Description : The total strain energy for a unit cube subjected to three principal stresses is given by? a) U= [(σέ) 1 + (σέ) 2+ (σέ) 3]/3 b) U= [(σ12+σ22+σ32)/2E] – (σ1σ2+σ2σ3+σ3σ1)2μ c) U= [(σέ) 1 + (σέ) 2+ (σέ) 3]/4 d) None of the mentioned
Last Answer : b) U= [(σ12+σ22+σ32)/2E] – (σ1σ2+σ2σ3+σ3σ1)2μ
Description : How many maximum shear stresses are there with three principal stresses? a. 1 b. 2 c. 3 d. None
Last Answer : c. 3
Description : Nature of the three principal stresses is a. Firstly All tensile b. Secondly All compressive c. Thirdly All shear d. None
Last Answer : a. Firstly All tensile
Description : In a body under pure shear, the magnitude and nature of the two principal stresses are a. Firstly Equals shear stress, opposite nature b. Secondly Equals shear stress, same nature c. Both (a) & (b) d. None
Last Answer : a. Firstly Equals shear stress, opposite nature
Description : Under complex loading, principal stresses exist as (a) Firstly σ 1 > σ 2 =σ 3 (b) Secondly σ 1 = σ 2 =σ 3 (c) Thirdly σ 1 > σ 2 < σ 3 (d) None
Last Answer : (d) None
Description : Symbols for principal stresses are a. Firstly σ, τ & γ b. Secondly σ 1 , σ 2 & σ 3
Last Answer : b. Secondly σ 1 , σ 2 & σ 3
Description : The maximum number of principal stresses is a. 1 b. 3 c. 5 d. None
Last Answer : b. 3
Description : The maximum number of principal stresses is a. 2 b. 4 c. 6 d. None
Last Answer : d. None
Description : Why do we determine principal stresses? a. Failure is due to simple stress or strain b. Failure is due to complex stress or strain c. Both (a) & (b) d. None
Last Answer : a. Failure is due to simple stress or strain
Description : Shear strain energy under principal tensile stresses σ1 and σ2 is (a) (1/12E) (σ1 — σ2) 2 + σ2 2 — σ1 2 ) (b) (1/12G) (σ1 — σ2) 2 + σ2 2 + σ1 2 ) (c) (1/12K) (σ1 — σ2) 2 + σ2 2 + σ1 2 ) (d) None
Last Answer : (b) (1/12G) (σ1 — σ2) 2 + σ2 2 + σ1 2 )
Description : Resilience under principal tensile stresses σ1 and σ2 is (a) (1/2E)( σ1 2 + σ2 2 –μ σ1 σ2) (b) (1/2E)( σ1 2 + σ2 2 –4μ σ1 σ2) (c) (1/2E)( σ1 2 + σ2 2 –2μ σ1 σ2) (d) None
Last Answer : (c) (1/2E)( σ1 2 + σ2 2 –2μ σ1 σ2)
Description : Resilience under principal tensile stresses σ1 and σ2 is (a) (1/2E)( σ1 2 + σ2 2 –3μ σ1 σ2) (b) (1/2E)( σ1 2 + σ2 2 –4μ σ1 σ2) (c) (1/2E)( σ1 2 + σ2 2 –5μ σ1 σ2) (d) None
Description : Principal stresses are found by a. Analytical method b. Graphical method c. Analytical & graphical methods d. None
Last Answer : c. Analytical & graphical methods
Description : Maximum shear stress in terms of principal stresses is a. Firstly (σ 1 +σ 2 )/2 b. Secondly (σ 1 /σ 2 ) c. Thirdly (σ 1 –σ 2 )/2 d. None
Last Answer : c. Thirdly (σ 1 –σ 2 )/2
Description : In the analysis, all the principal stresses are assumed as a. Shear stresses b. Compressive stresses c. Tensile stresses d. None
Last Answer : c. Tensile stresses
Description : Principal stresses are a. Firstly Maximum and minimum shear stresses b. Secondly Maximum and minimum normal stresses c. Both (a) & (b) d. None
Last Answer : b. Secondly Maximum and minimum normal stresses
Description : The order of magnitude of the principal stresses is a. Firstly σ 1 >σ 2 >σ 3 b. Secondly σ 2 >σ 3 >σ 1 c. Thirdly σ 1 >σ 3 >σ 2 d. None
Last Answer : a. Firstly σ 1 >σ 2 >σ 3
Description : All the principal stresses are at an angle of (a)90 0 (b) 45 0 (c) 135 0 (d) None
Last Answer : (a)90 0
Description : All the principal stresses are at an angle of (a) 45 0 (b) 60 0 (c) 75 0 (d) None
Description : The equations for principal stresses are valid only when (a)σ x and σ y are both tensile (b) σ x is compressive and σ y is tensile (c) σ x is tensile and σ y is compressive (d) None
Last Answer : (a)σ x and σ y are both tensile
Description : The magnitude of principal stresses due to complex stresses is (a) (1/2)[ (σ x + σ y ) ± ((σ x –σ y ) 2 + 4 τ 2 )) 0.5 ] (b) (1/2)[ (σx + σy) ± (1/2)((σx –σy) 2 + 4 τ 2 )) 0.5 ] (c) (1/2)[ (σx + σy) ± ((1/2)(σx –σy) 2 + 4 τ 2 )) 0.5 ]
Last Answer : (a) (1/2)[ (σ x + σ y ) ± ((σ x –σ y ) 2 + 4 τ 2 )) 0.5 ]
Description : Maximum shear stress is (a) Average sum of principal stresses (b) Average difference of principal stresses (c) Average sum as well as difference of principal stresses (d) None
Last Answer : (b) Average difference of principal stresses
Description : Which of the following stresses can be determined using Mohr's circle method? a. Torsional stress b. Bending stress c. Principal stress d. All of the above
Last Answer : c. Principal stress
Description : There are in all (a) Two principal strains (b) Three principal strains (c) Four principal strains (d) None
Last Answer : (b) Three principal strains
Description : There are in all (a) Two principal planes (b) Three principal planes (c) Four principal planes (d) None
Last Answer : (b) Three principal planes
Description : Total number of maximum shear stresses is (a) One (b) Three (c) Five (d) None
Last Answer : (b) Three
Description : In a general two dimensional stress system, there are a. Two principal planes b. Only one plane c. Three principal planes d. No principal plane
Last Answer : a. Two principal planes
Description : Split flywheel is made to (A) Avoid cooling stresses (B) Minimize large centrifugal forces (C) Reduce weight (D) All of the above
Last Answer : (A) Avoid cooling stresses
Description : When comes down to stress reduction, which one is preferred? a) Solid flywheel b) Split flywheel c) Both have equal stresses d) Cannot be determined
Last Answer : b) Split flywheel
Description : Torsional shear stresses are induced in the spring wire when (A) spring is under compression (B) spring is under tension (C) both (A) and (B) (D) none of the above
Last Answer : (C) both (A) and (B)
Description : Propagation of fatigue failure is always due to compressive stresses. a) Due to bending b) Due to tensile c) Due to fatigue d) None of the listed
Last Answer : b) Due to tensile
Description : What will happen if stresses induced due to surge in the spring exceeds the endurance limit stress of the spring. a) Fatigue Failure b) Fracture c) None of the listed d) Nipping
Last Answer : a) Fatigue Failure
Description : If spring index=2.5, what can be concluded about stresses in the wire? a) They are high b) They are negligible c) They are moderate d) Cannot be determined
Last Answer : a) They are high
Description : The helical spring ad wire of helical torsion spring, both are subjected to torsional shear stresses. a) True b) False
Last Answer : b) False
Description : Cotter joint is employed when the members are subjected to which sort of stresses? a) Axial tensile b) Axial compressive c) Axial tensile or compressive d) None of the above
Last Answer : c) Axial tensile or compressive
Description : Transverse fillet welds are under (i) Bending and shear stresses (ii)Compressive and torsion shear stresses (iii)Tensile and compressive stresses (iv)None
Last Answer : (iv)None
Description : The advantage of a welded joint over a riveted joint is (i) Introduce residual stresses (ii) Requires highly skilled labor and supervision (iii) Lighter in weight (iv) None
Last Answer : (iii) Lighter in weight
Description : Parallel fillet welds are under Shear and bending stresses Compressive and torsion shear stresses Tensile and compressive stresses None
Last Answer : None
Description : The following bracket is welded to the vertical column. The joint undergoes torsional stresses. a) True b) False
Description : Cotter joint is used when the members are subjected to which type of stresses? a) Axial tensile b) Axial compressive c) Axial tensile or compressive d) None of the mentioned
Description : Which of the following statements are true about eccentrically loaded circular base? a) All bolts are symmetrically spaced with equal angle on either side of vertical b) Bolts are not preloaded c) Bearing is rigid d) Dowel pins are used to relieve stresses
Last Answer : a) All bolts are symmetrically spaced with equal angle on either side of vertical
Description : The region of safety for biaxial stresses is of which shape in the case of maximum distortion energy theorem. a) Ellipse b) Circle c) Rectangle d) Square
Last Answer : a) Ellipse
Description : If the mean stress value for a sinusoidal stress function is zero, then this type of stress falls in which category? a) Fluctuating Stresses b) Alternating Stresses c) Repeated Stresses d) Reversed Stresses
Last Answer : d) Reversed Stresses
Description : The stress represented by cos (t) belongs to which category? a) Fluctuating Stresses b) Alternating Stresses c) Repeated Stresses d) Reversed Stresses
Description : The stress represented by sin (t) + 4 belongs to which category? a) Alternating Stresses b) None of the mentioned c) Repeated Stresses d) Reversed Stresses
Last Answer : a) Alternating Stresses
Description : The stress represented by sin (t) + 2 belongs to which category? a) Fluctuating Stresses b) None of the mentioned c) Repeated Stresses d) Reversed Stresses
Last Answer : a) Fluctuating Stresses
Description : The stress represented by sin (t) + 1 belongs to which category? a) Fluctuating Stresses b) Alternating stresses c) Repeated Stresses d) Reversed Stresses
Last Answer : c) Repeated Stresses
Description : The phenomenon of decreased resistance of the materials to fluctuating stresses is the main characteristic of _____ failure. a) Fracture b) Fatigue c) Yielding d) None of the mentioned
Last Answer : b) Fatigue