Description : A cantilever of length 3m carries a point load of 60 KN at a distance of 2m from the fixed end.If E= 2×105 and I=108, what is the deflection at the free end?. a.7 mm b.14 mm c.26 mm d.52 mm.
Last Answer : b.14 mm
Description : What is the maximum principle stress induced in a solid shaft of 40 mm diameter which is subjected to both bending moment and torque of 300 kN.mm and 150 kN.mm respectively? a. 21.69 N/mm2 b. 28.1 N/mm2 c. 50.57 N/mm2 d. 52.32 N/mm2
Last Answer : c. 50.57 N/mm2
Description : Which of the following is correct IPv4 address? a. 124.201.3.1.52 b. 01.200.128.123 c. 300.142.210.64 d. 128.64.0.0
Last Answer : d. 128.64.0.0
Description : In India, which one of the following should be considered the right combination of the age in days and live body weight in kg for a lamb for its weaning ? (A) 20 days to 30 days and 6 kg to 7 kg (B) 45 days to 60 ... (D) 75 days to 90 days and 12 kg to 15 kg (E) 55 days to 70 days and 9 kg to 11 kg
Last Answer : (C) 105 days to 120 days and 18 kg to 21 kg
Description : What city is 6 55 n 79 52 e?
Last Answer : 6.55 N 79.52 E is in the Laccadive Sea. The nearest city isColombo, the capital of Sri Lanka.
Description : The hexadecimal equivalent of decimal 21 is ________. 105) A) 1516 B) 1016 C) 2116 D) 1216
Last Answer : A) 1516
Description : The transport of a pair of electrons from NADH to O2 via the electron transport chain produces (A) –52,580 cal (B) –50,580 cal (C) 21,900 cal (D) +52,580 cal
Last Answer : D
Description : Calculate natural frequency of damped vibration, if damping factor is 0.52 and natural frequency of the system is 30 rad/sec which consists of machine supported on springs and dashpots. A 21 rad/sec B 25.62 rad/sec C 20.22 Hz D 3.15 Hz
Last Answer : B 25.62 rad/sec
Description : The numerical aperture of a material with acceptance angle of 60 degree in water will be a) 1.15 b) 2.15 c) 5.21 d) 1.52
Last Answer : a) 1.15
Description : A cantilever of length 3m carries a uniformly distributed load of 15KN/m over a length of 2m from the free end.If I= 108 mm4 and E= 2×105 N/mm2,find the slope at the free end? a.0.00326 rad b.0.00578 rad c.0.00677 rad d.0.00786 rad
Last Answer : a.0.00326 rad
Description : A cantilever of length 3 m carries two point loads of 2 KN at the free end and 4KN at a distance of 1m from the free end .What is the deflection at the free end? Take E= 2×105 N/mm2and I= 108 mm4. a.2.56 mm b.3.84 mm c.1.84 mm d.5.26mm
Last Answer : c.1.84 mm
Description : A cantilever of length 2m carries a point load of 30KN at the free end.If I = 108 mm4 and E= 2×105 N/mm2. What is the slope of the cantilever at the free end? a.0.503 rad b.0.677 rad c. 0.003 rad d.0.008
Last Answer : c. 0.003 rad
Description : 1 N (newton) is equal to A. 102 dynes B. 103 dynes C. 104 dynes D. 105 dynes
Last Answer : 105 dynes
Description : If a solid shaft (diameter 20 cm, length 400 cm, N = 0.8 × 105 N/mm2 ) when subjected to a twisting moment, produces maximum shear stress of 50 N/mm2 , the angle of twist in radians, is (A) 0.001 (B) 0.002 (C) 0.0025 (D) 0.003
Last Answer : (C) 0.0025
Description : Modulus elasticity of steel is generally taken as [ A ] 2 x 105 N/mm2 [ B ] 2 x 106 N/mm2 [ C ] 2 x 106 N/mm2 [ D ] 2 x 105 N/mm2
Last Answer : [ A ] 2 x 105 N/mm2
Description : A charge of 10μC and 14.4 μC are 12 cm apart, the force between them is: (a) 9 × 105 N (b) 9 × 107 N (c) 90 N (d) 108 × 107 N
Last Answer : (c) 90 N
Description : Name the city that is located 105 km upstream from Haldia. -Geography
Last Answer : Answer is: Kolkata.
Description : The average domestic consumption under normal conditions in an Indian city per day per person, is (A) 105 litres (B) 115 litres (C) 125 litres (D) 135 litres
Last Answer : (D) 135 litres
Description : What is located at 41 degree 52 n 12 degree 37 e?
Last Answer : Alaska
Description : Co-ordination number of Cr in `CrCl_(3^.)5H_(2)O` is six. The volume of 0.1 N `AgNO_(3)` needed to ppt. the chorine in outer sphere in 200 ml of 0.01
Last Answer : Co-ordination number of Cr in `CrCl_(3^.)5H_(2)O` is six. The volume of 0.1 N `AgNO_(3)` ... of 0.01 M solution of he possible complex es is/are:
Description : Looking for Hystar Steering Solenoid, p/n DSG-3C2-N-01, 110v a/c. Boat at sea and dead in the water. Where available?
Last Answer : You can find them at http://www.hystar.com.tw/hydraulic/hydraulic_2.htm there is an option to buy online even for that
Description : Which type of Sframe in HDLC exhibit the correspondence of last three bits [N(R)] by defining the negative acknowledgement (NAK) number with the code value of '01'? a. Receive ready b. Receive not ready c. Reject d. Selective Reject
Last Answer : c. Reject
Description : Most satisfactory formula for an estimate of fire demand Q for a city of population P in thousands for Indian conditions, is (A) Q = 1115 (p/5 + 20) (B) Q = 1640 P (1 - 0.01 P) (C) Q = 3180 P (D) None of these
Last Answer : (C) Q = 3180 P
Description : What is 52 equal 4 plus (n-1) x 3?
Last Answer : 52 = 4 + (n-1)3 → 3(n-1) = 48 → n - 1 = 16 → n = 17
Description : Three telephone circuits, each having an S/N ratio of 44 dB, are connected in tandem. What is the overall S/N ratio? A. 44 dB B. 39.2 dB C. 41 dB D. 43.52 dB
Last Answer : B. 39.2 dB
Description : Five persons M, N, O, P and Q request a bank for safety lockers. There are only 6 lockers available which are numbered from 52 to 57. The conditions are as follows: I. M's locker number is 2 less than O's lockers ... could be a) 52 or 53 only b) 53 or 54 only c) 54 or 55 only d) 53 or 55 only
Last Answer : c) 54 or 55 only
Description : Five persons M, N, O, P and Q request a bank for safety lockers. There are only 6 lockers available which are numbered from 52 to 57. The conditions are as follows: I. M's locker number is 2 less ... , then which locker number is not allocated? a) locker 52 b) locker 53 c) locker 54 d)locker 56
Last Answer : a) locker 52
Description : In case forces of 1 N, 2 N, 3 N, 4 N, 5 N and 6 N act in order along the sides of a regular hexagon, the resultant will be a.21 N b.107 dynes c.2 N d.6 N e.
Last Answer : d. 6 N
Description : One newton is equal to a.106 dynes b.105 dynes c.104 dynes d.103 dynes e.107 dynes
Last Answer : b. 105 dynes
Description : One joule is equal to a.105 ergs b.108 ergs c.104 ergs d.107 ergs e.106 ergs
Last Answer : d. 107 ergs
Description : Best of your own experience ... Thank you for any tips and links.
Last Answer : Need Answer
Description : Given E = 40xyi + 20x 2 j + 2k. Calculate the potential between two points (1,-1,0) and (2,1,3). a) 105 b) 106 c) 107 d) 108
Last Answer : b) 106
Description : Find the potential between two points p(1,-1,0) and q(2,1,3) with E = 40xy i + 20x 2 j + 2 k a) 104 b) 105 c) 106 d) 107
Last Answer : c) 106
Description : Correct viscosity of furnace oil at the burner tip for proper atomisation is about 25 centistokes. To reduce the viscosity of high viscosity furnace oil (250 centistokes) to the correct atomisation viscosity (i.e. 25 cst), it should be preheated to about ___________°C. (A) 70 (B) 85 (C) 105 (D) 145
Last Answer : (C) 105
Description : 187.5, 182, 171, ?, 132.5, 105, 72 a) 145.5 b) 155.5 c) 154.5 d) 144.5 e) None of these
Last Answer : The pattern is -5.5, -11, -16.5, -22 and so on. Answer: c)
Description : Vinoth could get equal number of Rs. 55, Rs. 85 and Rs. 105 ticket for a Zoo. He spend Rs. 3920 for all the tickets. How many of each did he buy? a) 15 b) 18 c) 16 d) 26 e) None of these
Last Answer : Total money = 55x + 85x + 105x = 3920 245x = 3920 x = 16 Answer: c)
Description : 2 9 30 105 ? 2195 a) 432 b) 426 c) 440 d) 436 e) None of these
Last Answer : The series is ×1 + 1 × 7, ×2 + 2 × 6, ×3 + 3 × 5... Answer: d)
Description : The ratio between two number is 3:4 ,if each number be increased by 9, the ratio becomes 18:23 find the sum of the number a) 135 b) 105 c) 155 d) 165 e) None of these
Last Answer : Let the two numbers be 3x and 4x. When they are increased by 9 they become 3x + 9 and 4x + 9. It is given that the ratio is 18:23 Thus, 3x + 9/4x + 9 = 18:23 23(3x + 9) = 18(4x + 9) 69x + 207 = 72x ... = -45 X = 15 Thus two numbers are 3x15 = 45 and 4 x 15 = 60 And the sum is 60+45 = 105 Answer: b)
Description : 136% of 105 – 84% of 165 = ? a) 4.2 b) 5.7 c) 6.4 d) 7.8 e) 8.6
Last Answer : a) 4.2
Description : 2 9 ? 105 436 2195 13182 a) 32 b) 45 c) 40 d) 30 e) 25
Last Answer : The series is (2 + 7) × 1 = 9; (9 + 6) × 2 = 30; (30 + 5) × 3 = 105; (105 + 4) × 4 = 436; (436 + 3) × 5 = 2195; (2195 + 2) × 6 = 13182 Answer: d)
Description : What is the percentage of successful candidates from institute E and F together over the candidates enrolled from these institutes together? a) 76 b) 105 c) 80 d) 74 e) None of these
Last Answer : a) 76
Description : Patient presents with rapidly progressive root caries on many teeth. Which of the following laboratory results would be a possible indicator of this? A. Stimulated salivary secretion rate of 1.5ml/min B. ... of 105 organism/ml E. Salivary buffering PH 5.5 > 100000 CFU/ml high caries incidence
Last Answer : E. Salivary buffering PH 5.5
Description : Using the RSA public key crypto system, if p=13, q=31 and d=7, then the value of e is (A) 101 (B) 105 (C) 103 (D) 107
Last Answer : (C) 103 Explanation: Basic RSA Algorithm: 1. Choose two primes, p & q. 2. Compute n=p*q and z=(p-1)*(q-1). 3. Choose a number relatively prime to z and call it d. 4. Find e such that e*d= ... each of these in turn by 7 to see which is divisible by 7, we find that 721/7 = 103, hence e = 103.
Description : Nandita scores 60% marks in five subjects together, viz., Hindi, Science, Mathematics, English and Sanskrit, where in the maximum marks of each subject were 105. How many marks did Nandita score in Science, if she scored 69 ... and 51 marks in English? a) 66 b) 68 c) 55 d) 65 e) None of these
Last Answer : Answer: D Total of maximum marks of all subjects=105×5=525 75% of 525=525 ×60/100= 315 Obtained marks of foru subjects (Hindi, Sanskrit, mathematics and English) =69+62+68+51=250 So, the obtained marks in Science=315-250=65
Description : In what ratio must a person mix three kinds of musted seeds costing Rs.65/kg, Rs.70/kg and Rs.105 /kg so that the resultant mixture when sold at Rs.96/kg yields a profit of 20%? a) 1:2:4 b) 3:7:6 c) 1:4:2 d)1:8:6 e) 40 : 8 : 25
Last Answer : E The resultant mixture is sold at a profit of 20% at Rs.96/kg i.e. 1.2 (cost) = Rs.96 => Cost = = Rs.80 / kg. Let the three varities be A, B, and C costing Rs.65, Rs.70 and Rs.105 respectively. The ... be mixed. A:C=4:5 B:C=2:5 The resultant ratio A : B : C :: 40 : 8 : 25.
Description : A foot ball team lost 75 % of the matches it played. If it won 45 matches, find the number of matches it played. a) 120 b) 145 c) 105 d) 140 e) 180
Last Answer : Answer: E Percentage of matches lost = 75 % Therefore Percentage of matches won (100 - 75) % = 25 % Let the number of matches played be x. Then 25 % of x = 45 25/100 × x =45 x = (45 × 100)/25 x = (4500)/25 x = 180 Therefore, the total number of matches played is 180.
Description : In final exam of class IX there are 130 students 20 % students failed. How many students passed to class X? a) 105 b) 112 c) 104 d) 117 e) 104.5
Last Answer : Answer: C) Percentage of students passed to class X = (100 % - 20 %) of 130 = 80 % of 130 =>80 % of 130 => 80/100 × 130 =>10400/100 => 104 Therefore, 104 students passed to class X
Description : The ball bearing is subjected to a radial load of 4000 N. Expected life for 90% bearings is 9000 hr and the shaft is rot (a) 42.21 kN (b) 37.29 kN (c) 26.33 kN (d) 35.22 kN
Last Answer : (b) 37.29 kN
Description : In the hexaploid wheat, the haploid (n) and basic (x) numbers of chromosomes are (a) n = 21 and x = 21 (b) n = 21 and x = 14 (c) n = 21 and x = 7 (d) n = 7 and x = 21.
Last Answer : (c) n = 21 and x = 7