r); where r: radius of ... (2gr); where r: radius of Earth or any other planet for that matter, g: gravitational field strength

Last Answer : √(2gr); where r: radius of Earth or any other planet for that matter, g: gravitational field strength

The value of x and y which satisfy the equations : √ e) x=1,y=0 f) x=0,y=0 g) x=1,y=1 h) x=0,y=1

Description : The value of x and y which satisfy the equations : √ e) x=1,y=0 f) x=0,y=0 g) x=1,y=1 h) x=0,y=1

Last Answer : f) x=0,y=0

Let f(n) and g(n) be asymptotically non-negative functions. Which of the following is correct? (A) θ(f(n) * g(n)) = min(f(n), g(n)) (B) θ(f(n) * g(n)) = max(f(n), g(n)) (C) θ(f(n) + g(n)) = min(f(n), g(n)) (D) θ(f(n) + g(n)) = max(f(n), g(n))

Description : Let f(n) and g(n) be asymptotically non-negative functions. Which of the following is correct? (A) θ(f(n) * g(n)) = min(f(n), g(n)) (B) θ(f(n) * g(n)) = max(f(n), g(n)) (C) θ(f(n) + g(n)) = min(f(n), g(n)) (D) θ(f(n) + g(n)) = max(f(n), g(n))

Last Answer : (D) θ(f(n) + g(n)) = max(f(n), g(n))

For spheres, volume shape factor is given by (A) π = (A/D2 ) (B) 2π = (2A/D2 ) (C) π/6 = (V/D3 ) (D) AD/V

Description : For spheres, volume shape factor is given by (A) π = (A/D2 ) (B) 2π = (2A/D2 ) (C) π/6 = (V/D3 ) (D) AD/V

Last Answer : (C) π/6 = (V/D3 )

For a function given by F = 4x i + 7y j +z k, the divergence theorem evaluates to which of the values given, if the surface considered is a cone of radius 1/2π m and height 4π 2 m. a) 1 b) 2 c) 3 d) 4

Description : For a function given by F = 4x i + 7y j +z k, the divergence theorem evaluates to which of the values given, if the surface considered is a cone of radius 1/2π m and height 4π 2 m. a) 1 b) 2 c) 3 d) 4

Last Answer : b) 2

Power in watts in a shaft having N RPM is given by the equation (a) Power = 2π NT/60 (b) Power = 2π N T (c) Power = 2000 π N T/60 (d) None

Description : Power in watts in a shaft having N RPM is given by the equation (a) Power = 2π NT/60 (b) Power = 2π N T (c) Power = 2000 π N T/60 (d) None

Last Answer : (a) Power = 2π NT/60

If cos2B = (cos(A+C))/(cos(A-C)) , then show that tan A, tan B and tan C are in G.P. -Maths 9th

Description : If cos2B = (cos(A+C))/(cos(A-C)) , then show that tan A, tan B and tan C are in G.P. -Maths 9th

Last Answer : answer: