Description : In a general two dimensional stress system, there are a. Two principal planes b. Only one plane c. Three principal planes d. No principal plane
Last Answer : a. Two principal planes
Description : In a general two dimensional stress system, planes of maximum shear stress are inclined at ___ with principal planes. a. 90 degree b. 180 degree c. 45 degree d. 60 degree
Last Answer : c. 45 degree
Description : Principal planes are mutually inclined at a. 45 degree b. 60 degree c. 90 degree d. 180 degree
Last Answer : c. 90 degree
Description : Principal planes are those planes on which a. Normal stress is maximum b. Normal stress is minimum c. Normal stress is either maximum or minimum d. Shear stress is maximum
Last Answer : c. Normal stress is either maximum or minimum
Description : There are in all (a) Two principal strains (b) Three principal strains (c) Four principal strains (d) None
Last Answer : (b) Three principal strains
Description : There are in all (a) Two principal stresses (b) Three principal stresses (c) Four principal stresses (d) None
Last Answer : (b) Three principal stresses
Description : Ellipse of stress is used to find a. Resultant stress on any plane in a bi-axial stress system b. Resultant stress on any plane in a general two dimensional system c. Maximum shear stress d. Location of planes of maximum shear stress
Last Answer : a. Resultant stress on any plane in a bi-axial stress system
Description : Angle of obliquity is defined as a. Angle between the plane on which stresses are evaluated and one of the given planes b. Angle between resultant stress and the plane of given normal stress c. Angle between resultant stress and shear stress d. Angle between resultant stress and normal stress
Last Answer : d. Angle between resultant stress and normal stress
Description : On the planes of maximum shear, there are (a) Normal stresses (b) Bending stresses (c) Bucking stresses (d) None
Last Answer : (a) Normal stresses
Description : The total strain energy for a unit cube subjected to three principal stresses is given by? a) U= [(σέ) 1 + (σέ) 2+ (σέ) 3]/3 b) U= [(σ12+σ22+σ32)/2E] – (σ1σ2+σ2σ3+σ3σ1)2μ c) U= [(σέ) 1 + (σέ) 2+ (σέ) 3]/4 d) None of the mentioned
Last Answer : b) U= [(σ12+σ22+σ32)/2E] – (σ1σ2+σ2σ3+σ3σ1)2μ
Description : How many maximum shear stresses are there with three principal stresses? a. 1 b. 2 c. 3 d. None
Last Answer : c. 3
Description : Nature of the three principal stresses is a. Firstly All tensile b. Secondly All compressive c. Thirdly All shear d. None
Last Answer : a. Firstly All tensile
Description : In a body under pure shear, the magnitude and nature of the two principal stresses are a. Firstly Equals shear stress, opposite nature b. Secondly Equals shear stress, same nature c. Both (a) & (b) d. None
Last Answer : a. Firstly Equals shear stress, opposite nature
Description : A transmission shaft subjected to pure bending moment should be designed on the basis of (A) Maximum principal stress theory (B) Maximum shear stress theory (C) Distortion energy theory (D) Goodman or Soderberg diagrams
Last Answer : (A) Maximum principal stress theory
Description : For a homogeneous & isotropic body under hydrostatic pressure, which theory of elastic failure does not fail (a) Firstly Maximum Principal Theory (b) Secondly Maximum Shear Stress Theory (c) Thirdly Maximum Principal Energy Theory (d) None
Last Answer : (a) Firstly Maximum Principal Theory
Description : For a homogeneous & isotropic body under hydrostatic pressure, which theory of elastic failure fails (a) Firstly Maximum Principal Theory (b) Secondly Maximum Principal strain Theory (c) Thirdly Maximum Principal Energy Theory (d) None
Last Answer : (c) Thirdly Maximum Principal Energy Theory
Description : Under complex loading, principal stresses exist as (a) Firstly σ 1 > σ 2 =σ 3 (b) Secondly σ 1 = σ 2 =σ 3 (c) Thirdly σ 1 > σ 2 < σ 3 (d) None
Last Answer : (d) None
Description : Under complex loading, if elastic limit reaches in tension, then failure occurs due to (a) Firstly Maximum principal strain theory (b) Secondly Maximum principal theory of strain energy (c) Thirdly Maximum Principal stress theory (d) None
Last Answer : (c) Thirdly Maximum Principal stress theory
Description : Under complex loading, if elastic limit reaches in tension, then failure occurs due to (a) Firstly Maximum principal strain theory (b) Secondly Maximum principal theory of strain energy (c) Thirdly Maximum shear stress theory (d) None
Description : A ductile material may not meet a failure if it has been tested for the theories of failure (a) Firstly Maximum Principal Theory (b) Secondly Maximum Principal Strain Theory (c) Thirdly Maximum principal strain energy theory (d) None
Description : Maximum principal strain is equal to when σ1 and σ2 are tensile (a) (σ1 –μσ2)/E (b) (σ1 + μσ2)/E (c) (–σ1 –μσ2)/E (d) None
Last Answer : (a) (σ1 –μσ2)/E
Description : Maximum principal strain theory is also called as (a) Guest’s theory (b) Haigh theory (c) St.Venant’s theory (d) None
Last Answer : (c) St.Venant’s theory
Description : Maximum principal strain theory is applicable to (a) Ductile materials (b) Brittle materials (c) Composite materials (d) None
Last Answer : (b) Brittle materials
Description : Maximum principal stress is equal to (a) (σx + σy)/2 + [ (σx –σy) 2 + τ 2 ] 0.5 (b) (σx + σy)/2 + 0.5 [ (σx –σy) 2 + τ 2 ] 0.5 (c) (σx + σy)/2 + 0.5 [ (σx –σy) 2 + 4τ 2 ] 0.5 (d) None
Last Answer : (c) (σx + σy)/2 + 0.5 [ (σx –σy) 2 + 4τ 2 ] 0.5
Description : Maximum principal theory is also known as (a) Beltrami Theory (b) Maximum normal stress theory (c) Saint Venant’s theory (d) None
Last Answer : (b) Maximum normal stress theory
Description : Maximum principal theory is also known as (a) Guest Theory (b) Beltrami Theory (c) Rankine Theory (d) None
Last Answer : (c) Rankine Theory
Description : Under maximum principal stress theory, maximum principal stress is equal to (a) Allowable stress in tension (b) Allowable stress in compression (c) Allowable stress in shear (d) None
Last Answer : (a) Allowable stress in tension
Description : Maximum principal stress theory is applicable to (a) Ductile materials (b) Brittle materials (c) Composite materials (d) None
Description : Maximum Principal Stress Theory is not good for brittle materials. a) True b) False
Last Answer : b) False
Description : If compressive yield stress and tensile yield stress are equivalent, then region of safety from maximum principal stress theory is of which shape? a) Rectangle b) Square c) Circle d) Ellipse
Last Answer : b) Square
Description : Symbols for principal stresses are a. Firstly σ, τ & γ b. Secondly σ 1 , σ 2 & σ 3
Last Answer : b. Secondly σ 1 , σ 2 & σ 3
Description : The maximum number of principal stresses is a. 1 b. 3 c. 5 d. None
Last Answer : b. 3
Description : The maximum number of principal stresses is a. 2 b. 4 c. 6 d. None
Last Answer : d. None
Description : Why do we determine principal stresses? a. Failure is due to simple stress or strain b. Failure is due to complex stress or strain c. Both (a) & (b) d. None
Last Answer : a. Failure is due to simple stress or strain
Description : Shear strain energy under principal tensile stresses σ1 and σ2 is (a) (1/12E) (σ1 — σ2) 2 + σ2 2 — σ1 2 ) (b) (1/12G) (σ1 — σ2) 2 + σ2 2 + σ1 2 ) (c) (1/12K) (σ1 — σ2) 2 + σ2 2 + σ1 2 ) (d) None
Last Answer : (b) (1/12G) (σ1 — σ2) 2 + σ2 2 + σ1 2 )
Description : Resilience under principal tensile stresses σ1 and σ2 is (a) (1/2E)( σ1 2 + σ2 2 –μ σ1 σ2) (b) (1/2E)( σ1 2 + σ2 2 –4μ σ1 σ2) (c) (1/2E)( σ1 2 + σ2 2 –2μ σ1 σ2) (d) None
Last Answer : (c) (1/2E)( σ1 2 + σ2 2 –2μ σ1 σ2)
Description : Resilience under principal tensile stresses σ1 and σ2 is (a) (1/2E)( σ1 2 + σ2 2 –3μ σ1 σ2) (b) (1/2E)( σ1 2 + σ2 2 –4μ σ1 σ2) (c) (1/2E)( σ1 2 + σ2 2 –5μ σ1 σ2) (d) None
Description : The principal stress ha a a. Variable b. Constant c. Constant & variable d. None
Last Answer : b. Constant
Description : Is principal a? a. Simple stress b. Complex stress c. Bending stress d. None
Last Answer : a. Simple stress
Description : A principal stress is a. Tensile or shear stress b. Compressive or shear stress c. Tensile or compressive stress d. None
Last Answer : c. Tensile or compressive stress
Description : The principal strain due to σ1(tensile) and σ2 (Compressive ) stress is (a) Firstly (b)Secondly (c)Thirdly (d) None
Last Answer : (b)Secondly
Description : Principal stresses are found by a. Analytical method b. Graphical method c. Analytical & graphical methods d. None
Last Answer : c. Analytical & graphical methods
Description : Maximum shear stress in terms of principal stresses is a. Firstly (σ 1 +σ 2 )/2 b. Secondly (σ 1 /σ 2 ) c. Thirdly (σ 1 –σ 2 )/2 d. None
Last Answer : c. Thirdly (σ 1 –σ 2 )/2
Description : The magnitude of maximum principal stress is a. Firstly (σ x +σ y )/2+ (1/2)( σ x +σ y ) +4τ 2 ) 5 b. Secondly (σ x +σ y )/2+ (1/2)( σ x -σ y ) 2 +4τ 2 ) 5 c. Thirdly (σ x +σ y )/2+ (1/2)( σ x +σ y ) 2 +4τ 2 ) 5 d. None
Last Answer : b. Secondly (σ x +σ y )/2+ (1/2)( σ x -σ y ) 2 +4τ 2 ) 5
Description : In the analysis, all the principal stresses are assumed as a. Shear stresses b. Compressive stresses c. Tensile stresses d. None
Last Answer : c. Tensile stresses
Description : Which is the maximum principal stress? a. Firstly σ 2 b. Secondly σ 3 c. Thirdly σ 1 d. None
Last Answer : c. Thirdly σ 1
Description : The angle between a principal plane and a plane of maximum shear is a. 15 0 b. 45 0 c. 75 0 d. None
Last Answer : b. 45 0
Description : The angle between a principal plane and a plane of maximum shear is a. 30 0 b. 60 0 c. 90 0 d. None
Description : Principal stresses are a. Firstly Maximum and minimum shear stresses b. Secondly Maximum and minimum normal stresses c. Both (a) & (b) d. None
Last Answer : b. Secondly Maximum and minimum normal stresses