One year ago, the ratio between A's and B's salary was 4:5. The ratio of their individual salaries of last year and present year are 3:5 and 2:3 respectively. If their total salaries for the present year is Rs 6800, the present salary of A is A) Rs 4080 B) Rs 3200 C) Rs 4533.40 D) Rs 2720 E) NONE

One year ago, the ratio between A's and B's salary was 4:5. The ratio of their individual salaries of last year and present year are 3:5 and 2:3 respectively. If their total salaries for the present year is Rs 6800, the present salary of A is A) Rs 4080 B) Rs 3200 C) Rs 4533.40 D) Rs 2720 E) NONE
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1 Answer

Answer :

Answer: B

Given, the Ratio of A's last year and present year salary = 3:5.

Let salary be 3x and 5x respectively.

Also, the Ratio of B's in last year and present year salary = 2:3

Let salary be 2y and 3y respectively.

Given, 3x/2y=4/5.

=>15x=8y . --------------- (i)

Also, 5x+3y=6800. --------------- (ii)

From equation (i) and (ii), we get :-

y=1200 and x=640.

Hence, A's present salary is 5x=5×640=3200.
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Description : Rs 4830 is divided among Abhishek, Dishant and Prashant such that if Abhishek's share diminishes by Rs 5, Dishant's share diminishes by Rs 10 and Prashant's share diminishes by Rs 15, their shares will be in the ratio 5:4:3. Find the Dishant's original share A) 1610 B) 2010 C) 2410 D) 1590 E) NONE

Last Answer : Answer: A Let actual share of Abhishek, Dishant and Prashant be A, D , P respectively. A+D+P=4830 Hence, A's, D's and P's share are diminished by Rs 5, Rs 10 and Rs 15, their net share ... . Dishant's diminished share = (4/12) * 4800 = Rs1600 Hence, Dishant actual share =Rs1600+Rs10= Rs 1610.

The monthly incomes of A and B are in the ratio 4:5, their expenses are in the ratio 5 : 6. If 'A' saves Rs.25 per month and 'B' saves Rs.50 per month, what are their respective incomes? A) Rs.400 and Rs.500 B) Rs.240 and Rs.300 C) Rs.320 and Rs.400 D) Rs.440 and Rs.550 E) NONE

Description : The monthly incomes of A and B are in the ratio 4:5, their expenses are in the ratio 5 : 6. If 'A' saves Rs.25 per month and 'B' saves Rs.50 per month, what are their respective incomes? A) Rs.400 and Rs.500 B) Rs.240 and Rs.300 C) Rs.320 and Rs.400 D) Rs.440 and Rs.550 E) NONE

Last Answer : Answer: A Let AA's income be = 4x AA's expenses, therefore = 4x–25 Let BB's income be = 5x BB's expenses, therefore = 5x–50 We know that the ratio of their expenses = 5:6 ⇒24x−150=25x−250 ⇒ Therefore, x=100 A's income =4x=400 and B's income =5x=500 

The ratio of the price of two houses was 17:24. Two years later, when the price of the first had risen by 20% while the price of second house increases by Rs.500 and their prices become 16:25. Find the original prices of the two houses together? a) Rs.2603 b) Rs.2503 c) Rs.2403 d) Rs.2303 e) None of these

Description : The ratio of the price of two houses was 17:24. Two years later, when the price of the first had risen by 20% while the price of second house increases by Rs.500 and their prices become 16:25. Find the original ... two houses together? a) Rs.2603 b) Rs.2503 c) Rs.2403 d) Rs.2303 e) None of these

Last Answer : Answer: A Let, new price of the first house=17x 120/100=102x/5 Let, new price of the second house=24x+500 According to the question, (102x/5) :(24x+500)=16 :25 ((102x/5))/((24x+500 ... price of second house=24 4000/63=1523.81 ~ Rs.1524 Required answer, =1079+1524=2603 Answer=d) Rs.2603

The ratio of prices of 2 dresses is 10:15.If the price of the first dress is increased by 10% and that of the second dress by Rs.400 then the ratio of their prices is 4:7.What are the initial prices of the dresses ? A) 910,1375 B) 920,1380 C) 930,1395 D) 940, 1410 E) None of these

Description : The ratio of prices of 2 dresses is 10:15.If the price of the first dress is increased by 10% and that of the second dress by Rs.400 then the ratio of their prices is 4:7.What are the initial prices of the dresses ? A) 910,1375 B) 920,1380 C) 930,1395 D) 940, 1410 E) None of these

Last Answer : Answer: D Let the initial price of the dress = 10x and 15x Price of the 1st dress after increment = 10x × (110/100) = 11x Price of the 2nd dress after increment = 15x+400 [11x/(15x+400)] = 4/7 77x = 60x + 1600 17x = 1600 X = 1600/17 = 94.11 = 94 So dresses will be 940, 1410

Consider two alloys A and B. 50 kg of alloy A is mixed with 70 kg of alloy B. A contains brass and copper in the ratio 3 : 2, and B contains them in the ratio 4 : 3 respectively. What is the ratio of copper to brass in the mixture? A) 8 : 5 B) 7 : 5 C) 5 : 11 D) 4 : 9 E) 5 : 7

Description : Consider two alloys A and B. 50 kg of alloy A is mixed with 70 kg of alloy B. A contains brass and copper in the ratio 3 : 2, and B contains them in the ratio 4 : 3 respectively. What is the ratio of copper to brass in the mixture? A) 8 : 5 B) 7 : 5 C) 5 : 11 D) 4 : 9 E) 5 : 7

Last Answer : Answer: E Brass in A = 3/5 * 50 = 30 kg, Brass in B = 4/7 * 70 = 40 kg Total brass = 30+40 = 70 kg So copper in mixture is (50+70) – 70 = 50 kg So copper to brass = 50 : 70=5:7

Two vessels contains equal quantity of solution contains milk and water in the ratio of 7:2 and 4:5 respectively. Now the solutions are mixed with each other then find the ratio of milk and water in the final solution? A) 11:7 B) 11:6 C) 11:5 D) 11:9 E) None of these

Description : Two vessels contains equal quantity of solution contains milk and water in the ratio of 7:2 and 4:5 respectively. Now the solutions are mixed with each other then find the ratio of milk and water in the final solution? A) 11:7 B) 11:6 C) 11:5 D) 11:9 E) None of these

Last Answer : Answer: A milk = 7/9 and water = 2/9 – in 1st vessel milk = 4/9 and water = 5/9 – in 2nd vessel (7/9 + 4/9)/ (2/9 + 5/9) = 11:7

Two numbers are respectively 40% and 60% more than than the third number. The ratio of the two number is A) 6:7 B) 7:8 C) 8:7 D) 7:5 E) None of these

Description : Two numbers are respectively 40% and 60% more than than the third number. The ratio of the two number is A) 6:7 B) 7:8 C) 8:7 D) 7:5 E) None of these

Last Answer : Answer: B Let third number = x (140/100)x = (7/5)x (160/100)x = (8/5)x (7/5) : (8/5) = 35 : 40 = 7 : 8

The number of candidates writing three different entrance exams is in the ratio 4:5:6. There is a proposal to increase these numbers of candidates by 40%, 60% and 85% respectively. What will be the ratio of increased numbers? a) 14:15:16 b) 12:15:19 c)13:19:21 d) 14:16:19 E) None of these

Description : The number of candidates writing three different entrance exams is in the ratio 4:5:6. There is a proposal to increase these numbers of candidates by 40%, 60% and 85% respectively. What will be the ratio of increased numbers? a) 14:15:16 b) 12:15:19 c)13:19:21 d) 14:16:19 E) None of these

Last Answer : Answer : E Given ratio of number of candidates is 4:5:6 Let the number of candidates for 3 exams be 4k, 5k and 6k respectively. After increasing, number of candidates become (140% of 4k), (160% of 5k) & (185% ... 111k/10 Now, the required new ratio is: 56k/100 : 80k/10 : 111k/10 = 56 : 80 : 111

IBM and KTC quote for a tender. On the tender opening day, IBM realizes that their quotations are in the ratio 7 :4 and hence decreases its price during negotiations to make it Rs 1 Lakh lower than KTC's quoted price. KTC realizes that the final quotes of the two were in the ratio 3:4. What was the price at which IBM won the bid? A) Rs 7 Lakh B) Rs 4 Lakh C) Rs 3 Lakh D) Rs 1.5 Lakh

Description :  IBM and KTC quote for a tender. On the tender opening day, IBM realizes that their quotations are in the ratio 7 :4 and hence decreases its price during negotiations to make it Rs 1 Lakh lower than KTC's quoted price. KTC ... won the bid? A) Rs 7 Lakh B) Rs 4 Lakh C) Rs 3 Lakh D) Rs 1.5 Lakh

Last Answer : Answer: C IBM initially quoted Rs 7x lakh. KTC quoted 4x lakh. IBM's final quote =(4x−1) Lakh Thus, (4x-1/4x) = 3/4 = x = 1 IBM's bid winning price = Rs 3 Lakh So IBM wins the bid at 4x−1= Rs 3 lakh.

Two alloys contain platinum and gold in the ratio of 1:2 and 1:3 respectively. A third alloy C is formed by mixing alloys one and alloy two in the ratio of 3:4. Find the percentage of gold in the mixture a) 79.2/7% b) 71.2/7% c) 73.2/7% d) 71.3/7% e) None of these

Description : Two alloys contain platinum and gold in the ratio of 1:2 and 1:3 respectively. A third alloy C is formed by mixing alloys one and alloy two in the ratio of 3:4. Find the percentage of gold in the mixture a) 79.2/7% b) 71.2/7% c) 73.2/7% d) 71.3/7% e) None of these

Last Answer : Answer: D Platinum = 1/3 and 1/4 gold = 2/3 and 3/4 Alloy one and two are mixed in the ratio of 3:4, so ratio of platinum and gold in final ratio – 2:5 So gold % = (5/7)*100 71.3/7%

Three friends Alice, Bond and Charlie divide $1105 amongst them in such a way that if $10, $20 and $15 are removed from the sums that Alice, Bond and Charlie received respectively, then the share of the sums that they got will be in the ratio of 11 : 18 : 24. How much did Charlie receive? a) $495 b) $510 c) $480 d) $375 e) $360

Description : Three friends Alice, Bond and Charlie divide $1105 amongst them in such a way that if $10, $20 and $15 are removed from the sums that Alice, Bond and Charlie received respectively, then the share of the sums that ... 18 : 24. How much did Charlie receive? a) $495 b) $510 c) $480 d) $375 e) $360

Last Answer : Answer: A Let the sums of money received by A, B and C be x, y and z respectively. Then x - 10 : y - 20 : z -15 is 11a : 18a : 24a When $10, $20 and $15 are removed, we are removing a total of $45 from ... or a= 20 We know that z - 15 = 24a = (24 * 20) = 480 Therefore, z = 480 + 15 = $495

Rs 650 was divided among 3 children A,B,C in the ratio 2 : 4 : 7. Had it been divided in the ratio 1/2 : 1/4 : 1/7, who would have gained the most and by how much? A) C, Rs 246 B) C, Rs 264 C) B, Rs 18 D) A, Rs 246 E) A, Rs 264

Description : Rs 650 was divided among 3 children A,B,C in the ratio 2 : 4 : 7. Had it been divided in the ratio 1/2 : 1/4 : 1/7, who would have gained the most and by how much? A) C, Rs 246 B) C, Rs 264 C) B, Rs 18 D) A, Rs 246 E) A, Rs 264

Last Answer : Answer: E New ratio = 1/2 : 1/4 : 1/7 = 14 : 7 : 4 So both ratio suggests that C has not gained any money, rather he has lose the money. For both ratio find the shares of A and B With ratio 2 : 4 : 7 ... [7/(14+7+4)] * 650 = 182 B has also lose the money, A gain the money and = 364 - 100 = 264

The price of a diamond is proportional to the square of its weight. The diamond accidentally fell and broke into four pieces whose weights are in the ratio of 1:2:3:4. If the price fetched is Rs. 70,000 less than the original price, find the original price? a) Rs. 100,000 b) Rs. 70,000 c) Rs. 160,000 d) Rs. 10800 e) Rs. 150,000

Description : The price of a diamond is proportional to the square of its weight. The diamond accidentally fell and broke into four pieces whose weights are in the ratio of 1:2:3:4. If the price fetched is Rs. 70,000 less than the ... a) Rs. 100,000 b) Rs. 70,000 c) Rs. 160,000 d) Rs. 10800 e) Rs. 150,000

Last Answer : Answer: A let price of diamond as kx^2 where k is a constant total price for 4 pieces kx^2[1+4+9+16]=30kx^2 price of original diamond=100kx^2 difference 70kx^2=$70000 or kx^2=1000 original price of the diamond=100*1000=100000

In a bag there are coins of 25p, 10p and 5p in the ratio 1:2:3.If there are Rs.45 in all then find how many 25p coins are there? A) 60 B) 65 C) 70 D) 75 E) None of these

Description : In a bag there are coins of 25p, 10p and 5p in the ratio 1:2:3.If there are Rs.45 in all then find how many 25p coins are there? A) 60 B) 65 C) 70 D) 75 E) None of these

Last Answer : Answer: D [(25x) + (10x × 2) + (5x × 3)] / 100 = 45 [25x + 20x + 15x] / 100 = 45 60 x = 4500 X = 4500/60 = 75

A noodles merchant buys two varieties of noodles the price of the first being twice that of the second. He sells the mixture at Rs 17.50 per kilogram thereby making a profit of 25% . If the ratio of the amounts of the first noodles and the second noodles in the mixture is 2:3, then the respective costs of each noodles are A) Rs 20, Rs 10 B) Rs 24, Rs 12 C) Rs 16, Rs 8 D) Rs 26, Rs 13 E) NONE

Description : A noodles merchant buys two varieties of noodles the price of the first being twice that of the second. He sells the mixture at Rs 17.50 per kilogram thereby making a profit of 25% . If the ratio of the amounts of the first noodles ... , Rs 10 B) Rs 24, Rs 12 C) Rs 16, Rs 8 D) Rs 26, Rs 13 E) NONE

Last Answer : Answer: A

If 40 percent of a number is subtracted from the second number then the second number is reduced to its 3/5. Find the ratio between the first number and the second number. A) 1:3 B) 1:2 C) 1:1 D) 2:3 E) None of these

Description :  If 40 percent of a number is subtracted from the second number then the second number is reduced to its 3/5. Find the ratio between the first number and the second number. A) 1:3 B) 1:2 C) 1:1 D) 2:3 E) None of these

Last Answer : Answer: C [ b – (40/100)a] = (3/5)b. So we get a = b. 1:1

The ratio between the number of boys and girls in a school is 4:5. If the number of boys are increased by 30 % and the number of girls increased by 40 %, then what will the new ratio of boys and girls in the school. A) 13/35 B) 26/35 C) 26/41 D) 23/13 E) None of these

Description : The ratio between the number of boys and girls in a school is 4:5. If the number of boys are increased by 30 % and the number of girls increased by 40 %, then what will the new ratio of boys and girls in the school. A) 13/35 B) 26/35 C) 26/41 D) 23/13 E) None of these

Last Answer : Answer: B boys = 4x and girls = 5x. Required ratio = [(130/100)*4x]/ [(140/100)*5x] 26/35

The sum of the squares between three numbers is 5000. The ratio between the first and the second number is 3:4 and that of second and third number is 4:5. Find the difference between first and the third number. A) 20 B) 30 C) 40 D) 50 E) None of these

Description : The sum of the squares between three numbers is 5000. The ratio between the first and the second number is 3:4 and that of second and third number is 4:5. Find the difference between first and the third number. A) 20 B) 30 C) 40 D) 50 E) None of these

Last Answer : Answer: A a^2 + b^2 + c^2 = 5000 a:b:c = 3:4:5 50x^2 = 5000. X = 10. 5x – 3x = 2*10 = 20

Determine the ratio of the number of people having characteristic X to the number of people having characteristic Y in a population of 100 subjects from the following table People having X and Y are 20 People having X but not Y are 10 People having Y but not X are 30 People having neither X nor Y are 40. a) 3 : 5 b) 3 : 2 c) 1 : 2 d) 2 : 3 e) None of these

Description : Determine the ratio of the number of people having characteristic X to the number of people having characteristic Y in a population of 100 subjects from the following table People having X and Y are 20 People having X but not Y are 10 ... 3 : 5 b) 3 : 2 c) 1 : 2 d) 2 : 3 e) None of these

Last Answer : Answer: A Number of people having characteristic X = 10 + 20 = 30 Number of people having characteristic Y = 20 + 30 = 50 Therefore Required ratio = 30 : 50 = 3 : 5

A vessel contains milk and water in the ratio of 4:3. If 14 litres of the mixture is drawn and filled with water, the ratio changes to 3:4. How much milk was there in the vessel initially? a) 24 b) 32 c) 40 d) 48 e) None of these

Description : A vessel contains milk and water in the ratio of 4:3. If 14 litres of the mixture is drawn and filled with water, the ratio changes to 3:4. How much milk was there in the vessel initially? a) 24 b) 32 c) 40 d) 48 e) None of these

Last Answer : Answer: B milk = 4x and water = 3x milk = 4x – 14*4/7 and water = 3x – 14*3/7 + 14 4x – 8: 3x + 8 = 3:4 X = 8, so milk = 8*4 = 32 litres