What Early board game where players moved around the squares?

What Early board game where players moved around the squares?
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Last Answer : (a) \(rac{13}{25}\)Let E : Event of drawing a queen in a single draw the pack of 52 cards. As there are 4 queens in a pack of 52 cards,P(E) = \(rac{4}{52}\) = \(rac{1}{13}\)P(\(\bar{E}\)) = P(not ... {25}\). [Sum of a G.P with infinite terms = \(rac{a}{1-r}\) where a = 1st term, r = common ratio.]

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Description : . In a zero-sum game, a. What one player wins, the other loses b. The sum of each player’s winnings if the game is played many times must be zero c. The game is fair-each person has an equal chance of winning d. Long-run profits must be zero

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If women had a bingo card for men, what would some squares include?

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I lie in the earth, and under the ground; A map may reveal me for journey's abound; I can be found in squares, to reduce down to size; Or at the end of a strand, where attachment lies. What am I? -Riddles

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Last Answer : Roots

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Last Answer : 5945. 5=5. 4+5=9=second digit 4^2 x 5^2 = 400 = four two noughts

A man has nine children, born at regular intervals. The sum of their squares of their ages is equal to the square of his own age.What are the ages of the children? -Riddles

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Last Answer : 2 - 5 - 8 - 11 - 14 - 17 - 20 - 23 - 26

Take eight small sticks, four of which are half the length of the other four. Make three equal squares out of the sticks. -Riddles

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Last Answer : Use the longer four sticks to be sharing sides between the squares and at the end their should be three intertwined squares.

There are two numbers whose product added to the sum of their squares is 109, and the difference of whose squares is 24. What are the two numbers? -Riddles

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Last Answer : 5 and 7. (5)² = 25 (7)² = 49 (5x7)+25+49=109 49-25=24

What number is that, which, added separately to 100 and 164, shall make them perfect squares? -Riddles

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Last Answer : 125

In the adjoining figure, ABC is an equilateral triangle inscribing a square of maximum possible area. Again in this squares -Maths 9th

Description : In the adjoining figure, ABC is an equilateral triangle inscribing a square of maximum possible area. Again in this squares -Maths 9th

Last Answer : (a) (873 - 504√3) cm2.Since ∠CPO = ∠COP = 60º, therefore, PCO is also an equilateral triangle. Let each side of the square MNOP be x cm. Then PC = CO = PO = x cm Then in ΔPAM,\(rac{PM}{PA}\) = sin 60º⇒ \(rac{x ... most square = y2= \(\big(3(7-4\sqrt2)\big)^2\)= 9(49 + 48 - 56√3) = (873 - 504√3) cm2.

The figure given besides shows five squares inside one another by joining the midpoints of the outer square. -Maths 9th

Description : The figure given besides shows five squares inside one another by joining the midpoints of the outer square. -Maths 9th

Last Answer : (c) \(rac{31}{16}a^2.\)Side of the square I = a ∴ Area of square I = a2= \(\sqrt{rac{a^2}{16}+rac{a^2}{16}}\) = \(\sqrt{rac{2a^2}{16}}\) = \(rac{a}{2\sqrt2}\)∴ Sum of the areas of the five squares= a2 + \( ... = a2 \(\bigg[1+ rac{1}{2} + rac{1}{4}+rac{1}{8}+rac{1}{16}\bigg]\) = \(rac{31}{16}a^2.\)

What is the ratio of sum of squares of roots to the product of the roots of the equation 7x^2 + 12x + 18 = 0? -Maths 9th

Description : What is the ratio of sum of squares of roots to the product of the roots of the equation 7x^2 + 12x + 18 = 0? -Maths 9th

Last Answer : Let α, β be the roots of the equation 7x2 + 12x + 18 = 0. ∴ Required ratio = α2 + β2 : αβ = ​​−10849187 = −67 = – 6 : 7.

If the sum of the roots of the equation ax^2 + bx + c = 0 is equal to the sum of their squares, then which one of the following is correct ? -Maths 9th

Description : If the sum of the roots of the equation ax^2 + bx + c = 0 is equal to the sum of their squares, then which one of the following is correct ? -Maths 9th

Last Answer : Given equation: ax2+bx+c=0 Let α and β be the roots of given quadratic equation Sum of the roots i.e. α+β=a−b Product of roots i.e. αβ=ac It is given that, Sum of the roots = Sum of squares of the roots i ... )2−2αβ i.e. a−b =(a−b )2−a2c i.e. −ab=b2−2ac i.e. ab+b2=2ac Hence, C is the correct option.