The Tm for PAH i.e the maximal secretory capacity of the tubule for PAH can be used to gavge the (A) Extent of tubular damage FATS AND FATTY ACID METABOLISM 81 (B) Impairment of the capacity of the tubule to perform osmotic work (C) Impairment of renal plasma flow (D) Glomerular filtration rate

The Tm for PAH i.e the maximal secretory capacity of the tubule for PAH can be used to gavge the (A) Extent of tubular damage FATS AND FATTY ACID METABOLISM 81 (B) Impairment of the capacity of the tubule to perform osmotic work (C) Impairment of renal plasma flow (D) Glomerular filtration rate
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An early feature of renal disease is (A) Impairment of the capacity of the tubule to perform osmotic work (B) Decrease in maximal tubular excretory capacity (C) Decrease in filtration factor (D) Decrease in renal plasma flow

Description : An early feature of renal disease is (A) Impairment of the capacity of the tubule to perform osmotic work (B) Decrease in maximal tubular excretory capacity (C) Decrease in filtration factor (D) Decrease in renal plasma flow

Last Answer : A

Measurement of insulin clearance test is a measure of (A) Glomerular filtration rate (B) Filtration factor (C) Renal plasma flow (D) Tubular secretory mass

Description : Measurement of insulin clearance test is a measure of (A) Glomerular filtration rate (B) Filtration factor (C) Renal plasma flow (D) Tubular secretory mass

Last Answer : Answer : A

Addis test is the measure of (A) Impairment of the capacity of the tubule to perform osmotic work (B) Secretory function of liver (C) Excretory function of liver (D) Activity of parenchymal cells of liver

Description : Addis test is the measure of (A) Impairment of the capacity of the tubule to perform osmotic work (B) Secretory function of liver (C) Excretory function of liver (D) Activity of parenchymal cells of liver

Last Answer : A

Inulin clearance is a measure of (A) Glomerular filtration rate (B) Tubular secretion flow (C) Tubular reabsorption rate (D) Renal plasma flow

Description : Inulin clearance is a measure of (A) Glomerular filtration rate (B) Tubular secretion flow (C) Tubular reabsorption rate (D) Renal plasma flow

Last Answer : Answer : B

Creatinine EDTA clearance is a test to measure (A) Renal plasma flow (B) Filtration fraction (C) Glomerular filtration rate (D) Tubular function

Description : Creatinine EDTA clearance is a test to measure (A) Renal plasma flow (B) Filtration fraction (C) Glomerular filtration rate (D) Tubular function

Last Answer : Answer : C

Urea clearance test is used to determine the (A) Glomerular filtration rate (B) Renal plasma flow (C) Ability of kidney to concentrate the urine (D) Measurement of tubular mass

Description : Urea clearance test is used to determine the (A) Glomerular filtration rate (B) Renal plasma flow (C) Ability of kidney to concentrate the urine (D) Measurement of tubular mass

Last Answer : Answer : A

Para-amino hippurate excretion test is an indicator of (A) Glomerular filtration (B) Tubular secretion (C) Tubular reabsorption (D) Renal plasma flow

Description : Para-amino hippurate excretion test is an indicator of (A) Glomerular filtration (B) Tubular secretion (C) Tubular reabsorption (D) Renal plasma flow

Last Answer : Answer : D

Phenolsulphonephthalein excretion test is an indicator of (A) Glomerular filtration (B) Tubular secretion (C) Tubular reabsorption (D) Renal blood low

Description : Phenolsulphonephthalein excretion test is an indicator of (A) Glomerular filtration (B) Tubular secretion (C) Tubular reabsorption (D) Renal blood low

Last Answer : Answer : D

If a drug undergoes net tubular secretion, its renal clearance will be: A. More than the glomerular filtration rate B. Equal to the glomerular filtration rate C. Less than the glomerular filtration rate D. Equal to the rate of urine formation

Description : If a drug undergoes net tubular secretion, its renal clearance will be: A. More than the glomerular filtration rate B. Equal to the glomerular filtration rate C. Less than the glomerular filtration rate D. Equal to the rate of urine formation

Last Answer : A. More than the glomerular filtration rate

If a drug undergoes net tubular secretion, its renal clearance will be: A. More than the glomerular filtration rate B. Equal to the glomerular filtration rate C. Less than the glomerular filtration rate D. Equal to the rate of urine formation

Description : If a drug undergoes net tubular secretion, its renal clearance will be: A. More than the glomerular filtration rate B. Equal to the glomerular filtration rate C. Less than the glomerular filtration rate D. Equal to the rate of urine formation

Last Answer : A. More than the glomerular filtration rate

Which one of the following correctly explains the function of a specific part of the human nephron? (a) Podocytes : create minute spaces (slit pores) for the filtration of blood into the Bowman’s capsule (b) Henle’s loop : most reabsorption of the major substances from the glomerular filtrate (c) Distal convoluted tubule : reabsorption of K+ ions into the surrounding blood capillaries (d) Afferent arteriole : carries the blood away from the glomerulus towards renal vein.

Description : Which one of the following correctly explains the function of a specific part of the human nephron? (a) Podocytes : create minute spaces (slit pores) for the filtration of blood into the ... blood capillaries (d) Afferent arteriole : carries the blood away from the glomerulus towards renal vein.

Last Answer : (a) Podocytes : create minute spaces (slit pores) for the filtration of blood into the Bowman’s capsule

The maximal renal tubular reabsorptive capacity for calcium (Tmca) in mg/min is about (A) 1.5 ± 0.1 (B) 4.99 ± 0.21 (C) 5.5 ± 1.2 (D) 10.2 ± 2.2

Description : The maximal renal tubular reabsorptive capacity for calcium (Tmca) in mg/min is about (A) 1.5 ± 0.1 (B) 4.99 ± 0.21 (C) 5.5 ± 1.2 (D) 10.2 ± 2.2

Last Answer : Answer : B

The plasma half life of pencillin-G is longer in the new born because their (a) Plasma protein level is low (b) Drug metabolizing enzymes are immature (c) Glomerular filtration rate is low (d) Tubular transport mechanisms are not well developed

Description : The plasma half life of pencillin-G is longer in the new born because their (a) Plasma protein level is low (b) Drug metabolizing enzymes are immature (c) Glomerular filtration rate is low (d) Tubular transport mechanisms are not well developed

Last Answer : Ans: D

The plasma half life of penicillin-G is longer in the new born because their: A. Plasma protein level is low B. Drug metabolizing enzymes are immature C. Glomerular filtration rate is low D. Tubular transport mechanisms are not well developed

Description : The plasma half life of penicillin-G is longer in the new born because their: A. Plasma protein level is low B. Drug metabolizing enzymes are immature C. Glomerular filtration rate is low D. Tubular transport mechanisms are not well developed

Last Answer : D. Tubular transport mechanisms are not well developed

Glomerular filtration of a drug is affected by its: A. Lipid solubility B. Plasma protein binding C. Degree of ionization D. Rate of tubular secretion

Description : Glomerular filtration of a drug is affected by its: A. Lipid solubility B. Plasma protein binding C. Degree of ionization D. Rate of tubular secretion

Last Answer : B. Plasma protein binding

The plasma half life of penicillin-G is longer in the new born because their: A. Plasma protein level is low B. Drug metabolizing enzymes are immature C. Glomerular filtration rate is low D. Tubular transport mechanisms are not well developed

Description : The plasma half life of penicillin-G is longer in the new born because their: A. Plasma protein level is low B. Drug metabolizing enzymes are immature C. Glomerular filtration rate is low D. Tubular transport mechanisms are not well developed

Last Answer : D. Tubular transport mechanisms are not well developed

Glomerular filtration of a drug is affected by its: A. Lipid solubility B. Plasma protein binding C. Degree of ionization D. Rate of tubular secretion

Description : Glomerular filtration of a drug is affected by its: A. Lipid solubility B. Plasma protein binding C. Degree of ionization D. Rate of tubular secretion

Last Answer : B. Plasma protein binding

The most important channel of elimination of digoxin is: A. Glomerular filtration B. Tubular secretion C. Hepatic metabolism D. Excretion in bile

Description : The most important channel of elimination of digoxin is: A. Glomerular filtration B. Tubular secretion C. Hepatic metabolism D. Excretion in bile

Last Answer : A. Glomerular filtration

Interindividual variations in equieffective doses of a drug are most marked if it is disposed by: A. Glomerular filtration B. Tubular secretion C. Both glomerular filtration and tubular secretion D. Hepatic metabolism

Description : Interindividual variations in equieffective doses of a drug are most marked if it is disposed by: A. Glomerular filtration B. Tubular secretion C. Both glomerular filtration and tubular secretion D. Hepatic metabolism

Last Answer : D. Hepatic metabolism

Interindividual variations in equieffective doses of a drug are most marked if it is disposed by: A. Glomerular filtration B. Tubular secretion C. Both glomerular filtration and tubular secretion D. Hepatic metabolism

Description : Interindividual variations in equieffective doses of a drug are most marked if it is disposed by: A. Glomerular filtration B. Tubular secretion C. Both glomerular filtration and tubular secretion D. Hepatic metabolism

Last Answer : D. Hepatic metabolism

Excretion of phenolsulphanpthalein (PSP) reflects (A) Glomerulonephritis (B) Maximaltabular excretory capacity (C) Filtration factor (D) Renal plasma flow

Description : Excretion of phenolsulphanpthalein (PSP) reflects (A) Glomerulonephritis (B) Maximaltabular excretory capacity (C) Filtration factor (D) Renal plasma flow

Last Answer : Answer : B

Measurement of inulin renal clearance is a measure for (A) Effective renal blood flow (B) Renal drug excretion rate (C) Active renal secretion (D) Glomerular filtration rate

Description : Measurement of inulin renal clearance is a measure for (A) Effective renal blood flow (B) Renal drug excretion rate (C) Active renal secretion (D) Glomerular filtration rate

Last Answer : (D) Glomerular filtration rate

The normal Tm in mg/min/1.73 sqm for PAH is (A) 20 (B) 40 (C) 60 (D) 80

Description : The normal Tm in mg/min/1.73 sqm for PAH is (A) 20 (B) 40 (C) 60 (D) 80

Last Answer : Answer : D

Which of the following is true concerning a 68 year old male with type 2 diabetes diagnosed with type IV renal tubal acidosis? 1) Aminoaciduria would be expected. 2) Fludrocortisone treatment is effective 3) Increased Glomerular filtration rate is expected. 4) Increased urinary bicarbonate would be expected. 5) Normal renal handling of K+ and H+

Description : Which of the following is true concerning a 68 year old male with type 2 diabetes diagnosed with type IV renal tubal acidosis? 1) Aminoaciduria would be expected. 2) Fludrocortisone treatment is effective ... 4) Increased urinary bicarbonate would be expected. 5) Normal renal handling of K+ and H+

Last Answer : Answers-2 H+ secretion, sodium reabsorption and ammonia production diminishes. RTA 4 is in effect hyporeninaemic hypoaldosteronism or failure of aldosterone action and thus helped treated with ... particularly. Aminoaciduria and increased urine bicarbonate are features of RTA types 1 and 2.

Among the following, a test of Glomerular function is (A) Urea clearance (B) PSP excretion test (C) PAH clearance (D) Hippuric acid excretion test

Description : Among the following, a test of Glomerular function is (A) Urea clearance (B) PSP excretion test (C) PAH clearance (D) Hippuric acid excretion test

Last Answer : Answer : D

The pharmacokinetics of drugs in the neonate differs from that in adults, because their: A. Intestinal transit is fast B. Drug metabolizing enzymes are overactive C. Tubular transport mechanisms are not well developed D. Glomerular filtration rate is high

Description : The pharmacokinetics of drugs in the neonate differs from that in adults, because their: A. Intestinal transit is fast B. Drug metabolizing enzymes are overactive C. Tubular transport mechanisms are not well developed D. Glomerular filtration rate is high

Last Answer : C. Tubular transport mechanisms are not well developed

The pharmacokinetics of drugs in the neonate differs from that in adults, because their: A. Intestinal transit is fast B. Drug metabolizing enzymes are overactive C. Tubular transport mechanisms are not well developed D. Glomerular filtration rate is high

Description : The pharmacokinetics of drugs in the neonate differs from that in adults, because their: A. Intestinal transit is fast B. Drug metabolizing enzymes are overactive C. Tubular transport mechanisms are not well developed D. Glomerular filtration rate is high

Last Answer : C. Tubular transport mechanisms are not well developed

Which one of the following statements in regard to the excretion by the human kidneys is correct? (a) Descending limb of loop of Henle is impermeable to water.(b) Distal convoluted tubule is incapable of reabsorbing HCO3 – . (c) Nearly 99 per cent of the glomerular filtrate is reabsorbed by the renal tubules. (d) Ascending limb of loop of Henle is impermeable to electrolytes.

Description : Which one of the following statements in regard to the excretion by the human kidneys is correct? (a) Descending limb of loop of Henle is impermeable to water. (b) Distal convoluted tubule is ... reabsorbed by the renal tubules. (d) Ascending limb of loop of Henle is impermeable to electrolytes.

Last Answer : (c) Nearly 99 per cent of the glomerular filtrate is reabsorbed by the renal tubules.

09. The reasons determing bioavailability are: a) Rheological parameters of blood b) Amount of a substance obtained orally and quantity of intakes c) Extent of absorption and hepatic first-pass effect d) Glomerular filtration rate

Description : 09. The reasons determing bioavailability are: a) Rheological parameters of blood b) Amount of a substance obtained orally and quantity of intakes c) Extent of absorption and hepatic first-pass effect d) Glomerular filtration rate

Last Answer : C

Renal glycosuria occurs due to (A) Increased filtration of glucose in glomeruli (B) Increased secretion of glucose by renal tubular cells (C) Decreased reabsorption of glucose by renal tubular cells (D) Increased conversion of glycogen into glucose in tubular cells

Description : Renal glycosuria occurs due to (A) Increased filtration of glucose in glomeruli (B) Increased secretion of glucose by renal tubular cells (C) Decreased reabsorption of glucose by renal tubular cells (D) Increased conversion of glycogen into glucose in tubular cells

Last Answer : Answer : D

In studies of the human body, which of the following terms is used to describe the first step in the production of urine? Is it: a) tubular secretion b) tubular reabsorption c) glomerular filtration d) none of these

Description : In studies of the human body, which of the following terms is used to describe the first step in the production of urine? Is it: a) tubular secretion b) tubular reabsorption c) glomerular filtration d) none of these

Last Answer : ANSWER: C -- GLOMERULAR FILTRATION

Among the following, a test of tubular function is (A) Creatinine clearance (B) Inulin clearance (C) PAH clearance (D) PSP excretion test

Description : Among the following, a test of tubular function is (A) Creatinine clearance (B) Inulin clearance (C) PAH clearance (D) PSP excretion test

Last Answer : Answer : D

Full activation of the sympathetic nervous system, as in maximal exercise, can produce all of the following responses except (a) Bronchial relaxation (b) Decreases intestinal motility (c) Increased renal blood flow (d) Mydriasis (e) Increased heart rate (tachycardia)

Description : Full activation of the sympathetic nervous system, as in maximal exercise, can produce all of the following responses except (a) Bronchial relaxation (b) Decreases intestinal motility (c) Increased renal blood flow (d) Mydriasis (e) Increased heart rate (tachycardia)

Last Answer : Ans: C

All of the following substances have been used to estimate GFR except (A) Inulin (B) Creatinine (C) Phenol red (D) Mannitol FATS AND FATTY ACID METABOLISM 105

Description : All of the following substances have been used to estimate GFR except (A) Inulin (B) Creatinine (C) Phenol red (D) Mannitol FATS AND FATTY ACID METABOLISM 105

Last Answer : Answer : C

During each cycle of on going fatty acid oxidation, all the following compounds are generated except (A) H2O (B) Acetyl CoA (C) Fatty acyl CoA (D) NADH FATS AND FATTY ACID METABOLISM 103

Description : During each cycle of on going fatty acid oxidation, all the following compounds are generated except (A) H2O (B) Acetyl CoA (C) Fatty acyl CoA (D) NADH FATS AND FATTY ACID METABOLISM 103

Last Answer : Answer : A

The major source of cholesterol in arterial smooth muscle cells is from (A) IDL (B) LDL (C) HDL (D) Chylomicrons FATS AND FATTY ACID METABOLISM 101

Description : The major source of cholesterol in arterial smooth muscle cells is from (A) IDL (B) LDL (C) HDL (D) Chylomicrons FATS AND FATTY ACID METABOLISM 101

Last Answer : Answer : B

Cholesterol is excreted as such into ________. (A) Urine (B) Faeces (C) Bile (D) Tears FATS AND FATTY ACID METABOLISM 99

Description : Cholesterol is excreted as such into ________. (A) Urine (B) Faeces (C) Bile (D) Tears FATS AND FATTY ACID METABOLISM 99

Last Answer : Answer : C

Rancidity of butter is prevented by the addition of (A) Vitamin D (B) Tocopherols (C) Presence of priotin (D) Presence of ‘Cu’ FATS AND FATTY ACID METABOLISM 97

Description : Rancidity of butter is prevented by the addition of (A) Vitamin D (B) Tocopherols (C) Presence of priotin (D) Presence of ‘Cu’ FATS AND FATTY ACID METABOLISM 97

Last Answer : Answer : B

All active prostaglandins have atleast one double bond between positions: (A) 7 and 8 (B) 9 and 10 (C) 11 and 12 (D) 13 and 14 FATS AND FATTY ACID METABOLISM 95

Description : All active prostaglandins have atleast one double bond between positions: (A) 7 and 8 (B) 9 and 10 (C) 11 and 12 (D) 13 and 14 FATS AND FATTY ACID METABOLISM 95

Last Answer : Answer : A

Instead of ester link plasmalogens possess an other link in position: (A) α (B) β (C) γ (D) None of these FATS AND FATTY ACID METABOLISM 93

Description : Instead of ester link plasmalogens possess an other link in position: (A) α (B) β (C) γ (D) None of these FATS AND FATTY ACID METABOLISM 93

Last Answer : Answer : B

In haemolytic jaundice, urine shows (A) Absence of bile pigments and urobilinogen (B) Presence of bile pigments and urobilinogen (C) Absence of bile pigments and presence of urobilinogen (D) Presence of bile pigments and absence of urobilinogen FATS AND FATTY ACID METABOLISM 91

Description : In haemolytic jaundice, urine shows (A) Absence of bile pigments and urobilinogen (B) Presence of bile pigments and urobilinogen (C) Absence of bile pigments and presence of urobilinogen (D) Presence of bile pigments and absence of urobilinogen FATS AND FATTY ACID METABOLISM 91

Last Answer : Answer : C

Hypocholesterolaemia can occur in (A) Hyperthyroidism (B) Nephrotic syndrome (C) Obstructive jaundice (D) Diabetes mellitus FATS AND FATTY ACID METABOLISM 89

Description : Hypocholesterolaemia can occur in (A) Hyperthyroidism (B) Nephrotic syndrome (C) Obstructive jaundice (D) Diabetes mellitus FATS AND FATTY ACID METABOLISM 89

Last Answer : Answer : A

One functional sub-unit of multi-enzyme complex for de novo synthesis of fatty acids contains (A) One —SH group (B) Two —SH groups (C) Three —SH groups (D) Four —SH groups FATS AND FATTY ACID METABOLISM 87

Description : One functional sub-unit of multi-enzyme complex for de novo synthesis of fatty acids contains (A) One —SH group (B) Two —SH groups (C) Three —SH groups (D) Four —SH groups FATS AND FATTY ACID METABOLISM 87

Last Answer : Answer : B

Glycerol released from adipose tissue by hydrolysis of triglycerides is mainly (A) Taken up by liver (B) Taken up by extrahepatic tissues (C) Reutilised in adipose tissue (D) Excreted from the body FATS AND FATTY ACID METABOLISM 85

Description : Glycerol released from adipose tissue by hydrolysis of triglycerides is mainly (A) Taken up by liver (B) Taken up by extrahepatic tissues (C) Reutilised in adipose tissue (D) Excreted from the body FATS AND FATTY ACID METABOLISM 85

Last Answer : Answer : A

Propionyl CoA is formed on oxidation of (A) Monounsaturated fatty acids (B) Polyunsaturated fatty acids (C) Fatty acids with odd number of carbon atoms (D) None of these FATS AND FATTY ACID METABOLISM 83

Description : Propionyl CoA is formed on oxidation of (A) Monounsaturated fatty acids (B) Polyunsaturated fatty acids (C) Fatty acids with odd number of carbon atoms (D) None of these FATS AND FATTY ACID METABOLISM 83

Last Answer : Answer : C

Normal quantity of urobilinogen excreted in the feces per day is about (A) 10–25 mg (B) 50–250 mg (C) 300–500 mg (D) 700–800 mg FATS AND FATTY ACID METABOLISM 79

Description : Normal quantity of urobilinogen excreted in the feces per day is about (A) 10–25 mg (B) 50–250 mg (C) 300–500 mg (D) 700–800 mg FATS AND FATTY ACID METABOLISM 79

Last Answer : Answer : B

Ochronosis is an important finding of (A) Tyrosinemia (B) Tyrosinosis (C) Alkaptonuria (D) Richner Hanhart syndrome FATS AND FATTY ACID METABOLISM 77

Description : Ochronosis is an important finding of (A) Tyrosinemia (B) Tyrosinosis (C) Alkaptonuria (D) Richner Hanhart syndrome FATS AND FATTY ACID METABOLISM 77

Last Answer : Answer : C

Palmitic, oleic or stearic acid ester of cholesterol used in manufacture of cosmetic creams is (A) Elaidic oil (B) Lanoline (C) Spermaceti (D) Chaulmoogric oil FATS AND FATTY ACID METABOLISM 75

Description : Palmitic, oleic or stearic acid ester of cholesterol used in manufacture of cosmetic creams is (A) Elaidic oil (B) Lanoline (C) Spermaceti (D) Chaulmoogric oil FATS AND FATTY ACID METABOLISM 75

Last Answer : Answer : B

Filtration fraction can be calculated from (A) Standard urea clearance and PSP excretion (B) Maximum urea clearance and PSP excretion (C) Maximum urea clearance and PAH clearance (D) Inulin clearance and PAH clearance

Description : Filtration fraction can be calculated from (A) Standard urea clearance and PSP excretion (B) Maximum urea clearance and PSP excretion (C) Maximum urea clearance and PAH clearance (D) Inulin clearance and PAH clearance

Last Answer : Answer : A