How Big Is 400 km In Miles?

Description : At a given port, the fetch is 400 nautical miles, the maximum height of storm wave will be (A) 2.073 m (B) 8.169 m (C) 9.144 m (D) 6.8

Last Answer : (C) 9.144 m

What to do if I broke the outer door and my parents are about 400 km from Prague !?

Last Answer : How did she break it? Lock? Call locksmiths ...... http://zamecnicka-pohotovost24.cz/

According to 1998 census the density of population in Punjab is: A. 220 Persons per Sq. Km B. 319 Persons per Sq. Km C. 353 Persons per Sq. Km D. 400 Persons per Sq. Km

Description : According to 1998 census the density of population in Punjab is: A. 220 Persons per Sq. Km B. 319 Persons per Sq. Km C. 353 Persons per Sq. Km D. 400 Persons per Sq. Km

Last Answer : ANSWER: C

According to 1998 census the density of population in Sindh Province is: A. 212 Persons per Sq. Km B. 243 Persons per Sq. Km C. 353 Persons per Sq. Km D. 400 Persons per Sq. Km

Description : According to 1998 census the density of population in Sindh Province is: A. 212 Persons per Sq. Km B. 243 Persons per Sq. Km C. 353 Persons per Sq. Km D. 400 Persons per Sq. Km

Last Answer : ANSWER: A

According to 1998 census the density of population in Sindh Province is: A. 212 Persons per Sq. Km B. 243 Persons per Sq. Km C. 353 Persons per Sq. Km D. 400 Persons per Sq. Km

Description : According to 1998 census the density of population in Sindh Province is: A. 212 Persons per Sq. Km B. 243 Persons per Sq. Km C. 353 Persons per Sq. Km D. 400 Persons per Sq. Km

Last Answer : ANSWER: A

According to 1998 census the density of population in Punjab is: A. 220 Persons per Sq. Km B. 319 Persons per Sq. Km C. 353 Persons per Sq. Km D. 400 Persons per Sq. Km

Description : According to 1998 census the density of population in Punjab is: A. 220 Persons per Sq. Km B. 319 Persons per Sq. Km C. 353 Persons per Sq. Km D. 400 Persons per Sq. Km

Last Answer : ANSWER: C

What is the propagation delay when a signal is transmitter by an earth station to a geosynchronous satellite about 38,500 km above earth’s equator and then received by the same earth station? A. 256 msec B. 128 msec C. 300 msec D. 400 msec

Description : What is the propagation delay when a signal is transmitter by an earth station to a geosynchronous satellite about 38,500 km above earth’s equator and then received by the same earth station? A. 256 msec B. 128 msec C. 300 msec D. 400 msec

Last Answer : A. 256 msec

During the night when the F2 layer combines with F1 layer it falls to what approximate height? A. 250 km B. 350 km C. 300 km D. 400 km

Description : During the night when the F2 layer combines with F1 layer it falls to what approximate height? A. 250 km B. 350 km C. 300 km D. 400 km

Last Answer : C. 300 km

For a space wave transmission, the radio horizon distance of a transmitting antenna with a height of 100 meters is approximately:A. 10 km B. 40 km C. 100 km D. 400 km

Description : For a space wave transmission, the radio horizon distance of a transmitting antenna with a height of 100 meters is approximately: A. 10 km B. 40 km C. 100 km D. 400 km

Last Answer : B. 40 km

Electromagnetic wave travel at __________ in free space. A. 300,000 km/sec B. 100,000 km/ sec C. 400,000 km/sec D. 200km/sec

Description : Electromagnetic wave travel at __________ in free space. A. 300,000 km/sec B. 100,000 km/ sec C. 400,000 km/sec D. 200km/sec

Last Answer : A. 300,000 km/sec

Orbital radius of GPS satellites is approximately: (A) 15,200 km (B) 26,600 km (C) 18,400 km (D) 36,000 km

Description : Orbital radius of GPS satellites is approximately: (A) 15,200 km (B) 26,600 km (C) 18,400 km (D) 36,000 km

Last Answer : Answer: Option B

The normal altitude of GPS satellite is about (A) 16,200 km (B) 20,200 km (C) 24,400 km (D) 36,100 km

Description : The normal altitude of GPS satellite is about (A) 16,200 km (B) 20,200 km (C) 24,400 km (D) 36,100 km

Last Answer : Answer: Option B

. The product of the bit rate and distance of a fiber-optic system is 2 Gbits-km/s. What is the maximum rate at 5 km? ∙ A. 100 Mbits/s ∙ B. 200 Mbits/s ∙ C. 400 Mbits/s ∙ D. 1000 Gbits/s

Description : . The product of the bit rate and distance of a fiber-optic system is 2 Gbits-km/s. What is the maximum rate at 5 km? ∙ A. 100 Mbits/s ∙ B. 200 Mbits/s ∙ C. 400 Mbits/s ∙ D. 1000 Gbits/s

Last Answer : C. 400 Mbits/s

The product of the bit rate and distance of a fiber-optic system is 2 Gbits km/s. What is the maximum rate at 5 km? ∙ a. 100 Mbits/s ∙ b. 200 Mbits/s ∙ c. 400 Mbits/s ∙ d. 1000 Gbits/s

Description : The product of the bit rate and distance of a fiber-optic system is 2 Gbits km/s. What is the maximum rate at 5 km? ∙ a. 100 Mbits/s ∙ b. 200 Mbits/s ∙ c. 400 Mbits/s ∙ d. 1000 Gbits/s

Last Answer : c. 400 Mbits/s

A client-server system uses a satellite network, with the satellite at a height of 40,000 kms. What is the best-case delay in response to a request? (Note that the speed of light in air is 3,00,000 km/second). (A) 133.33 m sec (B) 266.67 m sec (C) 400.00 m sec (D) 533.33 m sec

Description : A client-server system uses a satellite network, with the satellite at a height of 40,000 kms. What is the best-case delay in response to a request? (Note that the speed of light in air is 3,00,000 km/second). (A) 133.33 m sec (B) 266.67 m sec (C) 400.00 m sec (D) 533.33 m sec

Last Answer : (D) 533.33 m sec Explanation: The request has to go up and down, and the response has to go up and down. The total path length traversed is thus 160.000 km. The speed of light in air and vacuum is 300,000 km/sec, so the propagation delay alone is 160,000/300,000 sec or about 533 msec.

Anitha travels 400 km by bus at 70 km/hr, 600 km by train at 80km/hr, 250 km by bike at 60 km/hr and 50 kn by car at 40 km/hr. what is the average speed for the total distance? a) 68.45 b) 69.45 c) 67.45 d) 69.77

Description : Anitha travels 400 km by bus at 70 km/hr, 600 km by train at 80km/hr, 250 km by bike at 60 km/hr and 50 kn by car at 40 km/hr. what is the average speed for the total distance? a) 68.45 b) 69.45 c) 67.45 d) 69.77

Last Answer : D Total distance = (400+250+50+600)km =1300 km Total time taken = (400/70 + 600/80+250/60+50/40) hrs =(40/7 +60/8+25/6+5/4) =(24*40)+(21*60)+(28*25)+(42*5) / 168 =960+1260+700+210 / 168 =(3130 / 168) Average speed =(1300*168 / 3130) km/hr =218400/3130 =69.77 km/hr

A 10 km long line has a characteristic impedance of 400 ohms. If line length is 100 km, the characteristic

Description : A 10 km long line has a characteristic impedance of 400 ohms. If line length is 100 km, the characteristic impedance is: (1) 4000 Ω (2) 400 Ω (3) 40 Ω (4) 4 Ω

Last Answer : A 10 km long line has a characteristic impedance of 400 ohms. If line length is 100 km, the characteristic impedance is: 400 Ω

If you swim one km, how many miles do you swim? -Do You Know?