Number of bits per symbol used in Baudot code is a. 7 b. 5 c. 8d. 9

Number of bits per symbol used in Baudot code is
a. 7
b. 5
c. 8
d. 9
by

1 Answer

Answer :

5
by

Related questions

Which of the following code used in present day computing was developed by IBM Corporation?a. ASCII b. Hollerith Code c. Baudot Code d. EBCDIC Code

Description : Which of the following code used in present day computing was developed by IBM Corporation? a. ASCII b. Hollerith Code c. Baudot Code d. EBCDIC Code

Last Answer : EBCDIC Code

Consider a source with symbols A, B, C, D with probabilities 1/2, 1/4, 1/8, 1/8 respectively. What is the average number of bits per symbol for the Huffman code generated from above information? (A) 2 bits per symbol (B) 1.75 bits per symbol (C) 1.50 bits per symbol (D) 1.25 bits per symbol

Description : Consider a source with symbols A, B, C, D with probabilities 1/2, 1/4, 1/8, 1/8 respectively. What is the average number of bits per symbol for the Huffman code generated from above information? (A) 2 bits per symbol (B) 1.75 bits per symbol (C) 1.50 bits per symbol (D) 1.25 bits per symbol

Last Answer : (B) 1.75 bits per symbol

Given the symbols A, B, C, D, E, F, G and H with the probabilities 1/30, 1/30, 1/30, 2/30, 3/30, 5/30, 5/30 and 12/30 respectively. The average Huffman code size in bits per symbol is: (A) 67/30 (B) 70/34 (C) 76/30 (D) 78/30

Description : Given the symbols A, B, C, D, E, F, G and H with the probabilities 1/30, 1/30, 1/30, 2/30, 3/30, 5/30, 5/30 and 12/30 respectively. The average Huffman code size in bits per symbol is: (A) 67/30 (B) 70/34 (C) 76/30 (D) 78/30

Last Answer : (C) 76/30

Which of the following code used in present day computing was developed by IBM Corporation? A) ASCII B) Hollerith Code C) Baudot Code D) EBCDIC Code

Description : Which of the following code used in present day computing was developed by IBM Corporation? A) ASCII B) Hollerith Code C) Baudot Code D) EBCDIC Code

Last Answer : Answer : D

How many symbols exist in Baudot code? A) 32 B) 116 C) 58 D) 76

Description : How many symbols exist in Baudot code? A) 32 B) 116 C) 58 D) 76

Last Answer : Answer : A

Which of the following code is used in present day computing was developed by IBM corporation? a. ASCII b. Hollerith Code c. Baudot code d. EBCDIC code

Description : Which of the following code is used in present day computing was developed by IBM corporation? a. ASCII b. Hollerith Code c. Baudot code d. EBCDIC code

Last Answer : d. EBCDIC code

Which of the following code used in present day computing was developed by IBM Corporation? a. ASCII b. Hollerith Code c. Baudot Code d. EBCDIC Code

Description : Which of the following code used in present day computing was developed by IBM Corporation? a. ASCII b. Hollerith Code c. Baudot Code d. EBCDIC Code

Last Answer : d. EBCDIC Code

Which of the following code used in present day computing was developed by IBM Corporation? a. ASCII b. Hollerith Code c. Baudot Code d. EBCDIC Code

Description : Which of the following code used in present day computing was developed by IBM Corporation? a. ASCII b. Hollerith Code c. Baudot Code d. EBCDIC Code

Last Answer : d. EBCDIC Code

The ________ between two words is the number ofdifferences between corresponding bits. A) Hamming code B) Hamming distance C) Hamming rule D) none of the above

Description : The ________ between two words is the number ofdifferences between corresponding bits. A) Hamming code B) Hamming distance C) Hamming rule D) none of the above

Last Answer : Hamming distance

_______ can detect burst error of length less than or equal to degree of the polynomial and detects burst errors that affect odd number of bits. a. Hamming Code b. CRC c. VRC d. None of the above

Description : _______ can detect burst error of length less than or equal to degree of the polynomial and detects burst errors that affect odd number of bits. a. Hamming Code b. CRC c. VRC d. None of the above

Last Answer : b. CRC

Which type of Sframe in HDLC exhibit the correspondence of last three bits [N(R)] by defining the negative acknowledgement (NAK) number with the code value of '01'? a. Receive ready b. Receive not ready c. Reject d. Selective Reject

Description : Which type of Sframe in HDLC exhibit the correspondence of last three bits [N(R)] by defining the negative acknowledgement (NAK) number with the code value of '01'? a. Receive ready b. Receive not ready c. Reject d. Selective Reject

Last Answer : c. Reject

The ________ between two words is the number of differences between corresponding bits A. Hamming code B. Hamming distance C. Hamming rule D. none of the above

Description : The ________ between two words is the number of differences between corresponding bits A. Hamming code B. Hamming distance C. Hamming rule D. none of the above

Last Answer : B. Hamming distance

Which of the following summation operations is performed onthe bits to checkanerror-detecting code? A. Codec B. Coder-decoder C. Checksum D. Attenuation

Description : Which of the following summation operations is performed onthe bits to checkanerror-detecting code? A. Codec B. Coder-decoder C. Checksum D. Attenuation

Last Answer : Checksum

Let C be a binary linear code with minimum distance 2t + 1 then it can correct upto _____ bits of error. a. t + 1 b. t c. t - 2 d. t / 2

Description : Let C be a binary linear code with minimum distance 2t + 1 then it can correct upto _____ bits of error. a. t + 1 b. t c. t - 2 d. t / 2

Last Answer : b. t

A Huffman code: A = 1, B = 000, C = 001, D = 01 ,P(A) = 0.4, P(B) = 0.1, P(C) = 0.2, P(D) = 0.3 The average number of bits per letter is A. 8.0 bit B. 2.0 bit C. 1.9 bit D. 2.1 bit

Description : A Huffman code: A = 1, B = 000, C = 001, D = 01 ,P(A) = 0.4, P(B) = 0.1, P(C) = 0.2, P(D) = 0.3 The average number of bits per letter is A. 8.0 bit B. 2.0 bit C. 1.9 bit D. 2.1 bit

Last Answer : C. 1.9 bit

A Huffman code: A = 1, B = 000, C = 001, D = 01 ,P(A) = 0.4, P(B) = 0.1, P(C) = 0.2, P(D) = 0.3 The average number of bits per letter is a. 8.0 bit b. 2.0 bit c. 1.9 bit d. 2.1 bit

Description : A Huffman code: A = 1, B = 000, C = 001, D = 01 ,P(A) = 0.4, P(B) = 0.1, P(C) = 0.2, P(D) = 0.3 The average number of bits per letter is a. 8.0 bit b. 2.0 bit c. 1.9 bit d. 2.1 bit

Last Answer : c. 1.9 bit

The distance between two stations M and N is L kilometers. All frames are K bits long. The propagation delay per kilometer is t seconds. Let R bits/second be the channelcapacity. Assuming that processing delay is negligible, the minimum number of bits for the sequence number field in a frame for maximum utilization, when the sliding window protocol used is: a. A b. B c. C d. D

Description : The distance between two stations M and N is L kilometers. All frames are K bits long. The propagation delay per kilometer is t seconds. Let R bits/second be the channel capacity. Assuming that processing ... maximum utilization, when the sliding window protocol used is: a. A b. B c. C d. D

Last Answer : c. C

What is the usualnumber of bits transmitted simultaneously inparalleldata transmission used by microcomputers? A. 16 B. 9 C. 8 D. 4 E. None of the above

Description : What is the usualnumber of bits transmitted simultaneously inparalleldata transmission used by microcomputers? A. 16 B. 9 C. 8 D. 4 E. None of the above

Last Answer : 9

the storage capacity of a disk system depends on the bits per inch of track and the tracks per inch of a. Cylinder b. Hum c. Cluster d. Surface

Description : the storage capacity of a disk system depends on the bits per inch of track and the tracks per inch of a. Cylinder b. Hum c. Cluster d. Surface

Last Answer : Surface

a computer which CPU speed around 100 million instruction per second and with the word length of around 64 bits is known as a. Super computer b. Mini computer c. Micro computer d. Macro computer

Description : a computer which CPU speed around 100 million instruction per second and with the word length of around 64 bits is known as a. Super computer b. Mini computer c. Micro computer d. Macro computer

Last Answer : Super computer

a computer which CPU speed around 100 million instruction per second and with the word length of around 64 bits is known as a. Super computer b. Mini computer c. Micro computer d. Macro computer

Description : a computer which CPU speed around 100 million instruction per second and with the word length of around 64 bits is known as a. Super computer b. Mini computer c. Micro computer d. Macro computer

Last Answer : Super computer

Storage capacity of magnetic disk depends on a. tracks per inch of surface b. bits per inch of tracks c. disk pack in disk surface d. All of above

Description : Storage capacity of magnetic disk depends on a. tracks per inch of surface b. bits per inch of tracks c. disk pack in disk surface d. All of above

Last Answer : All of above

The cheapest modems cantransmit A. 300 bits per second B. 1,200 bitsper second C. 2,400 bits per second D. 4,800 bits per second E. None of the above

Description : The cheapest modems cantransmit A. 300 bits per second B. 1,200 bitsper second C. 2,400 bits per second D. 4,800 bits per second E. None of the above

Last Answer : 300 bits per second

What is the commonly used unit for measuring the speed of data transmission? A) Bytes per second B) Baud C) Bits per second D) Both B and C

Description : What is the commonly used unit for measuring the speed of data transmission? A) Bytes per second B) Baud C) Bits per second D) Both B and C

Last Answer : B) Baud

If link transmits 4000 frames per second and each slot has 8 bits, the transmission rate of circuit of this TDM is ______. a. 64 Kbps b. 32 Mbps c. 32 Kbps d. 64 MbpS

Description : If link transmits 4000 frames per second and each slot has 8 bits, the transmission rate of circuit of this TDM is ______. a. 64 Kbps b. 32 Mbps c. 32 Kbps d. 64 MbpS

Last Answer : c. 32 Kbps

A network with bandwidth of 10 Mbps can pass only an average of 12,000 frames per minute with each frame carrying an average of 10,000 bits. What is the throughput of this network ? a. 1 Mbps b. 2 Mbps c. 10 Mbps d. 12 Mbps

Description : A network with bandwidth of 10 Mbps can pass only an average of 12,000 frames per minute with each frame carrying an average of 10,000 bits. What is the throughput of this network ? a. 1 Mbps b. 2 Mbps c. 10 Mbps d. 12 Mbps

Last Answer : b. 2 Mbps

A network with bandwidth of 10 Mbps can pass only an average of 15,000 frames per minute with each frame carrying an average of 8,000 bits. What is the throughput of this network? a. 2 Mbps b. 60 Mbps c. 120 Mbps

Description : A network with bandwidth of 10 Mbps can pass only an average of 15,000 frames per minute with each frame carrying an average of 8,000 bits. What is the throughput of this network? a. 2 Mbps b. 60 Mbps c. 120 Mbps

Last Answer : a. 2 Mbps

Consider a CSMA/CD network that transmits data at a rate of 100 Mbps (108 bits per second) over a 1 km (kilometre) cable with no repeaters. If the minimum frame size required for this network is 1250 bytes, what is the signal speed (km/sec) in the cable? a. 8000 b. 10000 c. 16000 d. 20000

Description : Consider a CSMA/CD network that transmits data at a rate of 100 Mbps (108 bits per second) over a 1 km (kilometre) cable with no repeaters. If the minimum frame size required for this network is 1250 bytes, what is the signal speed (km/sec) in the cable? a. 8000 b. 10000 c. 16000 d. 20000

Last Answer : d. 20000

How many 8-bit characters can be transmitted per second over a 9600 baud serial communication link using asynchronous mode of transmission with one start bit, eight data bits, two stop bits, and one parity bit ? a. 600 b. 800 c. 876 d. 1200

Description : How many 8-bit characters can be transmitted per second over a 9600 baud serial communication link using asynchronous mode of transmission with one start bit, eight data bits, two stop bits, and one parity bit ? a. 600 b. 800 c. 876 d. 1200

Last Answer : b. 800

address use 7 bits for the <network> and 24 bits for the <host> portion of the IP a. address. b. Class A c. Class B d. Class C e. Class D

Description : address use 7 bits for the and 24 bits for the portion of the IP a. address. b. Class A c. Class B d. Class C e. Class D

Last Answer : a. address.

If `(3a+4b):(3a-4b)=(3c+8d):(3c-8d),` then which of the following is true?

Description : If `(3a+4b):(3a-4b)=(3c+8d):(3c-8d),` then which of the following is true?

Last Answer : If `(3a+4b):(3a-4b)=(3c+8d):(3c-8d),` then which of the following is true? A. ad=bc B. 2ad=bc C. 2ab=cd D. ab=cd

The stiffness of the close coil helical spring is (A) d 4N/8D 3n (B) d 4N/4D 3n (C) 4D 3N/d 4n (D) 8D 3N/d 4n

Description : The stiffness of the close coil helical spring is  (A) d 4N/8D 3n (B) d 4N/4D 3n (C) 4D 3N/d 4n (D) 8D 3N/d 4n

Last Answer : (A) d 4N/8D 3n

The greatest eccentricity which a load W can have without producing tension on the cross-section of a short column of external diameter D and internal diameter d, is (A) 4W/ (D² - d²) (B) (D² - d²)/32D (C) (D² + d²)/8D (D) (D² - d²)/8D

Description : The greatest eccentricity which a load W can have without producing tension on the cross-section of a short column of external diameter D and internal diameter d, is (A) 4W/ (D² - d²) (B) (D² - d²)/32D (C) (D² + d²)/8D (D) (D² - d²)/8D

Last Answer : (C) (D² + d²)/8D

If diameter of a reinforcement bar is d, the anchorage value of the hook is (A) 4d (B) 8d (C) 12d (D) 16d

Description : If diameter of a reinforcement bar is d, the anchorage value of the hook is (A) 4d (B) 8d (C) 12d (D) 16d

Last Answer : Answer: Option D

In Go-Back-N ARQ, if 5 is the number of bits for thesequencenumber, then the maximum size of the receive window mustbe _____ A) 15 B) 16 C) 31 D) 1

Description : In Go-Back-N ARQ, if 5 is the number of bits for thesequencenumber, then the maximum size of the receive window mustbe _____ A) 15 B) 16 C) 31 D) 1

Last Answer : 1

In Go-Back-N ARQ, if 5 is the number of bits for thesequencenumber, then the maximum size of the send window must be _____ A) 15 B) 16 C) 31 D) 1

Description : In Go-Back-N ARQ, if 5 is the number of bits for thesequencenumber, then the maximum size of the send window must be _____ A) 15 B) 16 C) 31 D) 1

Last Answer : 31

What is the minimum number of bits required in a PCM code for a range of 10,000? A. 12 B. 9 C. 14 D. 10

Description : What is the minimum number of bits required in a PCM code for a range of 10,000? A. 12 B. 9 C. 14 D. 10

Last Answer : C. 14

If in a computer, 16 bits are used to specify address in a RAM, the number of addresses will be a. 216 b. 65,536 c. 64K d. Any of the above

Description : If in a computer, 16 bits are used to specify address in a RAM, the number of addresses will be a. 216 b. 65,536 c. 64K d. Any of the above

Last Answer : 65,536

______ provides synchronization without increasingthe number of bits. A) Scrambling B) Line coding C) Block coding D) None of the above

Description : ______ provides synchronization without increasingthe number of bits. A) Scrambling B) Line coding C) Block coding D) None of the above

Last Answer : Scrambling

The _____ layer uses data compression to reduce the number of bits to be transmitted. a. presentation b. network c. data link d. application

Description : The _____ layer uses data compression to reduce the number of bits to be transmitted. a. presentation b. network c. data link d. application

Last Answer : a. presentation

Let G(x) be the generator polynomial used for CRC checking. What is the condition that should be satisfied by G(x) to detect odd number of bits in error? a. G(x) contains more than two terms b. G(x) does not divide 1+x^k, for any k not exceeding the frame length c. 1+x is a factor of G(x) d. G(x) has an odd number of terms

Description : Let G(x) be the generator polynomial used for CRC checking. What is the condition that should be satisfied by G(x) to detect odd number of bits in error? a. G(x) contains more than two terms b. G(x) does ... exceeding the frame length c. 1+x is a factor of G(x) d. G(x) has an odd number of terms

Last Answer : c. 1+x is a factor of G(x)

Determine the maximum length of the cable (in km) for transmitting data at a rate of 500 Mbps in an Ethernet LAN with frames of size 10,000 bits. Assume the signal speed in the cable to be 2,00,000 km/s.b. 2 c. 2.5 d. 5

Description : Determine the maximum length of the cable (in km) for transmitting data at a rate of 500 Mbps in an Ethernet LAN with frames of size 10,000 bits. Assume the signal speed in the cable to be 2,00,000 km/s. b. 2 c. 2.5 d. 5

Last Answer : b. 2

If a modulating wave is sampled 10 times per cycle with a 5-element binary code, how many bits of information are required to transmit the signal?

Description : If a modulating wave is sampled 10 times per cycle with a 5-element binary code, how many bits of information are required to transmit the signal?

Last Answer : 28. 50.

A byte consists of a. One bit b. Four bits c. Eight bits d. Sixteen bits

Description : A byte consists of a. One bit b. Four bits c. Eight bits d. Sixteen bits

Last Answer : Eight bits

A byte consists of a. One bit b. Four bits c. Eight bits d. Sixteen bits

Description : A byte consists of a. One bit b. Four bits c. Eight bits d. Sixteen bits

Last Answer : Eight bits

Avalanche photodiode receivers can detect bits of transmitted data by receiving a. 100 photons b. 200 photons c. 2000 photons d. 300 photons

Description : Avalanche photodiode receivers can detect bits of transmitted data by receiving a. 100 photons b. 200 photons c. 2000 photons d. 300 photons

Last Answer : 200 photons

A band is always equivalent to a. a byte b. a bit c. 100 bits d. none of above

Description : A band is always equivalent to a. a byte b. a bit c. 100 bits d. none of above

Last Answer : none of above

The synchronous modems are more costly than the asynchronous modems because a. they produce large volume of data b. they contain clock recovery circuits c. they transmit the data with stop and start bits d. they operate with a larger bandwidth e. none of above

Description : The synchronous modems are more costly than the asynchronous modems because a. they produce large volume of data b. they contain clock recovery circuits c. they transmit the data with stop and start bits d. they operate with a larger bandwidth e. none of above

Last Answer : they contain clock recovery circuits

In Ethernet addressing, ifall the bits are 1s, the address is _________. A) unicast B) multicast C) broadcast D) none of the above

Description : In Ethernet addressing, ifall the bits are 1s, the address is _________. A) unicast B) multicast C) broadcast D) none of the above

Last Answer : broadcast