The ratio of prices of 2 dresses is 10:15.If the price of the first dress is increased by 10% and that of the second dress by Rs.400 then the ratio of their prices is 4:7.What are the initial prices of the dresses ? A) 910,1375 B) 920,1380 C) 930,1395 D) 940, 1410 E) None of these

The ratio of prices of 2 dresses is 10:15.If the price of the first dress is increased by 10% and that of the second dress by Rs.400 then the ratio of their prices is 4:7.What are the initial prices of the dresses ? A) 910,1375 B) 920,1380 C) 930,1395 D) 940, 1410 E) None of these
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1 Answer

Answer :

Answer: D

Let the initial price of the dress = 10x and 15x

Price of the 1st dress after increment = 10x × (110/100) = 11x

Price of the 2nd dress after increment = 15x+400

[11x/(15x+400)] = 4/7

77x = 60x + 1600

17x = 1600

X = 1600/17 = 94.11 = 94

So dresses will be 940, 1410
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Last Answer : Answer: C Income of A = x, of B = 2x Expenditure of A = 2y, of B = 5y Savings is (income – expenditure). So x – 2y = 20,000 2x – 5y = 35,000 Solve the equations, x = 30,000 So total = x+2x = 3x = 3*30,000 = 90,000

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A bag contains one rupee, 50 paise and 25 paise coins in the ratio 2 : 3 : 5. Their total value is Rs. 144. The value of 50-paise coins is: a) Rs. 24 b) Rs. 36 c) Rs. 48 d) Rs. 72 e) None of these

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Last Answer : Answer: B Sol. Let the number of one-rupee coins, 50-paise coins and 25-paise coins be 2k, 3k and 5k, respectively. ∴ 2k × 1 + 3k × 0.50 + 5k × 0.25 = 114 ⇒ 2k + 1.50k + 1.25k = 114  ⇒ 4.75k = 114 ⇒ k = 24. 50 paise value = 1.5x = 1.5*24 = 36

One year ago, the ratio between A's and B's salary was 4:5. The ratio of their individual salaries of last year and present year are 3:5 and 2:3 respectively. If their total salaries for the present year is Rs 6800, the present salary of A is A) Rs 4080 B) Rs 3200 C) Rs 4533.40 D) Rs 2720 E) NONE

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Last Answer : Answer: B Given, the Ratio of A's last year and present year salary = 3:5. Let salary be 3x and 5x respectively. Also, the Ratio of B's in last year and present year salary = 2:3 Let salary be 2y and 3y ... i) and (ii), we get :- y=1200 and x=640. Hence, A's present salary is 5x=5 640=3200.

One year ago the ratio between Laxman and Gopal salary was 3:4. The individual ratios between their last year’s and this year’s salary are 4:5 and 2:3 respectively. At present the total of their salary is Rs.4160. The salary of laxman now is? a) 1800 b) 1500 c) 2160 d) 2560 e) 1600

Description : One year ago the ratio between Laxman and Gopal salary was 3:4. The individual ratios between their last year’s and this year’s salary are 4:5 and 2:3 respectively. At present the total of their salary is Rs.4160. The salary of laxman now is? a) 1800 b) 1500 c) 2160 d) 2560 e) 1600

Last Answer : Answer: E Let the salaries of Laxman and Gopal one year before be x1 ,y1 respectively. ∴ x1/y1 = 3/4 ......(1) x2 + y2 = 4160 .....(2)  From equations (1) and (2) x2 = Rs. 1600.

Rs.1870 is divided into three parts in such a way that half of the first part, one-third of the second part and one-sixth of the third part are equal. The third part is A) Rs.510 B) Rs.680 C) Rs.850 D) Rs.1020 E) None of these

Description : Rs.1870 is divided into three parts in such a way that half of the first part, one-third of the second part and one-sixth of the third part are equal. The third part is A) Rs.510 B) Rs.680 C) Rs.850 D) Rs.1020 E) None of these 

Last Answer : Answer: D F/2 = S/3= T/6 T = 2S = 3F F + S + T = 1870 T( 1/3 +1/2 + 1 ) = 1870 T= 1870 x 6/11 = 170 x 6 = 1020 Or the third part is a multiple of 6 and is large

If 40 percent of a number is subtracted from the second number then the second number is reduced to its 3/5. Find the ratio between the first number and the second number. A) 1:3 B) 1:2 C) 1:1 D) 2:3 E) None of these

Description :  If 40 percent of a number is subtracted from the second number then the second number is reduced to its 3/5. Find the ratio between the first number and the second number. A) 1:3 B) 1:2 C) 1:1 D) 2:3 E) None of these

Last Answer : Answer: C [ b – (40/100)a] = (3/5)b. So we get a = b. 1:1

The sum of three numbers is 210. If the ratio between the first and second number be 2:3 and that between the second and third be 4:5, then the difference between the first and third number? a) 21 b) 35 c) 42 d) 56 e) None of these

Description : The sum of three numbers is 210. If the ratio between the first and second number be 2:3 and that between the second and third be 4:5, then the difference between the first and third number? a) 21 b) 35 c) 42 d) 56 e) None of these

Last Answer : Answer: C a: b = 2:3 and b:c = 4:5 a:b:c = 8:12:15 Difference between first and third number = (7/35)*210 = 42

The sum of the three number is 68.If the ratio of the first to second is 3:2 and that of the second to the third is 5:3 , then the second number is approximately A) 21 B) 22 C) 23 D) 24 E) None of these

Description : The sum of the three number is 68.If the ratio of the first to second is 3:2 and that of the second to the third is 5:3 , then the second number is approximately A) 21 B) 22 C) 23 D) 24 E) None of these 

Last Answer : Answer: B A: B = 3:2 B:C = 5 : 3 B:C =(5×[2/5]) : (3×[2/5])= 2: (6/5) A:B:C = 3:2:(6/5) = 15:10:6 Second number = (10/31)×68 = 21.9 = 22

Joseph bought two varieties of rice, costing 5 cents per ounce and 6 cents per ounce each, and mixed them in some ratio. Then he sold the mixture at 7 cents per ounce, making a profit of 20 percent. What was the ratio of the mixture? A) 1:10 B) 1:5 C) 2:7 D) 3:8 E) NONE

Description : Joseph bought two varieties of rice, costing 5 cents per ounce and 6 cents per ounce each, and mixed them in some ratio. Then he sold the mixture at 7 cents per ounce, making a profit of 20 percent. What was the ratio of the mixture? A) 1:10 B) 1:5 C) 2:7 D) 3:8 E) NONE

Last Answer : Answer: B 1) 20% profit at the price of 7 cents means that cost of the mixture should be 70/12 cents per ounce (7 = 120% and x = 100% => x = 7*100/120) 2) Let the amount of 5 cent rice will be x and the amount ... which as we know should equal to 70/12 3) (5x + 6y)/(x + y) = 70/12 => x/y = 1/5

A sum of Rs 315 consists of 25 paise, 50 paise and 1 Re coins in the ratio 3 : 4 :6. What is the number of each kind of coin respectively? A) 216, 144, 27 B) 108, 144, 216 C) 27, 72, 216 D) 120, 35, 108 E) 102, 150, 210

Description :  A sum of Rs 315 consists of 25 paise, 50 paise and 1 Re coins in the ratio 3 : 4 :6. What is the number of each kind of coin respectively? A) 216, 144, 27 B) 108, 144, 216 C) 27, 72, 216 D) 120, 35, 108 E) 102, 150, 210

Last Answer : Answer: B 25 paise = 25/100 Rs, 50 paise = 50/100 Rs So value ratio of these coins become = 3*(25/100) : 4*(50/100) : 6*(1) = 3/4 : 2 : 6 = 3 : 8 : 24 So 25 paise coins value= [3/(3+8+24)] * ... 100/50) = 144 So 1 paise coins value= [24/(3+8+24)] * 315 = Rs 216, so coins = 215 * (100/100) = 216

In a pocket of A, the ratio of Rs.1 coins, 50p coins and 25p coins can be expressed by three consecutive odd prime numbers that are in ascending order. The total value of coins in the bag is Rs 58. If the number of Rs.1, 50p, 25p coins are reversed, find the new total value of coins in the pocket of A? A) Rs 68 B) Rs 43 C) Rs 75 D) Rs 82 E) NONE

Description : In a pocket of A, the ratio of Rs.1 coins, 50p coins and 25p coins can be expressed by three consecutive odd prime numbers that are in ascending order. The total value of coins in the bag is Rs 58. If the number of Rs.1 ... of coins in the pocket of A? A) Rs 68 B) Rs 43 C) Rs 75 D) Rs 82 E) NONE

Last Answer : Answer: D  Since the ratio of the number of Rs. 1, 50p and 25p coins can be represented by 3 consecutive odd numbers that are prime in ascending order, the only possibility for the ratio is 3:5:7. Let the number of ... =100 7k+50 5k+25 3k=1025k (In above we find the value of k). ⇒ 8200p = Rs 82.

What is the distance between two consecutive longitudes (910 E and 920 E) at-the Poles? -Do You Know?

Description : What is the distance between two consecutive longitudes (910 E and 920 E) at-the Poles? -Do You Know?

Last Answer : answer:

What is the distance between two consecutive longitudes (910 E and 920 E) at- the Poles?

Description : What is the distance between two consecutive longitudes (910 E and 920 E) at- the Poles?

Last Answer : 0 km

What is the distance between two consecutive longitudes (910 E and 920 E) at- the Poles?

Description : What is the distance between two consecutive longitudes (910 E and 920 E) at- the Poles?

Last Answer : 0 km

An outgoing batch of students wants to gift a PA system worth Rs 4,200 to their school. If the teachers, offer to pay 50% more than the students and an external benefactor gives three times the teacher's contribution, then how much should the teachers donate? A) Rs 600 B) Rs 840 C) Rs 900 D) Rs 1,200 E) NONE

Description : An outgoing batch of students wants to gift a PA system worth Rs 4,200 to their school. If the teachers, offer to pay 50% more than the students and an external benefactor gives three times the teacher's contribution, then ... the teachers donate? A) Rs 600 B) Rs 840 C) Rs 900 D) Rs 1,200 E) NONE

Last Answer : Answer: C The ratio of the share students : teacher: benefactor=1:1.5 : 4.5 So the proportion to teacher's share = 1.5/7 Hence, the teachers would donate 1.5/7×4200=Rs 900

Two vessels contains equal quantity of solution contains milk and water in the ratio of 7:2 and 4:5 respectively. Now the solutions are mixed with each other then find the ratio of milk and water in the final solution? A) 11:7 B) 11:6 C) 11:5 D) 11:9 E) None of these

Description : Two vessels contains equal quantity of solution contains milk and water in the ratio of 7:2 and 4:5 respectively. Now the solutions are mixed with each other then find the ratio of milk and water in the final solution? A) 11:7 B) 11:6 C) 11:5 D) 11:9 E) None of these

Last Answer : Answer: A milk = 7/9 and water = 2/9 – in 1st vessel milk = 4/9 and water = 5/9 – in 2nd vessel (7/9 + 4/9)/ (2/9 + 5/9) = 11:7

When 7 is added to the numerator and denominator of the fraction, then the new ratio of numerator and denominator becomes 13:19, what is the original ratio ? A) 11:13 B) 7:9 C) 4:7 D) Can’t be determined E) None of these

Description : When 7 is added to the numerator and denominator of the fraction, then the new ratio of numerator and denominator becomes 13:19, what is the original ratio ? A) 11:13 B) 7:9 C) 4:7 D) Can’t be determined E) None of these

Last Answer : Answer: D  X+7/y+7 = 13/19 x and y are different variable, so original fraction cannot be determined

Ratio of earnings of A and B is 3:5. If the earnings of A increase by 25% and those of B decrease by 30%, the new ratio of their earnings become 6:8.What is A’s earnings ? A) 16,000 B) 34,000 C) 15,000 D) 32,000 E) Data inadequate

Description : Ratio of earnings of A and B is 3:5. If the earnings of A increase by 25% and those of B decrease by 30%, the new ratio of their earnings become 6:8.What is A’s earnings ? A) 16,000 B) 34,000 C) 15,000 D) 32,000 E) Data inadequate

Last Answer : Answer: E Data inadequate We cannot derive the earnings from the given details

A working partner gets 25% as his commissions after his commissions paid that is equal to Rs.7500, then what is the total profit ? A) Rs.32,000 B) Rs.30,000 C) Rs.37,500 D) Rs.40,000 E) None of these

Description : A working partner gets 25% as his commissions after his commissions paid that is equal to Rs.7500, then what is the total profit ? A) Rs.32,000 B) Rs.30,000 C) Rs.37,500 D) Rs.40,000 E) None of these

Last Answer : Answer: C X=total profit 25/100*[x-7500] = 7500 x-7500 = 7500*100/25 =30,000 x = 37,500

In 1 kg mixture of sand and iron, 20% is iron. How much sand should be added so that the proportion of iron becomes 10%? a) 1 kg b) 200 gms c) 800 gms d) 1.8 kg e) None of these

Description : In 1 kg mixture of sand and iron, 20% is iron. How much sand should be added so that the proportion of iron becomes 10%? a) 1 kg b) 200 gms c) 800 gms d) 1.8 kg e) None of these

Last Answer : Answer: A If we add x grams of sand, the total amount would be 1,000 + x grams of mixture and we need 200 grams of iron to be 10% of that: 0.1(1,000 + x) = 200 --> x = 1,000. 

The sum of the squares between three numbers is 5000. The ratio between the first and the second number is 3:4 and that of second and third number is 4:5. Find the difference between first and the third number. A) 20 B) 30 C) 40 D) 50 E) None of these

Description : The sum of the squares between three numbers is 5000. The ratio between the first and the second number is 3:4 and that of second and third number is 4:5. Find the difference between first and the third number. A) 20 B) 30 C) 40 D) 50 E) None of these

Last Answer : Answer: A a^2 + b^2 + c^2 = 5000 a:b:c = 3:4:5 50x^2 = 5000. X = 10. 5x – 3x = 2*10 = 20