Consider a uniprocessor system where new processes arrive at an average of five processes per minute and each process needs an average of 6 seconds of service time. What will be the CPU utilization ? (A) 80 % (B) 50 % (C) 60 % (D) 30 %

Consider a uniprocessor system where new processes arrive at an average of five processes per minute and each process needs an average of 6 seconds of service time. What will be the CPU utilization ? (A) 80 % (B) 50 % (C) 60 % (D) 30 %
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(B) 50 %
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Consider three CPU intensive processes P1, P2, P3 which require 20, 10 and 30 units of time, arrive at times 1, 3 and 7 respectively. Suppose operating system is implementing Shortest Remaining Time first (preemptive scheduling) algorithm, then .............. context switches are required (suppose context switch at the beginning of Ready queue and at the end of Ready queue are not counted). (A) 3 (B) 2 (C) 4 (D) 5

Description : Consider three CPU intensive processes P1, P2, P3 which require 20, 10 and 30 units of time, arrive at times 1, 3 and 7 respectively. Suppose operating system is implementing Shortest Remaining Time first (preemptive scheduling) ... end of Ready queue are not counted). (A) 3 (B) 2 (C) 4 (D) 5

Last Answer : (A) 3

Consider a fuzzy set old as defined below Old = {(20, 0.1), (30, 0.2), (40, 0.4), (50, 0.6), (60, 0.8), (70, 1), (80, 1)} Then the alpha-cut for alpha = 0.4 for the set old will be (A) {(40, 0.4)} (B) {50, 60, 70, 80} (C) {(20, 0.1), (30, 0.2)} (D) {(20, 0), (30, 0), (40, 1), (50, 1), (60, 1), (70, 1), (80, 1)}

Description : Consider a fuzzy set old as defined below Old = {(20, 0.1), (30, 0.2), (40, 0.4), (50, 0.6), (60, 0.8), (70, 1), (80, 1)} Then the alpha-cut for alpha = 0.4 for the set old will be (A) {(40, 0.4)} (B) {50, 60, ... , (30, 0.2)} (D) {(20, 0), (30, 0), (40, 1), (50, 1), (60, 1), (70, 1), (80, 1)}

Last Answer : (D) {(20, 0), (30, 0), (40, 1), (50, 1), (60, 1), (70, 1), (80, 1)}

Assume that we need to download text documents at the rate of 100 pages per minute. A page is an average of 24 lines with 80 characters in each line and each character requires 8 bits. Then the required bit rate of the channel is ................ (A) 1.636 Kbps (B) 1.636 Mbps (C) 2.272 Mbps (D) 3.272 Kbps

Description : Assume that we need to download text documents at the rate of 100 pages per minute. A page is an average of 24 lines with 80 characters in each line and each character requires 8 bits. Then the required bit rate of the channel is ... ...... (A) 1.636 Kbps (B) 1.636 Mbps (C) 2.272 Mbps (D) 3.272 Kbps

Last Answer : Answer: Marks given to all

A software project was estimated at 352 Function Points (FP). A four person team will be assigned to this project consisting of an architect, two programmers, and a tester. The salary of the architect is Rs.80,000 per month, the programmer Rs.60,000 per month and the tester Rs.50,000 per month. The average productivity for the team is 8 FP per person month. Which of the following represents the projected cost of the project? (1) Rs.28,16,000 (2) Rs.20,90,000 (3) Rs.26,95,000 (4) Rs.27,50,000

Description : A software project was estimated at 352 Function Points (FP). A four person team will be assigned to this project consisting of an architect, two programmers, and a tester. The salary of the architect is Rs.80,000 per month, the ... ) Rs.28,16,000 (2) Rs.20,90,000 (3) Rs.26,95,000 (4) Rs.27,50,000

Last Answer : (4) Rs.27,50,000 

A network with bandwidth of 10 Mbps can pass only an average of 15,000 frames per minute with each frame carrying an average of 8,000 bits. What is the throughput of this network ? (A) 2 Mbps (B) 60 Mbps (C) 120 Mbps (D) 10 Mbps

Description : A network with bandwidth of 10 Mbps can pass only an average of 15,000 frames per minute with each frame carrying an average of 8,000 bits. What is the throughput of this network ? (A) 2 Mbps (B) 60 Mbps (C) 120 Mbps (D) 10 Mbps

Last Answer : (A) 2 Mbps Explanation: In data transmission, throughput is the amount of data moved successfully from one place to another in a given period of time, and typically measured in bits per second (bps), ... second (Mbps) or gigabits per second (Gbps). Here, Throughput = 15000 x 8000/60 = 2 Mbps 

Suppose that the number of instructions executed between page faults is directly proportional to the number of page frames allocated to a program. If the available memory is doubled, the mean interval between page faults is also doubled. Further, consider that a normal instruction takes one micro second, but if a page fault occurs, it takes 2001 micro seconds. If a program takes 60 sec to run, during which time it gets 15000 page faults, how long would it take to run if twice as much memory were available? (A) 60 sec (B) 30 sec (C) 45 sec (D) 10 sec

Description : Suppose that the number of instructions executed between page faults is directly proportional to the number of page frames allocated to a program. If the available memory is doubled, the mean interval between page faults is also ... memory were available? (A) 60 sec (B) 30 sec (C) 45 sec (D) 10 sec

Last Answer : Answer: C Explanation: T = Ninstr x 1µs + 15,000 x 2,000 µs = 60s Ninstr x 1µs = 60,000,000 µs - 30,000,000 µs = 30,000,000 µs Ninstr = 30,000,000 The number of instruction ... doesn't mean that the program runs twice as fast as on the first system. Here, the performance increase is of 25%.

Some of the criteria for calculation of priority of a process are: a. Processor utilization by an individual process. b. Weight assigned to a user or group of users. c. Processor utilization by a user or group of processes. In fair share scheduler, priority is calculated based on: (1) only (a) and (b) (2) only (a) and (c) (3) (a), (b) and (c) (4) only (b) and (c)

Description : Some of the criteria for calculation of priority of a process are: a. Processor utilization by an individual process. b. Weight assigned to a user or group of users. c. Processor utilization by a user or group of processes. In fair share ... (a) and (c) (3) (a), (b) and (c) (4) only (b) and (c)

Last Answer : (3) (a), (b) and (c)

Consider a system with twelve magnetic tape drives and three processes P1, P2 and P3. Process P1 requires maximum ten tape drives, process P2 may need as many as four tape drives and P3 may need upto nine tape drives. Suppose that at time t1, process P1 is holding five tape drives, process P2 is holding two tape drives and process P3 is holding three tape drives. At time t1, system is in: (A) safe state (B) unsafe state (C) deadlocked state (D) starvation state

Description : Consider a system with twelve magnetic tape drives and three processes P1, P2 and P3. Process P1 requires maximum ten tape drives, process P2 may need as many as four tape drives and P3 may need upto nine ... , system is in: (A) safe state (B) unsafe state (C) deadlocked state (D) starvation state

Last Answer : Answer: B

Consider the following justifications for commonly using the two-level CPU scheduling : I. It is used when memory is too small to hold all the ready processes. II. Because its performance is same as that of the FIFO. III. Because it facilitates putting some set of processes into memory and a choice is made from that. IV. Because it does not allow to adjust the set of in-core processes. Which of the following is true ? (A) I, III and IV (B) I and II (C) III and IV (D) I and III

Description : Consider the following justifications for commonly using the two-level CPU scheduling : I. It is used when memory is too small to hold all the ready processes. II. Because its performance is same as that of the FIFO. III. Because it ... ? (A) I, III and IV (B) I and II (C) III and IV (D) I and III

Last Answer : (D) I and III

The percentage of alumina in a good brick earth lies between (A) 5 to 10 % (B) 20 to 30 % (C) 50 to 60 % (D) 70 to 80 %

Description : The percentage of alumina in a good brick earth lies between (A) 5 to 10 % (B) 20 to 30 % (C) 50 to 60 % (D) 70 to 80 %

Last Answer : Answer: Option B

Percentage of silica in a good brick earth lies between (A) 5 to 10 % (B) 20 to 30 % (C) 50 to 60 % (D) 70 to 80

Description : Percentage of silica in a good brick earth lies between (A) 5 to 10 % (B) 20 to 30 % (C) 50 to 60 % (D) 70 to 80

Last Answer : Answer: Option C

The conductivity of copper is less than that of silver by (A) 5 – 10 %. (B) 50 – 60 %. (C) 80 – 90 %. (D) 20 – 30 %.

Description : The conductivity of copper is less than that of silver by (A) 5 – 10 %. (B) 50 – 60 %. (C) 80 – 90 %. (D) 20 – 30 %.

Last Answer : (A) 5 – 10 %.

The heart rate in an adult person is – (1) 50-60 times per minute (2) 70-80 times per hour (3) 70-80 times per second (4) 70-80 times per minute

Description : The heart rate in an adult person is – (1) 50-60 times per minute (2) 70-80 times per hour (3) 70-80 times per second (4) 70-80 times per minute

Last Answer : (4) 70-80 times per minute Explanation: Heart rate refers to the speed of the heartbeat, specifically the number of heartbeats per unit of time. The heart rate is typically expressed as beats per minute ( ... heart rate ranges from 60- 100 bpm; however 70-80 bpm is treated as the normal in adults.

The heart rate in an adult person is (1) 50-60 times per minute (2) 70-80 times per hour (3) 70-80 times per second (4) 70-80 times per minute

Description : The heart rate in an adult person is (1) 50-60 times per minute (2) 70-80 times per hour (3) 70-80 times per second (4) 70-80 times per minute

Last Answer : 70-80 times per minute

A network with bandwidth of 10 Mbps can pass only an average of 12,000 frames per minute with each frame carrying an average of 10,000 bits. What is the throughput of this network ? (A) 1 Mbps (B) 2 Mbps (C) 10 Mbps (D) 12 Mbps

Description : A network with bandwidth of 10 Mbps can pass only an average of 12,000 frames per minute with each frame carrying an average of 10,000 bits. What is the throughput of this network ? (A) 1 Mbps (B) 2 Mbps (C) 10 Mbps (D) 12 Mbps

Last Answer : (B) 2 Mbps

The average heartbeat per minute in a normal man is -----? A. 50 B. 70 (Answer) C. 80 D. 100

Description : The average heartbeat per minute in a normal man is -----? A. 50 B. 70 (Answer) C. 80 D. 100

Last Answer : B. 70 (Answer)

The average heartbeat per minute in a normal man is A.50 B.70 C.80 D.100

Description : The average heartbeat per minute in a normal man is A.50 B.70 C.80 D.100

Last Answer : B.70

Consider a source with symbols A, B, C, D with probabilities 1/2, 1/4, 1/8, 1/8 respectively. What is the average number of bits per symbol for the Huffman code generated from above information? (A) 2 bits per symbol (B) 1.75 bits per symbol (C) 1.50 bits per symbol (D) 1.25 bits per symbol

Description : Consider a source with symbols A, B, C, D with probabilities 1/2, 1/4, 1/8, 1/8 respectively. What is the average number of bits per symbol for the Huffman code generated from above information? (A) 2 bits per symbol (B) 1.75 bits per symbol (C) 1.50 bits per symbol (D) 1.25 bits per symbol

Last Answer : (B) 1.75 bits per symbol

Consider a system with seven processes A through G and six resources R through W. Resource ownership is as follows: process A holds R and wants T process B holds nothing but wants T process C holds nothing but wants S process D holds U and wants S & T process E holds T and wants V process F holds W and wants S process G holds V and wants U Is the system deadlocked ? If yes, ............. processes are deadlocked. (A) No (B) Yes, A, B, C (C) Yes, D, E, G (D) Yes, A, B, F

Description : Consider a system with seven processes A through G and six resources R through W. Resource ownership is as follows: process A holds R and wants T process B holds nothing but wants T process C holds nothing but wants S process D holds U ... No (B) Yes, A, B, C (C) Yes, D, E, G (D) Yes, A, B, F

Last Answer : (C) Yes, D, E, G

A DMA controller transfers 32-bit words to memory using cycle Stealing. The words are assembled from a device that transmits characters at a rate of 4800 characters per second. The CPU is fetching and executing instructions at an average rate of one million instructions per second. By how much will the CPU be slowed down because of the DMA transfer? (A) 0.06% (B) 0.12% (C) 1.2% (D) 2.5%

Description : A DMA controller transfers 32-bit words to memory using cycle Stealing. The words are assembled from a device that transmits characters at a rate of 4800 characters per second. The CPU is fetching and executing instructions at an average ... of the DMA transfer? (A) 0.06% (B) 0.12% (C) 1.2% (D) 2.5%

Last Answer : Answer: B

Two cogged wheels of which one has 32 cogs and other 54 cogs, work into each other. If the latter turns 80 times in three quarters of a minute, how often does the other turn in 8 seconds? A) 48 B) 24 C) 38 D) 39 E) None of these

Description : Two cogged wheels of which one has 32 cogs and other 54 cogs, work into each other. If the latter turns 80 times in three quarters of a minute, how often does the other turn in 8 seconds? A) 48 B) 24 C) 38 D) 39 E) None of these

Last Answer : Answer: B  Number of turns required= 80 × 54/32 × 8/45 = 24 24 times

Rapid gravity filters can remove bacterial impurities up to a maximum of (A) 50 % (B) 60 % (C) 70 % (D) 80 %

Description : Rapid gravity filters can remove bacterial impurities up to a maximum of  (A) 50 %  (B) 60 %  (C) 70 %  (D) 80 %

Last Answer : (D) 80 %

Degree of saturation of a natural soil deposit having water content 15%, specific gravity 2.50 and void ratio 0.5, is (A) 50 % (B) 60 % (C) 75 % (D) 80 %

Description : Degree of saturation of a natural soil deposit having water content 15%, specific gravity 2.50 and void ratio 0.5, is (A) 50 % (B) 60 % (C) 75 % (D) 80 %

Last Answer : (C) 75 %

A CPU handles interrupt by executing interrupt service subroutine................. (A) by checking interrupt register after execution of each instruction (B) by checking interrupt register at the end of the fetch cycle (C) whenever an interrupt is registered (D) by checking interrupt register at regular time interval

Description : A CPU handles interrupt by executing interrupt service subroutine................. (A) by checking interrupt register after execution of each instruction (B) by checking interrupt register ... cycle (C) whenever an interrupt is registered (D) by checking interrupt register at regular time interval

Last Answer : (A) by checking interrupt register after execution of each instruction

An intense rain is falling at a uniform rate of 7.5 cm/hour for a period of 60 minutes on a basin whose area is 500 hectares. If the average infiltration capacity during the entire rain period is assumed to be 1.5 cm/hr, the maximum run-off rate based on 10 minute peak percentage of 16% from distributing graph of the basin, is (A) 40 cumecs (B) 60 cumecs (C) 80 cumecs (D) 100 cumecs

Description : An intense rain is falling at a uniform rate of 7.5 cm/hour for a period of 60 minutes on a basin whose area is 500 hectares. If the average infiltration capacity during the entire rain period is assumed to be 1.5 ... of the basin, is (A) 40 cumecs (B) 60 cumecs (C) 80 cumecs (D) 100 cumecs

Last Answer : Answer: Option C

The distance between two stations M and N is L kilometers. All frames are K bits long. The propagation delay per kilometer is t seconds. Let R bits/second be the channelcapacity. Assuming that processing delay is negligible, the minimum number of bits for the sequence number field in a frame for maximum utilization, when the sliding window protocol used is: a. A b. B c. C d. D

Description : The distance between two stations M and N is L kilometers. All frames are K bits long. The propagation delay per kilometer is t seconds. Let R bits/second be the channel capacity. Assuming that processing ... maximum utilization, when the sliding window protocol used is: a. A b. B c. C d. D

Last Answer : c. C

A scheduling Algorithm assigns priority proportional to the waiting time of a process. Every process starts with priority zero (lowest priority). The scheduler re-evaluates the process priority for every 'T' time units and decides next process to be scheduled. If the process have no I/O operations and all arrive at time zero, then the scheduler implements .............. criteria. (A) Priority scheduling (B) Round Robin Scheduling (C) Shortest Job First (D) FCFS

Description : A scheduling Algorithm assigns priority proportional to the waiting time of a process. Every process starts with priority zero (lowest priority). The scheduler re-evaluates the process priority for every 'T' time ... (A) Priority scheduling (B) Round Robin Scheduling (C) Shortest Job First (D) FCFS

Last Answer : (B) Round Robin Scheduling

A thread is usually defined as a light weight process because an Operating System (OS) maintains smaller data structure for a thread than for a process. In relation to this, which of the following statement is correct? (A) OS maintains only scheduling and accounting information for each thread. (B) OS maintains only CPU registers for each thread. (C) OS does not maintain a separate stack for each thread. (D) OS does not maintain virtual memory state for each thread.

Description : A thread is usually defined as a light weight process because an Operating System (OS) maintains smaller data structure for a thread than for a process. In relation to this, which of the following ... separate stack for each thread. (D) OS does not maintain virtual memory state for each thread.

Last Answer : (B) OS maintains only CPU registers for each thread.

There are three processes P1, P2 and P3 sharing a semaphore for synchronising a variable. Initial value of semaphore is one. Assume that negative value of semaphore tells us how many processes are waiting in queue. Processes access the semaphore in following order: (a) P2 needs to access (b) P1 needs to access (c) P3 needs to access (d) P2 exits critical section (e) Pi exits critical section The final value of semaphore will be: (1) 0 (2) 1 (3) -1 (4) -2

Description : There are three processes P1, P2 and P3 sharing a semaphore for synchronising a variable. Initial value of semaphore is one. Assume that negative value of semaphore tells us how many processes are waiting in queue. Processes access ... The final value of semaphore will be: (1) 0 (2) 1 (3) -1 (4) -2 

Last Answer : Answer: 1

The percentage of the aggregate of F.M. 2.6 to be combined with coarse aggregate of F.M. 6.8 for obtaining the aggregates of F.M. 5.4, is (A) 30 % (B) 40 % (C) 50 % (D) 60 %

Description : The percentage of the aggregate of F.M. 2.6 to be combined with coarse aggregate of F.M. 6.8 for obtaining the aggregates of F.M. 5.4, is (A) 30 % (B) 40 % (C) 50 % (D) 60 %

Last Answer : (C) 50 %

A network with bandwidth of 10 Mbps can pass only an average of 15,000 frames per minute with each frame carrying an average of 8,000 bits. What is the throughput of this network? a. 2 Mbps b. 60 Mbps c. 120 Mbps

Description : A network with bandwidth of 10 Mbps can pass only an average of 15,000 frames per minute with each frame carrying an average of 8,000 bits. What is the throughput of this network? a. 2 Mbps b. 60 Mbps c. 120 Mbps

Last Answer : a. 2 Mbps

A software company needs to develop a project that is estimated as 1000 function points and is planning to use JAVA as the programming language whose approximate lines of code per function point is accepted as 50. Considering a=1.4 as multiplicative factor, b=1.0 as exponention factor for the basic COCOMO effort equation and c=3.0 as multiplicative factor, d=0.33 as exponention factor for the basic COCOMO duration equation, approximately how long does the project take to complete? (1) 11.2 months (2) 12.2 months (3) 13.2 months (4) 10.2 months

Description : A software company needs to develop a project that is estimated as 1000 function points and is planning to use JAVA as the programming language whose approximate lines of code per function point is accepted as 50. Considering a=1. ... ? (1) 11.2 months (2) 12.2 months (3) 13.2 months (4) 10.2 months

Last Answer : Generally, any projects are measured in weeks. However, the complex project might take more time depending on the level of object re-use available.

Consider a system having ‘m’ resources of the same type. These resources are shared by three processes P1, P2 and P3 which have peak demands of 2, 5 and 7 resources respectively. For what value of ‘m’ deadlock will not occur? (A) 70 (B) 14 (C) 13 (D) 7

Description : Consider a system having ‘m’ resources of the same type. These resources are shared by three processes P1, P2 and P3 which have peak demands of 2, 5 and 7 resources respectively. For what value of ‘m’ deadlock will not occur? (A) 70 (B) 14 (C) 13 (D) 7

Last Answer : (B) 14

ECE Board Exam March 1996 What is the transmission rate of a system for transmitting the output of a microcomputer to a line printer operating at a speed of 30 lines/minute? Assume that the line printer has 8 bits of data per character and prints out 80 characters/line. A. 800 bps B. 400 bps C. 320 bps D. 640 bps

Description : ECE Board Exam March 1996 What is the transmission rate of a system for transmitting the output of a microcomputer to a line printer operating at a speed of 30 lines/minute? Assume that the line printer has 8 bits ... and prints out 80 characters/line. A. 800 bps B. 400 bps C. 320 bps D. 640 bps

Last Answer : C. 320 bps

Suppose there are four processes in execution with 12 instances of a Resource R in a system. The maximum need of each process and current allocation are given below: Image With reference to current allocation, is system safe? If so, what is the safe sequence? (A) No (B) Yes, P1 P2 P3 P4 (C) Yes, P4 P3 P1 P2 (D) Yes, P2 P1 P3 P4

Description : Suppose there are four processes in execution with 12 instances of a Resource R in a system. The maximum need of each process and current allocation are given below: With reference to current allocation, is system safe? If so, ... B) Yes, P1 P2 P3 P4 (C) Yes, P4 P3 P1 P2 (D) Yes, P2 P1 P3 P4

Last Answer : (C) Yes, P4 P3 P1 P2

Consider a project with the following functional units : Number of user inputs = 50 Number of user outputs = 40 Number of user enquiries = 35 Number of user files = 06 Number of external interfaces = 04 Assuming all complexity adjustment factors and weighing factors as average, the function points for the project will be (A) 135 (B) 722 (C) 675 (D) 672

Description : Consider a project with the following functional units : Number of user inputs = 50 Number of user outputs = 40 Number of user enquiries = 35 Number of user files = 06 Number of external interfaces = 04 ... average, the function points for the project will be (A) 135 (B) 722 (C) 675 (D) 672

Last Answer : (D) 672

Consider a disk with 16384 bytes per track having a rotation time of 16 msec and average seek time of 40 msec. What is the time in msec to read a block of 1024 bytes from this disk? (A) 57 msec (B) 49 msec (C) 48 msec (D) 17 msec

Description : Consider a disk with 16384 bytes per track having a rotation time of 16 msec and average seek time of 40 msec. What is the time in msec to read a block of 1024 bytes from this disk? (A) 57 msec (B) 49 msec (C) 48 msec (D) 17 msec

Last Answer : Answer: B

An 18-year-old man shot once in the left chest has a blood pressure of 80/50 mm. Hg, a heart rate of 130 beats per minute, and distended neck veins. Immediate treatment might include: A. Administration of one liter of Ringer's lactate solution. B. Subxiphoid pericardiotomy. C. Needle decompression of the left chest in the second intercostal space. D. Emergency thoracotomy to cross-clamp the aorta.

Description : An 18-year-old man shot once in the left chest has a blood pressure of 80/50 mm. Hg, a heart rate of 130 beats per minute, and distended neck veins. Immediate treatment might include: A. ... of the left chest in the second intercostal space. D. Emergency thoracotomy to cross-clamp the aorta.

Last Answer : Answer: AC DISCUSSION: The finding of distended neck veins in conjunction with hypotension should suggest tension pneumothorax or pericardial tamponade. Absent ipsilateral breath sounds and a trachea ... injuries. There is no role for aortic cross-clamping in this scenario of cardiogenic shock

Sum of Rs.118 was shared among 50 boys and girls,each girl receive Rs.2.60 and boy receive Rs.1.80.Find the number of girls. A) 15 B)25 C)30 D)35

Description : Sum of Rs.118 was shared among 50 boys and girls,each girl receive Rs.2.60 and boy receive Rs.1.80.Find the number of girls. A) 15 B)25 C)30 D)35

Last Answer : D)35

An actor in an animation is a small program invoked ............... per frame to determine the characteristics of some object in the animation. (A) once (B) twice (C) 30 times (D) 60 times

Description : An actor in an animation is a small program invoked ............... per frame to determine the characteristics of some object in the animation. (A) once (B) twice (C) 30 times (D) 60 times

Last Answer : (A) once

Percentage of pozzolanic material containing clay upto 80% used for the manufacture of pozzolana cement, is (A) 30 % (B) 40 % (C) 50 % (D) 60 %

Description : Percentage of pozzolanic material containing clay upto 80% used for the manufacture of pozzolana cement, is (A) 30 % (B) 40 % (C) 50 % (D) 60 %

Last Answer : (A) 30 %

Brass is an alloy of copper and zinc having the relative percentage (A) 60-70% Cu and 30-40% Zn (B) 50-60% Cu and 40-50% Zn (C) 40-50 % Cu and 60-50% Zn (D) 30-40 % Cu and 60-70% Zn

Description : Brass is an alloy of copper and zinc having the relative percentage (A) 60-70% Cu and 30-40% Zn (B) 50-60% Cu and 40-50% Zn (C) 40-50 % Cu and 60-50% Zn (D) 30-40 % Cu and 60-70% Zn

Last Answer : A) 60-70% Cu and 30-40% Zn

There is 60 seconds in a minute, 60 minutes in a hour, how many seconds are in a race? -Riddles

Description : There is 60 seconds in a minute, 60 minutes in a hour, how many seconds are in a race? -Riddles

Last Answer : This answer was deleted by moderators

In process scheduling, …………………… determines when new processes are admitted to the system. A) long term scheduling B) medium term scheduling C) short term scheduling D) none of the above

Description : In process scheduling, …………………… determines when new processes are admitted to the system. A) long term scheduling B) medium term scheduling C) short term scheduling D) none of the above

Last Answer : A) long term scheduling

Station A uses 32 byte packets to transmit messages to station B using sliding window protocol. The round trip delay between A and B is 40 milli seconds and the bottleneck bandwidth on the path between A and B is 64 kbps. The optimal window size of A is (1) 20 (2) 10 (3) 30 (4) 40

Description : Station A uses 32 byte packets to transmit messages to station B using sliding window protocol. The round trip delay between A and B is 40 milli seconds and the bottleneck bandwidth on the path between A and B is 64 kbps. The optimal window size of A is (1) 20 (2) 10 (3) 30 (4) 40

Last Answer : (2) 10

While traveling in a straight line, a car uniformly changes its speed from 50 kilometers per hour to 110 kilometers per hour in 5 seconds. The acceleration of the car during this time is: w) 5 kilometers per hour per second x) 12 kilometers per hour per second y) 50 kilometers per hour per second z) 60 kilometers per hour per second

Description : While traveling in a straight line, a car uniformly changes its speed from 50 kilometers per hour to 110 kilometers per hour in 5 seconds. The acceleration of the car during this time is: w) 5 ... per hour per second y) 50 kilometers per hour per second z) 60 kilometers per hour per second

Last Answer : ANSWER: X -- 12 KILOMETERS PER HOUR PER SECOND

Consider the following transportation problem: Image The initial basic feasible solution of the above transportation problem using Vogel’s Approximation Method(VAM) is given below: The solution of the above problem: (A) is degenerate solution (B) is optimum solution (C) needs to improve (D) is infeasible solution

Description : Consider the following transportation problem: The initial basic feasible solution of the above transportation problem using Vogel's Approximation Method(VAM) is given below: The solution of the ... degenerate solution (B) is optimum solution (C) needs to improve (D) is infeasible solution

Last Answer : (B) is optimum solution

A job has four pages A, B, C, D and the main memory has two page frames only. The job needs to process its pages in following order: ABACABDBACD Assuming that a page interrupt occurs when a new page is brought in the main memory, irrespective of whether the page is swapped out or not. The number of page interrupts in FIFO and LRU page replacement algorithms are (A) 9 and 7 (B) 7 and 6 (C) 9 and 8 (D) 8 and 6

Description : A job has four pages A, B, C, D and the main memory has two page frames only. The job needs to process its pages in following order: ABACABDBACD Assuming that a page interrupt occurs when a new page is brought in the main ... replacement algorithms are (A) 9 and 7 (B) 7 and 6 (C) 9 and 8 (D) 8 and 6

Last Answer : (C) 9 and 8