If truly random find the probability of Sue not being chosen to cook dinner 4 nights in a row if there are 3 total that can cook.?

If truly random find the probability of Sue not being chosen to cook dinner 4 nights in a row if there are 3 total that can cook.?
by

1 Answer

Answer :

0.2
by

Related questions

There are 2 vessels. 1st vessel contains 5white and 5 blue thread roll. 2nd vessel contains 4 white and 6 black thread roll. One roll is taken at random from first vessel and put to second vessel without noticing its color. Now a roll is chosen at random from 2nd vessel. What is the probability of the second roll being a white colored roll? A) 11/13 B) 9/11 C) 13/11 D) 5/12

Description : There are 2 vessels. 1st vessel contains 5white and 5 blue thread roll. 2nd vessel contains 4 white and 6 black thread roll. One roll is taken at random from first vessel and put to second vessel without noticing its color ... second roll being a white colored roll? A) 11/13 B) 9/11 C) 13/11 D) 5/12

Last Answer : Answer: B) Case 1: first was a white roll Now it is put in second vessel, so total white rolls in second vessel = 4+1 = 5, and total rolls in second vessel = 10+1 = 11 So probability of white roll ... = 5/11+4/11 = 9/11 (added the cases because we want one of these cases to happen and not both)

750 families with 3 children were selected randomly and the following data recorded If a family member is chosen at random, compute the probability that it has : -Maths 9th

Description : 750 families with 3 children were selected randomly and the following data recorded If a family member is chosen at random, compute the probability that it has : -Maths 9th

Last Answer : (i) P(no boy child) =100 / 750 = 2 / 15 (ii) P (no girl child) = 120 /750 =4 / 25

750 families with 3 children were selected randomly and the following data recorded If a family member is chosen at random, compute the probability that it has : -Maths 9th

Description : 750 families with 3 children were selected randomly and the following data recorded If a family member is chosen at random, compute the probability that it has : -Maths 9th

Last Answer : (i) P(no boy child) =100 / 750 = 2 / 15 (ii) P (no girl child) = 120 /750 =4 / 25

An integer is chosen at random from the first two hundred positive integers. What is the probability that the integer chosen is divisible by 6 or 8 ? -Maths 9th

Description : An integer is chosen at random from the first two hundred positive integers. What is the probability that the integer chosen is divisible by 6 or 8 ? -Maths 9th

Last Answer : As there are 200 integers, total number of exhaustive, mutually exclusive and equally likely cases, i.e, n(S) = 200 Let A : Event of integer chosen from 1 to 200 being divisible by 6⇒ n(A) = 33 \(\bigg(rac{200}{6}=33rac{1}{3}\ ... (rac{25}{200}\) - \(rac{8}{200}\) = \(rac{50}{200}\) = \(rac{1}{4}\).

A natural number is chosen at random from amongst the first 300. What is the probability that the number chosen is a multiple of 2 or 3 or 5 ? -Maths 9th

Description : A natural number is chosen at random from amongst the first 300. What is the probability that the number chosen is a multiple of 2 or 3 or 5 ? -Maths 9th

Last Answer : (b) \(rac{11}{15}\)n(S) = 300 Let A : Event of getting a number divisible by 2 B : Event of getting a number divisible by 3 C : Event of getting a number divisible by 5 ∴ A ∩ B : Event of getting a number divisible by ... \(rac{320}{300}\) - \(rac{100}{300}\) = \(rac{220}{300}\) = \(rac{11}{15}\).

Three of the six vertices of a regular hexagon are chosen at random. The probability that the triangle with these vertices is equilateral equals : -Maths 9th

Description : Three of the six vertices of a regular hexagon are chosen at random. The probability that the triangle with these vertices is equilateral equals : -Maths 9th

Last Answer : (c) \(rac{1}{10}\)Let S be the sample space.Then n(S) = Number of triangles formed by selecting any three vertices of 6 vertices of a regular hexagon= 6C3 = \(rac{6 imes5 imes4}{3 imes2}\) = 20.Let A : Event that the ... Required probability = \(rac{n(A)}{n(S)}\) = \(rac{2}{20}\) = \(rac{1}{10}\).

If an integer P is chosen at random in the interval 0 ≤ p ≤ 5, the probability that the roots of the equation x^2 + px -Maths 9th

Description : If an integer P is chosen at random in the interval 0 ≤ p ≤ 5, the probability that the roots of the equation x^2 + px -Maths 9th

Last Answer : answer:

What number is chosen at random from 1 to 10. Find the probability of not selecting a multiple of 2 or a multiple of3?

Description : What number is chosen at random from 1 to 10. Find the probability of not selecting a multiple of 2 or a multiple of3?

Last Answer : Need answer

In a batch of 1160 calculators 5 were found to be defective. What is the probability that a calculator chosen at random will be defective Write the probability as a percent. Round to the nearest tenth?

Description : In a batch of 1160 calculators 5 were found to be defective. What is the probability that a calculator chosen at random will be defective Write the probability as a percent. Round to the nearest tenth?

Last Answer : What is the answer ?

If a number x is chosen at random from the numbers -2, -1, 0 1, 2. What is the probability that x 2 < 2? a. 2/5 b. 3/5 c. 1/4 d. 4/7

Description : If a number x is chosen at random from the numbers -2, -1, 0 1, 2. What is the probability that x 2 < 2? a. 2/5 b. 3/5 c. 1/4 d. 4/7

Last Answer : b. 3/5

There are 6 positive numbers and 8 negative numbers. Four numbers are chosen at random and multiplied. The probability that the product is a positive number is: a) 502/1001 b) 505/1001 c) 501/1001 d) 503/1001

Description : There are 6 positive numbers and 8 negative numbers. Four numbers are chosen at random and multiplied. The probability that the product is a positive number is: a) 502/1001 b) 505/1001 c) 501/1001 d) 503/1001

Last Answer : b) 505/1001

A cartoon contains 15 torch lights out of which 3 are defective. Two torch light are chosen at random from this cartoon. The probability that at least one of these is defective is. A) 13/35 B) 14/35 C) 11/35 D) 17/35

Description : A cartoon contains 15 torch lights out of which 3 are defective. Two torch light are chosen at random from this cartoon. The probability that at least one of these is defective is. A) 13/35 B) 14/35 C) 11/35 D) 17/35

Last Answer : Answer: A) P (none is defective) = 12c2/15c2 = (12*11/2*1)/(15*14/2*1) = 66/105=22/35 P (at least one is defective) = (1 – 22/35) =13/35

The letters of the word ‘SOCIETY’ are placed at random in a row. What is the probability that three vowels come together ? -Maths 9th

Description : The letters of the word ‘SOCIETY’ are placed at random in a row. What is the probability that three vowels come together ? -Maths 9th

Last Answer : There are 7 letters in the word SOCIETY. ∴ Total number of ways of arranging all the 7 letters = n(S) = 7!. When the case of three vowels being together is taken, then the three vowels are considered as one unit, so the ... = 5! 3! ∴ Required probability = \(rac{5! imes3!}{7!}\) = \(rac{1}{7}\)

How were the audience members of last night's debate chosen? (If you're from the south, please read this Q especially)

Description : How were the audience members of last night's debate chosen? (If you're from the south, please read this Q especially)

Last Answer : answer:Apparently they were selected by Gallup from a pool of “undecided voters” from the Nashville area. Keep watching. Some of the people are obviously trasplants to Nashville, w/ nice, easy to understand Midwestern accents :)

How would you feel with 5 1/2 hrs sleep for 2 nights in a row?

Description : How would you feel with 5 1/2 hrs sleep for 2 nights in a row?

Last Answer : I get about five to six hours every week day. It used to make me feel like shit, and I even got sick from it a couple of times, and blacked out once at work. Over time though, you get used to it. That’s probably not a good thing though.

What did people say about me. And ms. Snuggle after they camped for 99 nights in a row?

Description : What did people say about me. And ms. Snuggle after they camped for 99 nights in a row?

Last Answer : What did people say about Mr.and Mrs. Snuggle after they camped for 99 nights ... What did people say about mr and mrs snuggle after they camped for 99 days in a row? ... some people say NIGHTS is a girl ... games show that ... Give me food and I will live give me water and I will die what am I?

Among 15 players, 8 are batsman and 7 are bowlers. Find the probability that a team is chosen of 6 batsman and 5 bowlers ? -Maths 9th

Description : Among 15 players, 8 are batsman and 7 are bowlers. Find the probability that a team is chosen of 6 batsman and 5 bowlers ? -Maths 9th

Last Answer : The chosen consists of players (6 + 5). ∴ Number of ways of selecting 11 players out of 15 players = n(S) = 15C11 Let A : Event of choosing 6 batsmen of 8 batsmen and 5 bowlers of 7 bowlers Then, n(A) = 8C6 ... 7 imes6}{2}\) x \(rac{4 imes3 imes2 imes1}{15 imes14 imes13 imes12}\) = \(rac{28}{65}.\)

In a school, 22% of the students are sixth graders. What is the probability that a randomly chosen student will not be a sixth grader?

Description : In a school, 22% of the students are sixth graders. What is the probability that a randomly chosen student will not be a sixth grader?

Last Answer : 50 percent

Out of 3n consecutive natural numbers 3 natural numbers are chosen at random without replacement. -Maths 9th

Description : Out of 3n consecutive natural numbers 3 natural numbers are chosen at random without replacement. -Maths 9th

Last Answer : (c) \(rac{3n^2-3n+2}{(3n-1)(3n-2)}\)In 3n consecutive natural numbers, (i) n numbers are of the form 3p (ii) n numbers are of the form 3p + 1 (iii) n numbers are of the form 3p + 2 For the ... ) We can select one number from each set.∴ Favourable number of cases = nC3 + nC3 + nC3 + (nC1 nC1 nC1)

“Three gods, A, B, and C, are called, in some order, True, False, and Random. True always speaks truly, False always speaks falsely, but whether Random speaks truly or falsely is completely random. You must determine the identities of A, B, and C by asking three yes-or-no questions, and each question must be posed to exactly one god. The gods understand English but will answer all questions in their own language. In their unknown language, the words for “yes” and “no” are “da” and “ja,” in some order. You do not know which word means which.” -Riddles

Description : Three gods, A, B, and C, are called, in some order, True, False, and Random. True always speaks truly, False always speaks falsely, but whether Random speaks truly or falsely is completely random. You must ... are da and ja, in some order. You do not know which word means which. -Riddles

Last Answer : We're willing to bet that your brain feels pretty busted at this point. If you're ready to throw in the towel and hear the solution, we won't tell! Here are the three questions you ... start sorting out the solution with this 2008 paper, which claims to have the easiest answer to the brainteaser.

Three gods, A, B, and C, are called, in some order, True, False, and Random. True always speaks truly, False always speaks falsely, but whether Random speaks truly or falsely is completely random. You must determine the identities of A, B, and C by asking three yes-or-no questions, and each question must be posed to exactly one god. The gods understand English, but will answer all questions in their own language. In their unknown language, the words for 'yes' and 'no' are 'da' and 'ja', in some order. You do not know which word means which. So, which questions would you ask to identify each god? And no, it’s not a trick question. As a matter of fact, there are multiple ways to get the correct answer. -Riddles

Description : Three gods, A, B, and C, are called, in some order, True, False, and Random. True always speaks truly, False always speaks falsely, but whether Random speaks truly or falsely is completely random. ... a trick question. As a matter of fact, there are multiple ways to get the correct answer. -Riddles

Last Answer : 1. To god A: Does da' mean yes' if and only if you are True and if and only if B is Random? (We supposed A said, ja, making B True or False). 2. To god B: Does da mean yes' if and ... only if A is Random? Since B's True, he must say da, which means A is Random, leaving C to be False.

If you toss a die and it comes up with the number one 9 times in a row, what is the probability that it will come up with one on the next throw? -Riddles

Description : If you toss a die and it comes up with the number one 9 times in a row, what is the probability that it will come up with one on the next throw? -Riddles

Last Answer : One in six. A die has no memory of what it last showed.

6 boys and 6 girls are sitting in a row randomly. The probability that boys and girls sit alternately is -Maths 9th

Description : 6 boys and 6 girls are sitting in a row randomly. The probability that boys and girls sit alternately is -Maths 9th

Last Answer : (b) \(rac{1}{462}\)Let S be the sample space. Then, n(S) = Number of ways in which 6 boys and 6 girls can sit in a row = 12! Let E : Event of 6 girls and 6 boys sitting alternately. Then, the ... )= \(rac{2 imes6 imes5 imes4 imes3 imes2 imes1}{12 imes11 imes10 imes9 imes8 imes7}\) = \(rac{1}{462}\).

6 boys and 6 girls are seated in a row. Probability that all the boys sit together is -Maths 9th

Description : 6 boys and 6 girls are seated in a row. Probability that all the boys sit together is -Maths 9th

Last Answer : (d) \(rac{1}{132}\)Let S be the sample space for arranging 6 boys and 6 girls in a row. Then, n(S) = 12! If all 6 boys are to sit together, then consider the 6 boys as one entity. Now the ... ) = \(rac{7 imes6 imes5 imes4 imes3 imes2}{12 imes11 imes10 imes9 imes8 imes7}\) = \(rac{1}{132}\).

What is the probability of rolling a five on one die times in a row?

Description : What is the probability of rolling a five on one die times in a row?

Last Answer : Since there are 6 sides to the die, the probability of rolling a5 on one roll is 1/6. Since each roll is an independent event theprobability of the multiple results is the product of theprobability of each result. So 2 consecutive 5's would occur with aprobability of (1/6)(1/6) = 1/36

If someone offered to cook you anything you wanted for dinner, what would you ask them to cook, what would you want for dessert and drinks, who's cooking, and what would be the location for the dinner?

Description : If someone offered to cook you anything you wanted for dinner, what would you ask them to cook, what would you want for dessert and drinks, who's cooking, and what would be the location for the dinner?

Last Answer : answer:It depends who is cooking (since you mention your mom) because my MIL makes different dishes than my mom, and different from my husband, or even a chef. If I could, I'd like for my ex to ... to find. Dessert, as I have said before, my favorite is the Mounds cake from TooJays deli in Florida.

Do you have any ideas for an exciting dinner I can cook my boyfriend for his birthday?

Description : Do you have any ideas for an exciting dinner I can cook my boyfriend for his birthday?

Last Answer : answer:Ingredients 2 cups freshly squeezed orange juice, about 6 oranges, orange rinds reserved 1 (5-pound) duck, cleaned, with innards, wing tips and excess fat removed 2 oranges, zested ⅔ cup sugar 1 ... 10 minutes. Pour the orange sauce in the pan into a gravy boat and serve with carved duck.

Men, are you aware that today is national "Men Cook Dinner Day?

Description : Men, are you aware that today is national "Men Cook Dinner Day?

Last Answer : answer:So if a man cooks every day for his family, should the woman be doing the cooking tonight so maybe she'll get lucky? I find that the men who cook for their family actually know how ... who provide a balanced nutritional diet for their family daily. Plus I really hope she gets lucky tonight!

Can you help a beef ignorant woman cook herself a steak dinner?

Description : Can you help a beef ignorant woman cook herself a steak dinner?

Last Answer : answer:A tender cut such as rib eye, filet mignon or shell steak. Hot cast iron pan, a little butter and garlic, sear on both sides fast…fry some onions, too. Tender beef can be tasteless.

Can you help me cook some dinner?

Description : Can you help me cook some dinner?

Last Answer : FRIED RICE!!! haha Eggs, Rice, Beans, and Corn well you’ll need soy sauce lols

What's your favorite, "I don't want to cook dinner, but I have to eat" meal?

Description : What's your favorite, "I don't want to cook dinner, but I have to eat" meal?

Last Answer : Grilled cheese and tomato soup here.

What should I cook for dinner?

Description : What should I cook for dinner?

Last Answer : What ingredients do you have on hand, that you want to use up? We gotta have something to work with…

Does anyone have a good recipe for dinner I could cook.

Description : Does anyone have a good recipe for dinner I could cook.

Last Answer : answer:I just made ricotta gnocchi the other night. It wasn’t too hard and both the boyfriend and I thought it came out well! http://allrecipes.com/Recipe/Ricotta-Gnocchi/Detail.aspx

What is a good dish to cook for a home made dinner date?

Description : What is a good dish to cook for a home made dinner date?

Last Answer : Prime rib

What to cook for dinner?

Description : What to cook for dinner? I don't know what to cook anymore, advise me what you cook? What dishes do you cook? I cook 5 meals all the time. Thank you

Last Answer : It depends on who. When for someone who is without hot food all day or for someone who has only delicious demands. And it also depends on the wallet, time for shopping. (sorry2)

Can you cook chicken Kiev and white rice for dinner at the 4014 Wilderness Falls Trail in Texas?

Description : Can you cook chicken Kiev and white rice for dinner at the 4014 Wilderness Falls Trail in Texas?

Last Answer : As long as you don't start a forest fire you can cook anything you want.

What is the probability of a random string of numbers having a consistent pattern?

Description : What is the probability of a random string of numbers having a consistent pattern?

Last Answer : I think if it’s truely random then it is stochastic, but true randomness may not even be possible, so who knows?

A coin is tossed 500 times and we get Heads : 285 and tails : 215 times. When a coin is tossed at random, what is the probability of getting a. head? b. tail? -Maths 9th

Description : A coin is tossed 500 times and we get Heads : 285 and tails : 215 times. When a coin is tossed at random, what is the probability of getting a. head? b. tail? -Maths 9th

Last Answer : Given, Total number of events = 500 No. of times heads occur = 285 Probability of getting head when coin is tossed at random = 285/500 = 57/100 No. of times tails occur = 215 Probability of getting tails when coin is tossed at random = 215/500 = 43/100

Two coin are tossed 400 times and we get a. Two Heads : 112 times b. One Head : 160 times c. No Head : 128 times. When two coins are tossed at random, what is the probability of getting a. Two Heads b. One Head c. No Head -Maths 9th

Description : Two coin are tossed 400 times and we get a. Two Heads : 112 times b. One Head : 160 times c. No Head : 128 times. When two coins are tossed at random, what is the probability of getting a. Two Heads b. One Head c. No Head -Maths 9th

Last Answer : Given, Total number of events = 400 (a) No. of times two heads occur = 112 Probability of getting two heads = 112/400 = 7/25 (b) No. of times one heads occur = 160 Probability of getting one heads = 160/400 = 2/5 (c) No. of times no heads occur = 128 Probability of getting no heads = 128/400 = 8/25

In a class, there are x girls and y boys, a student is selected at random, then find the probability of selecting a boy. -Maths 9th

Description : In a class, there are x girls and y boys, a student is selected at random, then find the probability of selecting a boy. -Maths 9th

Last Answer : Number of boys = y Total students = (x + y) Thus,P(a boy)= y/(x+y)

A coin is tossed 500 times and we get Heads : 285 and tails : 215 times. When a coin is tossed at random, what is the probability of getting a. head? b. tail? -Maths 9th

Description : A coin is tossed 500 times and we get Heads : 285 and tails : 215 times. When a coin is tossed at random, what is the probability of getting a. head? b. tail? -Maths 9th

Last Answer : Given, Total number of events = 500 No. of times heads occur = 285 Probability of getting head when coin is tossed at random = 285/500 = 57/100 No. of times tails occur = 215 Probability of getting tails when coin is tossed at random = 215/500 = 43/100

Two coin are tossed 400 times and we get a. Two Heads : 112 times b. One Head : 160 times c. No Head : 128 times. When two coins are tossed at random, what is the probability of getting a. Two Heads b. One Head c. No Head -Maths 9th

Description : Two coin are tossed 400 times and we get a. Two Heads : 112 times b. One Head : 160 times c. No Head : 128 times. When two coins are tossed at random, what is the probability of getting a. Two Heads b. One Head c. No Head -Maths 9th

Last Answer : Given, Total number of events = 400 (a) No. of times two heads occur = 112 Probability of getting two heads = 112/400 = 7/25 (b) No. of times one heads occur = 160 Probability of getting one heads = 160/400 = 2/5 (c) No. of times no heads occur = 128 Probability of getting no heads = 128/400 = 8/25

In a class, there are x girls and y boys, a student is selected at random, then find the probability of selecting a boy. -Maths 9th

Description : In a class, there are x girls and y boys, a student is selected at random, then find the probability of selecting a boy. -Maths 9th

Last Answer : Number of boys = y Total students = (x + y) Thus,P(a boy)= y/(x+y)

What is the probability that a number selected at random from the set of numbers {1, 2, 3, …, 100} is a perfect cube? -Maths 9th

Description : What is the probability that a number selected at random from the set of numbers {1, 2, 3, …, 100} is a perfect cube? -Maths 9th

Last Answer : (a) \(rac{1}{25}\) Let us assume S as the sample space in all questions. S means the set denoting the total number of outcomes possible. Let S = {1, 2, 3, , 100} be the sample space. Then, n(S) = 100 Let A : ... ∴Required probability P(A) = \(rac{n(A)}{n(S)}\) = \(rac{4}{100}\) = \(rac{1}{25}\)

From a group of 3 man and 2 women, two person are selected at random. Find the probability that at least one women is selected. -Maths 9th

Description : From a group of 3 man and 2 women, two person are selected at random. Find the probability that at least one women is selected. -Maths 9th

Last Answer : (b) \(rac{7}{10}\)Total number of ways of selecting 2 persons at random out of 5 persons = 5C2 ∴ n(S) = 5C2 = \(rac{|\underline5}{|\underline3|\underline2}\) = \(rac{5 imes4}{2 imes1}\) = 10Let A : Event of selecting ... = 2 3 + 1 = 7 ∴ Required probability = \(rac{n(A)}{n(S)}\) = \(rac{7}{10}\).

A bag contains 7 red and 5 green balls. The probability of drawing all four balls asred balls, when four balls are drawn at random is -Maths 9th

Description : A bag contains 7 red and 5 green balls. The probability of drawing all four balls asred balls, when four balls are drawn at random is -Maths 9th

Last Answer : (b) \(rac{7}{99}\)There are (7 + 5) = 12 balls in the bag. 4 balls can be drawn at random from 12 balls in 12C4 ways. ∴ n(S) = 12C4 = \(rac{|\underline{7}}{|\underline3|\underline4}\) = \(rac{7 imes6 imes5}{3 ... ) = 35∴ Required probability = \(rac{n(A)}{n(S)}\) = \(rac{35}{495}\) = \(rac{7}{99}\).

Five horses are in a race. Mr A. Selects two of the horses at random and bets on them. The probability that Mr A selected the winning horse is -Maths 9th

Description : Five horses are in a race. Mr A. Selects two of the horses at random and bets on them. The probability that Mr A selected the winning horse is -Maths 9th

Last Answer : (b) \(rac{2}{5}\)As each horse has equal chance of winning the race, Number of ways in which one of the five horses wins the race = 5C1 ∴ n(S) =5C1 = \(rac{|\underline5}{|\underline4|\underline1}\) 5To find the chance ... n(E) = 2C1 = 2 ∴ Required probability = \(rac{n(E)}{n(S)}\) = \(rac{2}{5}\).

Two cards are drawn at random from a well-shuffled pack of 52 cards. What is the probability that either both are black or both are kings ? -Maths 9th

Description : Two cards are drawn at random from a well-shuffled pack of 52 cards. What is the probability that either both are black or both are kings ? -Maths 9th

Last Answer : (b) \(rac{55}{221}\)S : Drawing 2 cards out of 52 cards ⇒ n(S) = 52C2 = \(rac{|\underline{52}}{|\underline{52}|\underline2}\) = \(rac{52 imes51}{2}\) = 1326A : Event of drawing 2 black cards out of 26 black cards⇒ n ... ) + \(rac{6}{1326}\) - \(rac{1}{1326}\) = \(rac{330}{1326}\) = \(rac{55}{221}\).