The time period of a simple pendulum does not depend upon the mass of the body suspended at the free end of the string. This statement is known as ___________ . (A) law of gravity (B) law of mass (C) law of isochronism (D) law of length

The time period of a simple pendulum does not depend upon the mass of the body
suspended at the free end of the string. This statement is known as ___________ .
(A) law of gravity
(B) law of mass
(C) law of isochronism
(D) law of length
by

1 Answer

Answer :

(B) law of mass
by

Related questions

When a rigid body is suspended vertically and it oscillates with a small amplitude under the action of the force of gravity, the body is known as * 1 point (A) simple pendulum (B) torsional pendulum (C) compound pendulum (D) second’s pendulum

Description : When a rigid body is suspended vertically and it oscillates with a small amplitude under the action of the force of gravity, the body is known as * 1 point (A) simple pendulum (B) torsional pendulum (C) compound pendulum (D) second’s pendulum

Last Answer : (C) compound pendulum

When a rigid body is suspended vertically and it oscillates with a small amplitude under the action of the force of gravity, the body is known as A. simple pendulum B. torsional pendulum C. compound pendulum D. second’s pendulum

Description : When a rigid body is suspended vertically and it oscillates with a small amplitude under the action of the force of gravity, the body is known as A. simple pendulum B. torsional pendulum C. compound pendulum D. second’s pendulum

Last Answer : C. compound pendulum

When a rigid body is suspended vertically and it oscillates with a small amplitude under the action of the force of gravity, the body is known as (A) simple pendulum B) torsional pendulum (C) compound pendulum (D) second’s pendulum

Description : When a rigid body is suspended vertically and it oscillates with a small amplitude under the action of the force of gravity, the body is known as (A) simple pendulum B) torsional pendulum (C) compound pendulum (D) second’s pendulum

Last Answer : (C) compound pendulum

Natural frequency of simple pendulum is proportional to A. Length B. Acceleration due to gravity C. Both D. None

Description : Natural frequency of simple pendulum is proportional to A. Length B. Acceleration due to gravity C. Both D. None

Last Answer : B. Acceleration due to gravity

Time period of a simple pendulum depends upon the length of pendulum (l) and acceleration due to gravity (g). Using dimensional analysis

Description : Time period of a simple pendulum depends upon the length of pendulum (l) and acceleration due to gravity (g). Using dimensional analysis

Last Answer : Time period of a simple pendulum depends upon the length of pendulum (l) and acceleration due to ... expression for time period of a simple pendulum.

A rigid body is suspended vertically at a point and oscillates with a small amplitude under the action of the force of gravity. Such an arrangement is called a.Simple pendulum b.Rigid pendulum c.Second's pendulum d.Compound pendulum e.Newton's pendulum

Description : A rigid body is suspended vertically at a point and oscillates with a small amplitude under the action of the force of gravity. Such an arrangement is called a.Simple pendulum b.Rigid pendulum c.Second's pendulum d.Compound pendulum e.Newton's pendulum

Last Answer : d. Compound pendulum

The static deflection of a spring under gravity, when a mass of 1 kg is suspended from it, is 1 mm. Assume the acceleration due to gravity g = 10 m/s^2. The natural frequency of this spring-mass system (in rad/s) is A 100 B 150 C 200 D 250

Description : The static deflection of a spring under gravity, when a mass of 1 kg is suspended from it, is 1 mm. Assume the acceleration due to gravity g = 10 m/s^2. The natural frequency of this spring-mass system (in rad/s) is A 100 B 150 C 200 D 250

Last Answer : A 100

A simple pendulum consisting of a mass M attached to a string of length L is released from rest at an angle `alpha`. A pin is located at a distance l

Description : A simple pendulum consisting of a mass M attached to a string of length L is released from rest at an angle `alpha`. A pin is located at a distance l

Last Answer : A simple pendulum consisting of a mass M attached to a string of length L is released from rest at an angle `alpha` ... ^(-1) [(L cos alpha-l)/(L+l)]`

A body of mass 20 kg is suspended from a spring which deflects 20mm under this load. Calculate the frequency of free vibrations in Hz. a) 3.5 b) 5 c) 6 d) 7

Description : A body of mass 20 kg is suspended from a spring which deflects 20mm under this load. Calculate the frequency of free vibrations in Hz. a) 3.5 b) 5 c) 6 d) 7

Last Answer : a) 3.5

The acceleration due to gravity is determined by using a simple pendulum of length l = (100 ± 0.1) cm. If its time period is T = (2 ± 0.01)

Description : The acceleration due to gravity is determined by using a simple pendulum of length l = (100 ± 0.1) cm. If its time period is T = (2 ± 0.01)

Last Answer : The acceleration due to gravity is determined by using a simple pendulum of length l = (100 ... the maximum percentage error in the measurement of g.

A simple pendulum is found to vibrate at a frequency of 0.5Hz in vacuum and0.45 Hz in a viscous fluid medium. Find the damping factor. 0.5122 (B) 0.9272 (C) 0.4359 (D) 0.2568

Description : A simple pendulum is found to vibrate at a frequency of 0.5Hz in vacuum and0.45 Hz in a viscous fluid medium. Find the damping factor. 0.5122 (B) 0.9272 (C) 0.4359 (D) 0.2568

Last Answer : (C) 0.4359

A simple pendulum is found to vibrate at a frequency of 0.5Hz in vacuum and 0.45Hz in a viscous fluid medium. Find the damping factor. A 0.5122 B 0.9237 C 0.4359 D 0.2568

Description : A simple pendulum is found to vibrate at a frequency of 0.5Hz in vacuum and 0.45Hz in a viscous fluid medium. Find the damping factor. A 0.5122 B 0.9237 C 0.4359 D 0.2568

Last Answer : C 0.4359

The number of degrees of freedom of a simple pendulum is: (a) 0 (b) 1 (c) 2

Description : The number of degrees of freedom of a simple pendulum is: (a) 0 (b) 1 (c) 2

Last Answer : (b) 1

The period of pendulum depend upon _

Description : The period of pendulum depend upon _

Last Answer : Length

A particle is moving in Simple Harmonic Motion in a simple pendulum with some period of oscillation. Now in order to double the period of oscillation a.The length of pendulum should be quadrupled b.The length of pendulum should be doubled c.The mass of the bob should be halved d.The length of pendulum should be reduced to one fourth e.The mass of the bob should be doubled

Description : A particle is moving in Simple Harmonic Motion in a simple pendulum with some period of oscillation. Now in order to double the period of oscillation a.The length of pendulum should be quadrupled b.The ... length of pendulum should be reduced to one fourth e.The mass of the bob should be doubled

Last Answer : a. The length of pendulum should be quadrupled

What is a conical pendulum? Show that its time period is given by 2π √(l cos θ)/g, where l is the length of the string,

Description : What is a conical pendulum? Show that its time period is given by 2π √(l cos θ)/g, where l is the length of the string,

Last Answer : What is a conical pendulum? Show that its time period is given by 2π\(\sqrt{\frac{l\,cos\, ... the vertical and g is the acceleration due to gravity.

A cantilever shaft having 50 mm diameter and a length of 300mm has a disc of mass 100 kg at its free end. The Young’s modulus for the shaft material is 200 GN/m^2. Determine the static deflection of shaft in mm. A 0.144 B 0.244 C 0.344 D 0.444

Description : A cantilever shaft having 50 mm diameter and a length of 300mm has a disc of mass 100 kg at its free end. The Young’s modulus for the shaft material is 200 GN/m^2. Determine the static deflection of shaft in mm. A 0.144 B 0.244 C 0.344 D 0.444

Last Answer : A 0.144

A cantilever shaft having 50 mm diameter and length of 300 mm has a disc of mass 100 kg at its free enD. The Young’s modulus for the shaft material is 200 GN/m 2 . Calculate the natural longitudinal frequency in Hz. A. 575B. 625 C. 525 D. 550

Description : A cantilever shaft having 50 mm diameter and length of 300 mm has a disc of mass 100 kg at its free enD. The Young’s modulus for the shaft material is 200 GN/m 2 . Calculate the natural longitudinal frequency in Hz. A. 575B. 625 C. 525 D. 550

Last Answer : A. 575

A cantilever shaft having 50 mm diameter and a length of 300 mm has a disc of mass 100 kg at its free end. The Young’s modulus for the shaft material is 200 GN/m 3 . Determine the static deflection of the shaft in mm. a) 0.147 b) 0.213 c) 0.132 d) 0.112

Description : A cantilever shaft having 50 mm diameter and a length of 300 mm has a disc of mass 100 kg at its free end. The Young’s modulus for the shaft material is 200 GN/m 3 . Determine the static deflection of the shaft in mm. a) 0.147 b) 0.213 c) 0.132 d) 0.112

Last Answer : a) 0.147

A cantilever shaft having 50 mm diameter and a length of 300 mm has a disc of mass 100 kg at its free end. The Young’s modulus for the shaft material is 200 GN/m 2 . Determine the frequency of transverse vibrations of the shaft. a) 31 b) 35 c) 37 d) 41

Description : A cantilever shaft having 50 mm diameter and a length of 300 mm has a disc of mass 100 kg at its free end. The Young’s modulus for the shaft material is 200 GN/m 2 . Determine the frequency of transverse vibrations of the shaft. a) 31 b) 35 c) 37 d) 41

Last Answer : d) 41

A cantilever shaft having 50 mm diameter and length of 300 mm has a disc of mass 100 kg at its free end. The Young’s modulus for the shaft material is 200 GN/m 2 . Calculate the natural longitudinal frequency in Hz. a) 575 b) 625 c) 525 d) 550

Description : A cantilever shaft having 50 mm diameter and length of 300 mm has a disc of mass 100 kg at its free end. The Young’s modulus for the shaft material is 200 GN/m 2 . Calculate the natural longitudinal frequency in Hz. a) 575 b) 625 c) 525 d) 550

Last Answer : a) 575

A cantilever shaft has a diameter of 6 cm and the length is 40cm, it has a disc of mass 125 kg at its free end. The Young’s modulus for the shaft material is 250 GN/m2. Calculate the static deflection in nm. a) 0.001 b) 0.083c) 1.022 d) 0.065

Description : A cantilever shaft has a diameter of 6 cm and the length is 40cm, it has a disc of mass 125 kg at its free end. The Young’s modulus for the shaft material is 250 GN/m2. Calculate the static deflection in nm. a) 0.001 b) 0.083c) 1.022 d) 0.065

Last Answer : a) 0.001

A mass of 10 kg when suspended from a spring causes a static deflection of 0.01m. Find the spring stiffness for the same system. A 9810 N/m B 8910 N/m C 1098 N/m D 9801 N/m

Description : A mass of 10 kg when suspended from a spring causes a static deflection of 0.01m. Find the spring stiffness for the same system. A 9810 N/m B 8910 N/m C 1098 N/m D 9801 N/m

Last Answer : A 9810 N/m

A 1 kg mass is suspended by a spring having a stiffness of 0.4 N/mm. Determine the natural frequency. A 20 rad/sec B 30 rad/sec C 20 Hz D 30 Hz

Description : A 1 kg mass is suspended by a spring having a stiffness of 0.4 N/mm. Determine the natural frequency. A 20 rad/sec B 30 rad/sec C 20 Hz D 30 Hz

Last Answer : B 30 rad/sec

A mass of 10 kg when suspended from a spring causes a static deflection of 0.01m. Find the spring stiffness for the same system. A 9810 N/m B 8910 N/m C 1098 N/m D 9801 N/m

Description : A mass of 10 kg when suspended from a spring causes a static deflection of 0.01m. Find the spring stiffness for the same system. A 9810 N/m B 8910 N/m C 1098 N/m D 9801 N/m

Last Answer : D 9801 N/m

A mass of 10 kg when suspended from a spring causes a static deflection of A 0.01m. Find the spring stiffness for the same system. (A) 9810 N/m (B) 8910 N/m (C)1098 N/m (D) 9801 N/m

Description : A mass of 10 kg when suspended from a spring causes a static deflection of A 0.01m. Find the spring stiffness for the same system. (A) 9810 N/m (B) 8910 N/m (C)1098 N/m (D) 9801 N/m

Last Answer : A) 9810 N/m

A 10 Kg mass suspended by spring of stiffness 1000 N/m. the natural frequency of the system after giving excitation will be A. 0 Hz B. 1.59 Hz C. 2 Hz D. 15.9 Hz

Description : A 10 Kg mass suspended by spring of stiffness 1000 N/m. the natural frequency of the system after giving excitation will be A. 0 Hz B. 1.59 Hz C. 2 Hz D. 15.9 Hz

Last Answer : B. 1.59 Hz

Frequency of centrifugal pendulum absorber is always proportional to A) Oscillating motion B) Transfer motion C) Speed of rotating body D) All of the above

Description : Frequency of centrifugal pendulum absorber is always proportional to A) Oscillating motion B) Transfer motion C) Speed of rotating body D) All of the above

Last Answer : C) Speed of rotating body

When the body vibrates under the influence of external force, then the body is said to be under ___________ . * 1 point (A) free vibrations (B) natural vibrations (C) forced vibrations (D) damped vibrations

Description : When the body vibrates under the influence of external force, then the body is said to be under ___________ . * 1 point (A) free vibrations (B) natural vibrations (C) forced vibrations (D) damped vibrations

Last Answer : (C) forced vibrations

The acceleration due to gravity on the moon is 1.6 meters per second squared. If a pendulum is whose length is 6.4 meters is placed on the moon, its period will be: w) 1.57 seconds x) 3.14 seconds y) 12.56 seconds z) 25.12 seconds

Description : The acceleration due to gravity on the moon is 1.6 meters per second squared. If a pendulum is whose length is 6.4 meters is placed on the moon, its period will be: w) 1.57 seconds x) 3.14 seconds y) 12.56 seconds z) 25.12 seconds

Last Answer : not real

When a periodic disturbing force is applied to a machine, the force is transmitted to the ___________ by the means of spring. (A) dampers (B) foundation (C) mass (D) none of the above

Description : When a periodic disturbing force is applied to a machine, the force is transmitted to the ___________ by the means of spring. (A) dampers (B) foundation (C) mass (D) none of the above

Last Answer : (B) foundation

. In centrifugal pendulum absorber , the natural frequency in cycle per second can be given by A Fn =N √(R/L) B Fn =1/N √(R/L) C Fn =N/2 √(R/L) D Fn =N2 √(R/L)

Description : . In centrifugal pendulum absorber , the natural frequency in cycle per second can be given by A Fn =N √(R/L) B Fn =1/N √(R/L) C Fn =N/2 √(R/L) D Fn =N2 √(R/L)

Last Answer : A Fn =N √(R/L)

When the torsional pendulum vibrating the observed amplitudes on the same side of neutral axis for successive cycles are found to decay 50% of the initial value determine logarithmic decrement. A 0.065 B 0.006 C 0.693 D 0.5

Description : When the torsional pendulum vibrating the observed amplitudes on the same side of neutral axis for successive cycles are found to decay 50% of the initial value determine logarithmic decrement. A 0.065 B 0.006 C 0.693 D 0.5

Last Answer : C 0.693

When the torsional pendulum vibrating, the observed amplitudes on the same side of the neutral axis for successive cycles are found to decay 50% of the initial value determine logarithmic decrement. A 0.065 B 0.006 C 0.693 D 0.5

Description : When the torsional pendulum vibrating, the observed amplitudes on the same side of the neutral axis for successive cycles are found to decay 50% of the initial value determine logarithmic decrement. A 0.065 B 0.006 C 0.693 D 0.5

Last Answer : C 0.693

In centrifugal pendulum absorber , the natural frequency in cycle per second can be given by A) Fn =N √(R/L) B) Fn =1/N √(R/L) C) Fn =N/2 √(R/L) D) Fn =N2 √(R/L)

Description : In centrifugal pendulum absorber , the natural frequency in cycle per second can be given by A) Fn =N √(R/L) B) Fn =1/N √(R/L) C) Fn =N/2 √(R/L) D) Fn =N2 √(R/L)

Last Answer : A) Fn =N √(R/L)

Who discovered the concept of pendulum? A. Newton B. Einstein C. Galileo D. None

Description : Who discovered the concept of pendulum? A. Newton B. Einstein C. Galileo D. None

Last Answer : C. Galileo

The work done by the string of a simple pendulum during one complete oscillation is equal to (1) Total energy of the pendulum (2) Kinetic energy of the pendulum (3) Potential energy of the pendulum (4) Zero

Description : The work done by the string of a simple pendulum during one complete oscillation is equal to (1) Total energy of the pendulum (2) Kinetic energy of the pendulum (3) Potential energy of the pendulum (4) Zero

Last Answer : (4) Zero Explanation: Work done by the string of the simple pendulum during one complete oscillation is zero. Tension in the string exactly cancels the component parallel to the string. This leaves a net restoring force back toward the equilibrium position as equal to zero.

The work done by the string of a simple pendulum during one complete oscillation is equal to (1) Total energy of the pendulum (2) Kinetic energy of the pendulum (3) Potential energy of the pendulum (4) Zero

Description : The work done by the string of a simple pendulum during one complete oscillation is equal to (1) Total energy of the pendulum (2) Kinetic energy of the pendulum (3) Potential energy of the pendulum (4) Zero

Last Answer : Zero

If the length of a simple pendulum is halved then its period of oscillation is - (1) doubled (2) halved (3) increased by a factor √ 2 (4) decreased by a factor √ 2

Description : If the length of a simple pendulum is halved then its period of oscillation is - (1) doubled (2) halved (3) increased by a factor √ 2 (4) decreased by a factor √ 2

Last Answer : (4) decreased by a factor √ 2

If the length of a simple pendulum is halved then its period of oscillation is (1) doubled (2) halved (3) increased by a factor 2 (4) decreased by a factor 2

Description : If the length of a simple pendulum is halved then its period of oscillation is (1) doubled (2) halved (3) increased by a factor root 2 (4) decreased by a factor root  2

Last Answer : decreased by a factor root 2

Which of the following statements is/are true for coulomb damping? 1. Coulomb damping occurs due to friction between two lubricated surfaces2. Damping force is opposite to the direction of motion of vibrating body 3. For smooth surfaces, coefficient of friction depends upon velocity 4. Damping force depends upon the rubbing velocity between two rubbing surfaces a. Only statement 1 b. Statement 2, 3 and statement 4 c. Only statement 2 d. All the above statements are true

Description : Which of the following statements is/are true for coulomb damping? 1. Coulomb damping occurs due to friction between two lubricated surfaces2. Damping force is opposite to the direction of motion of vibrating body ... 2, 3 and statement 4 c. Only statement 2 d. All the above statements are true

Last Answer : c. Only statement 2

For small oscillations, what happens to the period of a simple pendulum when the mass of the pendulum bob is doubled?

Description : For small oscillations, what happens to the period of a simple pendulum when the mass of the pendulum bob is doubled? 

Last Answer : ANSWER: NOTHING or PERIOD IS UNAFFECTED

Which formula is used to calculate mass moment of inertia (I G ) of a circular rim about the axis through centre of gravity? a. mr 2 /2b. mr 2 /12 c. mr 2 /4 d. mr 2

Description : Which formula is used to calculate mass moment of inertia (I G ) of a circular rim about the axis through centre of gravity? a. mr 2 /2b. mr 2 /12 c. mr 2 /4 d. mr 2

Last Answer : d. mr 2

Increasing which of the following factor would result in increase of free torsional vibration? A. Radius of gyration B. Mass moment of inertia C. Polar moment of inertia D. Length

Description : Increasing which of the following factor would result in increase of free torsional vibration? A. Radius of gyration B. Mass moment of inertia C. Polar moment of inertia D. Length

Last Answer : C. Polar moment of inertia

Which of the following relation is correct regarding free torsional vibrations of a single motor system? a) Independent of modulus of rigidity b) Independent of polar moment of inertia c) Dependent on mass moment of inertia d) Independent of length of shaft

Description : Which of the following relation is correct regarding free torsional vibrations of a single motor system? a) Independent of modulus of rigidity b) Independent of polar moment of inertia c) Dependent on mass moment of inertia d) Independent of length of shaft

Last Answer : c) Dependent on mass moment of inertia

Increasing which of the following factor would result in increase of free torsional vibration? a) Radius of gyration b) Mass moment of inertiac) Polar moment of inertia d) Length

Description : Increasing which of the following factor would result in increase of free torsional vibration? a) Radius of gyration b) Mass moment of inertiac) Polar moment of inertia d) Length

Last Answer : c) Polar moment of inertia

A weight of 50 N is suspended from a spring of stiffness 4000N/m and subjected to a harmonic force of magnitude 60N and frequency 60 Hz. what will be the static displacement of the spring due to maximum applied force A. 0.015m B. 0.15 m C. 15 m D. 150m

Description : A weight of 50 N is suspended from a spring of stiffness 4000N/m and subjected to a harmonic force of magnitude 60N and frequency 60 Hz. what will be the static displacement of the spring due to maximum applied force A. 0.015m B. 0.15 m C. 15 m D. 150m

Last Answer : B. 0.15 m

If a mass whose moment of inertia is Ic/3 is placed at the free end and the constraint is assumed to be of negligible mass, then the kinetic energy is ______ a) 1/6 Icω 2 b) 1/2Icω 2 c) 1/3Icω 2 d) 1/12Icω 2

Description : If a mass whose moment of inertia is Ic/3 is placed at the free end and the constraint is assumed to be of negligible mass, then the kinetic energy is ______ a) 1/6 Icω 2 b) 1/2Icω 2 c) 1/3Icω 2 d) 1/12Icω 2

Last Answer : a) 1/6 Icω 2

For the same dimensions of the shaft which of the following has the greater natural frequency? A. Transverse B. Longitudinal C. Depends on thickness D. Depends upon length

Description : For the same dimensions of the shaft which of the following has the greater natural frequency? A. Transverse B. Longitudinal C. Depends on thickness D. Depends upon length

Last Answer : B. Longitudinal

For the same dimensions of the shaft which of the following has the greater natural frequency? (A) Transverse (B) Longitudinal (C) Depends on thickness (D) Depends upon length

Description : For the same dimensions of the shaft which of the following has the greater natural frequency? (A) Transverse (B) Longitudinal (C) Depends on thickness (D) Depends upon length

Last Answer : (B) Longitudinal