Surface area of a typical person is about A. 1 m2 B. 2 m2 C. 3 m2 D. 4 m2

Surface area of a typical person is about

A. 1 m2

B. 2 m2

C. 3 m2

D. 4 m2
by

1 Answer

Answer :

2 m2


by

Related questions

SI unit for the surface tension is ____. (1) kg/m2 (2) kg/m3 (3) N/m (4) kg/m

Description : SI unit for the surface tension is ____. (1) kg/m2 (2) kg/m3 (3) N/m (4) kg/m

Last Answer : (3) N/m Explanation: Surface tension is measured in force per unit length. Its SI unit is Newton per meter.

The inner diameter of a circular well is 3.5m. It is 10m deep. Find (i) its inner curved surface area, (ii) the cost of plastering this curved surface at the rate of Rs. 40 per m2. -Maths 9th

Description : The inner diameter of a circular well is 3.5m. It is 10m deep. Find (i) its inner curved surface area, (ii) the cost of plastering this curved surface at the rate of Rs. 40 per m2. -Maths 9th

Last Answer : Inner radius of circular well, r = 3.5/2m = 1.75m Depth of circular well, say h = 10m (i) Inner curved surface area = 2πrh = (2 (22/7 ) 1.75 10) = 110 Therefore, the inner curved surface ... area = Rs (110 40) = Rs.4400 Therefore, the cost of plastering the curved surface of the well is Rs. 4400.

The lateral surface area of a cube is 256 m2. The volume of the cube is -Maths 9th

Description : The lateral surface area of a cube is 256 m2. The volume of the cube is -Maths 9th

Last Answer : NEED ANSWER

The lateral surface area of a cube is 256 m2. The volume of the cube is -Maths 9th

Description : The lateral surface area of a cube is 256 m2. The volume of the cube is -Maths 9th

Last Answer : (a) Given, lateral surface area of a cube = 256 m2 We know that, lateral surface area of a cube = 4 x (Side)2 ⇒ 256 = 4 x (Side)2 ⇒ (Side)2 = 256/4 = 64 ⇒ Side = √64 = 8 m [taking positive square root ... of a cube = (Side)3 = (8)3 = 8 x 8 x 8 = 512 m3 Hence, the volume of the cube is 512 m3.

A boat (with a flat bottom) and its cargo weigh 4,600 N. The area of the boat's bottom is 8 m2. How far below the surface of the water is the boat's bottom when it is floating in water?

Description : A boat (with a flat bottom) and its cargo weigh 4,600 N. The area of the boat's bottom is 8 m2. How far below the surface of the water is the boat's bottom when it is floating in water?

Last Answer : lower

Mean drift velocity of electron in a copper wire having cross-sectional area 5.0 × 10-6 m2 carrying current of 1 A and having number density 8.5 × 1028 m3 is A. 0.015 mm s-1 B. 0.1 mm s-1 C. 0.5 mm s-1 D. 0.25 mm s-1

Description : Mean drift velocity of electron in a copper wire having cross-sectional area 5.0 × 10-6 m2 carrying current of 1 A and having number density 8.5 × 1028 m3 is A. 0.015 mm s-1 B. 0.1 mm s-1 C. 0.5 mm s-1 D. 0.25 mm s-1

Last Answer : 0.015 mm s-1

A cylindrical pillar is 50 cm in diameter and 3.5 m in height. Find the cost of painting the curved surface of the pillar at the rate of ₹12.50 per m2 . -Maths 9th

Description : A cylindrical pillar is 50 cm in diameter and 3.5 m in height. Find the cost of painting the curved surface of the pillar at the rate of ₹12.50 per m2 . -Maths 9th

Last Answer : Diameter of the pillar = 50 cm ∴ Radius (r) = 502m = 25 m = 14m and height (h) = 3.5m Curved surface area of a pillar = 2πrh ∴ Curved surface area to be painted = 112m2 ∴ Cost of painting of 1 m2 pillar = Rs. 12.50 ∴ Cost of painting of 112 m2 pillar = Rs. ( 112 x 12.50 ) = Rs. 68.75.

The slant height and base diameter of conical tomb are 25m and 14 m respectively. Find the cost of white-washing its curved surface at the rate of Rs. 210 per 100 m2 -Maths 9th

Description : The slant height and base diameter of conical tomb are 25m and 14 m respectively. Find the cost of white-washing its curved surface at the rate of Rs. 210 per 100 m2 -Maths 9th

Last Answer : Slant height of conical tomb, l = 25m Base radius, r = diameter/2 = 14/2 m = 7m CSA of conical tomb = πrl = (22/7)×7×25 = 550 CSA of conical tomb= 550m2 Cost of white-washing 550 m2 area, which is Rs (210×550)/100 = Rs. 1155 Therefore, cost will be Rs. 1155 while white-washing tomb.

Pick out the wrong statement. (A) Superheated steam is preferably not used for process heating because of its low heat transfer film co-efficient (B) In a shell and tube heat exchanger, the shell pressure drop is maximum for orifice baffles (C) S.I. unit of fouling factor is Watt/m2 .°K (D) Longitudinal fins are used in extended surface heat exchangers, when the direction of fluid flow is parallel to the axis of the tube

Description : Pick out the wrong statement. (A) Superheated steam is preferably not used for process heating because of its low heat transfer film co-efficient (B) In a shell and tube heat exchanger ... surface heat exchangers, when the direction of fluid flow is parallel to the axis of the tube

Last Answer : (C) S.I. unit of fouling factor is Watt/m2 .°K

The thermal radiative flux from a surface of emissivity = 0.4 is 22.68 kW/m2 . The approximate surface temperature (K) is (Stefan-Boltzmann constant = 5.67 × 10 -8 W/m2 .K4 )(A) 1000(B) 727(C) 800(D) 1200

Description : The thermal radiative flux from a surface of emissivity = 0.4 is 22.68 kW/m2 . The approximate surface temperature (K) is (Stefan-Boltzmann constant = 5.67 × 10 -8 W/m2 .K4 ) (A) 1000 (B) 727 (C) 800 (D) 1200

Last Answer : (A) 1000

5. Unit of surface tension in S.I. unit is (A) Watt/m (B) Joule/m2 (C) Newton/m2 (D) Joule/m

Description : 5. Unit of surface tension in S.I. unit is (A) Watt/m (B) Joule/m2 (C) Newton/m2 (D) Joule/m

Last Answer : Option B

The unit of surface tension is (A) N/m (B) N/m2 (C) N/m3 (D) N-m

Description : The unit of surface tension is (A) N/m (B) N/m2 (C) N/m3 (D) N-m

Last Answer : Answer: Option A

The pressure intensity in kN/m2 (or kPa) at any point in a liquid is (where w = Specific weight of liquid, and h = Depth of liquid from the surface) (A) w (B) wh (C) w/h (D) h/w

Description : The pressure intensity in kN/m2 (or kPa) at any point in a liquid is (where w = Specific weight of liquid, and h = Depth of liquid from the surface) (A) w (B) wh (C) w/h (D) h/w

Last Answer : Answer: Option B

Two point masses, M1 and M2, are 14 centimeters apart. M1 has a mass of 2 grams. M2 has a mass of 5 grams. Locate the center-of-mass of this system. w) 4 cm from M1 x) 4 cm from M2 y) 5 cm from M2 z) 7 cm from M1

Description : Two point masses, M1 and M2, are 14 centimeters apart. M1 has a mass of 2 grams. M2 has a mass of 5 grams. Locate the center-of-mass of this system. w) 4 cm from M1 x) 4 cm from M2 y) 5 cm from M2 z) 7 cm from M1

Last Answer : ANSWER: X -- 4 CM FROM M2

What is the unit of relative density? (1) kg/m (2) kg/m2 (3) kg/m3 (4) It has no unit

Description : What is the unit of relative density? (1) kg/m (2) kg/m2 (3) kg/m3 (4) It has no unit

Last Answer : It has no unit

S.I. unit of Magnetic flux is (1) weber (2) weber/m (3) weber/m4 (4) weber–m2

Description : S.I. unit of Magnetic flux is (1) weber (2) weber/m (3) weber/m4 (4) weber–m2 

Last Answer : weber

The diameter of a roller is 84 cm and its length is 120 cm. It takes 500 complete revolutions to move once over to level a playground. Find the area of the playground in m2. -Maths 9th

Description : The diameter of a roller is 84 cm and its length is 120 cm. It takes 500 complete revolutions to move once over to level a playground. Find the area of the playground in m2. -Maths 9th

Last Answer : The roller is in the form of a cylinder of diameter = 84 cm ⇒ Radius of the roller(r) = 842 cm = 42 cm Length of the roller (h) = 120 cm Curved surface area of the ... roller = 31680 cm2 = 3168010000m2 ∴ Area of the playground levelled in 500 revolutions = 500 x 3168010000m2 = 1584m2

The diameter of a roller is 84 cm and its length is 120 cm. It takes 500 complete revolutions to move once over to level a playground. Find the area of the playground in m2? -Maths 9th

Description : The diameter of a roller is 84 cm and its length is 120 cm. It takes 500 complete revolutions to move once over to level a playground. Find the area of the playground in m2? -Maths 9th

Last Answer : A roller is shaped like a cylinder. Let h be the height of the roller and r be the radius. h = Length of roller = 120 cm Radius of the circular end of roller = r = (84/2) cm = 42 cm Now, CSA of roller = 2πrh = ... , we have 2 (22/7) 0.7 h = 4.4 Or h = 1 Therefore, the height of the cylinder is 1 m.

The paint in a certain container is sufficient to paint an area equal to 9.375 m2. How many bricks of dimensions 22.5 cm×10 cm×7.5 cm can be painted out of this container? -Maths 9th

Description : The paint in a certain container is sufficient to paint an area equal to 9.375 m2. How many bricks of dimensions 22.5 cm×10 cm×7.5 cm can be painted out of this container? -Maths 9th

Last Answer : Total surface area of one brick = 2(lb +bh+lb) = [2(22.5 10+10 7.5+22.5 7.5)] cm2 = 2(225+75+168.75) cm2 = (2 468.75) cm2 = 937.5 cm2 Let n bricks can be painted out by the ... 93750 cm2 So, we have, 93750 = 937.5n n = 100 Therefore, 100 bricks can be painted out by the paint of the container.

A cylindrical roller 2.5 m in length, 1.75 m in radius when rolled on a road was found to cover the area of 5500 m2. -Maths 9th

Description : A cylindrical roller 2.5 m in length, 1.75 m in radius when rolled on a road was found to cover the area of 5500 m2. -Maths 9th

Last Answer : NEED ANSWER

A cylindrical roller 2.5 m in length, 1.75 m in radius when rolled on a road was found to cover the area of 5500 m2. -Maths 9th

Description : A cylindrical roller 2.5 m in length, 1.75 m in radius when rolled on a road was found to cover the area of 5500 m2. -Maths 9th

Last Answer : Solution of the question

What is the capture area of a dipole operated at 75 MHz? A. 4 mm B. 2 m2 C. 2.088 m2 D. 4.088 m2

Description : What is the capture area of a dipole operated at 75 MHz? A. 4 mm B. 2 m2 C. 2.088 m2 D. 4.088 m2

Last Answer : C. 2.088 m2

The capacity of a classifier in 'tons of solid/hr' is given by (where, A = cross-sectional area in m2 , V = rising velocity of fluid in m/sec, S = percentage of solids in the suspension by volume, ρ = density of solids in kg/m3 ) (A) 3.6 AVS.ρ (B) 3.6 A.V.ρ (C) 3.6 A.S. ρ (D) 3.6 AVS/ρ

Description : The capacity of a classifier in 'tons of solid/hr' is given by (where, A = cross-sectional area in m2 , V = rising velocity of fluid in m/sec, S = percentage of solids in the suspension by volume, ρ = density of solids in kg/m3 ) (A) 3.6 AVS.ρ (B) 3.6 A.V.ρ (C) 3.6 A.S. ρ (D) 3.6 AVS/ρ

Last Answer : (A) 3.6 AVS.ρ

The interfacial area per unit volume of dispersion, in a gas-liquid contactor, for fractional hold up of gas = 0.1 and gas bubble diameter = 0.5 mm is given by (in m2 /m3 ) (A) 500 (B) 1200 (C) 900 (D) 800

Description : The interfacial area per unit volume of dispersion, in a gas-liquid contactor, for fractional hold up of gas = 0.1 and gas bubble diameter = 0.5 mm is given by (in m2 /m3 ) (A) 500 (B) 1200 (C) 900 (D) 800

Last Answer : (A) 500

Unit of furnace loading is (A) Ton stock/hr/m2 hearth area (B) Ton stock/hr (C) Ton stock/m2 hearth area (D) Both (B) and (C)

Description : Unit of furnace loading is (A) Ton stock/hr/m2 hearth area (B) Ton stock/hr (C) Ton stock/m2 hearth area (D) Both (B) and (C)

Last Answer : (A) Ton stock/hr/m2 hearth area

A horse is tied to a peg hammered at one of the corner of a rectangular grass field of 40 m by 24 m by a rope 14 m long. Over how much area of the field can the horse graze? (1) 154 m2 (2) 308 m2 (3) 240 m2 (4) 480 m2

Description : A horse is tied to a peg hammered at one of the corner of a rectangular grass field of 40 m by 24 m by a rope 14 m long. Over how much area of the field can the horse graze? (1) 154 m2 (2) 308 m2 (3) 240 m2 (4) 480 m2

Last Answer : (1) 154 m2

A typical microwave oven produces microwave radiation with a wavelength of: w) 3 meters x) 3 x 10-2 meters (read: 3 times 10 to the minus 2 meters) y) 3 x 10 -6 meters (read: 3 times 10 to the minus 6 meters) z) 3 x 10-9 meters (read: 3 times 10 to the minus 9 meters)

Description : A typical microwave oven produces microwave radiation with a wavelength of: w) 3 meters x) 3 x 10-2 meters (read: 3 times 10 to the minus 2 meters) y) 3 x 10 -6 meters (read: 3 times 10 to the minus 6 meters) z) 3 x 10-9 meters (read: 3 times 10 to the minus 9 meters) 

Last Answer : ANSWER: X -- 3 x 10-2 METERS

What is a typical wavelength of an AM radio wave? w) 3000 meters x) 300 meters y) 30 meters z) 3 meters

Description : What is a typical wavelength of an AM radio wave? w) 3000 meters x) 300 meters y) 30 meters z) 3 meters

Last Answer : ANSWER: X -- 300 METERS

The units of moment of inertia are a.kgm4 b.kg-m2 c.kg/m2 d.kg/m e.m4

Description : The units of moment of inertia are a.kgm4 b.kg-m2 c.kg/m2 d.kg/m e.m4

Last Answer : c. kg/m2

A 100 kg flywheel having a radius of gyration of 1 m is rotating at 1000 rpm. The angular momentum of the flywheel about its axis of rotation, in kg m2/s is a.1000 b.107 dynes c.10000 d.10470 e.5235

Description : A 100 kg flywheel having a radius of gyration of 1 m is rotating at 1000 rpm. The angular momentum of the flywheel about its axis of rotation, in kg m2/s is a.1000 b.107 dynes c.10000 d.10470 e.5235

Last Answer : d. 10470

The floor of a rectangular hall has a perimeter 250 m. If the cost of painting the four walls at the rate of Rs.10 per m2 is Rs.15000, find the height of the hall. -Maths 9th

Description : The floor of a rectangular hall has a perimeter 250 m. If the cost of painting the four walls at the rate of Rs.10 per m2 is Rs.15000, find the height of the hall. -Maths 9th

Last Answer : Let length, breadth, and height of the rectangular hall be l, b, and h respectively. Area of four walls = 2lh+2bh = 2(l+b)h Perimeter of the floor of hall = 2(l+b) = 250 m Area of four walls = 2( ... of paining the walls is Rs. 15000. 15000 = 2500h Or h = 6 Therefore, the height of the hall is 6 m.

The length, breadth and height of a room are 5 m, 4 m and 3 m respectively. Find the cost of white washing the walls of the room and ceiling at the rate of Rs 7.50 per m2. -Maths 9th

Description : The length, breadth and height of a room are 5 m, 4 m and 3 m respectively. Find the cost of white washing the walls of the room and ceiling at the rate of Rs 7.50 per m2. -Maths 9th

Last Answer : Length (l) of room = 5m Breadth (b) of room = 4m Height (h) of room = 3m It can be observed that four walls and the ceiling of the room are to be white washed. Total area to be white washed = Area of walls + ... m2 area = Rs.7.50 (Given) Cost of white washing 74 m2 area = Rs. (74 7.50) = Rs. 555

Find the cost of laying grass in a triangular field of sides 50 m, 65 m and 65 m at the rate of Rs. 7 per m2. -Maths 9th

Description : Find the cost of laying grass in a triangular field of sides 50 m, 65 m and 65 m at the rate of Rs. 7 per m2. -Maths 9th

Last Answer : Sides of the triangle are a=50m,b=65m,c=65m Area of triangle, by Heron's formula =s(s−a)(s−b)(s−c)​where, s=2a+b+c​s=250+65+65​s=90 Area of triangle = 90(40)(25)(25)​Area of triangle = 1500m2 Cost of laying grass = Area ×7 Cost of laying grass =1500×7 Cost of laying grass = Rs 10500

Find the cost of laying grass in a triangular field of sides 50 m, 65 m and 65 m at the rate of Rs. 7 per m2. -Maths 9th

Description : Find the cost of laying grass in a triangular field of sides 50 m, 65 m and 65 m at the rate of Rs. 7 per m2. -Maths 9th

Last Answer : Sides of the triangle are a=50m,b=65m,c=65m Area of triangle, by Heron's formula =s(s−a)(s−b)(s−c)​where, s=2a+b+c​s=250+65+65​s=90 Area of triangle = 90(40)(25)(25)​Area of triangle = 1500m2 Cost of laying grass = Area ×7 Cost of laying grass =1500×7 Cost of laying grass = Rs 10500

If cosec |-sin |=l and sec |- cos |=m, prove that l2m2(l2+m2+3)=1 -Maths 9th

Description : If cosec |-sin |=l and sec |- cos |=m, prove that l2m2(l2+m2+3)=1 -Maths 9th

Last Answer : cosec(A) - sin(A) = l ⇒ 1/sin(A) - sin(A) = l ⇒ l² = 1/sin²(A) + sin²(A) - 2 --------- sec(A) - cos(A) = m ⇒ 1/cos(A) - cos(A) = m ⇒ m² = 1/cos²(A) + cos²(A) - 2 ---------- l²m² = [1/sin²(A) + ... A)) = = 1/(sin²(A)cos²(A)) ------------- ⇒ l²m² (l² + m² + 3) = sin²(A)cos²(A) / [sin²(A)cos²(A)] = 1

1 hectare how many m2?

Description : 1 hectare how many m2? We have now inherited a 14 hectare arable land and I would like to know how many m2 it can be.

Last Answer : The area is pretty serious, even if it's arable land. 1 hectare is 10,000 m2, that is, your area is 140,000 m2, which is nothing. 

Why is F=G M1 M2 /d^2?

Description : Why is F=G M1 M2 /d^2?

Last Answer : F is force and it is equal to the gravitational constant times the mass of the first object times the mass of the second object divided by the distance between the two squared.

Which of the following statement(s) is/are true concerning oxygen consumption (O2)? a. O2 is normally 100–120 cc2/m2/min b. Resting O2 is controlled by the level of thyroid and catecholamine hormones c. Under steady state conditions the amount of oxygen consumed exceeds the amount of oxygen taken up by the pulmonary capillaries d. O2 is dependent on the status of pulmonary function

Description : Which of the following statement(s) is/are true concerning oxygen consumption (O2)? a. O2 is normally 100-120 cc2/m2/min b. Resting O2 is controlled by the level of thyroid and catecholamine ... of oxygen taken up by the pulmonary capillaries d. O2 is dependent on the status of pulmonary function

Last Answer : Answer: a, b Oxygen consumed in the process of metabolism is expressed as the volume of oxygen per minute (O2). O2 is normally 100-120 cc2/m2/min, or 200 cc/min for a typical adult. ... , so we measure O2 across the lung and assume that it is exactly the amount consumed in the systemic metabolism

The cardiac muscarinic receptors (a) Are of the M1 subtype (b) Are of the M2 subtype (c) Are selectively blocked by pirenzepine (d) Function through the PIP2 ? IP3/DAG pathway

Description : The cardiac muscarinic receptors (a) Are of the M1 subtype (b) Are of the M2 subtype (c) Are selectively blocked by pirenzepine (d) Function through the PIP2 ? IP3/DAG pathway

Last Answer : Ans: B

Oxytremorine is a selective agonist of muscarinic _______ receptors (a) M1 (b) M2 (c) M3 (d) M4

Description : Oxytremorine is a selective agonist of muscarinic _______ receptors (a) M1 (b) M2 (c) M3 (d) M4

Last Answer : Ans: A

A 19 year-old female is referred following a visit to the dentist where marked erosion of her teeth was noted. She was entirely asymptomatic and her only medication was the oral contraceptive pill. On examination her blood pressure was 110/70 mmHg and her body mass index was 21.5 kg/m2 (18 - 25). Investigations sodium 135 mmol/l potassium 2.1 mmol/l bicarbonate 42 mmol/l urea 2.6 mol/L corrected calcium 2.08 mmol/ alkaline phosphatase 201 iu/l (50-110) What is the most likely diagnosis? 1) Bulimia nervosa 2) Conn's syndrome 3) Laxative abuse 4) Pregnancy 5) Primary hypoparathyroidism

Description : A 19 year-old female is referred following a visit to the dentist where marked erosion of her teeth was noted. She was entirely asymptomatic and her only medication was the oral contraceptive pill ... ) Bulimia nervosa 2) Conn's syndrome 3) Laxative abuse 4) Pregnancy 5) Primary hypoparathyroidism

Last Answer : Answers-5 This patient has tooth erosion associated with hypokalaemic metabolic alkalosis and hypocalcaemia. This suggests a diagnosis of hypoparathyroidism. Conn's is unlikely in this age group, is ... raised alkaline phosphatase would not be expected. Early pregnancy would not fit this picture.

Body Mass Index= A. Height in centimeters Weight (kg) B. Weight (kg) Height (M2) C. Height (M2) Weight (kg) D. Weight (kg) Height in centimeters

Description : Body Mass Index= A. Height in centimeters Weight (kg) B. Weight (kg) Height (M2) C. Height (M2) Weight (kg) D. Weight (kg) Height in centimeters

Last Answer : Ans: B

Lahore-Islamabad Motorway M2 was completed in 1997 and _____ Km long. A. 252 Km B. 410 Km C. 390 Km D. 375 Km

Description : Lahore-Islamabad Motorway M2 was completed in 1997 and _____ Km long. A. 252 Km B. 410 Km C. 390 Km D. 375 Km

Last Answer : ANSWER: D

Potential of air pollution increases when the ventilation coefficient is – (1) > 119000 m2/s (2) > 7,600 m2/s (3) < 3.600 m2/s (4) < 6,000 m2/s

Description : Potential of air pollution increases when the ventilation coefficient is – (1) > 119000 m2/s (2) > 7,600 m2/s (3) < 3.600 m2/s (4) < 6,000 m2/s

Last Answer : (4) < 6,000 m2/s Explanation: The product of the maximum mixing depth and the average wind speed within the mixing depth is sometimes used as an indicator of the atmosphere's dispersive ... than about 6000 m2is are considered indicative of high air pollution potential (Portelli and Lewis, 1987).

Which of the following is the most liquid money? A. M1 B. M2 C. Securities D. M3 E. Call Money

Description : Which of the following is the most liquid money? A. M1 B. M2 C. Securities D. M3 E. Call Money

Last Answer : A. M1 Explanation: The most liquid portions of the money supply are measured by M1 because it contains currency and assets that can be converted to cash quickly. ―Near money‖ and ―near, near money,‖ which fall under M2 and M3, cannot be converted to currency as quickly.