Four bits are used for packed sequence numbering in a sliding window protocol used in a computer network. What is the maximum window size ? 

(A) 4 (B) 8 (C) 15 (D) 16

1 Answer

Answer :

(C) 15 

Related questions

Description : Four bits are used for packet sequence numbering in a sliding window protocol used in computer network. What is maximum window size?  A) 4 B) 8 C) 15 D) 16

Last Answer : Four bits are used for packet sequence numbering in a sliding window protocol used in computer network. What is maximum window size?  15

Description : The distance between two stations M and N is L kilometers. All frames are K bits long. The propagation delay per kilometer is t seconds. Let R bits/second be the channel capacity. Assuming that processing ... maximum utilization, when the sliding window protocol used is: a. A b. B c. C d. D

Last Answer : c. C

Description : Station A uses 32 byte packets to transmit messages to station B using sliding window protocol. The round trip delay between A and B is 40 milli seconds and the bottleneck bandwidth on the path between A and B is 64 kbps. The optimal window size of A is (1) 20 (2) 10 (3) 30 (4) 40

Last Answer : (2) 10

Description : The maximum size of the window in a Sliding Window Protocol is _______ A. 2m – 1 B. 2m + 1 C. 2m D. 2m-1

Last Answer : A. 2m – 1

Description : In Go-Back-N ARQ, if 5 is the number of bits for thesequencenumber, then the maximum size of the receive window mustbe _____ A) 15 B) 16 C) 31 D) 1

Last Answer : 1

Description : In Go-Back-N ARQ, if 5 is the number of bits for thesequencenumber, then the maximum size of the send window must be _____ A) 15 B) 16 C) 31 D) 1

Last Answer : 31

Description : The virtual address generated by a CPU is 32 bits. The Translation Lookaside Buffer (TLB) can hold total 64 page table entries and a 4-way set associative (i.e. with 4- cache lines in the set). The page size is 4 KB. The minimum size of TLB tag is (A) 12 bits (B) 15 bits (C) 16 bits (D) 20 bits

Last Answer : (C) 16 bits Explanation: VirtualAddress = 32 bits PageSize = 4KB = 12 bits therefore : VPNTag = 20 bits, OffsetTag = 12 bits TLBEntryLength = VPNTag = 20 bits TotalTLBEntries = 64, 4-way implies ... therefore : TLBIndex = 4 bits TLBTag = TLBEntryLength - TLBIndex = 20 - 4 = 16 bits

Description : A memory management system has 64 pages with 512 bytes page size. Physical memory consists of 32 page frames. Number of bits required in logical and physical address are respectively: (1) 14 and 15 (2) 14 and 29 (3) 15 and 14 (4) 16 and 32

Last Answer : (3) 15 and 14

Description : Station A uses 32 byte packets to transmit messages to Station B using a sliding window protocol. The round trip delay between A and B is 80 milliseconds and the bottleneck bandwidth on the path between A and B ... What is the optimal window size that A should use? a. 20 b. 40 c. 160 d. 320

Last Answer : b. 40

Description : In Selective Repeat ARQ, if 5 is the number ofbits for the sequence number, then the maximum size of the receive window mustbe _____ A) 15 B) 16 C) 31 D) 1

Last Answer : 16

Description : In Selective Repeat ARQ, if 5 is the number ofbits for the sequence number, then the maximum size of the send window must be _____ A) 15 B) 16 C) 31 D) 1

Last Answer : 16

Description : What is the size of the 'total length' field in IPv 4 datagram ? (A) 4 bits (B) 8 bits (C) 16 bits (D) 32 bits

Last Answer : (C) 16 bits 

Description : A network with bandwidth of 10 Mbps can pass only an average of 15,000 frames per minute with each frame carrying an average of 8,000 bits. What is the throughput of this network ? (A) 2 Mbps (B) 60 Mbps (C) 120 Mbps (D) 10 Mbps

Last Answer : (A) 2 Mbps Explanation: In data transmission, throughput is the amount of data moved successfully from one place to another in a given period of time, and typically measured in bits per second (bps), ... second (Mbps) or gigabits per second (Gbps). Here, Throughput = 15000 x 8000/60 = 2 Mbps 

Description : the maximum window size for data transmission using the selective reject protocol with n-bit frame sequence numbers is: a. 2^n b. 2^(n-1) c. 2^n – 1 d. 2^(n-2)

Last Answer : b. 2^(n-1)

Description : The range of sequence number which is the concern of the receiver is called the receive sliding window. A. receive sliding window. B. sliding window C. frame buffer D. both a and b

Last Answer : A. receive sliding window.

Description : What is the bit rate for transmitting uncompressed 800x600 pixel colour frames with 8 bits/pixel at 40 frames/second ? (A) 2.4 Mbps (B) 15.36 Mbps (C) 153.6 Mbps (D) 1536 Mbps 

Last Answer : (C) 153.6 Mbps Explanation: The number of bits/sec is just 800x600x40x8 or 153.6 Mbps.

Description : Consider a 32 - bit microprocessor, with a 16 - bit external data bus, driven by an 8 MHz input clock. Assume that the microprocessor has a bus cycle whose minimum duration equals four input clock cycles. What ... (A) 8x106 bytes/sec (B) 4x106 bytes/sec (C) 16x106 bytes/sec (D) 4x109 bytes/sec 

Last Answer : (B) 4x106 bytes/sec

Description : A byte addressable computer has a memory capacity of 2 m Kbytes and can perform 2 n operations. An instruction involving 3 operands and one operator needs a maximum of (A) 3m bits (B) m + n bits (C) 3m + n bits (D) 3m + n + 30 bits

Last Answer : (D) 3m + n + 30 bits

Description : The IEEE-754 double-precision format to represent floating point numbers, has a length of ........... bits. (A) 16 (B) 32 (C) 48 (D) 64

Last Answer : (D) 64

Description : Suppose there are four processes in execution with 12 instances of a Resource R in a system. The maximum need of each process and current allocation are given below: With reference to current allocation, is system safe? If so, ... B) Yes, P1 P2 P3 P4 (C) Yes, P4 P3 P1 P2 (D) Yes, P2 P1 P3 P4

Last Answer : (C) Yes, P4 P3 P1 P2

Description : Which of the following statement is true? i) An address with all bits 1 is interpreted as all networks or all hosts. ii) The class A network 128.0.0.0 is defined as the loopback network. A) i only B) ii only C) Both A and B D) None of the above

Last Answer : A) i only

Description : .................. address use 7 bits for the and 24 bits for the portion of the IP address. A) Class A B) Class B C) Class C D) Class D

Last Answer : A) Class A

Description : A network with bandwidth of 10 Mbps can pass only an average of 12,000 frames per minute with each frame carrying an average of 10,000 bits. What is the throughput of this network ? (A) 1 Mbps (B) 2 Mbps (C) 10 Mbps (D) 12 Mbps

Last Answer : (B) 2 Mbps

Description : A sender uses the Stop-and-Wait ARQ protocol for reliable transmission of frames. Frames are of size 1000 bytes and the transmission rate at the sender is 80 Kbps (1Kbps = 1000 bits/second). Size of ... is lost, the sender throughput is __________ bytes/second. a. 2500 b. 2000 c. 1500 d. 500

Last Answer : a. 2500

Description : A node X on a 10 Mbps network is regulated by a token bucket. The token bucket is filled at a rate of 2 Mbps. Token bucket is initially filled with 16 megabits. The maximum duration taken by X to transmit at full rate of 10 Mbps is ............ secs. (1) 1 (2) 2 (3) 3 (4) 4

Last Answer : (2) 2 

Description : Native – protocol pure Java converts ……….. into the ………… used by DBMSs directly. A) JDBC calls, network protocol B) ODBC class, network protocol C) ODBC class, user call D) JDBC calls, user call

Last Answer : A) JDBC calls, network protocol

Description : ………………….. is used to carry traffic of one protocol over network that does not support that protocol directly. A) Tunneling B) Transferring C) Trafficking D) Switching

Last Answer : A) Tunneling

Description : ………………….. is responsible for converting the higher level protocol addresses (IP addresses) to physical network addresses. A) Address Resolution Protocol (ARP) B) Reverse Address Resolution Protocol (RARP) C) Bootstrap Protocol (BOOTP) D) Internet Control Message Protocol (ICMP)

Last Answer : A) Address Resolution Protocol (ARP)

Description : ........ is responsible for converting the higher level protocol addresses to physical Network Addresses. A) Address Resolution Protocol (ARP) B) Reverse Address Resolution Protocol (RARP) C) Bootstrap Protocol (BOOTP) D) Internet Control Message Protocol (ICMP)

Last Answer : D) Internet Control Message Protocol (ICMP)

Description : In which OSI layers does the FDDI protocol operate? A) Physical B) Data link C) Network D) A and B

Last Answer : D) A and B

Description : Which is the protocol for performing RPCs between applications in a language and system independent way? (A) Hyper Text Transmission Protocol (HTTP) (B) Simple Network Management Protocol (SNMP) (C) Simple Object Access Protocol (SOAP) (D) Simple Mail Transfer Protocol (SMTP)

Last Answer : (C) Simple Object Access Protocol (SOAP)

Description : Float a[15], what is the size of array? A) 17 B) 14 C) 15 D) 16

Last Answer : 16

Description : In hierarchical routing with 4800 routers, what region and cluster sizes should be chosen to minimize the size of the routing table for a three layer hierarchy? (A) 10 clusters, 24 regions and 20 routers (B ... (C) 16 clusters, 12 regions and 25 routers (D) 15 clusters, 16 regions and 20 routers

Last Answer : (D) 15 clusters, 16 regions and 20 routers Rooters minimum, then regions minimum, then clusters minimum.

Description : Find the false statement: (A) In Modern Cryptography, symmetric key algorithms use same key both for Encryption and Decryption. (B) The Symmetric cipher DES (Data Encryption Standard) was widely used ... and 124 bits. (D) Public key algorithms use two different keys for Encryption and Decryption.

Last Answer : (C) The AES (Advanced Encryption Standard) cryptosystem allows variable key lengths of size 56 bits and 124 bits.

Description : Given the symbols A, B, C, D, E, F, G and H with the probabilities 1/30, 1/30, 1/30, 2/30, 3/30, 5/30, 5/30 and 12/30 respectively. The average Huffman code size in bits per symbol is: (A) 67/30 (B) 70/34 (C) 76/30 (D) 78/30

Last Answer : (C) 76/30

Description : In a classful addressing, first four bits in Class A IP address is (A) 1010 (B) 1100 (C) 1011 (D) 1110

Last Answer : Answer: A,B,C,D

Description : A multiplexer combines four 100-Kbps channels using a time slot of 2 bits. What is the bit rate? (A) 100 Kbps (B) 200 Kbps (C) 400 kbps (D) 1000 Kbps

Last Answer : (C) 400 kbps

Description : The versions of windows operating system like windows XP and window Vista uses following file system: (A) FAT-16 (B) FAT-32 (C) NTFS (NT File System) (D) All of the above

Last Answer : (D) All of the above

Description : A UNIX file system has 1 KB block size and 4-byte disk addresses. What is the maximum file size if the inode contains ten direct block entries, one single indirect block entry, one double indirect block entry and one triple indirect block entry? (A) 30 GB (B) 64 GB (C) 16 GB (D) 1 GB

Last Answer : (C) 16 GB

Description : A unix file system has 1-KB blocks and 4-byte disk addresses. What is the maximum file size if i-nodes contain 10 direct entries and one single, double and triple indirect entry each? (A) 32 GB (B) 64 GB (C) 16 GB (D) 1 GB

Last Answer : (C) 16 GB

Description : The order of a leaf node in a B+ tree is the maximum number of children it can have. Suppose that block size is 1 kilobytes, the child pointer takes 7 bytes long and search field value takes 14 bytes long. The order of the leaf node is ............ (1) 16 (2) 63 (3) 64 (4) 65

Last Answer : Answer: All

Description : Which layer of OSI reference model is responsible for decomposition of messages and generation of sequence numbers to ensure correct re-composition from end to end of the network? (A) Physical (B) Data-link (C) Transport (D) Application

Last Answer : (C) Transport 

Description : Let A and B be two fuzzy integers defined as: A={(1,0.3), (2,0.6), (3,1), (4,0.7), (5,0.2)} B={(10,0.5), (11,1), (12,0.5)} Using fuzzy arithmetic operation given by (A) {(11,0.8), (13,1), (15,1)} ( ... ,0.2)} (D) {(11,0.3), (12,0.5), (13,0.6), (14,1), (15,0.7), (16,0.5), (17,0.2)}

Last Answer : (D) {(11,0.3), (12,0.5), (13,0.6), (14,1), (15,0.7), (16,0.5), (17,0.2)}

Description : Suppose a digitized voice channel is made by digitizing 8 kHz bandwidth analog voice signal. It is required to sample the signal at twice the highest frequency (two samples per hertz). What is the bit rate required, if it ... sample requires 8 bits? (A) 32 kbps (B) 64 kbps (C) 128 kbps (D) 256 kbps

Last Answer : (C) 128 kbps

Description : For the 8-bit word 00111001, the check bits stored with it would be 0111. Suppose when the word is read from memory, the check bits are calculated to be 1101. What is the data word that was read from memory? (A) 10011001 (B) 00011001 (C) 00111000 (D) 11000110

Last Answer : (B) 00011001

Description : Consider a source with symbols A, B, C, D with probabilities 1/2, 1/4, 1/8, 1/8 respectively. What is the average number of bits per symbol for the Huffman code generated from above information? (A) 2 bits per symbol (B) 1.75 bits per symbol (C) 1.50 bits per symbol (D) 1.25 bits per symbol

Last Answer : (B) 1.75 bits per symbol

Description : Assume that we need to download text documents at the rate of 100 pages per minute. A page is an average of 24 lines with 80 characters in each line and each character requires 8 bits. Then the required bit rate of the channel is ... ...... (A) 1.636 Kbps (B) 1.636 Mbps (C) 2.272 Mbps (D) 3.272 Kbps

Last Answer : Answer: Marks given to all

Description : If link transmits 4000 frames per second and each slot has 8 bits, the transmission rate of circuit of this TDM is ............... (A) 64 Kbps (B) 32 Mbps (C) 32 Kbps (D) 64 Mbps

Last Answer : (C) 32 Kbps

Description : A software project was estimated at 352 Function Points (FP). A four person team will be assigned to this project consisting of an architect, two programmers, and a tester. The salary of the architect is Rs.80,000 per month, the ... ) Rs.28,16,000 (2) Rs.20,90,000 (3) Rs.26,95,000 (4) Rs.27,50,000

Last Answer : (4) Rs.27,50,000 

Description : A bed of spherical particles (specific gravity 2.5) of uniform size 1500 μm is 0.5 m in diameter and 0.5 m high. In packed bed state, the porosity may be taken as 0.4. Ergun's equation for the above fluid-particle ... fluidisation velocity, VOM is (A) 12 mm/s (B) 16 mm/s (C) 24 mm/s (D) 28 mm/s

Last Answer : (B) 16 mm/s