1 N (newton) is equal to A. 102 dynes B. 103 dynes C. 104 dynes D. 105 dynes

 1 N (newton) is equal to

A. 102 dynes

B. 103 dynes

C. 104 dynes

D. 105 dynes
by

1 Answer

Answer :

105 dynes
by

Related questions

One newton is equal to a.106 dynes b.105 dynes c.104 dynes d.103 dynes e.107 dynes

Description : One newton is equal to a.106 dynes b.105 dynes c.104 dynes d.103 dynes e.107 dynes

Last Answer : b. 105 dynes

Actual op-amp may have an open loop gain of A. 102 B. 105 C. 103 D. 104

Description : Actual op-amp may have an open loop gain of A. 102 B. 105 C. 103 D. 104

Last Answer : 105

Which of the following implies the greatest precision? w) 1.02 x 105 x) 102 x 103 y) 0.102 x 106 z) 1.020 x 105

Description : Which of the following implies the greatest precision? w) 1.02 x 105 x) 102 x 103 y) 0.102 x 106 z) 1.020 x 105

Last Answer : ANSWER: Z -- 1.020 x 105

Find the magnetic field intensity of a toroid of turns 40 and radius 20cm. The current carried by the toroid be 3.25A. a) 103.45 b) 102 c) 105.7 d) 171

Description : Find the magnetic field intensity of a toroid of turns 40 and radius 20cm. The current carried by the toroid be 3.25A. a) 103.45 b) 102 c) 105.7 d) 171

Last Answer : a) 103.45

Rs.4900 was divided among a group of 150 children. If each girl gets Rs.50 and each boy gets Rs.25 then, the number of boys in the group is: (a) 100 (b) 102 (c) 104 (d) 105

Description : Rs.4900 was divided among a group of 150 children. If each girl gets Rs.50 and each boy gets Rs.25 then, the number of boys in the group is: (a) 100 (b) 102 (c) 104 (d) 105

Last Answer : (c) 104

The power of a locomotive is 315 kW and the total weight of the train is 2000 kN. If the track resistance is 15 N per kN, the maximum speed that the locomotive can attain on level track will be a.43 kmph b.83 kmph c.103 kmph d.107 dynes e.38 kmph

Description : The power of a locomotive is 315 kW and the total weight of the train is 2000 kN. If the track resistance is 15 N per kN, the maximum speed that the locomotive can attain on level track will be a.43 kmph b.83 kmph c.103 kmph d.107 dynes e.38 kmph

Last Answer : e. 38 kmph

One Joule is equal to-----? A. 105 ergs B. 103 ergs C. 107 ergs (Answer) D. 1011 ergs

Description : One Joule is equal to-----? A. 105 ergs B. 103 ergs C. 107 ergs (Answer) D. 1011 ergs

Last Answer : C. 107 ergs (Answer)

Actual velocity of electrons between collisions is A. 1030 m s-1 B. 1020 m s-1 C. 102 m s-1D. 105 m s-1

Description : Actual velocity of electrons between collisions is A. 1030 m s-1 B. 1020 m s-1 C. 102 m s-1 D. 105 m s-1

Last Answer : 1020 m s-1

One joule is equal to a.105 ergs b.108 ergs c.104 ergs d.107 ergs e.106 ergs

Description : One joule is equal to a.105 ergs b.108 ergs c.104 ergs d.107 ergs e.106 ergs

Last Answer : d. 107 ergs

were can i find episode 103 and 104 of kodocha?

Description : were can i find episode 103 and 104 of kodocha?

Last Answer : cardinality of ℝ

If intensity of rainfall in cm per hour is I, percentage coefficient of run-off is P, area of catchment in square kilometres is A, the total run-off Q, is given by (A) Q = 1.758 × 102 × API(B) Q = 2.758 × 102 × API(C) Q = 2.758 × 103 × API(D) Q = 2.758 × 103 × A/PI

Description : If intensity of rainfall in cm per hour is I, percentage coefficient of run-off is P, area of catchment in  square kilometres is A, the total run-off Q, is given by  (A) Q = 1.758 102   API (B) Q = 2.758 ... API (C) Q = 2.758 103   API (D) Q = 2.758 103   A/PI

Last Answer : (C) Q = 2.758 × 103  × API

Under which Act GST was introduced? (A) 100 (B) 101 (C) 102 (D) 103

Description : Under which Act GST was introduced? (A) 100 (B) 101 (C) 102 (D) 103

Last Answer : (B) 101

GST was introduced as the ................... amendment Act. A 100 (B) 101 (C) 102 (D) 103

Description : GST was introduced as the ................... amendment Act. A 100 (B) 101 (C) 102 (D) 103

Last Answer : (B) 101

If arithmetic of 6 numbers is 17 then the sum of numbers is---- (a) 102 (b) 103 © 150 (d) 120.

Description : If arithmetic of 6 numbers is 17 then the sum of numbers is---- (a) 102 (b) 103 © 150 (d) 120.

Last Answer : (a) 102

The open loop gain of the amplifier is ______ (a) 105 (b) 103 (c) 106 (d) 108

Description : The open loop gain of the amplifier is ______ (a) 105 (b) 103 (c) 106 (d) 108

Last Answer : (a) 105

Using the RSA public key crypto system, if p=13, q=31 and d=7, then the value of e is (A) 101 (B) 105 (C) 103 (D) 107

Description : Using the RSA public key crypto system, if p=13, q=31 and d=7, then the value of e is (A) 101 (B) 105 (C) 103 (D) 107

Last Answer : (C) 103 Explanation: Basic RSA Algorithm: 1. Choose two primes, p & q. 2. Compute n=p*q and z=(p-1)*(q-1). 3. Choose a number relatively prime to z and call it d. 4. Find e such that e*d= ... each of these in turn by 7 to see which is divisible by 7, we find that 721/7 = 103, hence e = 103. 

The power of a locomotive is 315 kW and the total weight of the train is 2000 kN. If the track resistance is qN per kN, the maximum speed that the locomotive can attain on level track will be a.103 kmph b.83 kmph c.107 dynes d.43 kmph e.63 kmph

Description : The power of a locomotive is 315 kW and the total weight of the train is 2000 kN. If the track resistance is qN per kN, the maximum speed that the locomotive can attain on level track will be a.103 kmph b.83 kmph c.107 dynes d.43 kmph e.63 kmph

Last Answer : e. 63 kmph

Molecular weight of heterogenous nuclear RNA (hnRNA) is (A) More than 107 (B) 105 to 106 (C) 104 to 105 (D) Less than 104

Description : Molecular weight of heterogenous nuclear RNA (hnRNA) is (A) More than 107 (B) 105 to 106 (C) 104 to 105 (D) Less than 104

Last Answer : Answer : A

Find the potential between two points p(1,-1,0) and q(2,1,3) with E = 40xy i + 20x 2 j + 2 k a) 104 b) 105 c) 106 d) 107

Description : Find the potential between two points p(1,-1,0) and q(2,1,3) with E = 40xy i + 20x 2 j + 2 k a) 104 b) 105 c) 106 d) 107

Last Answer : c) 106

Staff readings on pegs x and y from X station are 1.755 m and 2.850 m, and from station Y on staff head at Y and X are 0.655 m and 1.560 m. If reduced level of X is 105.5 m, the reduced level of Y is (A) 104.0 m (B) 104.5 m (C) 105.0 m (D) 105.5 m

Description : Staff readings on pegs x and y from X station are 1.755 m and 2.850 m, and from station Y on staff head at Y and X are 0.655 m and 1.560 m. If reduced level of X is 105.5 m, the reduced level of Y is (A) 104.0 m (B) 104.5 m (C) 105.0 m (D) 105.5 m

Last Answer : (B) 104.5 m

In final exam of class IX there are 130 students 20 % students failed. How many students passed to class X? a) 105 b) 112 c) 104 d) 117 e) 104.5

Description : In final exam of class IX there are 130 students 20 % students failed. How many students passed to class X? a) 105 b) 112 c) 104 d) 117 e) 104.5

Last Answer : Answer: C) Percentage of students passed to class X = (100 % - 20 %) of 130  = 80 % of 130 =>80 % of 130 => 80/100 × 130 =>10400/100 => 104 Therefore, 104 students passed to class X

The population of India as per 2001 census a.105.84crore b.115.52crore c. 102.70 crore. d.107.30crore

Description : The population of India as per 2001 census a.105.84crore b.115.52crore c. 102.70 crore. d.107.30crore

Last Answer : c. 102.70 crore.

If span is 150 mts and sag is 10 ft of a cable carrying a load of 3200 kg per horizontal metre then tension of ends is a.104,000 kg b.107 dynes c.1200,000 kg d.932,000 kg e.584,000 kg

Description : If span is 150 mts and sag is 10 ft of a cable carrying a load of 3200 kg per horizontal metre then tension of ends is a.104,000 kg b.107 dynes c.1200,000 kg d.932,000 kg e.584,000 kg

Last Answer : d. 932,000 kg

What is the total acceleration of a point on the rim of a flywheel 4 mts in diameter 0.6 see after it has started from rest if it accelarates uniformly from rest to 2000 rpm in 20 secs. a.68.9 mts/sec2 b.102.6 mts/sec2 c.78.94 mts/sec2 d.107 dynes e.33.2 mts/sec2

Description : What is the total acceleration of a point on the rim of a flywheel 4 mts in diameter 0.6 see after it has started from rest if it accelarates uniformly from rest to 2000 rpm in 20 secs. a.68.9 mts/sec2 b.102.6 mts/sec2 c.78.94 mts/sec2 d.107 dynes e.33.2 mts/sec2

Last Answer : c. 78.94 mts/sec2

The torque of 50 Nm is applied on the wheel operating a valve. If the wheel is rotated through two revolutions, work done in Newton-metres is given by a.628 b.107 dynes c.314 d.25 e.100

Description : The torque of 50 Nm is applied on the wheel operating a valve. If the wheel is rotated through two revolutions, work done in Newton-metres is given by a.628 b.107 dynes c.314 d.25 e.100

Last Answer : a. 628

Newton, dyne and poundal are known as a.absolute units b.fundamental units c.gravitational units d.absolute units e.107 dynes

Description : Newton, dyne and poundal are known as a.absolute units b.fundamental units c.gravitational units d.absolute units e.107 dynes

Last Answer : d. absolute units

The specific weight of water in S.I. units is taken as (A) 9.81 kN/m3 (B) 9.81 × 103 N/m3 (C) 9.81 × 10-6 N/mm3 (D) Any one of these

Description : The specific weight of water in S.I. units is taken as (A) 9.81 kN/m3 (B) 9.81 × 103 N/m3 (C) 9.81 × 10-6 N/mm3 (D) Any one of these

Last Answer : Answer: Option D

Molecular volume of any perfect gas at 600 x 103 N/m2 and 27°C will be  (a) 4.17m3/kgmol  (b) 400 m3/kg mol  (c) 0.15 m3/kg mol  (d) 41.7 m3/kg mol  (e) 417m3/kgmol.

Description : Molecular volume of any perfect gas at 600 x 103 N/m2 and 27°C will be  (a) 4.17m3/kgmol  (b) 400 m3/kg mol  (c) 0.15 m3/kg mol  (d) 41.7 m3/kg mol  (e) 417m3/kgmol.

Last Answer : Answer : a

The electric intensity at a distance of 1m from the point charge is 1μC is: (a) 9 × 109 N/C (b) 9 × 106 N/C (c) 9 × 103 N/C (d) 9 N/C

Description : The electric intensity at a distance of 1m from the point charge is 1μC is: (a) 9 × 109 N/C (b) 9 × 106 N/C (c) 9 × 103 N/C (d) 9 N/C

Last Answer : c) 9 × 103 N/C

What is the weight of a mass of 1kg equal to Newton ?

Description : What is the weight of a mass of 1kg equal to Newton ?

Last Answer : Sitting on the earth , the weight of an object of mass 1 kg = mg = 1 * 9.8 [g = 9.8ms ^ -2] = 9.8 N ( Newton) Therefore , the weight of an object of mass 1 kg on Earth is 9.8 Newtons.

A Newton is equal to which of the following? w) kilogram-meter per second x) meter per second squared y) kilogram-meter per second squared z) kilogram per meter-second

Description : A Newton is equal to which of the following? w) kilogram-meter per second x) meter per second squared y) kilogram-meter per second squared z) kilogram per meter-second

Last Answer : ANSWER: Y -- KILOGRAM-METER PER SECOND SQUARED

What state is at 41 8' N 104 48' W?

Description : What state is at 41 8' N 104 48' W?

Last Answer : It is Cheyenne, Wyoming, USA.

Pick out the wrong conversion of absolute & kinematic viscosities. (A) 1 stoke = 1 cm2/sec (B) 1 N.sec/m2 = 10 paise (C) 1 stoke = 1 m2/sec (D) 1 m2/sec = 104 stokes

Description : Pick out the wrong conversion of absolute & kinematic viscosities. (A) 1 stoke = 1 cm2/sec (B) 1 N.sec/m2 = 10 paise (C) 1 stoke = 1 m2/sec (D) 1 m2/sec = 104 stokes

Last Answer : (C) 1 stoke = 1 m2/sec

A beam of uniform rectangular section 200 mm wide and 300mm deep is simply supported at its ends.It carries a uniformly distributed load of 9KN/m run over the entire span of 5m.If E=1×104 N/mm2, what is the maximum deflection? a.14.26 mm b.17.28 mm c.18.53 mm d.16.27 mm.

Description : A beam of uniform rectangular section 200 mm wide and 300mm deep is simply supported at its ends.It carries a uniformly distributed load of 9KN/m run over the entire span of 5m.If E=1×104 N/mm2, what is the maximum deflection? a.14.26 mm b.17.28 mm c.18.53 mm d.16.27 mm.

Last Answer : d.16.27 mm.

A project has the following cash inflows Rs.34,444; Rs.39,877; Rs.25,000; and Rs.52,800 for years 1 through 4, respectively. The initial cash outflow is Rs.104,000. Which of the following four statements is correct concerning the project internal rate of return (IRR)? A. The IRR is less than 10%. B. The IRR is greater than or equal to 10%, but less than 14%. C. The IRR is greater than or equal to 14%, but less than 18%. D. The IRR is greater than or equal to 18%.

Description : A project has the following cash inflows Rs.34,444; Rs.39,877; Rs.25,000; and Rs.52,800 for years 1 through 4, respectively. The initial cash outflow is Rs.104,000. Which of the following four statements ... than or equal to 14%, but less than 18%. D. The IRR is greater than or equal to 18%.

Last Answer : C. The IRR is greater than or equal to 14%, but less than 18%.

If the area of storm hydrograph is equal to 102 cm, the ordinates of a unit hydrograph may be obtained by dividing the ordinates of the storm hydrograph by (A) 0.5 (B) 1 (C) 2 D) 4

Description : If the area of storm hydrograph is equal to 102 cm, the ordinates of a unit hydrograph may be obtained by dividing the ordinates of the storm hydrograph by (A) 0.5 (B) 1 (C) 2 D) 4

Last Answer : Answer: Option D

If Z = 78 and ACT = 72, then MAT will be equal to a)25 b) 102 c) 40 d) 170

Description : If Z = 78 and ACT = 72, then MAT will be equal to a)25 b) 102 c) 40 d) 170

Last Answer : Answer key : (b)

The phenomena of pair production occurs only when the energy of incident photon is least equal a) 10.2 MeV b) 1.02 MeV c) 1.02 eV d) 0.102 MeV

Description : The phenomena of pair production occurs only when the energy of incident photon is least equal a) 10.2 MeV b) 1.02 MeV c) 1.02 eV d) 0.102 MeV

Last Answer : b) 1.02 MeV

What city is 21 01 n 105 52 e?

Description : What city is 21 01 n 105 52 e?

Last Answer : 21.01 N 105.52 E is Khu Công Nghệ Cao Hòa Lạc, Thạch Thất, Hà Nội, Vietnam.The capital city is Hanoi.

If a solid shaft (diameter 20 cm, length 400 cm, N = 0.8 × 105 N/mm2 ) when subjected to a twisting moment, produces maximum shear stress of 50 N/mm2 , the angle of twist in radians, is (A) 0.001 (B) 0.002 (C) 0.0025 (D) 0.003

Description : If a solid shaft (diameter 20 cm, length 400 cm, N = 0.8 × 105  N/mm2 ) when subjected to a twisting  moment, produces maximum shear stress of 50 N/mm2 , the angle of twist in radians, is  (A) 0.001  (B) 0.002  (C) 0.0025  (D) 0.003 

Last Answer : (C) 0.0025 

Modulus elasticity of steel is generally taken as [ A ] 2 x 105 N/mm2 [ B ] 2 x 106 N/mm2 [ C ] 2 x 106 N/mm2 [ D ] 2 x 105 N/mm2

Description : Modulus elasticity of steel is generally taken as [ A ] 2 x 105 N/mm2 [ B ] 2 x 106 N/mm2 [ C ] 2 x 106 N/mm2 [ D ] 2 x 105 N/mm2

Last Answer : [ A ] 2 x 105 N/mm2

Modulus elasticity of steel is generally taken as [ A ] 2 x 105 N/mm2 [ B ] 2 x 106 N/mm2 [ C ] 2 x 106 N/mm2 [ D ] 2 x 105 N/mm2

Description : Modulus elasticity of steel is generally taken as [ A ] 2 x 105 N/mm2 [ B ] 2 x 106 N/mm2 [ C ] 2 x 106 N/mm2 [ D ] 2 x 105 N/mm2

Last Answer : [ A ] 2 x 105 N/mm2

A charge of 10μC and 14.4 μC are 12 cm apart, the force between them is: (a) 9 × 105 N (b) 9 × 107 N (c) 90 N (d) 108 × 107 N

Description : A charge of 10μC and 14.4 μC are 12 cm apart, the force between them is: (a) 9 × 105 N (b) 9 × 107 N (c) 90 N (d) 108 × 107 N

Last Answer : (c) 90 N

A cantilever of length 3m carries a uniformly distributed load of 15KN/m over a length of 2m from the free end.If I= 108 mm4 and E= 2×105 N/mm2,find the slope at the free end? a.0.00326 rad b.0.00578 rad c.0.00677 rad d.0.00786 rad

Description : A cantilever of length 3m carries a uniformly distributed load of 15KN/m over a length of 2m from the free end.If I= 108 mm4 and E= 2×105 N/mm2,find the slope at the free end? a.0.00326 rad b.0.00578 rad c.0.00677 rad d.0.00786 rad

Last Answer : a.0.00326 rad

A cantilever of length 3 m carries two point loads of 2 KN at the free end and 4KN at a distance of 1m from the free end .What is the deflection at the free end? Take E= 2×105 N/mm2and I= 108 mm4. a.2.56 mm b.3.84 mm c.1.84 mm d.5.26mm

Description : A cantilever of length 3 m carries two point loads of 2 KN at the free end and 4KN at a distance of 1m from the free end .What is the deflection at the free end? Take E= 2×105 N/mm2and I= 108 mm4. a.2.56 mm b.3.84 mm c.1.84 mm d.5.26mm

Last Answer : c.1.84 mm

A cantilever of length 2m carries a point load of 30KN at the free end.If I = 108 mm4 and E= 2×105 N/mm2. What is the slope of the cantilever at the free end? a.0.503 rad b.0.677 rad c. 0.003 rad d.0.008

Description : A cantilever of length 2m carries a point load of 30KN at the free end.If I = 108 mm4 and E= 2×105 N/mm2. What is the slope of the cantilever at the free end? a.0.503 rad b.0.677 rad c. 0.003 rad d.0.008

Last Answer : c. 0.003 rad

A stone weighing 20 N is whirling in a vertical circle at the extremity of a string 100 cm long. The tension in the string will be zero a.at the highest position b.at the lowest position c.at the midway position d.at none of the above e.107 dynes

Description : A stone weighing 20 N is whirling in a vertical circle at the extremity of a string 100 cm long. The tension in the string will be zero a.at the highest position b.at the lowest position c.at the midway position d.at none of the above e.107 dynes

Last Answer : a. at the highest position

A hammer gains 50 Ns momentum in 0.05 sec. The average force on the hammer will be a.500 N b.2000 N c.1500 N d.107 dynes e.1000 N

Description : A hammer gains 50 Ns momentum in 0.05 sec. The average force on the hammer will be a.500 N b.2000 N c.1500 N d.107 dynes e.1000 N

Last Answer : e. 1000 N

The breaking strength of a rope is 400 N. A fireman weighing 60 kg slides down the rope. The rope will break if a.107 dynes b.the acceleration is 7.5 m/s2 c.the acceleration is 1.2 m/s2 d.the acceleration is 3.1 m/s2 e.the slides with an acceleration of 15 m/s2

Description : The breaking strength of a rope is 400 N. A fireman weighing 60 kg slides down the rope. The rope will break if a.107 dynes b.the acceleration is 7.5 m/s2 c.the acceleration is 1.2 m/s2 d.the acceleration is 3.1 m/s2 e.the slides with an acceleration of 15 m/s2

Last Answer : c. the acceleration is 1.2 m/s2

The tension T1 will be a.5 N b.20 N c.60 N d.10 N e.107 dynes

Description : The tension T1 will be a.5 N b.20 N c.60 N d.10 N e.107 dynes

Last Answer : d. 10 N