What 103.468 liters rounded to the nearest liter?

What 103.468 liters rounded to the nearest liter?
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What 103.468 liters rounded to the nearest liter?

Description : What 103.468 liters rounded to the nearest liter?

Last Answer : 1

What is 103.468 to the nearest number?

Description : What is 103.468 to the nearest number?

Last Answer : It is already a number but if you mean to the nearest whole number then it is 103 because .4 is less than .5

When 0.50 liter of a 12M solution is diluted to 1.0 liters the molarity of this new solution is?

Description : When 0.50 liter of a 12M solution is diluted to 1.0 liters the molarity of this new solution is?

Last Answer : 6.0 M when you multiply 12M by the .50 liters you will get the6.0 M

Shan bought 30 liters of milk at the rate of Rs.8 per liter. He got it churned after spending Rs.10 and 5kg of cream and 30 liter of toned milk were obtained. If he sold the cream at Rs.30 per kg and toned milk at Rs.4 per liter, his profit in the transaction is: A. 20% B. 8% C. 30% D. 40%

Description : Shan bought 30 liters of milk at the rate of Rs.8 per liter. He got it churned after spending Rs.10 and 5kg of cream and 30 liter of toned milk were obtained. If he sold the cream at Rs.30 per kg and toned milk at Rs.4 per liter, his profit in the transaction is: A. 20% B. 8% C. 30% D. 40%

Last Answer : Answer – B .8% Explanation: CP =Rs.(30 x 8 + 10) = Rs.250 SP = Rs. (30 x 5 + 30 x 4) = Rs.270 Gain% = (20/250 x 100)% = 8%

You have to measure exactly 4 liters of water, but you only have a 3-liter bottle and a 5-liter bottle. How do you do it?

Description : You have to measure exactly 4 liters of water, but you only have a 3-liter bottle and a 5-liter bottle. How do you do it?

Last Answer : Fill the 3-litre bottle and pour it into the empty 5-litre bottle. Fill the 3-litre bottle again, and pour enough to fill 5-litre bottle. This leaves exactly 1 litre in the 3-litre bottle. Empty the ... 3-litre bottle and pour it into the 5-litre bottle. The 5-litre bottle now has exactly 4 litres.

What is 45.12 rounded to the nearest liter?

Description : What is 45.12 rounded to the nearest liter?

Last Answer : 45 L

What is 103.7 rounded?

Description : What is 103.7 rounded?

Last Answer : Feel Free to Answer

What is the whole number for 468?

Description : What is the whole number for 468?

Last Answer : Feel Free to Answer

In an estimation of sulphur by carius method 0.468 g of an organic compound gave 0.668 g of barium sulphate. Find the percentage of sulphur in the compound.

Description : In an estimation of sulphur by carius method 0.468 g of an organic compound gave 0.668 g of barium sulphate. Find the percentage of sulphur in the compound.

Last Answer : Mass of the compound = 0.468 g Mass of the barium sulphate = 0.668 g % of sulphur = 32 X Mass of barium sulphate X 100/ 233 X Mass of the compound = 32 x 0.668x100/ 233 x0.468 = 19.60 %

Find the shear stress in the spring wire used to design a helical compression sprig if a load of 1200N is applied on the spring. Spring index is 6, and wire diameter 7mm. a) 452.2N/mm² b) 468.6N/mm² c) 512.2N/mm² d) None of the listed

Description : Find the shear stress in the spring wire used to design a helical compression sprig if a load of 1200N is applied on the spring. Spring index is 6, and wire diameter 7mm. a) 452.2N/mm² b) 468.6N/mm² c) 512.2N/mm² d) None of the listed

Last Answer : b) 468.6N/mm²

The batting average of runs of a cricket player of 30 innings was 96. How many runs must he make in his next innings so as to increase his average of runs by 12? A) 468 b) 668 C) 648 D) 486

Description : The batting average of runs of a cricket player of 30 innings was 96. How many runs must he make in his next innings so as to increase his average of runs by 12? A) 468 b) 668 C) 648 D) 486

Last Answer : A  Given that the total average runs of a cricket player (30 innings) = 96 After 31 innings = 108 Required number of runs = (108 * 31 – (96 *30) =3348 – 2880 =468

Tire question, can I replace a 103 load rating with a 101 rating?

Description : Tire question, can I replace a 103 load rating with a 101 rating?

Last Answer : Short NO! Long Tire load rating for maximum load per tire. Load Index 101 = 1819lbs (825kg) per tire Speed Rating T = 118mph Load Index 103 = 1929lbs (875kg) per tire Speed Rating T = 118mph ... use a lower rated tire, becuz you could end upside down on the side of the road with a blow-out.

One newton is equal to a.106 dynes b.105 dynes c.104 dynes d.103 dynes e.107 dynes

Description : One newton is equal to a.106 dynes b.105 dynes c.104 dynes d.103 dynes e.107 dynes

Last Answer : b. 105 dynes

The power of a locomotive is 315 kW and the total weight of the train is 2000 kN. If the track resistance is 15 N per kN, the maximum speed that the locomotive can attain on level track will be a.43 kmph b.83 kmph c.103 kmph d.107 dynes e.38 kmph

Description : The power of a locomotive is 315 kW and the total weight of the train is 2000 kN. If the track resistance is 15 N per kN, the maximum speed that the locomotive can attain on level track will be a.43 kmph b.83 kmph c.103 kmph d.107 dynes e.38 kmph

Last Answer : e. 38 kmph

The power of a locomotive is 315 kW and the total weight of the train is 2000 kN. If the track resistance is qN per kN, the maximum speed that the locomotive can attain on level track will be a.103 kmph b.83 kmph c.107 dynes d.43 kmph e.63 kmph

Description : The power of a locomotive is 315 kW and the total weight of the train is 2000 kN. If the track resistance is qN per kN, the maximum speed that the locomotive can attain on level track will be a.103 kmph b.83 kmph c.107 dynes d.43 kmph e.63 kmph

Last Answer : e. 63 kmph

Using identities solve 103^ -Maths 9th

Description : Using identities solve 103^ -Maths 9th

Last Answer : NEED ANSWER

Using identities solve 103^ -Maths 9th

Description : Using identities solve 103^ -Maths 9th

Last Answer : FRIEND YOUR QUESTION IS NOT CLEAR

Evaluate each of the following: (i) (103)3 (ii) (98)3 (iii) (9.9)3 (iv) (10.4)3 (v) (598)3 (vi) (99)3 -Maths 9th

Description : Evaluate each of the following: (i) (103)3 (ii) (98)3 (iii) (9.9)3 (iv) (10.4)3 (v) (598)3 (vi) (99)3 -Maths 9th

Last Answer : answer:

were can i find episode 103 and 104 of kodocha?

Description : were can i find episode 103 and 104 of kodocha?

Last Answer : cardinality of ℝ

What do you call a fish with 52,103 eyes?

Description : What do you call a fish with 52,103 eyes?

Last Answer : This answer is too long to say.

What is 9 x 1002 x 103 x 0.1 7 x 0.001 in a decimal?

Description : What is 9 x 1002 x 103 x 0.1 7 x 0.001 in a decimal?

Last Answer : 9 * 1002 * 103 * 0.1 7 * 0.001 = 157.90518

What is 103 353 divided by 259?

Description : What is 103 353 divided by 259?

Last Answer : 399 R 12

What is the answer algebra with pizzazz page 103?

Description : What is the answer algebra with pizzazz page 103?

Last Answer : The novice Water Polo player who was upset because his horsecould not swim.

What mountains 30 north latitude 103 east longitude?

Description : What mountains 30 north latitude 103 east longitude?

Last Answer : What is the answer ?

How much horsepower does the Harley Davidson 103 motor have?

Description : How much horsepower does the Harley Davidson 103 motor have?

Last Answer : Need answer

What does a Mobil M1-103 fit?

Description : What does a Mobil M1-103 fit?

Last Answer : Need answer

How many times does 25 go into 103?

Description : How many times does 25 go into 103?

Last Answer : how many times does 25 go into 103.

How many times does 100 go into 103?

Description : How many times does 100 go into 103?

Last Answer : Help

How many times dose 12 go into 103?

Description : How many times dose 12 go into 103?

Last Answer : 12 goes into 103 8.58333 times

During each cycle of on going fatty acid oxidation, all the following compounds are generated except (A) H2O (B) Acetyl CoA (C) Fatty acyl CoA (D) NADH FATS AND FATTY ACID METABOLISM 103

Description : During each cycle of on going fatty acid oxidation, all the following compounds are generated except (A) H2O (B) Acetyl CoA (C) Fatty acyl CoA (D) NADH FATS AND FATTY ACID METABOLISM 103

Last Answer : Answer : A

CHOOSE THE WORD FROM THE OPTIONS WHICH IS NEARLY OPPOSITE IN MEANING TO THE GIVENWORD: Obscure A. Academic 103 B. Implicit C. Explicit D. Ugly

Description : CHOOSE THE WORD FROM THE OPTIONS WHICH IS NEARLY OPPOSITE IN MEANING TO THE GIVENWORD: Obscure A. Academic 103 B. Implicit C. Explicit D. Ugly

Last Answer : ANSWER: C

What is the total number of bones that are present in human body? (1) 309 (2) 405 (3) 103 (4) 206

Description : What is the total number of bones that are present in human body? (1) 309 (2) 405 (3) 103 (4) 206

Last Answer : (4) 206 Explanation: The human skeleton is the internal framework of the body. It is composed of around 270 bones at birth this total decrease to around 206 bones by adulthood after some bones get fused together.

When a voltage of 112 VDC is applied to the circuit illustrated with a resistance of 10,230 ohms the current will be________. EL-0018 A. .010 amps B. .913 amps C. 103 m amps D. 934 m amps

Description : When a voltage of 112 VDC is applied to the circuit illustrated with a resistance of 10,230 ohms the current will be________. EL-0018 A. .010 amps B. .913 amps C. 103 m amps D. 934 m amps

Last Answer : Answer: A

When a voltage of 95 VDC is applied to the illustrated circuit with a resistance of 32 ohms the current will be _______. EL-0018 A. 0.336 amps B. 2.968 amps C. 103.78 milliamps D. 127 milliamps

Description : When a voltage of 95 VDC is applied to the illustrated circuit with a resistance of 32 ohms the current will be _______. EL-0018 A. 0.336 amps B. 2.968 amps C. 103.78 milliamps D. 127 milliamps

Last Answer : Answer: B

When a voltage of 115 VDC is applied to the illustrated circuit with a resistance of 10,230 ohms the current will be _______ EL-0018 A. 88.95 milliamps B. 103.45 milliamps C. 11.24 milliamps D. 0.91 amps

Description : When a voltage of 115 VDC is applied to the illustrated circuit with a resistance of 10,230 ohms the current will be _______ EL-0018 A. 88.95 milliamps B. 103.45 milliamps C. 11.24 milliamps D. 0.91 amps

Last Answer : Answer: C

Elements with atomic number 89-103 are known as?

Description : Elements with atomic number 89-103 are known as?

Last Answer : Actinides (radio active rare earths)

1 N (newton) is equal to A. 102 dynes B. 103 dynes C. 104 dynes D. 105 dynes

Description :  1 N (newton) is equal to A. 102 dynes B. 103 dynes C. 104 dynes D. 105 dynes

Last Answer : 105 dynes

One Joule is equal to-----? A. 105 ergs B. 103 ergs C. 107 ergs (Answer) D. 1011 ergs

Description : One Joule is equal to-----? A. 105 ergs B. 103 ergs C. 107 ergs (Answer) D. 1011 ergs

Last Answer : C. 107 ergs (Answer)

Actual op-amp may have an open loop gain of A. 102 B. 105 C. 103 D. 104

Description : Actual op-amp may have an open loop gain of A. 102 B. 105 C. 103 D. 104

Last Answer : 105

. For what value of Prandtl number, the Col-burn analogy is valid?(A) 0.06 to 120 (B) 0.6 to 120 (C) 1 to 103 (D) 1 to 50

Description : . For what value of Prandtl number, the Col-burn analogy is (A) 0.06 to 120 (B) 0.6 to 120 (C) 1 to 103 (D) 1 to 50

Last Answer : (B) 0.6 to 120

Find the magnetic field intensity of a toroid of turns 40 and radius 20cm. The current carried by the toroid be 3.25A. a) 103.45 b) 102 c) 105.7 d) 171

Description : Find the magnetic field intensity of a toroid of turns 40 and radius 20cm. The current carried by the toroid be 3.25A. a) 103.45 b) 102 c) 105.7 d) 171

Last Answer : a) 103.45

Purity of oxygen used for blowing in steel making L.D. converter is 99.5%. The boiling point of oxygen is about __________ °C. (A) -53 (B) -103 (C) -183 (D) -196

Description : Purity of oxygen used for blowing in steel making L.D. converter is 99.5%. The boiling point of oxygen is about __________ °C. (A) -53 (B) -103 (C) -183 (D) -196

Last Answer : (C) -183

103. Which one is the Low Level Language: a) Assembly b) Visual Basic c) Java d) C++ e) None of The Above

Description : 103. Which one is the Low Level Language: a) Assembly b) Visual Basic c) Java d) C++ e) None of The Above

Last Answer : a) Assembly

If intensity of rainfall in cm per hour is I, percentage coefficient of run-off is P, area of catchment in square kilometres is A, the total run-off Q, is given by (A) Q = 1.758 × 102 × API(B) Q = 2.758 × 102 × API(C) Q = 2.758 × 103 × API(D) Q = 2.758 × 103 × A/PI

Description : If intensity of rainfall in cm per hour is I, percentage coefficient of run-off is P, area of catchment in  square kilometres is A, the total run-off Q, is given by  (A) Q = 1.758 102   API (B) Q = 2.758 ... API (C) Q = 2.758 103   API (D) Q = 2.758 103   A/PI

Last Answer : (C) Q = 2.758 × 103  × API

Electrical conductivities of semi-conductors are of the order of __________ ohm/cm. (A) 10-3 (B) 103 (C) 10-15 (D) 1015

Description : Electrical conductivities of semi-conductors are of the order of __________ ohm/cm. (A) 10-3 (B) 103 (C) 10-15 (D) 1015

Last Answer : OptionA

The specific weight of water in S.I. units is taken as (A) 9.81 kN/m3 (B) 9.81 × 103 N/m3 (C) 9.81 × 10-6 N/mm3 (D) Any one of these

Description : The specific weight of water in S.I. units is taken as (A) 9.81 kN/m3 (B) 9.81 × 103 N/m3 (C) 9.81 × 10-6 N/mm3 (D) Any one of these

Last Answer : Answer: Option D

The atmospheric pressure at sea level is (A) 103 kN/m2 (B) 10.3 m of water (C) 760 mm of mercury (D) All of these

Description : The atmospheric pressure at sea level is (A) 103 kN/m2 (B) 10.3 m of water (C) 760 mm of mercury (D) All of these

Last Answer : Answer: Option D

103. What is specific energy consumption. a) energy consumption per month b) Energy consumed per unit of production c) energy consumption per year d) none of the above

Description : 103. What is specific energy consumption. a) energy consumption per month b) Energy consumed per unit of production c) energy consumption per year d) none of the above

Last Answer : Energy consumed per unit of production

Molecular volume of any perfect gas at 600 x 103 N/m2 and 27°C will be  (a) 4.17m3/kgmol  (b) 400 m3/kg mol  (c) 0.15 m3/kg mol  (d) 41.7 m3/kg mol  (e) 417m3/kgmol.

Description : Molecular volume of any perfect gas at 600 x 103 N/m2 and 27°C will be  (a) 4.17m3/kgmol  (b) 400 m3/kg mol  (c) 0.15 m3/kg mol  (d) 41.7 m3/kg mol  (e) 417m3/kgmol.

Last Answer : Answer : a

Convert the binary number 10010.0100 to decimal. 103) A) 16.25 B) 18.25 C) 18.40 D) 24.50

Description : Convert the binary number 10010.0100 to decimal. 103) A) 16.25 B) 18.25 C) 18.40 D) 24.50

Last Answer : B) 18.25