The equivalent stiffness of spring connected in parallel having stiffnesses k1 and k2 can be written as * 1 point (A)(1/k1) + (1/k2) (B) (1/k1) - (1/k2) (C) k1 + k2 (D) None of the above

The equivalent stiffness of spring connected in parallel having stiffnesses k1 and k2 can be
written as *
1 point
(A)(1/k1) + (1/k2)
(B) (1/k1) - (1/k2)
(C) k1 + k2
(D) None of the above
by

1 Answer

Answer :

(C) k1 + k2
by

Related questions

Equivalent stiffness of spring connected in paralled having stiffness k1 and k2 can be given as A) K = k1+ k2 B) K = k1- k2 C) 1/k = 1/k1 + 1/k2 D) 1/k = 1/k1 - 1/k2

Description : Equivalent stiffness of spring connected in paralled having stiffness k1 and k2 can be given as A) K = k1+ k2 B) K = k1- k2 C) 1/k = 1/k1 + 1/k2 D) 1/k = 1/k1 - 1/k2

Last Answer : A) K = k1+ k2

Which of the following relations is true when springs are connected parallelly? where K = spring stiffness a.Ke= K1 +K2 b. (1/Ke)=(1/K1)+(1/K2) c.Ke= (1/K1)+(1/K2) d.None of the above

Description : Which of the following relations is true when springs are connected parallelly? where K = spring stiffness a.Ke= K1 +K2 b. (1/Ke)=(1/K1)+(1/K2) c.Ke= (1/K1)+(1/K2) d.None of the above

Last Answer : a.Ke= K1 +K2

Two springs of stiffness k1 and k2 are connected in parallel, the combined stiffness of the connection is given by, (A) k1k2/k1 + k2 (B) k1k2/k1 - k2 (C) k1 + k2 (D) k1 + k2/k1k2

Description : Two springs of stiffness k1 and k2 are connected in parallel, the combined stiffness of the connection is given by, (A) k1k2/k1 + k2 (B) k1k2/k1 - k2 (C) k1 + k2 (D) k1 + k2/k1k2

Last Answer : (C) k1 + k2

Two springs of stiffness k1 and k2 are connected in series, the combined (A) k1k2/k1 + k2 (B) k1k2/k1 - k2 (C) k1 + k2 (D) k1 + k2/k1k2

Description : Two springs of stiffness k1 and k2 are connected in series, the combined (A) k1k2/k1 + k2 (B) k1k2/k1 - k2 (C) k1 + k2 (D) k1 + k2/k1k2

Last Answer : (A) k1k2/k1 + k2

Two springs have spring stiffness of 1500 N/m and 1 KN/m respectively. If they are connected in series, what will be the equivalent spring stiffness? A 1KN/m B 600 N/m C 1 N/m D 600 KN/m

Description : Two springs have spring stiffness of 1500 N/m and 1 KN/m respectively. If they are connected in series, what will be the equivalent spring stiffness? A 1KN/m B 600 N/m C 1 N/m D 600 KN/m

Last Answer : B 600 N/m

Two springs have spring stiffness of 1500 N/m and 1 KN/m respectively. If they are connected in series, what will be the equivalent spring stiffness? A 1KN/m B 600 N/m C 1 N/m D 600 KN/m

Description : Two springs have spring stiffness of 1500 N/m and 1 KN/m respectively. If they are connected in series, what will be the equivalent spring stiffness? A 1KN/m B 600 N/m C 1 N/m D 600 KN/m

Last Answer : B 600 N/m

Two springs have spring stiffness of 1500 N/m and 2000 N/m respectively. If they are connected in series, what is the spring stiffness if they are replaced by an equivalent system.3500 N/m A. 3500 N/m B. 1166 N/mC. 857.63 N/m D. None of the above

Description : Two springs have spring stiffness of 1500 N/m and 2000 N/m respectively. If they are connected in series, what is the spring stiffness if they are replaced by an equivalent system.3500 N/m A. 3500 N/m B. 1166 N/mC. 857.63 N/m D. None of the above

Last Answer : C. 857.63 N/m

Two springs have spring stiffness of 1500 N/m and 2000 N/m respectively. If they are connected in series, what is the spring stiffness if they are replaced by an equivalent system.3500 N/m A) 3500 N/m B) 1166 N/m C) 857.63 N/m D) None of the above

Description : Two springs have spring stiffness of 1500 N/m and 2000 N/m respectively. If they are connected in series, what is the spring stiffness if they are replaced by an equivalent system.3500 N/m A) 3500 N/m B) 1166 N/m C) 857.63 N/m D) None of the above

Last Answer : C) 857.63 N/m

Two springs have spring stiffness of 1500 N/m and 1 KN/m respectively. If they B are connected in series, what will be the equivalent spring stiffness? (A) 1KN/m (B) 600 N/m (C) 1 N/m (D) 600 KN/m

Description : Two springs have spring stiffness of 1500 N/m and 1 KN/m respectively. If they B are connected in series, what will be the equivalent spring stiffness? (A) 1KN/m (B) 600 N/m (C) 1 N/m (D) 600 KN/m

Last Answer : (B) 600 N/m

Two springs have spring stiffness of 1500 N/m and 2000 N/m respectively. If they are connected in series, what is the spring stiffness if they are replaced by an equivalent system.3500 N/m a. 3500 N/m b. 1166 N/m c. 857.63 N/m d. None of the above

Description : Two springs have spring stiffness of 1500 N/m and 2000 N/m respectively. If they are connected in series, what is the spring stiffness if they are replaced by an equivalent system.3500 N/m a. 3500 N/m b. 1166 N/m c. 857.63 N/m d. None of the above

Last Answer : c. 857.63

Determine the equivalent spring constant of the system shown in FigK1=10 N/m, K2=20 N/m. K3=30 N/m, K4=34 N/m, K5=40 N/m a) 10N/m b)20N/m c)30N/m d) None

Description : Determine the equivalent spring constant of the system shown in FigK1=10 N/m, K2=20 N/m. K3=30 N/m, K4=34 N/m, K5=40 N/m a) 10N/m b)20N/m c)30N/m d) None

Last Answer : b)20N/m

If two springs having individual stiffness K, are in parallel, then their equivalent stiffness will be A. 2K B. K C. K/2 D. 4K

Description : If two springs having individual stiffness K, are in parallel, then their equivalent stiffness will be A. 2K B. K C. K/2 D. 4K

Last Answer : A. 2K

Determine natural frequency of a system, which has equivalent spring stiffness of 30000 N/m and mass of 20 kg? A 12.32 Hz B 4.10 Hz C 6.16 HzD None of the above

Description : Determine natural frequency of a system, which has equivalent spring stiffness of 30000 N/m and mass of 20 kg? A 12.32 Hz B 4.10 Hz C 6.16 HzD None of the above

Last Answer : C 6.16 Hz

Determine natural frequency of a system, which has equivalent spring stiffness of 43200 N/m and mass of 12 kg. A 40.22 rad/sec B 40 Hz C 60 Hz D 60 rad/sec

Description : Determine natural frequency of a system, which has equivalent spring stiffness of 43200 N/m and mass of 12 kg. A 40.22 rad/sec B 40 Hz C 60 Hz D 60 rad/sec

Last Answer : D 60 rad/sec

Determine natural frequency of a system, which has equivalent spring stiffness of 30000 N/m and mass of 20 kg? A. 12.32 Hz B. 4.10 Hz C. 6.16 Hz D. None of the above

Description : Determine natural frequency of a system, which has equivalent spring stiffness of 30000 N/m and mass of 20 kg? A. 12.32 Hz B. 4.10 Hz C. 6.16 Hz D. None of the above

Last Answer : C. 6.16 Hz

Determine natural frequency of a system, which has equivalent spring stiffness of 30000 N/m and mass of 20 kg? A) 12.32 Hz B) 4.10 Hz C) 6.16 Hz D) None of the above

Description : Determine natural frequency of a system, which has equivalent spring stiffness of 30000 N/m and mass of 20 kg? A) 12.32 Hz B) 4.10 Hz C) 6.16 Hz D) None of the above

Last Answer : C) 6.16 Hz

Determine natural frequency of a system, which has equivalent spring stiffness of 30000 N/m and mass of 20 kg? C ( A )12.32 Hz (B) 4.10 Hz ( C )6.16 Hz (D)None of the above

Description : Determine natural frequency of a system, which has equivalent spring stiffness of 30000 N/m and mass of 20 kg? C ( A )12.32 Hz (B) 4.10 Hz ( C )6.16 Hz (D)None of the above

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Determine natural frequency of a system, which has equivalent spring stiffness of 30000 N/m mass of 20 kg? a. 12.32 Hz b. 4.10 Hz c. 6.16 Hz d. None of the above

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Two springs have spring stiffness of 1500 N/m and 2000 N/m respectively. If they are connected in series, what is the spring stiffness a. 3500 N/m b. 1166 N/m c. 857.63 N/m d. None of the above

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Last Answer : c. 857.63 N/m

A vibrating system having mass 1kg, a spring of stiffness 1000N/m and damping factor of 0.632 and it is put to harmonic excitation of 10N. Find the amplitude at resonance. A 0.079 B 7.9C 0.056 D 0.00791

Description : A vibrating system having mass 1kg, a spring of stiffness 1000N/m and damping factor of 0.632 and it is put to harmonic excitation of 10N. Find the amplitude at resonance. A 0.079 B 7.9C 0.056 D 0.00791

Last Answer : D 0.00791

A 1 kg mass is suspended by a spring having a stiffness of 0.4 N/mm. Determine the natural frequency. A 20 rad/sec B 30 rad/sec C 20 Hz D 30 Hz

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In a 2-mass 3 spring vibrating system the two masses each are of 9.8 kg coupling spring is having a stiffness of 3430 N/m whereas the other two springs have each a stiffness of 8820 N/m. The two natural frequencies in rad /sec are A) 10 & 20 B) 20 & 30 C) 30 & 40D) 40 & 50

Description : In a 2-mass 3 spring vibrating system the two masses each are of 9.8 kg coupling spring is having a stiffness of 3430 N/m whereas the other two springs have each a stiffness of 8820 N/m. The two natural frequencies in rad /sec are A) 10 & 20 B) 20 & 30 C) 30 & 40D) 40 & 50

Last Answer : C) 30 & 40

If the spring mass system with m and spring stiffness k is taken to very high altitude, the natural frequency of longitudinal vibrations * 1 point (A) increases (B) decreases (C) remain unchanged (D) may increase or decrease depending upon the value of the mass

Description : If the spring mass system with m and spring stiffness k is taken to very high altitude, the natural frequency of longitudinal vibrations * 1 point (A) increases (B) decreases (C) remain unchanged (D) may increase or decrease depending upon the value of the mass

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In a spring mass system of mass m and stiffness k, the end of the spring are securely fixed and mass is attached to intermediate point of spring. The natural frequency of longitudinal vibration of the system A) Is maximum when mass is attached to mid point of the spring B) Is minimum when mass is attached to mid point of the spring C) Decreases as the distance from the top end where mass is attached decreases D) Decreases as the distance from the bottom end where mass is attached decreases

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Last Answer : B) Is minimum when mass is attached to mid point of the spring

Which of the following relations is true when springs are connected in parallel? where K = spring stiffnessa. K e = K 1 + K 2 b. (1 / K e ) = (1/K 1 ) + (1/ K 2 ) c. K e = (1/K 1 ) + (1/ K 2 ) d. None of the above

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Last Answer : a. K e = K 1 + K 2

A vehicle suspension system consists of a spring and a damper. Stiffness of spring is 3.5 KN/m and damping constant of damper is 400Ns/m. If mass is 50 kg, then damping factor is A 0.606 B 0.10 C 0.666 D 0.471

Description : A vehicle suspension system consists of a spring and a damper. Stiffness of spring is 3.5 KN/m and damping constant of damper is 400Ns/m. If mass is 50 kg, then damping factor is A 0.606 B 0.10 C 0.666 D 0.471

Last Answer : D 0.471

A mass of 10 kg when suspended from a spring causes a static deflection of 0.01m. Find the spring stiffness for the same system. A 9810 N/m B 8910 N/m C 1098 N/m D 9801 N/m

Description : A mass of 10 kg when suspended from a spring causes a static deflection of 0.01m. Find the spring stiffness for the same system. A 9810 N/m B 8910 N/m C 1098 N/m D 9801 N/m

Last Answer : A 9810 N/m

A mass of 10 kg when suspended from a spring causes a static deflection of 0.01m. Find the spring stiffness for the same system. A 9810 N/m B 8910 N/m C 1098 N/m D 9801 N/m

Description : A mass of 10 kg when suspended from a spring causes a static deflection of 0.01m. Find the spring stiffness for the same system. A 9810 N/m B 8910 N/m C 1098 N/m D 9801 N/m

Last Answer : D 9801 N/m

A weight of 50 N is suspended from a spring of stiffness 4000N/m and subjected to a harmonic force of magnitude 60N and frequency 60 Hz. what will be the static displacement of the spring due to maximum applied force A. 0.015m B. 0.15 m C. 15 m D. 150m

Description : A weight of 50 N is suspended from a spring of stiffness 4000N/m and subjected to a harmonic force of magnitude 60N and frequency 60 Hz. what will be the static displacement of the spring due to maximum applied force A. 0.015m B. 0.15 m C. 15 m D. 150m

Last Answer : B. 0.15 m

A system has a mass of 0.5 kg and spring stiffness of 2452 N/m. Find the natural frequency of the system. A. 5.14 Hz B. 9.14 Hz C. 11.14 Hz D. 28.14 Hz

Description : A system has a mass of 0.5 kg and spring stiffness of 2452 N/m. Find the natural frequency of the system. A. 5.14 Hz B. 9.14 Hz C. 11.14 Hz D. 28.14 Hz

Last Answer : C. 11.14 Hz

A vertical spring-mass system has a mass of 0.5 kg and an initial deflection of 0.2 cm. Find the spring stiffness. A. 345 N/m B. 245 N/m C. 3452 N/mD. 2452 N/m

Description : A vertical spring-mass system has a mass of 0.5 kg and an initial deflection of 0.2 cm. Find the spring stiffness. A. 345 N/m B. 245 N/m C. 3452 N/mD. 2452 N/m

Last Answer : D. 2452 N/m

If the spring mass system with m and spring stiffness k is taken to very high altitude , the natural frequency of longitudinal vibrations A) Increases B) Decreases C) Remain unchanged D) May be increase or decrease depending upon the value of the mass

Description : If the spring mass system with m and spring stiffness k is taken to very high altitude , the natural frequency of longitudinal vibrations A) Increases B) Decreases C) Remain unchanged D) May be increase or decrease depending upon the value of the mass

Last Answer : C) Remain unchanged

In the spring mass system if the mass of the system is doubled with spring stiffness halved, the natural frequency of longitudinal vibration A) Remained unchanged B) Is doubled C) Is halved D) Is quadruped

Description : In the spring mass system if the mass of the system is doubled with spring stiffness halved, the natural frequency of longitudinal vibration A) Remained unchanged B) Is doubled C) Is halved D) Is quadruped

Last Answer : C) Is halved

A mass of 10 kg when suspended from a spring causes a static deflection of A 0.01m. Find the spring stiffness for the same system. (A) 9810 N/m (B) 8910 N/m (C)1098 N/m (D) 9801 N/m

Description : A mass of 10 kg when suspended from a spring causes a static deflection of A 0.01m. Find the spring stiffness for the same system. (A) 9810 N/m (B) 8910 N/m (C)1098 N/m (D) 9801 N/m

Last Answer : A) 9810 N/m

In spring mass experiment, the natural frequency of 10 kg mass was found to be 12 rad/sec. the stiffness of the spring is A. 800 N/m B. 1200 N/m C. 1440 N/m D. 2000 N/m

Description : In spring mass experiment, the natural frequency of 10 kg mass was found to be 12 rad/sec. the stiffness of the spring is A. 800 N/m B. 1200 N/m C. 1440 N/m D. 2000 N/m

Last Answer : C. 1440 N/m

A 10 Kg mass suspended by spring of stiffness 1000 N/m. the natural frequency of the system after giving excitation will be A. 0 Hz B. 1.59 Hz C. 2 Hz D. 15.9 Hz

Description : A 10 Kg mass suspended by spring of stiffness 1000 N/m. the natural frequency of the system after giving excitation will be A. 0 Hz B. 1.59 Hz C. 2 Hz D. 15.9 Hz

Last Answer : B. 1.59 Hz

The natural frequency of the spring mass is inversely proportional to A. Stiffness B. Mass C. Density D. Deflection

Description : The natural frequency of the spring mass is inversely proportional to A. Stiffness B. Mass C. Density D. Deflection

Last Answer : B. Mass

A vehicle suspension system consists of a spring and a damper. The stiffness of the spring is 3.6 kN/m and the damping constant of the damper is 400 Ns/m. If the mass is 50 kg, then the damping factor (d ) and damped natural frequency (f n ), respectively, are a) 0.471 and 1.19 Hz b) 0.471 and 7.48 Hz c) 0.666 and 1.35 Hz

Description : A vehicle suspension system consists of a spring and a damper. The stiffness of the spring is 3.6 kN/m and the damping constant of the damper is 400 Ns/m. If the mass is 50 kg, then the damping factor (d ) and damped natural ... , are a) 0.471 and 1.19 Hz b) 0.471 and 7.48 Hz c) 0.666 and 1.35 Hz

Last Answer : a) 0.471 and 1.19 Hz

A gun barrel of mass 600 Kg has a recoil spring of stiffness 294 KN/m. If the barrel recoils 1.3 m on firing, what will be the initial recoil velocity of the barrel? (A) 28.77 m/s (B) 32.77 m/s (C) 35.77 m/s (D) 40.77 m/s

Description : A gun barrel of mass 600 Kg has a recoil spring of stiffness 294 KN/m. If the barrel recoils 1.3 m on firing, what will be the initial recoil velocity of the barrel? (A) 28.77 m/s (B) 32.77 m/s (C) 35.77 m/s (D) 40.77 m/s

Last Answer : (A) 28.77 m/s

A system has a mass of 0.5 kg and spring stiffness of 2452 N/m. Find the natural frequency of the system. (A) 5.14 Hz (B) 9.14 Hz (C) 11.14 Hz (D) 28.14 Hz

Description : A system has a mass of 0.5 kg and spring stiffness of 2452 N/m. Find the natural frequency of the system. (A) 5.14 Hz (B) 9.14 Hz (C) 11.14 Hz (D) 28.14 Hz

Last Answer : (C) 11.14 Hz

A vehicle suspension system consists of a spring and a damper. The stiffness of the spring is 3.6 kN/m and the damping constant of the damper is 400 Ns/m. If the mass is 50 kg, then the damping factor (d ) and damped natural frequency (f n ), respectively, are a) 0.471 and 1.19 Hz b) 0.471 and 7.48 Hz c) 0.666 and 1.35 Hz d) 0.666 and 8.50 Hz

Description : A vehicle suspension system consists of a spring and a damper. The stiffness of the spring is 3.6 kN/m and the damping constant of the damper is 400 Ns/m. If the mass is 50 kg, then the damping factor (d ) and damped natural ... .19 Hz b) 0.471 and 7.48 Hz c) 0.666 and 1.35 Hz d) 0.666 and 8.50 Hz

Last Answer : a) 0.471 and 1.19 Hz

for the system shown below K1=20N/m K1=10N/m K1=20N/m K1=50N/mFind W such that the natural frequency of the system will be 1.592 cycles per second a)0.125kg b)0.25kg c)0.5kg 4)4kg

Description : for the system shown below K1=20N/m K1=10N/m K1=20N/m K1=50N/mFind W such that the natural frequency of the system will be 1.592 cycles per second a)0.125kg b)0.25kg c)0.5kg 4)4kg

Last Answer : b)0.25kg

With increase in K2 /K1 in case of a unimolecular type elementary reactions as shown in the bellow figure, the fractional yield of 'R' in mixed reactor (for a given conversion of 'A'). (A) Decreases (B) Increases (C) Increases linearly (D) Remain same

Description : With increase in K2 /K1 in case of a unimolecular type elementary reactions as shown in the bellow figure, the fractional yield of 'R' in mixed reactor (for a given conversion of 'A'). (A) Decreases (B) Increases (C) Increases linearly (D) Remain same

Last Answer : (A) Decreases

The following gas phase reactions are carried out isothermally in a CSTR. A → 2R ; r1 = k1pA ; k1 = 20mole/(sec.m3 bar)A → 3S ; r2 = k2 pA ;k2 = 40mole/(sec.m3.bar)What is the maximum possible value of FR(mole/sec.)?(A) 1/3(B) 1/2(C) 2/3(D) 2

Description : The following gas phase reactions are carried out isothermally in a CSTR. A → 2R ; r1 = k1pA ; k1 = 20mole/(sec.m3 bar) A → 3S ; r2 = k2 pA ; k2 = 40mole/(sec.m3 .bar) What is the maximum possible value of FR(mole/sec.)? (A) 1/3 (B) 1/2 (C) 2/3 (D) 2

Last Answer : (C) 2/3

Decomposition rate of a liquid 'X' which decomposes as per the reaction as shown in the bellow figure is given by: (A) K1 . CX (B) (K1 + K2 + K3 ) CX (C) (K1 + K2 ) CX (D) (K2 + K3 ) CX

Description : Decomposition rate of a liquid 'X' which decomposes as per the reaction as shown in the bellow figure is given by: (A) K1 . CX (B) (K1 + K2 + K3 ) CX (C) (K1 + K2 ) CX (D) (K2 + K3 ) CX

Last Answer : (C) (K1 + K2 ) CX

Which of the following is the rate law for SN1 mechanisms? (a) Rate = k[Alkyl Halide] [Nucleophile] (b) Rate = k[Nucleophile] (c) Rate = k[Alkyl Halide](d) Rate = k1[Alkyl Halide] + k2[Nucleophile]

Description : Which of the following is the rate law for SN1 mechanisms? (a) Rate = k[Alkyl Halide] [Nucleophile] (b) Rate = k[Nucleophile] (c) Rate = k[Alkyl Halide] (d) Rate = k1[Alkyl Halide] + k2[Nucleophile]

Last Answer : Rate = k[Alkyl Halide]

The thickness of oxide film is y at time t. If K1, K2 and K3 are the temperature dependent constants, the parabolic law of oxidation is given by (A) y2 = 2k1t + k2 (B) y = k1 ln (k2t + k3) (C) y = k1 t + k2 (D) y = k1t3 + k2

Description : The thickness of oxide film is y at time t. If K1, K2 and K3 are the temperature dependent constants, the parabolic law of oxidation is given by (A) y2 = 2k1t + k2 (B) y = k1 ln (k2t + k3) (C) y = k1 t + k2 (D) y = k1t3 + k2

Last Answer : Option A

Pick out the wrong statement. (A) The equivalent stiffness of two springs (of equal stiffness 'S') in series is S/2 while in parallel is 2S (B) For a helical spring, deflection is proportional to D3(D = mean coil diameter) or d4(d = wire diameter) (C) Crushing load or columns is less than the buckling load (D) Modulus of resilience is proportional to (stress at elastic limit)2

Description : Pick out the wrong statement. (A) The equivalent stiffness of two springs (of equal stiffness 'S') in series is S/2 while in parallel is 2S (B) For a helical spring, deflection is ... is less than the buckling load (D) Modulus of resilience is proportional to (stress at elastic limit)2

Last Answer : (C) Crushing load or columns is less than the buckling load