What numbers are 21 divisible by?

What numbers are 21 divisible by?
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They are members of the infinite set of numbers of the form 21*kwhere k is an integer.
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Which of the following represents the largest 4-digit number which can be added to 7249 in order to make the derived number divisible by each of 12,14,21,33 and 54? a) 9123 b) 9383 c) 8727 d) 8673

Description : Which of the following represents the largest 4-digit number which can be added to 7249 in order to make the derived number divisible by each of 12,14,21,33 and 54? a) 9123 b) 9383 c) 8727 d) 8673

Last Answer : b) 9383

How many numbers are divisible by 5 from 1 to 100 ?

Description : 20

Last Answer : 20 numbers from 1-100 are divisible by 5.

What Number are divisible by 8 can be also divisible by what numbers?

Description : What Number are divisible by 8 can be also divisible by what numbers?

Last Answer : They can also be evenly divided by 1, 2 and 4.

How many numbers between 16 to 189 are divisible by 9 but not by 4?

Description : How many numbers between 16 to 189 are divisible by 9 but not by 4?

Last Answer : There are 14 such numbers between 16 and 189.

What numbers are divisible by 4 or 6?

Description : What numbers are divisible by 4 or 6?

Last Answer : 12 and any multiples of 12

Which of these numbers are divisible by 3 - a. 29 b. 16 c. 24 d. 14?

Description : Which of these numbers are divisible by 3 - a. 29 b. 16 c. 24 d. 14?

Last Answer : Only c. 24 is evenly divisible by 324/3 =- 8

What is 519 divisible by in whole numbers?

Description : What is 519 divisible by in whole numbers?

Last Answer : It is divisible by any of its factors which are 1, 3, 173 and519

What which of these numbers is divisible by 12 is it a. 6 b. 26 c. 12 d. 42?

Description : What which of these numbers is divisible by 12 is it a. 6 b. 26 c. 12 d. 42?

Last Answer : c.

What which of these numbers are divisible by 13 is it a. 52 or b. 9 c. 30 d. 27?

Description : What which of these numbers are divisible by 13 is it a. 52 or b. 9 c. 30 d. 27?

Last Answer : a.

What numbers are divisible by 3 9 6?

Description : What numbers are divisible by 3 9 6?

Last Answer : Any number of the form 18*k where k is an integer.

The least number that is divisible by all the numbers from 1 to 5 is: (a) 70 (b) 60 (c) 80 (d) 90

Description : The least number that is divisible by all the numbers from 1 to 5 is: (a) 70 (b) 60 (c) 80 (d) 90

Last Answer : (b) 60

The odd numbers from 1 to 45 which are exactly divisible by 3 are arranged in an ascending order. The number at 6 th position is (A) 18 (B) 24 (C) 33 (D) 36

Description : The odd numbers from 1 to 45 which are exactly divisible by 3 are arranged in an ascending order. The number at 6 th position is (A) 18 (B) 24 (C) 33 (D) 36

Last Answer : Answer: C

Which of the following is greater between each of the two numbers ? (i) `3^(30), 7^(15)` (ii) `2^(25), 4^(14)` (iii) `2^(21)` and `3^(14)`

Description : Which of the following is greater between each of the two numbers ? (i) `3^(30), 7^(15)` (ii) `2^(25), 4^(14)` (iii) `2^(21)` and `3^(14)`

Last Answer : Which of the following is greater between each of the two numbers ? (i) `3^(30), 7^(15)` (ii) `2^(25), 4^(14)` (iii) `2^(21)` and `3^(14)`

ROC allows 21 digit numbers at the time of issuing Certificate of Incorporation.

Description : ROC allows 21 digit numbers at the time of issuing Certificate of Incorporation.

Last Answer : Write a word or a term or a phrase that can substitute each of the following statements. ... at the time of issuing Certificate of Incorporation.

Which of these numbers prime 20 or 21 or 22 or 23 or 24?

Description : Which of these numbers prime 20 or 21 or 22 or 23 or 24?

Last Answer : You can work this out, Prime numbers can only be divided bythemselves or 1. Therefore as 20 can be divided by 2 it it notprime. The same is true for 22 and 24. Thus the prime must beeither 21 or 23.See if either of these numbers can be divided by 7, if it canthen the prime must be the other number.

How do you write 21 thousands in numbers?

Description : How do you write 21 thousands in numbers?

Last Answer : As a number it is: 21,000

What numbers multiply by 21?

Description : What numbers multiply by 21?

Last Answer : Any number can be multiplied by 21

How do you write 21 as a product of prime numbers?

Description : How do you write 21 as a product of prime numbers?

Last Answer : It is 3 time 7 = 21

What are the Odd numbers less than 21?

Description : What are the Odd numbers less than 21?

Last Answer : 1,3,5,7,9,11,13,15,17,19,21

How can you make 24 using the numbers 21 22 23 and 20?

Description : How can you make 24 using the numbers 21 22 23 and 20?

Last Answer : (23-21) x 22-20

What is the product of two whole numbers if their sum is 21 and positive difference is 5?

Description : What is the product of two whole numbers if their sum is 21 and positive difference is 5?

Last Answer : The numbers are 13 and 8The product is 104

In the hexaploid wheat, the haploid (n) and basic (x) numbers of chromosomes are (a) n = 21 and x = 21 (b) n = 21 and x = 14 (c) n = 21 and x = 7 (d) n = 7 and x = 21.

Description : In the hexaploid wheat, the haploid (n) and basic (x) numbers of chromosomes are (a) n = 21 and x = 21 (b) n = 21 and x = 14 (c) n = 21 and x = 7 (d) n = 7 and x = 21.

Last Answer : (c) n = 21 and x = 7

Three consecutive numbers such that twice the first, 3 times the second and 4 times the third together make 182. The numbers in question are 1. 18, 22 and 23 2. 18, 19 and 20 3. 19, 20 and 21 4. 20, 21 and 22 5. 21, 22 and 23

Description : Three consecutive numbers such that twice the first, 3 times the second and 4 times the third together make 182. The numbers in question are 1. 18, 22 and 23 2. 18, 19 and 20 3. 19, 20 and 21 4. 20, 21 and 22 5. 21, 22 and 23

Last Answer : Answer- 3( 19,20,21) Explanation:- let number be x,x+1,x+2 2x + 3(x+1)+4(x+2)=180 x=19 so numbers are 19,20,21

How many natural numbers are factors of 26 including the number 1 and itself? a) 1 b) 7 c) 6 d) 21

Description : How many natural numbers are factors of 26 including the number 1 and itself? a) 1 b) 7 c) 6 d) 21

Last Answer : b) 7

A person writes all the numbers from 0 to 99. The number of times digit 3 will be written is (A) 18 (B) 19 (C) 20 (D) 21

Description : A person writes all the numbers from 0 to 99. The number of times digit 3 will be written is (A) 18 (B) 19 (C) 20 (D) 21

Last Answer : Answer: C

In the sequence of numbers 2/3, 4/7, X, 11/21, 16/31 The missing number X is: (A) 8/10 (B) 6/10 (C) 5/10 (D) 7/13

Description : In the sequence of numbers 2/3, 4/7, X, 11/21, 16/31 The missing number X is: (A) 8/10 (B) 6/10 (C) 5/10 (D) 7/13

Last Answer : Answer: D

The sum of three numbers is 210. If the ratio between the first and second number be 2:3 and that between the second and third be 4:5, then the difference between the first and third number? a) 21 b) 35 c) 42 d) 56 e) None of these

Description : The sum of three numbers is 210. If the ratio between the first and second number be 2:3 and that between the second and third be 4:5, then the difference between the first and third number? a) 21 b) 35 c) 42 d) 56 e) None of these

Last Answer : Answer: C a: b = 2:3 and b:c = 4:5 a:b:c = 8:12:15 Difference between first and third number = (7/35)*210 = 42

The number of candidates writing three different entrance exams is in the ratio 4:5:6. There is a proposal to increase these numbers of candidates by 40%, 60% and 85% respectively. What will be the ratio of increased numbers? a) 14:15:16 b) 12:15:19 c)13:19:21 d) 14:16:19 E) None of these

Description : The number of candidates writing three different entrance exams is in the ratio 4:5:6. There is a proposal to increase these numbers of candidates by 40%, 60% and 85% respectively. What will be the ratio of increased numbers? a) 14:15:16 b) 12:15:19 c)13:19:21 d) 14:16:19 E) None of these

Last Answer : Answer : E Given ratio of number of candidates is 4:5:6 Let the number of candidates for 3 exams be 4k, 5k and 6k respectively. After increasing, number of candidates become (140% of 4k), (160% of 5k) & (185% ... 111k/10 Now, the required new ratio is: 56k/100 : 80k/10 : 111k/10 = 56 : 80 : 111

What is the longest and yet the shortest thing in the world; the swiftest and yet the slowest; the most divisible and the most extended; the least valued and the most regretted; without which nothing can be done; which devours every thing, however small, and yet gives life and spirits to every object, however great? -Riddles

Description : What is the longest and yet the shortest thing in the world; the swiftest and yet the slowest; the most divisible and the most extended; the least valued and the most regretted; without which ... every thing, however small, and yet gives life and spirits to every object, however great? -Riddles

Last Answer : Time.

For what value of m is x3 -2mx2 +16 divisible by x + 2 ? -Maths 9th

Description : For what value of m is x3 -2mx2 +16 divisible by x + 2 ? -Maths 9th

Last Answer : Let p(x) = x3 -2mx2 +16 Since, p(x) is divisible by (x+2), then remainder = 0 P(-2) = 0 ⇒ (-2)3 -2m(-2)2 + 16=0 ⇒ -8-8m+16=0 ⇒ 8 = 8 m m = 1 Hence, the value of m is 1 .

Without actual division, prove that 2x4 – 5x3 + 2x2 – x+ 2 is divisible by x2-3x+2. -Maths 9th

Description : Without actual division, prove that 2x4 – 5x3 + 2x2 – x+ 2 is divisible by x2-3x+2. -Maths 9th

Last Answer : Let p(x) = 2x4 - 5x3 + 2x2 - x+ 2 firstly, factorise x2-3x+2. Now, x2-3x+2 = x2-2x-x+2 [by splitting middle term] = x(x-2)-1 (x-2)= (x-1)(x-2) Hence, 0 of x2-3x+2 are land 2. We have to prove that, 2x4 ... )2 - 2 + 2 = 2x16-5x8+2x4+ 0 = 32 - 40 + 8 = 40 - 40 =0 Hence, p(x) is divisible by x2-3x+2.

For what value of m is x3 -2mx2 +16 divisible by x + 2 ? -Maths 9th

Description : For what value of m is x3 -2mx2 +16 divisible by x + 2 ? -Maths 9th

Last Answer : Let p(x) = x3 -2mx2 +16 Since, p(x) is divisible by (x+2), then remainder = 0 P(-2) = 0 ⇒ (-2)3 -2m(-2)2 + 16=0 ⇒ -8-8m+16=0 ⇒ 8 = 8 m m = 1 Hence, the value of m is 1 .

Without actual division, prove that 2x4 – 5x3 + 2x2 – x+ 2 is divisible by x2-3x+2. -Maths 9th

Description : Without actual division, prove that 2x4 – 5x3 + 2x2 – x+ 2 is divisible by x2-3x+2. -Maths 9th

Last Answer : Let p(x) = 2x4 - 5x3 + 2x2 - x+ 2 firstly, factorise x2-3x+2. Now, x2-3x+2 = x2-2x-x+2 [by splitting middle term] = x(x-2)-1 (x-2)= (x-1)(x-2) Hence, 0 of x2-3x+2 are land 2. We have to prove that, 2x4 ... )2 - 2 + 2 = 2x16-5x8+2x4+ 0 = 32 - 40 + 8 = 40 - 40 =0 Hence, p(x) is divisible by x2-3x+2.

FOR WHAT VALUE OF K, THE POLYNOMIAL X2+(4-K)X+2 IS DIVISIBLE BY X-2 -Maths 9th

Description : FOR WHAT VALUE OF K, THE POLYNOMIAL X2+(4-K)X+2 IS DIVISIBLE BY X-2 -Maths 9th

Last Answer : As the given polynomial divisible by x-2 means the polynomial satisfies for the value x=2 So putting x=2 in x²+(4-k)x+2 yields 0 ⇒2²+(4-k)2+2=0 ⇒4+8-2k+2=0 ⇒ 2k=14 ⇒ k= ... ;-3x+2 if factorized yields (x-1)(x-2). Thus is divisible by x-2 as well as divisible by x-1.

FOR WHAT VALUE OF K, THE POLYNOMIAL X2+(4-K)X+2 IS DIVISIBLE BY X-2 -Maths 9th

Description : FOR WHAT VALUE OF K, THE POLYNOMIAL X2+(4-K)X+2 IS DIVISIBLE BY X-2 -Maths 9th

Last Answer : The value of 'k' is 4

An integer is chosen at random from the first two hundred positive integers. What is the probability that the integer chosen is divisible by 6 or 8 ? -Maths 9th

Description : An integer is chosen at random from the first two hundred positive integers. What is the probability that the integer chosen is divisible by 6 or 8 ? -Maths 9th

Last Answer : As there are 200 integers, total number of exhaustive, mutually exclusive and equally likely cases, i.e, n(S) = 200 Let A : Event of integer chosen from 1 to 200 being divisible by 6⇒ n(A) = 33 \(\bigg(rac{200}{6}=33rac{1}{3}\ ... (rac{25}{200}\) - \(rac{8}{200}\) = \(rac{50}{200}\) = \(rac{1}{4}\).

Find the probability that a two digit number formed by the digit 1, 2, 3, 4 and 5 is divisible by 4. -Maths 9th

Description : Find the probability that a two digit number formed by the digit 1, 2, 3, 4 and 5 is divisible by 4. -Maths 9th

Last Answer : The two digit numbers can be formed by putting any of 5 digits at the one 's place and also one of the 5 digits at ten's place. So, Total number of 2-digit numbers that can be formed using these 5-digits = 5 5 = ... 52}, i.e, 5 in number. ∴ Required probability = \(rac{5}{25}\) = \(rac{1}{5}.\)

A five digit number is formed by the digits 0, 1, 2, 3, 4 (without repetition). Find the probability that the number formed is divisible by 4 ? -Maths 9th

Description : A five digit number is formed by the digits 0, 1, 2, 3, 4 (without repetition). Find the probability that the number formed is divisible by 4 ? -Maths 9th

Last Answer : Without repetition, a five -digit number can be formed using the five digits in 5! ways (5 4 3 2 1) Out of these 5! numbers, 4! numbers will be starting with digit 0. (0 (fixed) 4 3 2 1) ∴ Total ... + 6 + 6 + 4 + 4 + 4 = 30∴ Required probability = \(rac{30}{96}\) = \(rac{5}{16}.\)

If three natural numbersfrom 1 to 100 are selected randomly, then the probability that all are divisible by both 2 and 3 is -Maths 9th

Description : If three natural numbersfrom 1 to 100 are selected randomly, then the probability that all are divisible by both 2 and 3 is -Maths 9th

Last Answer : (c) \(rac{4}{1155}\)Let n(S) = Number of ways of selecting 3 numbers from 100 numbers = 100C3 Let E : Event of selecting three numbers divisible by both 2 and 3 from numbers 1 to 100 = Event of selecting three ... C_3}{^{100}C_3}\) = \(rac{16 imes15 imes14}{100 imes99 imes98}\) = \(rac{4}{1155}\).

For what value of m will the expression 3x^3 + mx^2 + 4x – 4m be divisible by x + 2 ? -Maths 9th

Description : For what value of m will the expression 3x^3 + mx^2 + 4x – 4m be divisible by x + 2 ? -Maths 9th

Last Answer : f(x) = 3x3 + mx2 + 4x – 4m f(x) is divisible by (x + 2) if f(–2) = 0 Now f(–2) = 3(–2)3 + m(–2)2 + 4(–2) – 4m = – 24 + 4m – ... ; 4m = – 32 ≠ 0 ∴ No such value of m exists for which (x + 2) is a factor of the given expression

If x^5 – 9x^2 + 12x – 14 is divisible by (x – 3), what is the remainder ? -Maths 9th

Description : If x^5 – 9x^2 + 12x – 14 is divisible by (x – 3), what is the remainder ? -Maths 9th

Last Answer : answer:

Without actual division show that 2x^4 – 6x^3 + 3x^2 + 3x – 2 is exactly divisible by x^2 – 3x + 2 -Maths 9th

Description : Without actual division show that 2x^4 – 6x^3 + 3x^2 + 3x – 2 is exactly divisible by x^2 – 3x + 2 -Maths 9th

Last Answer : answer:

Without actual division, show that (x – 1)^2n – x^2n + 2x – 1 is divisible by 2x^3 – 3x^2 + x. -Maths 9th

Description : Without actual division, show that (x – 1)^2n – x^2n + 2x – 1 is divisible by 2x^3 – 3x^2 + x. -Maths 9th

Last Answer : answer:

For what value of k, will the expression (3x^3 – kx^2 + 4x + 16) be divisible by (x – k/2) ? -Maths 9th

Description : For what value of k, will the expression (3x^3 – kx^2 + 4x + 16) be divisible by (x – k/2) ? -Maths 9th

Last Answer : Given f(x) = 3x³ - kx² + 4x + 16. Since (x - k/2) is a factor of polynomial. This means x = k/2 is the zero of the given polynomial. ⇒ f(k/2) = 3(k/2)³ - k(k/2)² + 4(k/2) + 16 ⇒ 0 ... - 4k + 32) + 4(k² - 4k + 32) ⇒ 0 = (k + 4)(k² - 4k + 32) ⇒ k = -4.

x^4 + xy^3 + x^3y + xz^3 + y^4 + yz^3 is divisible by : -Maths 9th

Description : x^4 + xy^3 + x^3y + xz^3 + y^4 + yz^3 is divisible by : -Maths 9th

Last Answer : answer:

If the expression (px^3 + x^2 – 2x – q) is divisible by (x – 1) and (x + 1), then the values of p and q respectively are ? -Maths 9th

Description : If the expression (px^3 + x^2 – 2x – q) is divisible by (x – 1) and (x + 1), then the values of p and q respectively are ? -Maths 9th

Last Answer : Let f(x)=px3+x2−2x−q Since f(x) is divisible by (x−1) and (x+1) so x=1 and −1 must make f(x)=0. Therefore, p+1−2−q=0, i.e., p−q=1; and −p+1+2−q=0, i.e., p+q=3 Thus p=2 and q=1

If the polynomial x^6 + px^5 + qx^4 – x^2 – x – 3 is divisible by x^4 – 1, then the value of p^2 + q^2 is : -Maths 9th

Description : If the polynomial x^6 + px^5 + qx^4 – x^2 – x – 3 is divisible by x^4 – 1, then the value of p^2 + q^2 is : -Maths 9th

Last Answer : The divisor is x4−1=(x−1)(x+1)(x2+1) By factor theorem, f(1)=f(−1)=0 Thus, 1+p+q−1−1−3=0 and 1+q−1−3=p−1 i.e., p+q=4 and p−q=−2 Adding the two, 2p=2 i.e. p=1 and ∴ q=3. ∴ p2+q2=1+9=10

Which one of the following is divisible by (1 + a + a^5) and (1 + a^4 + a^5) individually ? -Maths 9th

Description : Which one of the following is divisible by (1 + a + a^5) and (1 + a^4 + a^5) individually ? -Maths 9th

Last Answer : answer:

Consider the following statements : 1. a^n + b^n is divisible by a + b if n = 2k + 1, where k is a positive integer. -Maths 9th

Description : Consider the following statements : 1. a^n + b^n is divisible by a + b if n = 2k + 1, where k is a positive integer. -Maths 9th

Last Answer : Statement (1) is correct as for k = 1, n = 2 × 1 + 1 = 3. ∴ a3 + b3 = (a + b) (a2 + b2 – ab) which is divisible by (a + b), statement (2) is also correct as for k = 1, n = 2, ∴ a2 – b2 = (a – b) (a + b) which is divisible by (a – b).

What should be subtracted from 27x^3 – 9x^2 – 6x – 5 to make it exactly divisible by (3x – 1) -Maths 9th

Description : What should be subtracted from 27x^3 – 9x^2 – 6x – 5 to make it exactly divisible by (3x – 1) -Maths 9th

Last Answer : answer: