If two springs having individual stiffness K, are in parallel, then their equivalent stiffness will be
A. 2K
B. K
C. K/2
D. 4K

1 Answer

Answer :

A. 2K

Related questions

Description : Two springs have spring stiffness of 1500 N/m and 1 KN/m respectively. If they are connected in series, what will be the equivalent spring stiffness? A 1KN/m B 600 N/m C 1 N/m D 600 KN/m

Last Answer : B 600 N/m

Description : Two springs have spring stiffness of 1500 N/m and 1 KN/m respectively. If they are connected in series, what will be the equivalent spring stiffness? A 1KN/m B 600 N/m C 1 N/m D 600 KN/m

Last Answer : B 600 N/m

Description : Two springs have spring stiffness of 1500 N/m and 2000 N/m respectively. If they are connected in series, what is the spring stiffness if they are replaced by an equivalent system.3500 N/m A. 3500 N/m B. 1166 N/mC. 857.63 N/m D. None of the above

Last Answer : C. 857.63 N/m

Description : Two springs have spring stiffness of 1500 N/m and 2000 N/m respectively. If they are connected in series, what is the spring stiffness if they are replaced by an equivalent system.3500 N/m A) 3500 N/m B) 1166 N/m C) 857.63 N/m D) None of the above

Last Answer : C) 857.63 N/m

Description : Two springs have spring stiffness of 1500 N/m and 1 KN/m respectively. If they B are connected in series, what will be the equivalent spring stiffness? (A) 1KN/m (B) 600 N/m (C) 1 N/m (D) 600 KN/m

Last Answer : (B) 600 N/m

Description : Two springs have spring stiffness of 1500 N/m and 2000 N/m respectively. If they are connected in series, what is the spring stiffness if they are replaced by an equivalent system.3500 N/m a. 3500 N/m b. 1166 N/m c. 857.63 N/m d. None of the above

Last Answer : c. 857.63

Description : A mass of 1 kg is attached to two identical springs each with stiffness k = 20 kN/m as shown in the figure. Under frictionless condition, the natural frequency of the system in Hz is close to * 1 point (A) 32 (B) 23 (C) 16 (D) 11

Last Answer : (A) 32

Description : Which of the following relations is true when springs are connected parallelly? where K = spring stiffness a.Ke= K1 +K2 b. (1/Ke)=(1/K1)+(1/K2) c.Ke= (1/K1)+(1/K2) d.None of the above

Last Answer : a.Ke= K1 +K2

Description : The equivalent stiffness of spring connected in parallel having stiffnesses k1 and k2 can be written as * 1 point (A)(1/k1) + (1/k2) (B) (1/k1) - (1/k2) (C) k1 + k2 (D) None of the above

Last Answer : (C) k1 + k2

Description : Equivalent stiffness of spring connected in paralled having stiffness k1 and k2 can be given as A) K = k1+ k2 B) K = k1- k2 C) 1/k = 1/k1 + 1/k2 D) 1/k = 1/k1 - 1/k2

Last Answer : A) K = k1+ k2

Description : In a 2-mass 3 spring vibrating system the two masses each are of 9.8 kg coupling spring is having a stiffness of 3430 N/m whereas the other two springs have each a stiffness of 8820 N/m. The two natural frequencies in rad /sec are A) 10 & 20 B) 20 & 30 C) 30 & 40D) 40 & 50

Last Answer : C) 30 & 40

Description : Two springs have spring stiffness of 1500 N/m and 2000 N/m respectively. If they are connected in series, what is the spring stiffness a. 3500 N/m b. 1166 N/m c. 857.63 N/m d. None of the above

Last Answer : c. 857.63 N/m

Description : In coulomb damping, the amplitude of motion in each cycle is reduced by A. F/K B. 2F/K C. 4F/K D. F/4K

Last Answer : C. 4F/K

Description : What is the effect on the undamped natural frequency of a single-degree-of-freedom system if the stiffness of one or more of the springs is increased? (A) The frequency will increase (B) The frequency will stay the same (C) The frequency will decrease (D) None of these

Last Answer : (A) The frequency will increase

Description : Which of the following relations is true when springs are connected in parallel? where K = spring stiffnessa. K e = K 1 + K 2 b. (1 / K e ) = (1/K 1 ) + (1/ K 2 ) c. K e = (1/K 1 ) + (1/ K 2 ) d. None of the above

Last Answer : a. K e = K 1 + K 2

Description : For a program of k variables, boundary value analysis yields .............. test cases. (A) 4k – 1 (B) 4k (C) 4k + 1 (D) 2k – 1

Last Answer : (C) 4k + 1

Description : A helical spring of constant k is cut into four equal pieces and the four pieces are then combined in parallel. The equivalent spring constant will be (a) k/16 (b) k/4 (c) 4k (d) 16k

Last Answer : (d) 16k

Description : Pick out the wrong statement. (A) The equivalent stiffness of two springs (of equal stiffness 'S') in series is S/2 while in parallel is 2S (B) For a helical spring, deflection is ... is less than the buckling load (D) Modulus of resilience is proportional to (stress at elastic limit)2

Last Answer : (C) Crushing load or columns is less than the buckling load

Description : For two springs in parallel, effective stiffness (k) is Where k 1 & k 2 are stiffness of springs 1 & 2 respectively (A) k 1 k 2 / (k 1 + k 2 ) (B) k 1 + k 2 (C) k 1 k 2 (D) (k 1 + k 2 ) / k 1 k 2

Last Answer : (B) k 1 + k 2

Description : Determine natural frequency of a system, which has equivalent spring stiffness of 30000 N/m and mass of 20 kg? A 12.32 Hz B 4.10 Hz C 6.16 HzD None of the above

Last Answer : C 6.16 Hz

Description : Determine natural frequency of a system, which has equivalent spring stiffness of 43200 N/m and mass of 12 kg. A 40.22 rad/sec B 40 Hz C 60 Hz D 60 rad/sec

Last Answer : D 60 rad/sec

Description : Determine natural frequency of a system, which has equivalent spring stiffness of 30000 N/m and mass of 20 kg? A. 12.32 Hz B. 4.10 Hz C. 6.16 Hz D. None of the above

Last Answer : C. 6.16 Hz

Description : Determine natural frequency of a system, which has equivalent spring stiffness of 30000 N/m and mass of 20 kg? A) 12.32 Hz B) 4.10 Hz C) 6.16 Hz D) None of the above

Last Answer : C) 6.16 Hz

Description : Determine natural frequency of a system, which has equivalent spring stiffness of 30000 N/m and mass of 20 kg? C ( A )12.32 Hz (B) 4.10 Hz ( C )6.16 Hz (D)None of the above

Last Answer : ( C )6.16 Hz

Description : Determine natural frequency of a system, which has equivalent spring stiffness of 30000 N/m mass of 20 kg? a. 12.32 Hz b. 4.10 Hz c. 6.16 Hz d. None of the above

Last Answer : c. 6.16 Hz

Description : Calculate equivalent stiffness of the spring for the system shown below, which has spring stiffness of 3000 N/m a. 1000 N/m b. 2250 N/m c. 2000 N/m d. None of the above

Last Answer : b. 2250 N/m

Description : If the spring mass system with m and spring stiffness k is taken to very high altitude, the natural frequency of longitudinal vibrations * 1 point (A) increases (B) decreases (C) remain unchanged (D) may increase or decrease depending upon the value of the mass

Last Answer : (C) remain unchanged

Description : In a spring mass system of mass m and stiffness k, the end of the spring are securely fixed and mass is attached to intermediate point of spring. The natural frequency of longitudinal ... is attached decreases D) Decreases as the distance from the bottom end where mass is attached decreases

Last Answer : B) Is minimum when mass is attached to mid point of the spring

Description : If the spring mass system with m and spring stiffness k is taken to very high altitude , the natural frequency of longitudinal vibrations A) Increases B) Decreases C) Remain unchanged D) May be increase or decrease depending upon the value of the mass

Last Answer : C) Remain unchanged

Description : Reduction in vibration amplitude after one complete cycle of single degree free vibration with dry friction damping is_____, if where F"= frictional force between mass and surface and k =stiffness of the system. a)4F/k a b) 2f/K C) 3F/k D)8F/k

Last Answer : a)4F/k

Description : Which of the following relations is true when springs are connected series. A K e = K 1 + K 2 B (1 / K e ) = (1/K 1 ) + (1/ K 2 ) C K e = (1/K 1 ) + (1/ K 2 ) D (1 / K e ) = K 1 + K 2

Last Answer : B (1 / K e ) = (1/K 1 ) + (1/ K 2 )

Description : Which of the following relations is true when springs are connected parallelly? A K e = K 1 + K 2 B (1 / K e ) = (1/K 1 ) + (1/ K 2 ) C K e = (1/K 1 ) + (1/ K 2 ) D (1 / K e ) = K 1 + K 2

Last Answer : A K e = K 1 + K 2

Description : Which of the following relations is true when springs are connected series. (A) K e = K 1 + K 2 (B) (1 / K e ) = (1/K 1 ) + (1/ K 2 ) (C) K e = (1/K 1 ) + (1/ K 2 ) (D) (1 / K e ) = K 1 + K 2

Last Answer : (B) (1 / K e ) = (1/K 1 ) + (1/ K 2 )

Description : A vibrating system having mass 1kg, a spring of stiffness 1000N/m and damping factor of 0.632 and it is put to harmonic excitation of 10N. Find the amplitude at resonance. A 0.079 B 7.9C 0.056 D 0.00791

Last Answer : D 0.00791

Description : A 1 kg mass is suspended by a spring having a stiffness of 0.4 N/mm. Determine the natural frequency. A 20 rad/sec B 30 rad/sec C 20 Hz D 30 Hz

Last Answer : B 30 rad/sec

Description : A car having a mass of 1000 kg deflects its springs 4 cm under its load. Determine the natural frequency of the car in vertical direction. A 5 Hz B 4.67 Hz C 9.8 Hz D 2.49 Hz

Last Answer : D 2.49 Hz

Description : A car having a mass of 1000 kg deflects its springs 4 cm under its load. Determine the natural frequency of the car in vertical direction. A 5 HzB 4.67 Hz C 9.8 Hz D 2.49 Hz

Last Answer : D 2.49 Hz

Description : A car having a mass of 1000 kg deflects its springs 4 cm under its load. D Determine the natural frequency of the car in vertical direction. (A)5 Hz (B) 4.67 Hz (C) 9.8 Hz (D) 2.49 Hz

Last Answer : (D) 2.49 Hz

Description : A vehicle suspension system consists of a spring and a damper. Stiffness of spring is 3.5 KN/m and damping constant of damper is 400Ns/m. If mass is 50 kg, then damping factor is A 0.606 B 0.10 C 0.666 D 0.471

Last Answer : D 0.471

Description : A vehicle suspension system consists of a spring and a damper. The stiffness of the spring is 3.6 kN/m and the damping constant of the damper is 400 Ns/m. If the mass is 50 kg, then the damping factor (d ) and damped natural ... , are a) 0.471 and 1.19 Hz b) 0.471 and 7.48 Hz c) 0.666 and 1.35 Hz

Last Answer : a) 0.471 and 1.19 Hz

Description : A vehicle suspension system consists of a spring and a damper. The stiffness of the spring is 3.6 kN/m and the damping constant of the damper is 400 Ns/m. If the mass is 50 kg, then the damping factor (d ) and damped natural ... .19 Hz b) 0.471 and 7.48 Hz c) 0.666 and 1.35 Hz d) 0.666 and 8.50 Hz

Last Answer : a) 0.471 and 1.19 Hz

Description : Two springs of stiffness k1 and k2 are connected in parallel, the combined stiffness of the connection is given by, (A) k1k2/k1 + k2 (B) k1k2/k1 - k2 (C) k1 + k2 (D) k1 + k2/k1k2

Last Answer : (C) k1 + k2

Description : For two springs in series, effective stiffness (k) is Where k 1 & k 2 are stiffness of springs 1 & 2 respectively (A) k 1 k 2 / (k 1 + k 2 ) (B) k 1 + k 2 (C) k 1 k 2 (D) (k 1 + k 2 ) / k 1 k 2

Last Answer : (A) k 1 k 2 / (k 1 + k 2 )

Description : The mass, stiffness, and damping matrices of a two-degree-of-freedom system are symmetric.

Last Answer : True

Description : A mass of 10 kg when suspended from a spring causes a static deflection of 0.01m. Find the spring stiffness for the same system. A 9810 N/m B 8910 N/m C 1098 N/m D 9801 N/m

Last Answer : A 9810 N/m

Description : The critical speed of a shaft depends upon its A. Mass B. Stiffness C. Mass and stiffnessD. Stiffness and eccentricity

Last Answer : C. Mass and stiffness

Description : Calculate the value of critical damping coefficient if a vibrating system has mass of 4kg and stiffness of 100N/m A 20 N-sec/m B 40 N-sec/m C 60 N-sec/m D 80 N-sec/m

Last Answer : B 40 N-sec/m

Description : A mass of 10 kg when suspended from a spring causes a static deflection of 0.01m. Find the spring stiffness for the same system. A 9810 N/m B 8910 N/m C 1098 N/m D 9801 N/m

Last Answer : D 9801 N/m

Description : The natural frequency of a system is a function of A The stiffness of the system B The mass of the system C Both A and B D None of the mentioned

Last Answer : C Both A and B

Description : A weight of 50 N is suspended from a spring of stiffness 4000N/m and subjected to a harmonic force of magnitude 60N and frequency 60 Hz. what will be the static displacement of the spring due to maximum applied force A. 0.015m B. 0.15 m C. 15 m D. 150m

Last Answer : B. 0.15 m