Description : The gas constant is equal to a. Cp – Cv b. Cp + Cv c. Cp – Cv + k d. None of the above
Last Answer : Cp – Cv
Description : The value of specific heat at constant pressure (cp) is __________ that of at constant volume (cv). A. less than B. equal to C. more than
Last Answer : Answer: C
Description : The ratio of specific heat at constant pressure (Cp) and specific heat at constant volume (cv) is A. equal to one B. less than one C. greater than one D. none of these
Description : The heat supplied to the gaS at constant volume is (where m = Mass of gas, cv = Specific heat at constant volume, cp = Specific heat at constant pressure, T2 – T1 = Rise in temperature, and R = Gas constant) A. mR(T2 – T1) B. mcv(T2 – T1) C. mcp(T2 – T1) D. mcp(T2 + T1)
Last Answer : Answer: B
Description : General gas equation is (a) PV=nRT (b) PV=mRT (d) PV = C (c) PV=KiRT (e) Cp-Cv = Wj
Last Answer : Answer : b
Description : A certain gas, with cp = 0.529Btu/ lb. °Rand R = 96.2ft.lb/lb. °R, expands from 5 cu ft and 80°F to 15 cu ft while the pressure remains constant at 15.5psia. Compute for T2. a.1520°R b. 1620°R c. 1720°R d. 1820°R formula: T2= T1V2/V1
Last Answer : 1620°R
Description : A perfect gas has a value of R= 319.2 J/ kf.K and k= 1.26. If 120 kJ are added to 2.27 kf\g of this gas at constant pressure when the initial temp is 32.2°C? Find T2. a. 339.4 K b. 449.4 K c. 559.4K d. 669.4K formula: cp = kR/ k-1 Q= mcp(T2-T1)
Last Answer : 339.4 K
Description : A certain gas with cp = 0.529Btu/lb°R and R = 96.2ft/lbºR expands from 5 ft and 80ºF to 15 ft while the pressure remains constant at 15.5 psia. a. T2=1.620ºR, ∫H = 122.83 Btu b. T2 = 2°R, ∫H = 122.83 Btu c. ... , ∫H = 122.83 Btu d. T2 = 1°R, ∫H = 122.83 Btu T2= V2(t2)/V1 and ∫H = mcp (T2-T1)
Last Answer : T2=1.620ºR, ∫H = 122.83 Btu
Description : A certain gas, with cp = 0.529Btu/lb.°R and R = 96.2 ft.lb/lb.°R, expands from 5 cu ft and 80°F to 15 cu ft while the pressure remains constant at 15.5 psia. Compute for T2. (Formula: T2= T1V2/V1) a. 460°R b. 270°R c. 1620 °R d. None of the above
Last Answer : 1620 °R
Description : For a certain gas R = 320 J/kg.K and cv= 0.84kJ/kg.K. Find k? a. 1.36 b. 1.37 c. 1.38 d. 1.39 formula: k= R / cv+1
Last Answer : 1.38
Description : Find the change in internal energy of 5 lb. of oxygen gas when the temperature changes from 100 ˚F to 120 ˚F. CV = 0.157 BTU/lbm-˚R A.14.7 BTU B.15.7 BTU C. 16.8 BTU D. 15.9 BTU Formula: U= mcv T
Last Answer : 15.7 BTU
Description : The value of the product of molecular weight and the gas characteristic constant for all the gases in S.I. units is (a) 29.27 J/kmol°K (b) 83.14J/kmol°K (c) 848J/kmol°K (d) All J/kmol °K (e) 735 J/kmol °K.
Description : The value of the product of molecular weight and the gas characteristic constant for all the gases in M.K.S. unit is (a) 29.27 kgfm/mol°K (b) 8314kgfm/mol°K (c) 848kgfm/mol°K (d) 427kgfm/mol°K (e) 735 kgfm/mol°K.
Last Answer : Answer : c
Description : If a gas is heated against a pressure, keeping the volume constant, then work done will be equal to (a) + v (b) – ve (c) zero (d) pressure x volume (e) any where between zero and infinity.
Description : Water (specific heat cv= 4.2 kJ/ kg ∙ K ) is being heated by a 1500 W h eater. What is the rate of change in temperature of 1kg of the water? A. 0.043 K/s B. 0.179 K/s C. 0.357 K/s D. 1.50 K/s Formula: Q = mcv ( T)
Last Answer : 0.179 K/s
Description : Universal gas constant is defined as equal to product of the molecular weight of the gas and (a) specific heat at constant pressure (b) specific heat at constant volume (c) ratio of two specific heats (d) gas constant (e) unity.
Last Answer : Answer : d
Description : For perfect gas a. cp – cv = R b. cp + cv = R c. cp / cv = R d. cp X cv = R Where cp & cv are specific heats at constant pressure and volume.
Last Answer : ANSWER a. CP – CV = R
Description : The gas constant (R) is equal to the __________ of two specific heats. A. sum B. difference C. product D. ratio
Description : According to Avogadro's law A. the product of the gas constant and the molecular mass of an ideal gas is constant B. the sum of partial pressure of the mixture of two gases is sum of the ... all gases, at the same temperature and pressure, contain equal number of molecules D. all of the above
Description : The same volume of all gases would represent their (a) densities (b) specific weights (c) molecular weights (d) gas characteristic constants (e) specific gravities.
Description : The compressibility factor, x, is used for predicting the behavior of nonideal gases. How is the compressibility ty factor defined relative to an ideal gas? (subscript c refers to critical value) A. ... compressibility factor, x, is an dimensionless constant given by pV=zRT. Therefore z = pV / RT
Last Answer : z = pV/ RT
Description : One kg of gas occupying 0.1m^3 at pressure of 14 bar is expanded at constant pressure to 0.2m^3. Determine an initial and final temperature of gas. Take Cp=1.008KJ/KgK, Cv =0.72KJ/KgK.
Last Answer : V1=0.1m^3 V2=0.2 m^3 P1=P2=14 bar Cp=1.008 KJ/KgK Cv=0.72 KJ/KgK R=Cp-Cv R=1.008-0.72 R=0.288KJ/KgK Characteristic gas equation, P1V1=mRT1 14*10^5*0.1=1*288*T1 T1=486.11K For constant pressure process, V1/T1=V2/T2 0.1/486.11=0.2/T2 T2=972.22K
Description : Change in internal energy in a closed system is equal to heat transferred if the reversible process takes place at constant (a) pressure (b) temperature (c) volume (d) internal energy (e) entropy.
Description : Change in enthalpy in a closed system is equal to heat transferred if the reversible process takes place at constant (a) pressure (b) temperature (c) volume (d) internal energy (e) entropy.
Last Answer : Answer : a
Description : Specific heat of air at constant pressure is equal to (a) 0.17 (b) 0.21 (c) 0.24 (d) 1.0 (e) 1.41
Description : Gas turbine cycle consists of (a) two isothermals and two isentropics (b) two isentropics and two constant volumes (c) two isentropics, one constant volume and one constant pressure (d) two isentropics and two constant pressures (e) none of the above.
Description : The unit’of universal gas constant is (a) watts/°K (b) dynes/°C (c) ergscm/°K (d)erg/°K (e) none of the above.
Description : Addition of heat at constant pressure to a gas results in (a) raising its temperature (b) raising its pressure (c) raising its volume (d) raising its temperature and doing external work (e) doing external work.
Description : In an isothermal process, the internal energy of gas molecules (a) increases (b) decreases (c) remains constant (d) may increase/decrease depending on the properties of gas (e) shows unpredictable behaviour.
Description : A perfect gas at 27°C is heated at constant pressure till its volume is double. The final temperature is (a) 54°C (b) 327°C (c) 108°C (d) 654°C (e) 600°C
Description : According to Avogadro's Hypothesis (a) the molecular weights of all the perfect gases occupy the same volume under same conditions of pressure and temperature (b) the sum of partial pressure of ... gases have two values of specific heat (e) all systems can be regarded as closed systems.
Description : Which law states that the specific heat of a gas remains constant at all temperatures and pressures (a) Charles’ Law (b) Joule’s Law (c) Regnault’s Law (d) Boyle’s Law (e) there is no such law.
Description : According to Gay-Lussac law for a perfect gas, the absolute pressure of given mass varies directly as (a) temperature (b) absolute (c) absolute temperature, if volume is kept constant ... , if temperature is kept constant (e) remains constant,if volume and temperature are kept constant.
Description : The prefix “iso” used to designate a process means ______. A. Cannot be interchanged B. Remains constant C. Approximately equal D. Slight difference
Last Answer : Remains constant
Description : According to first law of thermodynamics (a) work done by a system is equal to heat transferred by the system (b) total internal energy of a system during a process remains constant ( ... , enthalpy and entropy during a process remain constant (d) total energy of a system remains constant
Description : y = specific heat ratio of an ideal gas is equal to (A) Cp/Cv (B) Cp/(CP-R) (C) 1 + (R/CV) (D) All (A), (B) and (C)
Last Answer : D) All (A), (B) and (C)
Description : The volume of a gas under constant pressure increases or decrease with temperature. a. Gay- Lussac’s Law b. Ideal Gas Law c. Charles’ Law d. Boyle’s Law
Last Answer : Charles’ Law
Description : An ideal gas is compressed in a cylinder so well insulated that there is essentially no heat transfer. The temperature of gas a. Remains constant b. increases c. decreases d. is basically zero
Last Answer : increases
Description : What Law states that the pressure of gas is inversely proportional to its volume at constant temperature? a. Charles’ law b. Gay-Lussac’s Law c. Boyle’s Law d. Dalton’s Law
Last Answer : Boyle’s Law
Description : The volume of a confined gas is held constant, the pressure is directly proportional to the absolute temperature. a. Charle’s Law b. Boyle’s Law c. Joule’s Law d. Specific Heat
Description : The pressure of the confined gas is held constant, the volume directly proportional to the absolute temperature. a. Charle’s Law b. Boyle’s Law c. Zeroth Law d. Gas Law
Last Answer : Charle’s Law
Description : Gas being heated at constant volume is undergoing the process of. a. isometric b. specific heat c. enthalpy d. isothermal
Last Answer : isometric
Description : “If the temperature o f a fixed quantity of a gas is held constant during a change of state, the volume varies inversely with the absolute pressure. a. Charle’s Law b. Boyle’s Law c. Dalton’s Law d. Amagat’s Law
Description : A gas having a volume of100 ft³ at 27ºC is expanded to 120 ft³by heated at constant pressure to what temperature has it been heated to have this new volume? a. 87°C b. 85°C c. 76°C d. 97°C t2= T2–T1
Last Answer : 87°C
Description : The volume of the gas held at constant pressure increases 4 cm² at 0°C to 5cm². What is the final pressure? a. 68.65ºC b. 68.25ºC c. 70.01°C d. 79.1ºC t2= T2–T1
Last Answer : 981 N
Description : An ideal gas at 45psig and 80ºF is heated in the close container to 130ºF. What is the final pressure? a. 65.10 psi b. 65.11 psi c. 65.23 psi d. 61.16 psi P1V1/T1= P2V2/T2;V = Constant
Last Answer : 65.23 psi
Description : There are 1.36 kg of gas, for which R = 377 J/kg.k and k = 1.25, that undergo a nonflow constant volume process from p1 = 551.6 kPa and t1 = 60°C to p2 = 1655 kPa. During the process the gas is internally stirred and ... (Formula: T2= T1p2/ p1) a. 999 K b. 888 K c. 456 K d. One of the above
Last Answer : 999 K
Description : Gas is enclosed in a cylinder with a weighted piston as the stop boundary. The gas is heated and expands from a volume of 0.04 m^3 to 0.10 m^3 at a constant pressure of 200kPa.Calculate the work done by the system. A. 8 kJ B. 10 kJ C.12 kJ D.14 kJ Formula: W = p(V2-V1)
Last Answer : 12 kJ
Description : Twenty grams of oxygen gas are compressed at a constant temperature of 30 ˚C to 5%of their original volume. What work is done on the system. A.824 cal B.924 cal C.944 cal D.1124 cal Formula: W = -mRTln (V2/V1) Where R = (1.98 cal/gmole·K) (32 g/gmole)
Last Answer : 1124 cal
Description : A gas is enclosed in a cylinder with a weighted piston as the top boundary. The gas is heated and expands from a volume of 0.04 m3 to 0.10 m3 at a constant pressure of 200 kPa. Find the work done on the system. a. 5 kJ b. 15 kJ c. 10 kJ d. 12 kJ