Finding allowable stress after the application of theories of failure ensures

(a) Soundness of design

(b) Lapses in design

(c) Both (a) & (b)

(d) None

1 Answer

Answer :

(a) Soundness of design

Related questions

Description : A ductile material may not meet a failure if it has been tested for the theories of failure (a) Firstly Maximum Shear Stress Theory (b) Secondly Maximum Shear Strain Energy Theory (c) Both (a) & (b) (d) None

Last Answer : (c) Both (a) & (b)

Description : Theories of elastic failure while dealing with brittle materials consider the failure criterion as (a) Ultimate stress (b) Yield stress (c) Both ultimate and yield stress (d) None

Last Answer : (a) Ultimate stress

Description : Theories of elastic failure while dealing with ductile materials consider the failure criterion as (a) Ultimate stress (b) Yield stress (c) Both ultimate and yield stress (d) None

Last Answer : (b) Yield stress

Description : Theories of elastic failure establishes the (a) Firstly Reasons of failure (b) Secondly Reasons of safety (c) Both (a) & (b) (d) None

Last Answer : (c) Both (a) & (b)

Description : Theories of elastic failure is the (a) Firstly analysis of the various failures (b) Secondly analysis of the strength of a material (c) Both (a) & (b) (d) None

Last Answer : (c) Both (a) & (b)

Description : Theories of elastic failure help in the (a) Material development (b) Development of method of manufacture (c) Both (a) & (b) (d) None

Last Answer : (c) Both (a) & (b)

Description : Under complex loading, theories of elastic failure establishes the (a) Margin of failure (b) Margin of safety (c) Both (a) & (b) (d) None

Last Answer : (b) Margin of safety

Description : Theories of elastic failure help to recognize (a) Weak materials (b) Strong materials (c) Both weak and strong materials (d) None

Last Answer : (c) Both weak and strong materials

Description : According to the ASME code, maximum allowable shear stress is taken as X% of yield strength or Y% of ultimate strength. a) X=30 Y=18 b) X=30 Y=30 c) X=18 Y=18 d) X=18 Y=30

Last Answer : a) X=30 Y=18

Description : According to the ASME code, maximum allowable shear stress is taken as X% of yield strength or Y% of ultimate strength. a) X=30 Y=18 b) X=30 Y=30 c) X=18 Y=18 d) X=18 Y=30

Last Answer : a) X=30 Y=18

Description : Under maximum shear stress theory, maximum shear stress is equal to (a) Allowable stress in tension (b) Allowable stress in compression (c) Allowable stress in shear (d) None

Last Answer : (c) Allowable stress in shear

Description : Under maximum principal stress theory, maximum principal stress is equal to (a) Allowable stress in tension (b) Allowable stress in compression (c) Allowable stress in shear (d) None

Last Answer : (a) Allowable stress in tension

Description : To predict failure in design components which failure criteria is not assumed, when mean stress and stress amplitude are nonzero? a. Goodman criterion b. Soderberg criteria c. Gerber criteria d. None of the above

Last Answer : d. None of the above

Description : A ductile material may not meet a failure if it has been tested for the theories of failure (a) Firstly Maximum Principal Theory (b) Secondly Maximum Principal Strain Theory (c) Thirdly Maximum principal strain energy theory (d) None

Last Answer : (d) None

Description : Why do we determine principal stresses? a. Failure is due to simple stress or strain b. Failure is due to complex stress or strain c. Both (a) & (b) d. None

Last Answer : a. Failure is due to simple stress or strain

Description : For a homogeneous & isotropic body under hydrostatic pressure, which theory of elastic failure does not fail (a) Firstly Maximum Principal Theory (b) Secondly Maximum Shear Stress Theory (c) Thirdly Maximum Principal Energy Theory (d) None

Last Answer : (a) Firstly Maximum Principal Theory

Description : Determine the length of kennedy key required to transmit 1200N-m and allowable shear in the key is 40N/mm2. The diameter of shaft and width of key can be taken as 40mm and 10mm respectively. a) 49mm b) 36mm c) 46mm d) 53mm

Last Answer : d) 53mm

Description : Determine the length of kennedy key required to transmit 1200N-m and allowable shear in the key is 40N/mm2. The diameter of shaft and width of key can be taken as 40mm and 10mm respectively. a) 49mm b) 36mm c) 46mm d) 53mm

Last Answer : d) 53mm

Description : What will happen if stresses induced due to surge in the spring exceeds the endurance limit stress of the spring. a) Fatigue Failure b) Fracture c) None of the listed d) Nipping

Last Answer : a) Fatigue Failure

Description : When a coupler nut is subjected to crushing stress, crushing failure can be avoided if _____ a. crushing stress induced is more than permissible crushing stress in the nut b. permissible crushing ... threads c. crushing stress induced is equal to permissible crushing stress d. all of the above

Last Answer : b. permissible crushing stress is more than crushing stress induced in the threads

Description : While designing screw threads, adequate length of engaged threads between the screw and nut is provided so as to prevent failure of threads due to (A) Direct shear stress (B) Torsional shear stress (C) Tensile stress (D) Compressive stress

Last Answer : (A) Direct shear stress

Description : The endurance or fatigue limit is defined as the maximum value of the stress which a polished standard specimen can withstand without failure, for infinite number of cycles, when subjected to (a) static load (b) dynamic load (c) static as well as dynamic load (d) completely reversed load

Last Answer : (d) completely reversed load

Description : Under complex loading, if elastic limit reaches in tension, then failure occurs due to (a) Firstly Maximum principal strain theory (b) Secondly Maximum principal theory of strain energy (c) Thirdly Maximum Principal stress theory (d) None

Last Answer : (c) Thirdly Maximum Principal stress theory

Description : Under complex loading, if elastic limit reaches in tension, then failure occurs due to (a) Firstly Maximum principal strain theory (b) Secondly Maximum principal theory of strain energy (c) Thirdly Maximum shear stress theory (d) None

Last Answer : (d) None

Description : Under complex loading, theories of elastic failures ensure (a) Stability (b) Instability (c) Both stability and instability (d) None

Last Answer : (a) Stability

Description : For an ordinary Portland cement (A) Residual does not exceed 10% when sieved through IS Sieve No. 9 (B) Soundness varies from 5 to 10 mm (C) Initial setting time is not less than 30 minutes (D) Compressive stress after 7 days, is not less than 175 kg/cm2

Last Answer : (C) Initial setting time is not less than 30 minutes

Description : Steel beam theory is used for (A) Design of simple steel beams (B) Steel beams encased in concrete (C) Doubly reinforced beams ignoring compressive stress in concrete (D) Beams if shear exceeds 4 times allowable shear stress

Last Answer : Answer: Option C

Description : Which of the following theories of failure is most appropriate for a brittle material? (a) Maximum principal strain theory (b) Maximum principal stress theory (c) Maximum shear stress theory (d) Maximum strain energy theory

Last Answer : (b) Maximum principal stress theory

Description : For a homogeneous & isotropic body under hydrostatic pressure, which theory of elastic failure fails (a) Firstly Maximum Principal Theory (b) Secondly Maximum Principal strain Theory (c) Thirdly Maximum Principal Energy Theory (d) None

Last Answer : (c) Thirdly Maximum Principal Energy Theory

Description : While calculating bending stress in the following welded joints which of the welds moment of inertia can be neglected? a) 1 b) None of the listed c) Both 1 & 3 d) Both 2 & 4

Last Answer : b) None of the listed

Description : The angle of obliquity is the angle between the a. Firstly Resultant and the shear stress b. Secondly Resultant & the normal stress c. Both (a) & (b) d. None

Last Answer : b. Secondly Resultant & the normal stress

Description : In a body under pure shear, the magnitude and nature of the two principal stresses are a. Firstly Equals shear stress, opposite nature b. Secondly Equals shear stress, same nature c. Both (a) & (b) d. None

Last Answer : a. Firstly Equals shear stress, opposite nature

Description : A principal stress is a a. Shear stress with zero normal stress b. Normal stress with zero shear stress c. Both (a) & (b) d. None

Last Answer : b. Normal stress with zero shear stress

Description : The principal stress ha a a. Variable b. Constant c. Constant & variable d. None

Last Answer : b. Constant

Description : AN ..................... JOURNALIST WORK IS TO DISCOVER THE TRUTH AND TO IDENTIFY LAPSES FROM it in whatever media may be available.a) Interpretative b) Investigative c) Both A and B d) War

Last Answer : b) Investigative

Description : The maximum pressure which the soil can carry safely without the risk of shear failure is called a) Safe bearing capacity b) Ultimate bearing capacity* c) Allowable bearing capacity d) Shear bearing capacity

Last Answer : b) Ultimate bearing capacity*

Description : For finding out the bending moment for the arm (spoke) of flywheel the arm is assumed as 1. a cantilever beam fixed at the rim and subjected to tangential force at the hub 2. a simply ... tangential force at the rim 4. a fixed beam fixed at hub and rim and carrying uniformly distributed load

Last Answer : 3. a cantilever hub fixed at the rim and subjected to tangential force at the rim

Description : For finding out the bending moment for the arm (spoke) of flywheel, the arm is assumed as, (A) A cantilever beam fixed at the rim and subjected to tangential force at the hub (B) A simply ... tangential force at the rim (D) A fixed beam fixed at hub and rim and carrying uniformly distributed load

Last Answer : (C) A cantilever beam fixed at the hub and subjected to tangential force at the rim

Description : Which of the following is (are) true? (A) Cast iron has poor tensile strength compared to steel (B) Failure of cast iron flywheel is sudden and total (C) Machinability of cast iron flywheel is poor compared to steel flywheel (D) All of the above

Last Answer : (D) All of the above

Description : Which of the following is not true for cast iron flywheels? a) Excellent damping b) Cheap c) Given complex shape d) Sudden failure

Last Answer : d) Sudden failure

Description : _____ is a surface fatigue failure which occurs when the load on the bearing part exceeds the surface endurance strength of the material. (a) Scoring (b) Pitting (c) Corrosion

Last Answer : (b) Pitting

Description : Propagation of fatigue failure is always due to compressive stresses. a) Due to bending b) Due to tensile c) Due to fatigue d) None of the listed

Last Answer : b) Due to tensile

Description : Standard coarse threads are equally strong in failure by shear and failure by tension, if the height of nut is (A) h = 0.4 d (B) h = 0.6 d (C) h = 0.5 d (D) h = d

Last Answer : (A) h = 0.4 d

Description : The connecting rod bolts are tightened up with the initial tension greater than external load so that (A) Failure of bolt will be static (B) The resultant load on bolt will not be affected by ... ) The bolt will not fail by fatigue although the external load is fluctuating (D) All the three

Last Answer : (D) All the three

Description : Failure of a material is called fatigue when it fails (a) at the elastic limit (b) below the elastic limit (c) at the yield point (d) below the yield point

Last Answer : (d) below the yield point

Description : There is sufficient plastic deformation prior to fatigue failure, which gives a warning well in advance. a) True b) False

Last Answer : b) False

Description : Fatigue failure is time dependent failure. a) True b) False

Last Answer : a) True

Description : The phenomenon of decreased resistance of the materials to fluctuating stresses is the main characteristic of _____ failure. a) Fracture b) Fatigue c) Yielding d) None of the mentioned

Last Answer : b) Fatigue

Description : When comes down to stress reduction, which one is preferred? a) Solid flywheel b) Split flywheel c) Both have equal stresses d) Cannot be determined

Last Answer : b) Split flywheel

Description : Parallel fillet weld and transverse fillet weld both have the plane in which maximum shear stress occurs at 45’ to the leg dimension. a) True b) False

Last Answer : b) False