One kg of gas occupying 0.1m^3 at pressure of 14 bar is expanded at constant pressure to 0.2m^3. Determine an initial and final temperature of gas. Take Cp=1.008KJ/KgK, Cv =0.72KJ/KgK.

1 Answer

Answer :

V1=0.1m^3

V2=0.2 m^3

P1=P2=14 bar

Cp=1.008 KJ/KgK

Cv=0.72 KJ/KgK

R=Cp-Cv

R=1.008-0.72

R=0.288KJ/KgK

Characteristic gas equation,

 P1V1=mRT1

14*10^5*0.1=1*288*T1

T1=486.11K

For constant pressure process,

V1/T1=V2/T2

0.1/486.11=0.2/T2

T2=972.22K


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