Description : If The exact area of a circle is 81pi square inches what are the radius and diameter of the circle explain?
Last Answer : The radius is 9 inches because area of circle is pi*9 squared =81pi square inches and the diameter is twice the radius which is2*9 = 18 inches
Description : What is the circumstances of a circle with a radius of 9.7 inches Use 3.14 for pi?
Last Answer : I assume you mean "circumference".The circumference of a circle with a radius of 9.7 inches is 60.95 inches.Circumference = 2 * pi * radius-or-2 * 3.14 * 9.7 = 60.95
Description : A chord of a circle of radius 20 cm subtends an angle of 90° at the centre. Find the area of the corresponding major segment of the circle. -Maths 10th
Last Answer : Area of the minor segment = { pi × 90 /360 - sin 45 × cos 45 } × r × r ={ 3.14 ×1/4 - 1÷√2 ×1÷√2 } × 20 × 20 = { 3.14 ... Area of major segment = area of circle - area of minor segment = 1256 - 114 = 1142 HOPE IT HELPS YOU
Description : What is the area of a circle with a diameter of 49 inches?
Last Answer : Using 3.14 as Pi the area of circle is: 1884.785
Description : An isosceles triangle of vertical angle `2theta` is inscribed in a circle of radius `a` . Show that the area of the triangle is maximum when `theta=pi
Last Answer : An isosceles triangle of vertical angle `2theta` is inscribed in a circle of radius `a` . Show that the area of ... pi/4` C. `pi/6` D. None of these.
Description : (i) The radius of a circle is increasing at the rate of 5 cm/sec. Find the rate of increasing of its perimeter. (ii) If the area of a circle increases
Last Answer : (i) The radius of a circle is increasing at the rate of 5 cm/sec. Find the rate ... to its circumference is iversely proportional to its radius.
Description : The area of a circle (A) varies directly as the square of its radius. The area of the circle of radius 7 cm is 154 `cm^(2)`. What is the area of the c
Last Answer : The area of a circle (A) varies directly as the square of its radius. The area of the circle of ... What is the area of the circle of radius 35 cm?
Description : A is the area of a circle with radius r units. Write the formula of area, making r as the subject.
Last Answer : A is the area of a circle with radius r units. Write the formula of area, making r as the subject.
Description : If the radius of a circle that is 5 what is the area?
Last Answer : It is 78.5 square units.
Description : What is a polynomial for the area of a circle with radius(x plus 2) feet?
Last Answer : A = pi()*(x2 + 4x +4) square feet.
Description : What is The area of a circle depending on the radius. Use the equation A(r) r2 to compute A(7). Round your answer to the nearest hundredth.?
Last Answer : The area of a circle is: pi times radius squared
Description : What is the area in feet of a circle with a radius of 9?
Last Answer : Area of circle: pi times 9 squared = 254.469 square feet roundedto 3 decimal places
Description : What is the area of a circle radius equal to 2?
Last Answer : Using 3.14 as Pi the area of circle is: 12.56
Description : What is the area of a circle with a radius of 4mm use 3.14 for pi?
Last Answer : A)12.56mm2 B)25.12mm2 C)50.24mm2 D)502.4mm2
Description : What is the area of a circle if the radius is 15.35 in?
Last Answer : Using 3.14 as Pi the area of circle is: 739.85465
Description : What is the area of a circle when the radius is 5.5 cm?
Last Answer : Using 3.14 as Pi the area of circle is: 94.985
Description : If the radius of a circle is doubled, what about its area?(a) Area is 2 times (b) Area is 4 times (c) Area is half (d) does not change
Last Answer : (b) Area is 4 times
Description : What is the area of the corresponding major sector of a circle of radius 28 cm and the central angle 45 o ? (a) 4312 cm 2 (b) 2156 cm 2 (c) 1256 cm 2 (d) 3412 cm 2
Last Answer : (b) 2156 cm 2
Description : In a circle of radius 14 cm, an arc subtends an angle of 45 O at the centre, then the area of the sector is (a) 71 cm 2(b) 76 cm 2 (c) 77 cm 2 (d) 154 cm 2
Last Answer : (c) 77 cm 2
Description : What is the radius of the circle/ I.Ratio of its area to circumference is >7. II.Diameter of the circle is ≤ 32. If the question can be answered with the help of statement I alone, If ... the statements. If the data in either statement I or statement II alone is sufficient to answer the question.
Last Answer : Let the radius of the circle be r units From statement 1: [πr^2]/ [ 2 πr ] > 7 or r > 14 From statement II: 2r≤32 R ≤ 16 Hence, r can be 15 or 16 units Hence, Answer : d
Description : A wire can be bent to form a circle of radius 56 cm. if it is instead bent in the form of a square, then its area will be: a) 6400 sq.cm b) 2025 sq.cm c) 7744 sq.cm d) 6561 sq.cm e) none of these
Last Answer : Length of the wire = circumference of the circle 2 × (22/7) × 56 = 2 × 22 × 8 = 352 cm side of square = 352/4 = 88cm area of square = 88 × 88 = 7744 sq.cm Answer: c)
Description : Area of a rectangle is equal to the area of circle whose radius is 14 cms. If the breadth of the rectangle is 22 cms. What is its length? a) 27 cms b) 28 cms c) 25 cms. d) 29 cms e) None of these
Last Answer : According to question, l×b = ¶r2 l ×22 = 22/7 ×14 × 14 l = 22/7 ×14 × 14/22 cms = 28 cms. Answer: b)
Description : Write a C++ program to declare a class ‘circle’ with data members as radius and area. Declare a function getdata to accept radius and putdata to calculate and display area of circle.
Last Answer : #include<iostream.h> #include<conio.h> class circle { float radius,area; public: void getdata() { cout<<"Enter radius:"; cin>>radius; } void putdata() { area=3 ... { circle c; clrscr(); c.getdata(); c.putdata(); getch(); }
Description : Define a class circle having data members pi and radius. Initialize and display values of data members also calculate area of circle and display it.
Last Answer : class abc { float pi,radius; abc(float p, float r) { pi=p; radius=r; } void area() { float ar=pi*radius*radius; System.out.println("Area="+ar); } void display() { System.out.println("Pi="+pi ... void main(String args[]) { abc a=new abc(3.14f,5.0f); a.display(); a.area(); } }
Description : If the radius of a circle is increased by 50 per cent. Its area is increased by: (A) 125 per cent (B) 100 per cent (C) 75 per cent (D) 50 per cent
Last Answer : Answer: A Area of circle = pie * Radius *Radius. Suppose radius is 100 Hence Area= 3.14 *100 *100 =31400 Radius increase by 50% i.e 150 Therefore Area = 3.14 *150 *150 =70650 which is 125 % of original
Description : A screw jack has 4 threads per inch. The mean radius of the thread is 2.338 inches. The mean diameter of the bearing surface under the cap is 3.25 inches. What is the turning moment required to raise the bload of 150 kg ( a.5.61 kg-inch b.50.6 kg-inch c.107 dynes d.30.3 kg-inch e.23.6 kg-inch
Last Answer : b. 50.6 kg-inch
Description : What is the volume of this shere that has a radius of 6 inches?
Last Answer : Volume of sphere: 4/3 times pi times 6 cubed = 288*pi cubicinches
Description : Hydraulic radius of 6" × 12" cross-section, is __________ inches. (A) 2 (B) 0.5 (C) 1.5 (D) None of these
Last Answer : (A) 2
Description : How many square inches in a 8 inch circle?
Last Answer : That depends on what the 8 inches represents but the area of acircle is pi*radius^2
Description : How many square inches in a 8 inch diameter circle?
Last Answer : Area = pi*42 = 50.265 square inches to 3 decimal places
Description : If you have a circle 2 inches across how many square inches is that?
Last Answer : 3.141 square inches
Description : For Q 51, find radius of circle a.3 b.3.6 c.4 d.3.5
Last Answer : b.3.6
Description : A circle is represented by center point [5,5] and radius 6 units. Find the parametricequation of circle and determine the various points on circle in first quadrant if increment in angle by 45o a.9.24,9.24 b.9.42,9.42 c.9,9 d.11,5
Last Answer : a.9.24,9.24
Description : The moment of inertia of a semi-circle of radius r with respect to a centroidal axis parallel to the diameter is a.0.33 r2 b.0.11 r2 c.0.055 r2 d.0.05 r2 e.0.22 r2
Last Answer : b. 0.11 r2
Description : The satellite moves in a circle around the earth. The radius of this circle is equal to one-half the radius of the moons orbit. The satellite will complete one revolution in a.1 lunar month b.2-3/4 lunar month c.2-2/3 lunar month d.None of the above e.
Last Answer : e. None of the above
Description : A chord of a circle of radius 7.5 cm with centre 0 is of length 9 cm. Find its distance from the centre. -Maths 9th
Last Answer : ∵ PM = MQ = 1/2 = PQ = 45 cm and OP = 7.5 cm In right angled ΔOMP, using phthagoras theorem OM2 = OP2 - PM2 ⇒OM2 = 7.52 - 4.52 ⇒OM2 = 56.25 - 20.25 ⇒OM2 = 36 ∴ OM = √36 = 6 cm
Description : The given figure shows a circle with centre O in which a diameter AB bisects the chord PQ at the point R. If PR = RQ = 8 cm and RB = 4 cm, then find the radius of the circle. -Maths 9th
Last Answer : Let r be the radius, then OQ = OB = r and OR = (r - 4) ∴ OQ2 = OR2 + RO2 ⇒ r2 = 64 + (r-4)2 ⇒ r2 = 64 + r2 + 16 - 8r ⇒ 8r = 80 ⇒ r = 10 cm
Description : If AB = 12 cm, BC = 16 cm and AB is perpendicular to BC, then the radius of the circle passing through the points A, B and C is -Maths 9th
Last Answer : According to question the radius of the circle passing through the points A, B and C .
Description : A chord of a circle is equal to its radius. Find the angle subtended by this chord at a point in major segment. -Maths 9th
Last Answer : Given, AB is a chord of a circle, which is equal to the radius of the circle, i.e., AB = BO …(i) Join OA, AC and BC. Since, OA = OB= Radius of circle OA = AS = BO
Description : AB and AC are two chords of a circle of radius r such that AB = 2AC. -Maths 9th
Last Answer : According to question 4q 2 = p 2+ 3r 2.
Description : Find the equation of the circle which touches the both axes in first quadrant and whose radius is a. -Maths 9th
Last Answer : circle of radius a touches both axis in 1st quadrant so its centre will be (a,a). ∴ Required equation ⇒(x−a)2+(y−a)2=a2 ⇒x2+a2−2ax+y2+a2−2ay=a2 ⇒x2+y2−2ax−2ay+2a2−a2=0 ⇒x2−y2−2ax−2ay+a2=0.
Last Answer : Given that the circle of radius ‘a’ touches both axis. So, its centre is (a, a) So, the equation of required circles is : (x-a)2 + (y-a)2 = a2 ⇒ x2 - 2ax + a2+y2 - 2ay + a2 = a2 ⇒ x2 + y2 - 2ax - 2ay + a2 = 0