What is the greatest common factor of 28 and 42 56 70?

Description : Find the greatest unit of time with which 5 hours 15 minutes and 8 hours 24 minutes can both be represented as integers. (a) 70 min. (b) 63 min. (c) 48 min. (d) 42 min.

Last Answer : 63 min.

What is the greatest common factor of 28 plus 20 distributive?

Description : What is the greatest common factor of 28 plus 20 distributive?

Last Answer : 4(7 + 5)

What is the Greatest common factor of 5 70 and 35?

Description : What is the Greatest common factor of 5 70 and 35?

Last Answer : The GCF of the given three numbers is 5

What is actual length in feet of a one-half wavelength of a coax with a velocity factor of 0.59 at 26 MHz? A. 11.16 B. 40.29 C. 42.46 D. 46.28

Description : What is actual length in feet of a one-half wavelength of a coax with a velocity factor of 0.59 at 26 MHz? A. 11.16 B. 40.29 C. 42.46 D. 46.28

Last Answer : A. 11.16

What is the least common multiple of 16 28 and 56?

Description : What is the least common multiple of 16 28 and 56?

Last Answer : The LCM of the given three numbers is 112

What is the greatest common of 9 18 and 42?

Description : What is the greatest common of 9 18 and 42?

Last Answer : The GCF of the given three numbers is 3

Rosa can run 4 miles in 56 minutes. How many miles does Rosa run if she runs for 42 minutes?

Description : Rosa can run 4 miles in 56 minutes. How many miles does Rosa run if she runs for 42 minutes?

Last Answer : 2.99 miles.

Number of human live lost during 1980-2010 due to natural and induced hazards in India? a. 1,42,265 b. 1,56,897 c. 1,43,039 d. 1,23,987

Description : Number of human live lost during 1980-2010 due to natural and induced hazards in India? a. 1,42,265 b. 1,56,897 c. 1,43,039 d. 1,23,987

Last Answer : c. 1,43,039

A sample of natural gas containing 80% methane (CH4 ) and rest nitrogen (N2 ) is burnt with 20% excess air. With 80% of the combustibles producing CO2 and the remainder going to CO, the Orsat analysis in volume percent is (A) CO2 : 6.26, CO : 1.56, O2 : 3.91, H2O :15.66, N2 : 72.60 (B) CO2 : 7.42, CO : 1.86, O2 : 4.64, N2 :86.02 (C) CO2 : 6.39, CO : 1.60, O2 : 3.99, H2O:25.96, N2 :72.06 (D) CO2 : 7.60, CO : 1.90, O2 : 4.75, N2 : 85.74

Description : A sample of natural gas containing 80% methane (CH4 ) and rest nitrogen (N2 ) is burnt with 20% excess air. With 80% of the combustibles producing CO2 and the remainder going to CO, the Orsat analysis in volume percent is (A) CO2 : 6 ... 96, N2 :72.06 (D) CO2 : 7.60, CO : 1.90, O2 : 4.75, N2 : 85.74

Last Answer : (B) CO2 : 7.42, CO : 1.86, O2 : 4.64, N2 :86.02

The maximum comfortable retardation applied to moving vehicles, is (A) 3.42 m/sec2 (B) 4.42 m/sec2 (C) 5.56 m/sec2 (D) 7.80 m/sec2

Description : The maximum comfortable retardation applied to moving vehicles, is (A) 3.42 m/sec2 (B) 4.42 m/sec2 (C) 5.56 m/sec2 (D) 7.80 m/sec2

Last Answer : Answer: Option A

5, 8, 12, 18, 24, 30, 36, 42, ____ a) 52 b) 46 c) 48 d) 54 e) 56

Description : 5, 8, 12, 18, 24, 30, 36, 42, ____ a) 52 b) 46 c) 48 d) 54 e) 56

Last Answer : Each term in the series is the addition of successive prime numbers. Like Prime numbers are2, 3, 5, 7, 11, 13, 17, 19, 23, 29 and so on. So first term is addition of (2 + 3). Ie 5, then second term is (3 + 5) ie ... +17)ie. 30, then (17+19)ie.36, then (19+23)ie., 42, then (23+29)i.e. 52. Answer: a)

2, 6, 12, 20 , 30 , 42 ? (a) 50 (b) 52 (c) 54 (d) 56

Description : 2, 6, 12, 20 , 30 , 42 ? (a) 50 (b) 52 (c) 54 (d) 56

Last Answer : The difference between the numbers in this series is increased by 2 at each step.

A sum of amount of money is adequate to pay peter’s salary for 42 days and Harish’s salary for 56 days. The same money is adequate to pay the salary of both for. a) 12 days b) 24 days c) 36 days d) 48 days

Description : A sum of amount of money is adequate to pay peter’s salary for 42 days and Harish’s salary for 56 days. The same money is adequate to pay the salary of both for. a) 12 days b) 24 days c) 36 days d) 48 days

Last Answer : B Let the total money be Rs.x Peter’s 1 day salary = Rs. x/42 Harish 1 day salary = Rs. x/56 (peter+harish)’s 1 day salary = Rs(x/42+x/56) =(4x+3x)/168 =7x/168 =x/24 Money is adequate to pay the salary of both for 24 days.

The sum of three numbers is 210. If the ratio between the first and second number be 2:3 and that between the second and third be 4:5, then the difference between the first and third number? a) 21 b) 35 c) 42 d) 56 e) None of these

Description : The sum of three numbers is 210. If the ratio between the first and second number be 2:3 and that between the second and third be 4:5, then the difference between the first and third number? a) 21 b) 35 c) 42 d) 56 e) None of these

Last Answer : Answer: C a: b = 2:3 and b:c = 4:5 a:b:c = 8:12:15 Difference between first and third number = (7/35)*210 = 42

Find the median of the data 35, 28, 49, 56, 79, 81, 73 and 80.

Description : Find the median of the data 35, 28, 49, 56, 79, 81, 73 and 80.

Last Answer : Find the median of the data 35, 28, 49, 56, 79, 81, 73 and 80. A. 64.5 B. 65 C. 65.5 D. 66

A Pitot tube indicates 5 cm of water (manometer) when it is being used for measuring velocity of air. The velocity of air in m/sec is (A) 5 (B) 14.1 (C) 56.22 (D) 28.2

Description : A Pitot tube indicates 5 cm of water (manometer) when it is being used for measuring velocity of air. The velocity of air in m/sec is (A) 5 (B) 14.1 (C) 56.22 (D) 28.2

Last Answer : (D) 28.2

I. 20a^2 + 51a + 28 = 0 II. 15b^2 − 61b + 56 = 0 1 : if a > b 2 : if a < b 3 : if a ≥ b 4 : if a ≤ b 5 : if a = b or the relation between a and b cannot be established.

Description : I. 20a^2 + 51a + 28 = 0 II. 15b^2 − 61b + 56 = 0 1 : if a > b 2 : if a < b 3 : if a ≥ b 4 : if a ≤ b 5 : if a = b or the relation between a and b cannot be established.

Last Answer : 2 : if a < b

An animal drawn seed drill has k number of furrow openers 180mm apart. If the speed of operation is 2.0kmph, the area covered (ha), in 8-11day is given by: A. 1.85/1000k B. 28.8 x 10-2k C. k/6.56 D. 1.762k

Description : An animal drawn seed drill has k number of furrow openers 180mm apart. If the speed of operation is 2.0kmph, the area covered (ha), in 8-11day is given by: A. 1.85/1000k B. 28.8 x 10-2k C. k/6.56 D. 1.762k

Last Answer : B. 28.8 x 10-2k

Acceleration of a rocket having mass 5000 kg and resultant force acting on it is 200,000 N is A. 50 m s-2 B. 56 m s-2 C. 70 m s-2 D. 40 m s-2

Description : Acceleration of a rocket having mass 5000 kg and resultant force acting on it is 200,000 N is A. 50 m s-2 B. 56 m s-2 C. 70 m s-2 D. 40 m s-2

Last Answer : . 40 m s-2

Avinash, Bala and Chandran invested Rs.45,000/-, Rs. 70, 000/- and Rs. 90,000/- respectively to start a business. At the end of two years, they earned a profit of Rs.1,64,000/-. What will be Bala’s share in the profit? a) Rs.56, 000/- b) Rs.46, 000/- c) Rs. 50, 000/- d) Rs.75, 000/- e) None of these

Description : Avinash, Bala and Chandran invested Rs.45,000/-, Rs. 70, 000/- and Rs. 90,000/- respectively to start a business. At the end of two years, they earned a profit of Rs.1,64,000/-. What will be Bala’s share in the profit? a) Rs.56, 000/- b) Rs.46, 000/- c) Rs. 50, 000/- d) Rs.75, 000/- e) None of these

Last Answer : Profit sharing ratio of Avinash,Bala & Chandran = 45000 : 70000 : 90,000 = 45 : 70 : 90 = 9 : 14 : 18 Bala's share of profit after two year =Rs.164000 × 14 × 41 = Rs. 4000 ×14 = Rs. 56000 Answer: a)

In a 100 quadrat study of 1 sqm each Cyperus rotundus was found in 80 quadrats with overall of 5640 individuals. The frequency (%), abun dance and density (m2) would be a). 70.5, 80.0 and 56.4 b). 56.4, 70.5 and 80.0 c). 80.0, 70.5 and 56.4 d). 80.0, 56.4 and 70.5

Description : In a 100 quadrat study of 1 sqm each Cyperus rotundus was found in 80 quadrats with overall of 5640 individuals. The frequency (%), abun dance and density (m2) would be a). 70.5, 80.0 and 56.4 b). 56.4, 70.5 and 80.0 c). 80.0, 70.5 and 56.4 d). 80.0, 56.4 and 70.5

Last Answer : c). 80.0, 70.5 and 56.4

A number is increased by 70 % and then decreased by 70 %. Find the net increase or decrease per cent. a) 25 b) 56 c) 45 c) 49 e) 98

Description : A number is increased by 70 % and then decreased by 70 %. Find the net increase or decrease per cent. a) 25 b) 56 c) 45 c) 49 e) 98

Last Answer : Answer: D Let the number be 100. Increase in the number = 70 % = 40 % of 100 = (40/100 100) = 70 Therefore, increased number = 100 + 70 = 170 This number is decreased by 70 % Therefore, decrease ... = 100 - 51 = 49 Hence, net percentage decrease = (49/100 100) = (4900/100) = 49 %

What is the greast common factor for 42 and 99?

Description : What is the greast common factor for 42 and 99?

Last Answer : 3 is the greatest common factor of 42 and 99.

1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16, 17, 18, 19, 20, 21, 23, 24, 25, 26, 27, 28, 29, 30, 31, 32, 33, 34, 35, 36, 37, 38, 39, 40, 41, 42, 43, 44, 45, 46, 47, 48, 49, 50'. What number is missing? -Riddles

Description : 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16, 17, 18, 19, 20, 21, 23, 24, 25, 26, 27, 28, 29, 30, 31, 32, 33, 34, 35, 36, 37, 38, 39, 40, 41, 42, 43, 44, 45, 46, 47, 48, 49, 50'. What number is missing? -Riddles

Last Answer : 22

If 618 birds eat 28 pounds of birdseed, how many birds can survive on 42 pounds of birdseed?

Description : If 618 birds eat 28 pounds of birdseed, how many birds can survive on 42 pounds of birdseed?

Last Answer : 927

What is 28 over 42?

Description : What is 28 over 42?

Last Answer : 28/42 is 2/3 in its lowest terms

42,35.28,21___ what comes next?

Description : 42,35.28,21___ what comes next?

Last Answer : 14

Deuterium oxide and inulin are injected into a normal 30-year-old man. The volume of distribution of deuterium oxide is found to be 42 L and that of inulin 14 L. a. The man’s intracellular fluid volume is about 14 L. b. The man’s intracellular fluid volume is about 28 L. c. The man’s plasma volume is about 7 L. d. The man’s interstitial fluid volume is about 9 L. e. The man’s total body water cannot be calculated from these data

Description : Deuterium oxide and inulin are injected into a normal 30-year-old man. The volume of distribution of deuterium oxide is found to be 42 L and that of inulin 14 L. a. The man's intracellular fluid ... fluid volume is about 9 L. e. The man's total body water cannot be calculated from these data

Last Answer : The man’s intracellular fluid volume is about 28 L.

This modem standard has a speed of 28.8k and has error-correction features. A. V.42 B. V.32bis C. V.90 D. V.34

Description : This modem standard has a speed of 28.8k and has error-correction features. A. V.42 B. V.32bis C. V.90 D. V.34

Last Answer : V.42

28, 42, 84, 210, 630, ? a) 2675 b) 2515 c) 2445 d) 2375 e) 2205

Description : 28, 42, 84, 210, 630, ? a) 2675 b) 2515 c) 2445 d) 2375 e) 2205

Last Answer : Series is × 1.5, ×2, ×2.5, ×3, ×3.5 Answer: e)

12.28× 1.5 -36÷ 2.4 = ? a) 3.24 b) 7.325 c) 6.42 d) 4.32 e) None of these

Description : 12.28× 1.5 -36÷ 2.4 = ? a) 3.24 b) 7.325 c) 6.42 d) 4.32 e) None of these

Last Answer : 12.28 × 1.5 - 15 = ? 18.42 - 15 = ? ? = 3.42 Answer: e)

The external length, breadth and height of a closed box are 10cm, 9cm and 7cm respectively. The total inner surface area of the box is 262 sq.cm. If the walls of the box are of uniform thickness “t” cm, then “t” equals a) 1cm b) 23/3 cm c) 28/9 cm d) 42.5 cm

Description : The external length, breadth and height of a closed box are 10cm, 9cm and 7cm respectively. The total inner surface area of the box is 262 sq.cm. If the walls of the box are of uniform thickness “t” cm, then “t” equals a) 1cm b) 23/3 cm c) 28/9 cm d) 42.5 cm

Last Answer : a) 1cm

Rakchita can do a piece of work in 28 days, while Shreya can do the same work in 42 days.They started the work together but 6 days before the completion of the work, Rakchita left the work. The total number of days to complete the work is a) 3 b) 4 c) 5 d) 6

Description : Rakchita can do a piece of work in 28 days, while Shreya can do the same work in 42 days.They started the work together but 6 days before the completion of the work, Rakchita left the work. The total number of days to complete the work is a) 3 b) 4 c) 5 d) 6

Last Answer : D 6 days before the completion of the work Rakchita left the work means in last 6 days only Shreya has worked alone So, in last 6 days worked done by Shreya = 6*1/42=6/42=1/7 So, the rest = 1-1/7 =6/7 So 6/7work was done by Rakchita and Shreya worked together=6/7*70/10 =420/70=6 days

What is 42 of 70?

Description : What is 42 of 70?

Last Answer : 42/70 x 100% = 60%

Chemical score of proteins of bengal gram is (A) 70 (B) 60 (C) 44 (D) 42

Description : Chemical score of proteins of bengal gram is (A) 70 (B) 60 (C) 44 (D) 42

Last Answer : Answer : C

A 19 year-old female is referred following a visit to the dentist where marked erosion of her teeth was noted. She was entirely asymptomatic and her only medication was the oral contraceptive pill. On examination her blood pressure was 110/70 mmHg and her body mass index was 21.5 kg/m2 (18 - 25). Investigations sodium 135 mmol/l potassium 2.1 mmol/l bicarbonate 42 mmol/l urea 2.6 mol/L corrected calcium 2.08 mmol/ alkaline phosphatase 201 iu/l (50-110) What is the most likely diagnosis? 1) Bulimia nervosa 2) Conn's syndrome 3) Laxative abuse 4) Pregnancy 5) Primary hypoparathyroidism

Description : A 19 year-old female is referred following a visit to the dentist where marked erosion of her teeth was noted. She was entirely asymptomatic and her only medication was the oral contraceptive pill ... ) Bulimia nervosa 2) Conn's syndrome 3) Laxative abuse 4) Pregnancy 5) Primary hypoparathyroidism

Last Answer : Answers-5 This patient has tooth erosion associated with hypokalaemic metabolic alkalosis and hypocalcaemia. This suggests a diagnosis of hypoparathyroidism. Conn's is unlikely in this age group, is ... raised alkaline phosphatase would not be expected. Early pregnancy would not fit this picture.

P2O5 content in triple superphosphate is about __________ percent. (A) 42-50 (B) 15-20 (C) 85-90 (D) 70-75

Description : P2O5 content in triple superphosphate is about __________ percent. (A) 42-50 (B) 15-20 (C) 85-90 (D) 70-75

Last Answer : (A) 42-50

The terminal value in year 6 is closest to __________. a) Rs.22.57 b) Rs.20.42 c) Rs.24.30 d) Rs.25.70

Description : The terminal value in year 6 is closest to __________. a) Rs.22.57 b) Rs.20.42 c) Rs.24.30 d) Rs.25.70

Last Answer : a) Rs.22.57

Compute the maximum shearing stress developed in a phosphor bronze spring having mean diameter of 200 mm and consisting of 24 turns of 20-mm diameter wire when the spring is stretched 100 mm. and G = 42 GPa. a. 51 MPa b. 31.89 MPa c. 80 MPa d. 70 MPa

Description : Compute the maximum shearing stress developed in a phosphor bronze spring having mean diameter of 200 mm and consisting of 24 turns of 20-mm diameter wire when the spring is stretched 100 mm. and G = 42 GPa. a. 51 MPa b. 31.89 MPa c. 80 MPa d. 70 MPa

Last Answer : b. 31.89 MPa

Two numbers are in the ration 3:5. If 9 is subtracted from the numbers, the ratio becomes 12:23. The numbers are (A) 30, 50 (B) 36, 60 (C) 33, 55 (D) 42, 70

Description : Two numbers are in the ration 3:5. If 9 is subtracted from the numbers, the ratio becomes 12:23. The numbers are (A) 30, 50 (B) 36, 60 (C) 33, 55 (D) 42, 70

Last Answer : Answer: C

Four persons rented a grassland. P grazed 48 goats for 3 months, Q grazed 20 goats for 5 months, R grazed 70 goats for 4 months and S grazed 42 goats for 3 months. If p’s share of rent is Rs.1420. Find the total rent of the field? A) 6410 B) 6200 C) 6400 D) 6300

Description : Four persons rented a grassland. P grazed 48 goats for 3 months, Q grazed 20 goats for 5 months, R grazed 70 goats for 4 months and S grazed 42 goats for 3 months. If p’s share of rent is Rs.1420. Find the total rent of the field? A) 6410 B) 6200 C) 6400 D) 6300

Last Answer : Answer: A) Ratio of shares P,Q, R, S = 48*3 : 20 *5 : 70*4 :42*3 = 144 : 100: 280 : 126 = 72:50:140:63 Let total rent be Rs x Then P’s share = Rs. 72x/325 72x /325 = 1420 X = Rs.6410

What is the highest common factor of 28 and 210?

Description : What is the highest common factor of 28 and 210?

Last Answer : The GCF is 14.

What is the highest common factor for 28 49 and 84?

Description : What is the highest common factor for 28 49 and 84?

Last Answer : The GCF is 7.

What is the greatest common factor of 28 and 42 56 70?

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