Description : What is the size of the ‘total length’ field in IPv4 datagram? a. 4 bit b. 8 bit c. 16 bit d. 32 bit
Last Answer : c. 16 bit
Description : The virtual address generated by a CPU is 32 bits. The Translation Lookaside Buffer (TLB) can hold total 64 page table entries and a 4-way set associative (i.e. with 4- cache lines in the set). The page size is 4 KB. The minimum size of TLB tag is (A) 12 bits (B) 15 bits (C) 16 bits (D) 20 bits
Last Answer : (C) 16 bits Explanation: VirtualAddress = 32 bits PageSize = 4KB = 12 bits therefore : VPNTag = 20 bits, OffsetTag = 12 bits TLBEntryLength = VPNTag = 20 bits TotalTLBEntries = 64, 4-way implies ... therefore : TLBIndex = 4 bits TLBTag = TLBEntryLength - TLBIndex = 20 - 4 = 16 bits
Description : The IEEE-754 double-precision format to represent floating point numbers, has a length of ........... bits. (A) 16 (B) 32 (C) 48 (D) 64
Last Answer : (D) 64
Description : A memory management system has 64 pages with 512 bytes page size. Physical memory consists of 32 page frames. Number of bits required in logical and physical address are respectively: (1) 14 and 15 (2) 14 and 29 (3) 15 and 14 (4) 16 and 32
Last Answer : (3) 15 and 14
Description : In IPV 4, the IP address 200.200.200.200 belongs to (A) Class A (B) Class B (C) Class C (D) Class D
Last Answer : (C) Class C
Description : Four bits are used for packed sequence numbering in a sliding window protocol used in a computer network. What is the maximum window size ? (A) 4 (B) 8 (C) 15 (D) 16
Last Answer : (C) 15
Description : Suppose a digitized voice channel is made by digitizing 8 kHz bandwidth analog voice signal. It is required to sample the signal at twice the highest frequency (two samples per hertz). What is the bit rate required, if it ... sample requires 8 bits? (A) 32 kbps (B) 64 kbps (C) 128 kbps (D) 256 kbps
Last Answer : (C) 128 kbps
Description : If link transmits 4000 frames per second and each slot has 8 bits, the transmission rate of circuit of this TDM is ............... (A) 64 Kbps (B) 32 Mbps (C) 32 Kbps (D) 64 Mbps
Last Answer : (C) 32 Kbps
Description : The word length of Micro computers lies in the range between ________ (A) 8 and 16 bits (B) 8 and 21 bits (C) 8 and 24 bits (D) 8 and 32 bits
Last Answer : (D) 8 and 32 bits
Description : In IPv4 header, the field is needed to allow the destination host to determine which datagram a newly arrived fragment belongs to. (A) identification (B) fragment offset (C) time to live (D) header checksum
Last Answer : (A) identification
Description : A unix file system has 1-KB blocks and 4-byte disk addresses. What is the maximum file size if i-nodes contain 10 direct entries and one single, double and triple indirect entry each? (A) 32 GB (B) 64 GB (C) 16 GB (D) 1 GB
Last Answer : (C) 16 GB
Description : The Internet addresses are ______ bits in length in IPV4 addressing scheme A. 16 B. 64 C. 32 D. 48
Last Answer : C. 32
Description : The Internet addresses are ……….. bits in length in IPV4 addressing scheme a. 16 b. 64 c. 48 d. 32
Last Answer : d. 32
Description : Consider a 32 - bit microprocessor, with a 16 - bit external data bus, driven by an 8 MHz input clock. Assume that the microprocessor has a bus cycle whose minimum duration equals four input clock cycles. What ... (A) 8x106 bytes/sec (B) 4x106 bytes/sec (C) 16x106 bytes/sec (D) 4x109 bytes/sec
Last Answer : (B) 4x106 bytes/sec
Description : The maximum length (in bytes) of an IPv4 datagram is? A. 32 B. 1024 C. 65535 D. 512
Last Answer : C. 65535
Description : The Width of a processor’s data path is measured in bits. Which of the following are common data paths? A) 8 bits B) 12 bits C) 16 bits D) 32 bits
Last Answer : Answer : A
Description : A nibble is equal to _______ A. 4 bits B. 8 bits C. 16 bits D. 32 bits
Last Answer : A. 4 bits
Description : The Width of a processor’s data path is measured in bits. Which of the following are common data paths? a. 8 bits b. 12 bits c. 16 bits d. 32 bits
Last Answer : a. 8 bits
Description : A nibble is equal to_____ bits. (1) 32 (2) 4 (3) 8 (4) 16
Last Answer : 4
Description : What is the probability that a randomly selected bit string of length 10 is a palindrome? (A) 1/64 (B) 1/32 (C) 1/8 (D) ¼
Last Answer : (B) 1/32
Description : A data file of 1,00,000 characters contains only the characters g-l, with the frequencies as indicated in table: using the variable-length code by Huffman codes, the file can be encoded with (A) 2,52,000 bits (B) 2,64,000 bits (C) 2,46,000 bits (D) 2,24,000 bits
Last Answer : (D) 2,24,000 bits
Description : The order of a leaf node in a B+ tree is the maximum number of children it can have. Suppose that block size is 1 kilobytes, the child pointer takes 7 bytes long and search field value takes 14 bytes long. The order of the leaf node is ............ (1) 16 (2) 63 (3) 64 (4) 65
Last Answer : Answer: All
Description : The ……………. is used to provide integrity check, authentication and encryption to IP datagram. A) SSL B) ESP C) TSL D) PSL
Last Answer : B) ESP
Description : The data unit in the TCP/IP layer called a ..... A) Message B) Segment C) Datagram D) Frame
Last Answer : D) Frame
Description : Which of the following fields in IPv4 datagram is not related to fragmentation? (A) Type of service (B) Fragment offset (C) Flags (D) Identification
Last Answer : (A) Type of service
Description : Find the false statement: (A) In Modern Cryptography, symmetric key algorithms use same key both for Encryption and Decryption. (B) The Symmetric cipher DES (Data Encryption Standard) was widely used ... and 124 bits. (D) Public key algorithms use two different keys for Encryption and Decryption.
Last Answer : (C) The AES (Advanced Encryption Standard) cryptosystem allows variable key lengths of size 56 bits and 124 bits.
Description : Given the symbols A, B, C, D, E, F, G and H with the probabilities 1/30, 1/30, 1/30, 2/30, 3/30, 5/30, 5/30 and 12/30 respectively. The average Huffman code size in bits per symbol is: (A) 67/30 (B) 70/34 (C) 76/30 (D) 78/30
Last Answer : (C) 76/30
Description : Suppose transmission rate of a channel is 32 kbps. If there are ‘8’ routes from source to destination and each packet p contains 8000 bits. Total end to end delay in sending packet P is _____. a. 2 sec b. 3 sec c. 4 sec d. 1 sec
Last Answer : a. 2 sec
Description : The versions of windows operating system like windows XP and window Vista uses following file system: (A) FAT-16 (B) FAT-32 (C) NTFS (NT File System) (D) All of the above
Last Answer : (D) All of the above
Description : Windows 32 API supports (A) 16-bit Windows (B) 32-bit Windows (C) 64-bit Windows (D) All of the above
Description : WOW32 is a: (A) Win 32 API library for creating processes and threads. (B) Special kind of file system to the NT name space. (C) Kernel - mode objects accessible through Win32 API (D) Special execution environment used to run 16 bit Windows applications on 32 - bit machines.
Last Answer : (D) Special execution environment used to run 16 bit Windows applications on 32 - bit machines.
Description : A Multicomputer with 256 CPUs is organized as 16x16 grid. What is the worst case delay (in hops) that a message might have to take? (A) 16 (B) 15 (C) 32 (D) 30
Last Answer : (D) 30
Description : What is the bit rate for transmitting uncompressed 800x600 pixel colour frames with 8 bits/pixel at 40 frames/second ? (A) 2.4 Mbps (B) 15.36 Mbps (C) 153.6 Mbps (D) 1536 Mbps
Last Answer : (C) 153.6 Mbps Explanation: The number of bits/sec is just 800x600x40x8 or 153.6 Mbps.
Description : For the 8-bit word 00111001, the check bits stored with it would be 0111. Suppose when the word is read from memory, the check bits are calculated to be 1101. What is the data word that was read from memory? (A) 10011001 (B) 00011001 (C) 00111000 (D) 11000110
Last Answer : (B) 00011001
Description : A network with bandwidth of 10 Mbps can pass only an average of 15,000 frames per minute with each frame carrying an average of 8,000 bits. What is the throughput of this network ? (A) 2 Mbps (B) 60 Mbps (C) 120 Mbps (D) 10 Mbps
Last Answer : (A) 2 Mbps Explanation: In data transmission, throughput is the amount of data moved successfully from one place to another in a given period of time, and typically measured in bits per second (bps), ... second (Mbps) or gigabits per second (Gbps). Here, Throughput = 15000 x 8000/60 = 2 Mbps
Description : Consider a source with symbols A, B, C, D with probabilities 1/2, 1/4, 1/8, 1/8 respectively. What is the average number of bits per symbol for the Huffman code generated from above information? (A) 2 bits per symbol (B) 1.75 bits per symbol (C) 1.50 bits per symbol (D) 1.25 bits per symbol
Last Answer : (B) 1.75 bits per symbol
Description : Assume that we need to download text documents at the rate of 100 pages per minute. A page is an average of 24 lines with 80 characters in each line and each character requires 8 bits. Then the required bit rate of the channel is ... ...... (A) 1.636 Kbps (B) 1.636 Mbps (C) 2.272 Mbps (D) 3.272 Kbps
Last Answer : Answer: Marks given to all
Description : A memory unit stores 2^16 bytes in 32-bit words. How many address bits are necessary in order to retrieve a single word from this memory unit?
Last Answer : Each word is 4 bytes, which occupies 4 consecutive addresses at 16 bits each. The first 14 bits of these addresses will be the same, differing only in the two least significant bits. You only need to specify the first 14 bits, because there are only 2^14 words occupying those 2^16 bytes.
Description : Which instruction are 32 bits long , with extra 16 bits. a. Memory reference instruction b. Memory reference format c. Both d. None of these
Last Answer : a. Memory reference instruction
Description : How many bits internet address isassigned to eachhost on a TCP/IP internet which is used in all communications withthehost? A. 16 - bits B. 32 - bits C. 48 - bits D. 64 - bits E. None of the above
Last Answer : 32 - bits
Description : Because we wish to allow each ASCII code to occupy one location in memory, most memories are _____ addressable. a. BYTE b. NIBBLE c. WORD (16 bits) d. DOUBLEWORD (32 bits)
Last Answer : a. BYTE
Description : The processor 80386/80486 and the Pentium processor uses _____ bits address bus: a. 16 b. 32 c. 36 d. 64
Last Answer : b. 32
Description : How many address bits are required to represent a 32 K memory (A) 10 bits. (B) 12 bits. (C) 14 bits. (D) 16 bits.
Last Answer : (D) 16 bits.
Description : The VPIof an NNI is _______ bits in length. A) 8 B) 12 C) 16 D) 24
Last Answer : 12
Description : The VPIof a UNI is _______ bits in length. A) 8 B) 12 C) 16 D) 24
Last Answer : 8
Description : Word Length of a Personal Computer is ______: a) 4 Bits b) 8 Bits c) 16 Bits d) None of The Above
Last Answer : b) 8 Bits
Description : Word length if a personal computer ia _________ 1) 4 bits 2) 8 bits 3) 16 bits 4) 64 bits
Last Answer : 1) 4 bits
Description : Word length if a personal computer ia _________ 1 4 bits 2 8 bits 3 16 bits 4 64 bits
Last Answer : 1 4 bits
Description : Which processes does TCP, but not UDP, use?Source Port - 16 bits, Destination Port - 16 bits, Length - 16 Bits, Checksum - 16 bits, Data * Destination Port - 16 bits, Source Port - 16 bits, Length - ... * Source Port - 8 bits, Destination Port - 8 bits, Length -8 Bits, Checksum - 8 bits, Data
Last Answer : Correct answer: A The UDP format for a segment is as follows: Source Port 16 bits Destination Port 16 bits Length 16 bits Checksum 16 bits Data xx bits