Is 4000 m greater than 40 km?

Is 4000 m greater than 40 km?
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Is 4000 m is greater than 40 km?

Description : Is 4000 m is greater than 40 km?

Last Answer : No because 4000 m equals 4 km which is less than 40 km

. The three-stage Agni-V has a range of (a) 2000 KM (b) 3000 KM (c) 4000 KM (d) 5000 KM

Description : . The three-stage Agni-V has a range of (a) 2000 KM (b) 3000 KM (c) 4000 KM (d) 5000 KM

Last Answer : (d) 5000 KM

Which is greater 40 meters or 4 km?

Description : Which is greater 40 meters or 4 km?

Last Answer : 4 km equals 4000 meters which is greater than 40 meters

Is 4000 ponds greater than 2 tons?

Description : Is 4000 ponds greater than 2 tons?

Last Answer : 4000 pounds = 2 tons

A common-emitter circuit has an input voltage of 0.1 volt, an output voltage of 2.0 volts, an input current of 0.5 milliamps, and an output current of 10 milliamps. What is the power gain? A. 20 B. 40 C. 400 D. 4000

Description : A common-emitter circuit has an input voltage of 0.1 volt, an output voltage of 2.0 volts, an input current of 0.5 milliamps, and an output current of 10 milliamps. What is the power gain? A. 20 B. 40 C. 400 D. 4000

Last Answer : Answer: C

A and B established a firm together. A’s investment was thrice that of B’s. A also kept the investment for twice as much time as B. If B got a profit of 4000, what was the total profit? A.30,000 B.28,000 C.40,000 D.45,000

Description : A and B established a firm together. A’s investment was thrice that of B’s. A also kept the investment for twice as much time as B. If B got a profit of 4000, what was the total profit? A.30,000 B.28,000 C.40,000 D.45,000

Last Answer : Answer- B(28,000) Explanation:- let B’s investment= X then A’s investment= 3X lets tim for B = t then,A’s time= 2t A:B 3X x 3t : X x t 6:1 B’s share= 1/7 x total = 4000 total=28,000

In a business, X,Y and Z inversed Rs.20,000/-,Rs.30,000/- and Rs.40,000/- respectively. After 1 year X adds Rs.10000/- to the initial investment.Y and Z withdrew Rs.10000/- and Rs.15,000/- respectively. After 2 years the total profit is Rs.9900/-. What is X’s share?. A) 3000 B) 2700 C) 3600 D) 4000

Description : In a business, X,Y and Z inversed Rs.20,000/-,Rs.30,000/- and Rs.40,000/- respectively. After 1 year X adds Rs.10000/- to the initial investment.Y and Z withdrew Rs.10000/- and Rs.15,000/- respectively. After 2 years the total profit is Rs.9900/-. What is X’s share?. A) 3000 B) 2700 C) 3600 D) 4000

Last Answer : Answer: A)  X's Share = Rs.20000/- per first 1 year, Next year 10000/- added = Rs.20000/- 1 + Rs.30000/- 1 = Rs.50000/- Y's Share = Rs.30000/- per first 1 year, Next year 10000/- reduced = Rs.30000 ... /-  1 part------> Rs300/- Then, X's share is 10 parts = Rs.300/- 10 parts = Rs.3000/-

Is 6 km greater or smaller or equal than 660 m?

Description : Is 6 km greater or smaller or equal than 660 m?

Last Answer : 6 km equals 6000 m which is greater than 660 m

A car moving with a speed of 40 km/hr can be stopped by applying brakes after at least 2 m. If the same car is moving with a speed of 80 km/hr. What i

Description : A car moving with a speed of 40 km/hr can be stopped by applying brakes after at least 2 m. If the same car is moving with a speed of 80 km/hr. What i

Last Answer : A car moving with a speed of 40 km/hr can be stopped by applying brakes after at least 2 m. If the same car is moving ... A. 2 m B. 4 m C. 6 m D. 8 m

Speed of sound in water is 1500 m s-1, depth of water when reflected sound waves are detected after 0.40 s is A. 700 m B. 600 km C. 600 m D. 750 km

Description : Speed of sound in water is 1500 m s-1, depth of water when reflected sound waves are detected after 0.40 s is A. 700 m B. 600 km C. 600 m D. 750 km

Last Answer : 600 m

A district road with a bituminous pavement has a horizontal curve of 1000 m for a design speed of 75 km ph. The super-elevation is (A) 1 in 40 (B) 1 in 50 (C) 1 in 60 (D) 1 in 70

Description : A district road with a bituminous pavement has a horizontal curve of 1000 m for a design speed of 75 km ph. The super-elevation is (A) 1 in 40 (B) 1 in 50 (C) 1 in 60 (D) 1 in 70

Last Answer : Answer: Option A

Two trains of equal length are running on parallel lines in the same direction at 46 km/hr and 36 km/hr. The faster train passes the slower train in 36 seconds. The length of each train is: A.40 m B.55 m C.65 m D.50 m E.None of these

Description : Two trains of equal length are running on parallel lines in the same direction at 46 km/hr and 36 km/hr. The faster train passes the slower train in 36 seconds. The length of each train is: A.40 m B.55 m C.65 m D.50 m E.None of these

Last Answer : Answer- D (50) Explanation – Relative speed= total lengths/time (46-36) x 5/18 = [L + L ] / 36 10 x (5/18) x36 x (1/2)= L L=50 m

Two trains are running at 40 km/hr and 20 km/hr respectively in the same direction. Fast train completely passes a man sitting in the slower train in 5 seconds. What is the length of the fast train? A.27 7/9 m B.28 m C.29 m D.30 2/7 m E.None of these

Description : Two trains are running at 40 km/hr and 20 km/hr respectively in the same direction. Fast train completely passes a man sitting in the slower train in 5 seconds. What is the length of the fast train? A.27 7/9 m B.28 m C.29 m D.30 2/7 m E.None of these 

Last Answer : Answer – A (27 7/9 m) Explanation – When SAME direction- MINUS Relative speed = (40-20) km/hr = [20 x 5/18] m/sec = [50/9] m/sec. Length of faster train = sxt=[50/9 x 5] m = 250/9 m = 27 7/9 m.

A client-server system uses a satellite network, with the satellite at a height of 40,000 kms. What is the best-case delay in response to a request? (Note that the speed of light in air is 3,00,000 km/second). (A) 133.33 m sec (B) 266.67 m sec (C) 400.00 m sec (D) 533.33 m sec

Description : A client-server system uses a satellite network, with the satellite at a height of 40,000 kms. What is the best-case delay in response to a request? (Note that the speed of light in air is 3,00,000 km/second). (A) 133.33 m sec (B) 266.67 m sec (C) 400.00 m sec (D) 533.33 m sec

Last Answer : (D) 533.33 m sec Explanation: The request has to go up and down, and the response has to go up and down. The total path length traversed is thus 160.000 km. The speed of light in air and vacuum is 300,000 km/sec, so the propagation delay alone is 160,000/300,000 sec or about 533 msec. 

Ravi walks to and fro to a Gym. He spends 30 minutes in gym. If he walks at speed of 20 km an hour, he returns to home at 8.00 a.m. If he walks at 30 km an hour, he returns to home at 7.30 a.m. How fast must he walk in order to return at 7.15 hours? a) 40 km/hr b) 30 km/hr c) 60 km/hr d) 50 km/hr

Description : Ravi walks to and fro to a Gym. He spends 30 minutes in gym. If he walks at speed of 20 km an hour, he returns to home at 8.00 a.m. If he walks at 30 km an hour, he returns to home at 7.30 a.m. How fast must he walk in order to return at 7.15 hours? a) 40 km/hr b) 30 km/hr c) 60 km/hr d) 50 km/hr

Last Answer :  A As per the question, let D be the total distance and ‘t’ is the time taken. So we have: D=20t 20t =30(t-0.5) 20t=30t-15 10t=15 t=3/2 D= 30 km Now, for the condition given we have: 30=S(t-3/4) 30=S(3/2-3/4) 30=S((6-3)/4) 30=S(3/4) S=40 km/hr

A train 170 m long is running at a speed of 22.5 km/hr. what time will it take to cross a 80m long bridge? A) 20 sec B) 40 sec C) 15 sec D) 30sec

Description : A train 170 m long is running at a speed of 22.5 km/hr. what time will it take to cross a 80m long bridge? A) 20 sec B) 40 sec C) 15 sec D) 30sec

Last Answer : ANSWER:B Explanation: Length of the train = 170 m Length of the bridge = 80 m Therefore, length of the train + length of the bridge = (170 + 80) m = 250m Speed of the train = 22.5 km/hr Speed ... .25m/sec Therefore, time taken by the train to cross the bridge = 250 m/6.25 m/sec. = 40 seconds.

Density of water in kg m-3 is A. 1000 B. 100 C. 10 000 D. 4000

Description : Density of water in kg m-3 is A. 1000 B. 100 C. 10 000 D. 4000

Last Answer : 1000

Elevation of temperate region from sea level ranges: a. 1000-2000 m b. 2500-3000 m c. 3500-4000 m d. b & c

Description : Elevation of temperate region from sea level ranges: a. 1000-2000 m b. 2500-3000 m c. 3500-4000 m d. b & c

Last Answer : b & c

Total pressure on a lmxlm gate immersed vertically at a depth of 2 m below the free water surface will be (A) 1000 kg (B) 4000 kg (C) 2000 kg (D) 8000 kg

Description : Total pressure on a lmxlm gate immersed vertically at a depth of 2 m below the free water surface will be (A) 1000 kg (B) 4000 kg (C) 2000 kg (D) 8000 kg

Last Answer : Answer: Option A

Is 7500000 cm greater than 750 km?

Description : Is 7500000 cm greater than 750 km?

Last Answer : i dont know

India's latitudinal and longitudinal extent measured in degrees are almost the same, but its north-south extent measured in km is greater than its east-west extent. This is due to the fact that (a) longitudes are not parallel lines (b) the distance between latitudes remains the same but the distance between longitudes is greatest at the Equator and nil at the poles where all longitudes join (c) all longitudes with their opposites form great circles (d) the earth is not a perfect sphere

Description : India's latitudinal and longitudinal extent measured in degrees are almost the same, but its north-south extent measured in km is greater than its east-west extent. This is due to the fact that (a) ... (c) all longitudes with their opposites form great circles (d) the earth is not a perfect sphere

Last Answer : Ans: (b)

Is 56 cm greater or 56000 km greater?

Description : Is 56 cm greater or 56000 km greater?

Last Answer : The second one.

The distance (in km) of 40 engineers -Maths 9th

Description : The distance (in km) of 40 engineers -Maths 9th

Last Answer : Frequency distribution of above data in tabular form is given as : It is observed that 36 engineers out of 40 live at a distance not more than 20 km from their residence.

A diver rowing at the rate of 5 km/h in still water takes double the time in going 40 km upstream as in going 40 km downstream. Find the speed of the stream. -Maths 10th

Description : A diver rowing at the rate of 5 km/h in still water takes double the time in going 40 km upstream as in going 40 km downstream. Find the speed of the stream. -Maths 10th

Last Answer : 5/3 km/h Step-by-step explanation: Speed in still water = 5km/h Define x: Let the speed of the steam be x Upstream speed = (5 - x) km/h Downstream speed = (5 + x) km/h Time taken going upstream: Time taken = ... 40x = 400 - 80x 120x = 200 x = 200 120 = 5/3 The speed of the stream is 5/3 km/h

A car moving with a speed of 40 km/h can be stopped by applying brakes after at least 2m. If the same car is moving with a speed of 80 km/h., what is

Description : A car moving with a speed of 40 km/h can be stopped by applying brakes after at least 2m. If the same car is moving with a speed of 80 km/h., what is

Last Answer : A car moving with a speed of 40 km/h can be stopped by applying brakes after at least 2m. If the same car is moving ... A. 2 m B. 4 m C. 6 m D. 8 m

A train covers the first half of the distance between two stations with a speed of 40 km/h and the other half with 60 km/h. Then its average speed is

Description : A train covers the first half of the distance between two stations with a speed of 40 km/h and the other half with 60 km/h. Then its average speed is

Last Answer : A train covers the first half of the distance between two stations with a speed of 40 km/h and the other half with ... 48 km/h C. 52 km/h D. 100 km/h

A car moves at a constant speed of 60 km/hr for 1 km and 40 km/hr for next 1 km. What is the average speed of the car?

Description : A car moves at a constant speed of 60 km/hr for 1 km and 40 km/hr for next 1 km. What is the average speed of the car?

Last Answer : A car moves at a constant speed of 60 km/hr for 1 km and 40 km/hr for next 1 km. What is the average speed of the car?

What is the average speed in kmh for a car that travels 50.0 km in 40.0 min?

Description : What is the average speed in kmh for a car that travels 50.0 km in 40.0 min?

Last Answer : It is travelling at 75 kmph.

How much distance was traveled by first Train of India? A. 30 km B. 34 km C. 40 km D. 44 km

Description : How much distance was traveled by first Train of India? A. 30 km B. 34 km C. 40 km D. 44 km

Last Answer : B [34 km] Explanation: India's first train ran from Mumbai to Thane in 1853. The first train on the Indian sub-continent ran from Bori Bunder in Mumbai to Thane at 3.30 pm on April 16, 1853.

Part of a microwave link can be approximated by free space conditions. The antenna gain are each 40 dB, the frequency is 10 GHz, and the path length is 80 km. Calculate the receive power for a transmitted power of 10 W? A. 0.871 μW B. 871 μW C. 0.871 mW D. 871 nW

Description : Part of a microwave link can be approximated by free space conditions. The antenna gain are each 40 dB, the frequency is 10 GHz, and the path length is 80 km. Calculate the receive power for a transmitted power of 10 W? A. 0.871 μW B. 871 μW C. 0.871 mW D. 871 nW

Last Answer : A. 0.871 μW

For a space wave transmission, the radio horizon distance of a transmitting antenna with a height of 100 meters is approximately:A. 10 km B. 40 km C. 100 km D. 400 km

Description : For a space wave transmission, the radio horizon distance of a transmitting antenna with a height of 100 meters is approximately: A. 10 km B. 40 km C. 100 km D. 400 km

Last Answer : B. 40 km

How far away is the radio horizon of an antenna 100ft high? A. 14.14 mi B. 40km C. 14.14 km D. 40 mi

Description : How far away is the radio horizon of an antenna 100ft high? A. 14.14 mi B. 40km C. 14.14 km D. 40 mi

Last Answer : A. 14.14 mi

what is the height of The atmosphere layer mesosphere? A. 85 km (Answer) B. 50 km C. 40 km D. 10 km

Description : what is the height of The atmosphere layer mesosphere? A. 85 km (Answer) B. 50 km C. 40 km D. 10 km

Last Answer : A. 85 km (Answer)

Mass of Earth when it's radius is 6400 km and gravitational field strength is 9.81 N kg-1 is A. 6.0 × 1024 kg B. 5 × 1023 kg C. 40 × 109 kg D. 9 × 1024 kg

Description : Mass of Earth when it's radius is 6400 km and gravitational field strength is 9.81 N kg-1 is A. 6.0 × 1024 kg B. 5 × 1023 kg C. 40 × 109 kg D. 9 × 1024 kg

Last Answer : 5 × 1023 kg

A boat goes 30 km upstream and 44 km downstream in 10 hours. In 13 hours it can go 40 km upstream and 55 km downstream. Then what is the speed of the stream? (a) 3km/hr (b) 5km/hr (c) 6km/hr (d) 7km/hr

Description : A boat goes 30 km upstream and 44 km downstream in 10 hours. In 13 hours it can go 40 km upstream and 55 km downstream. Then what is the speed of the stream? (a) 3km/hr (b) 5km/hr (c) 6km/hr (d) 7km/hr

Last Answer : (a) 3km/hr

A boat goes 30 km upstream and 44 km downstream in 10 hours. In 13 hours it can go 40 km upstream and 55 km downstream. Then what is the speed of the stream? (a) 3km/hr (b) 5km/hr (c) 6km/hr (d) 7km/hr

Description : A boat goes 30 km upstream and 44 km downstream in 10 hours. In 13 hours it can go 40 km upstream and 55 km downstream. Then what is the speed of the stream? (a) 3km/hr (b) 5km/hr (c) 6km/hr (d) 7km/hr

Last Answer : (a) 3km/hr

Express Parcel Post is all about value for money. It costs just INR 25 within the city for 2 kg parcels and INR 40 for towns within 500 km. Above statement is a) True b) False

Description : Express Parcel Post is all about value for money. It costs just INR 25 within the city for 2 kg parcels and INR 40 for towns within 500 km. Above statement is a) True b) False

Last Answer : a) True

While designing hair pin bends on highways, the minimum (A) Designed speed is 20 km/hour(B) Gradient is 1 in 40 (C) Gradient is 1 in 200 (D) All the above

Description : While designing hair pin bends on highways, the minimum (A) Designed speed is 20 km/hour (B) Gradient is 1 in 40 (C) Gradient is 1 in 200 (D) All the above

Last Answer : Answer: Option D

If a train runs at 40 km/hour, it reaches its destination late by 11 minutes. But if it runs at 50 km/hour, it is late by 5 minutes only. The correct time (in minutes) for the train to complete the journey is? a) 13 b) 15 c) 19 d) 21 e) None of these

Description : If a train runs at 40 km/hour, it reaches its destination late by 11 minutes. But if it runs at 50 km/hour, it is late by 5 minutes only. The correct time (in minutes) for the train to complete the journey is? a) 13 b) 15 c) 19 d) 21 e) None of these

Last Answer : If the distance be x km, then x/40-x/50=6/60 x/4-x/5=1 x=20 km. Required time = (20/40) hour – 11 minutes = (1/2×60-11) minutes = 19 minutes Answer: c)

A person covered a certain distance by bus at the rate of 40 kmph and walked back to the initial point at the rate of 6 kmph. The whole journey took 13 hours and 48 minutes. What distance did he walk? a) 60km b) 64 km c) 70km d) 72km e) 80 km

Description : A person covered a certain distance by bus at the rate of 40 kmph and walked back to the initial point at the rate of 6 kmph. The whole journey took 13 hours and 48 minutes. What distance did he walk? a) 60km b) 64 km c) 70km d) 72km e) 80 km

Last Answer : Let the distance be x km. then (x/40) + (x/6) = 13 + (48/60) = 69/5 Answer is: d)

A train starts from Delhi and reaches Lucknow in 24.5 hours. If it travels the first half of journey at 30 kmph and second half at 40 kmph then what is the total distance it travelled? 1) 750 km 2) 800 km 3) 840 km 4) 900 km 5) 920 km

Description : A train starts from Delhi and reaches Lucknow in 24.5 hours. If it travels the first half of journey at 30 kmph and second half at 40 kmph then what is the total distance it travelled? 1) 750 km 2) 800 km 3) 840 km 4) 900 km 5) 920 km

Last Answer : 3) 840 km

The loss in single-mode fiber-optic cable due to the glass is about: a. 40 dB per km b. 4 db per km c. 0.4 dB per km d. zero loss

Description : The loss in single-mode fiber-optic cable due to the glass is about: a. 40 dB per km b. 4 db per km c. 0.4 dB per km d. zero loss

Last Answer : c. 0.4 dB per km

Transmission voltage of ll kV is normally used for distances upto (a) 20—25 km (b) 40—50 km (c) 60—70 km (d) 80—100 km

Description : Transmission voltage of ll kV is normally used for distances upto (a) 20—25 km (b) 40—50 km (c) 60—70 km (d) 80—100 km

Last Answer : (a) 20—25 km

A bus starts at bus stop and reaches a destination in 4 hours. If it travels first and second half at the speed of 40 km/hr and 50 km/hr respectively then the distance between bus stop and destination is a) 177.7 km b) 154.2 km c) 163.5 km d) 147.3 km

Description : A bus starts at bus stop and reaches a destination in 4 hours. If it travels first and second half at the speed of 40 km/hr and 50 km/hr respectively then the distance between bus stop and destination is a) 177.7 km b) 154.2 km c) 163.5 km d) 147.3 km

Last Answer : A Let the distance between bus stop and destination be X. The total time taken by the bus to cover X = 4 hours Since X/2 by 40km/hr and remaining X/2 by 50km/hr Then by Time = distance/speed, we have ... = 1600 9X = 1600 X = 1600/9 = 177.7 Hence 177.7 km is the required answer.

Raghu starts a bike at 40 km/hr and he increases his speed in every hour by 4 km/hr. Then the maximum distance covered by him in 12 hours is: a) 744 km b) 658 km c) 436 km d) 512 km

Description : Raghu starts a bike at 40 km/hr and he increases his speed in every hour by 4 km/hr. Then the maximum distance covered by him in 12 hours is: a) 744 km b) 658 km c) 436 km d) 512 km

Last Answer : A Speed of the rider = 40km/hr. Distance covered in 1st hour = 40 km. He increased his speed in every 1 hour by 4 km/hr. Distance covered in every 1 hours will be, 44, 48, ,... upto 12 terms.(for 12 hours). ... (2(40)+(11)4) = 6(80 + 44) = 6(124) = 744. Hence, he covers 744 km in 12 hours.

Anitha travels 400 km by bus at 70 km/hr, 600 km by train at 80km/hr, 250 km by bike at 60 km/hr and 50 kn by car at 40 km/hr. what is the average speed for the total distance? a) 68.45 b) 69.45 c) 67.45 d) 69.77

Description : Anitha travels 400 km by bus at 70 km/hr, 600 km by train at 80km/hr, 250 km by bike at 60 km/hr and 50 kn by car at 40 km/hr. what is the average speed for the total distance? a) 68.45 b) 69.45 c) 67.45 d) 69.77

Last Answer : D Total distance = (400+250+50+600)km =1300 km Total time taken = (400/70 + 600/80+250/60+50/40) hrs =(40/7 +60/8+25/6+5/4) =(24*40)+(21*60)+(28*25)+(42*5) / 168 =960+1260+700+210 / 168 =(3130 / 168) Average speed =(1300*168 / 3130) km/hr =218400/3130 =69.77 km/hr

A girl covered a definite distance at same speed. Had she moved 6 km/hr faster, she would have taken 30 mins less. If she had moved 4 km/hr slower, she would have taken 30 mins more. The distance (in km) is. a) 50 b) 40 c) 70 d) 60

Description : A girl covered a definite distance at same speed. Had she moved 6 km/hr faster, she would have taken 30 mins less. If she had moved 4 km/hr slower, she would have taken 30 mins more. The distance (in km) is. a) 50 b) 40 c) 70 d) 60

Last Answer : D Let distance = x km Rate = y km/hr x/y - x / (y+6) = 30/60 (x(y+6)-xy) / y(y+6) = ½ (xy +6x - xy) / y(y+6) = ½ 12x = y(y+6) ------------>1 And x/ (y-4) - x/y = 30/60 (Xy - x(y-4 ... = (y+6) / (y-4) 3y - 12 = 2y +12 Y = 24km Put y value in 1 we get 12x = 24 (24+6) 12x = 24 *30 X=60km

A taxi driver make a trip from the plains to ooty which are 340km apart at an average speed of 60km/hr. In the return trip, he covers the speed distance at an average of 30 km/hr. the average speed of the taxi over the entire distance of 680 km is a) 30 b) 40 c) 50 d) 60

Description : A taxi driver make a trip from the plains to ooty which are 340km apart at an average speed of 60km/hr. In the return trip, he covers the speed distance at an average of 30 km/hr. the average speed of the taxi over the entire distance of 680 km is a) 30 b) 40 c) 50 d) 60 

Last Answer : B Average speed =(2xy/( x+y)) km/hr Given x =60 km/hr y = 30km/hr Average speed = (2*60*30/ (60+30)) km/hr =(3600/ 90) =40 km/hr

Tharun has to cover a distance of 84 km in 40 minutes. If he covers one-half of the distance in one-fourth of the total time, to cover the remaining distance in the remaining time, what should be his speed in km/hr? a) 42 km/hr b) 64km/hr c) 84km/hr d)76km/hr

Description : Tharun has to cover a distance of 84 km in 40 minutes. If he covers one-half of the distance in one-fourth of the total time, to cover the remaining distance in the remaining time, what should be his speed in km/hr? a) 42 km/hr b) 64km/hr c) 84km/hr d)76km/hr

Last Answer : C Tharun needs to cover 84 km in 40minutes Given that he covers one-half of the distance in one-fourth of the total time ⇒ he covers half of 84km in one-fourth of 40 minutes ⇒ He covers 42 km in ¼ * ... Distance =42km Time =30minutes =1/2 hr Required Speed = Distance / Time =42/(1/2)=84 km/hr

1/2of a certain travel is covered at the rate of 30km/hr, one-third at the rate of 40 km/hr and the rest at 35km/hr. Find the average speed for the whole travel. A) 33 1/3 B) 33 3/5 C) 34 3/7 D) None of these

Description : 1/2of a certain travel is covered at the rate of 30km/hr, one-third at the rate of 40 km/hr and the rest at 35km/hr. Find the average speed for the whole travel. A) 33 1/3 B) 33 3/5 C) 34 3/7 D) None of these

Last Answer : B) let the total travel be X km.  Then X/2 km at the speed of 30 km/hr and X/3 km at 40 km/hr and the rest distance( X - X/2 - X/3) =1/6 X at the speed of 35km/hr. Total time taken during the travel ... 2*30 hrs+ X/3*40hrs+ X/6*35hrs = 5X/168 hrs Average speed =X/(5x/168) = 168/5 =33 3/5km hr