What is 0.79 more than the difference of 78.3 and 14.975?

What is 0.79 more than the difference of 78.3 and 14.975?
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78.3 - 14.975 = 63.32563.325 +0.79 = 64.115
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The average of weight of three men A,B and C is 84 kg. Another man D joins the group and the average now becomes 80 kg. If another man E, whose weight is 3 kg.more than that of D, replaces A, then the average weight of B,C,D and E becomes 79 kg. The weight of A is : a) 70 kg b) 72 kg c) 75 kg d) 80 kg e) 78 kg

Description : The average of weight of three men A,B and C is 84 kg. Another man D joins the group and the average now becomes 80 kg. If another man E, whose weight is 3 kg.more than that of D, replaces A, then the average weight of B,C ... 79 kg. The weight of A is : a) 70 kg b) 72 kg c) 75 kg d) 80 kg e) 78 kg

Last Answer : A+B+C = 3×84=252 A+B+C+D= (4×80)=320 D = (320-252)=68 and E = (68+3)=71 Now, B+C+D+E = (4×79)=316 B+C+D=(316-71)=245 kg So, A = (320-245)=75 kg Answer: c)

What are 5 decimals between 4.78 and 4.79?

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Presumptions as to documents are given- a) Secton 75 to 78 b) Section 78 to 81 c) Section 79 to 90 d) Section 81 to 84

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In the schematic diagram of the DC compound generator shown in the illustration, the positive ammeter reading is 500 amps and the negative ammeter reading is 475 amps. What is the current flow through the neutral bus? EL-0037 A. 0 amp B. 12.5 amp C. 25 amp D. 975 amp

Description : In the schematic diagram of the DC compound generator shown in the illustration, the positive ammeter reading is 500 amps and the negative ammeter reading is 475 amps. What is the current flow through the neutral bus? EL-0037 A. 0 amp B. 12.5 amp C. 25 amp D. 975 amp

Last Answer : Answer: C

The full range of VHF frequencies used for communications is: a. 3 to 30 MHz b. 88 to 108 MHz c. 108.0 to 139.95 MHz d. 118.0 to 136.975 MHz

Description : The full range of VHF frequencies used for communications is: a. 3 to 30 MHz b. 88 to 108 MHz c. 108.0 to 139.95 MHz d. 118.0 to 136.975 MHz

Last Answer : d. 118.0 to 136.975 MHz

The full range of VHF frequencies used for communications is: a. 3 to 30 MHz b. 88 to 108 MHz c. 108.0 to 139.95 MHz d. 118.0 to 136.975 MHz

Description : The full range of VHF frequencies used for communications is: a. 3 to 30 MHz b. 88 to 108 MHz c. 108.0 to 139.95 MHz d. 118.0 to 136.975 MHz

Last Answer : d. 118.0 to 136.975 MHz

Calculate natural frequency of damped vibration, if damping factor is 0.52 and natural frequency of the system is 30 rad/sec which consists of machine supported on springs and dashpots. A 25.62 rad/sec B 20.78 rad/sec C 14.4 rad/sec D 15.33 rad/sec

Description : Calculate natural frequency of damped vibration, if damping factor is 0.52 and natural frequency of the system is 30 rad/sec which consists of machine supported on springs and dashpots. A 25.62 rad/sec B 20.78 rad/sec C 14.4 rad/sec D 15.33 rad/sec

Last Answer : A 25.62 rad/sec

Calculate natural frequency of damped vibration, if damping factor is 0.52 and A natural frequency of the system is 30 rad/sec which consists of machine supported on springs and dashpots. ( A )25.62 rad/sec ( B )20.78 rad/sec ( C )14.4 rad/sec ( D )15.33 rad/sec

Description : Calculate natural frequency of damped vibration, if damping factor is 0.52 and A natural frequency of the system is 30 rad/sec which consists of machine supported on springs and dashpots. ( A )25.62 rad/sec ( B )20.78 rad/sec ( C )14.4 rad/sec ( D )15.33 rad/sec

Last Answer : ( A )25.62 rad/sec

Calculate natural frequency of damped vibration, if damping factor is 0.52 and natural frequ the system is 30 rad/sec which consists of machine supported on springs and dashpots. a. 25.62 rad/secb. 20.78 rad/sec c. 14.4 rad/sec d. 15.33 rad/sec

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Last Answer : a. 25.62 rad/sec

A rectangular plot has a concrete path running inner side of the plot is used as a lawn, which has an area of 432 sq.m. If the width of the path is 4 m and the length of the plot is greater than its breadth by 2m, what is the area of the rectangular plot? 1) 980 m^2 2) 975 m^2 3) 984 m^2 4) 960 m^2 5) 965 m^2

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A national random sample of 20 ACT scores from 2010 is listed below. Calculate the sample mean and standard deviation. 29, 26, 13, 23, 23, 25, 17, 22, 17, 19, 12, 26, 30, 30, 18, 14, 12, 26, 17, 18 a. 20.50, 5.79 b. 20.50, 5.94 c. 20.85, 5.79 d. 20.85, 5.94

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What is 76.975 rounded to the nearest hundreth?

Description : What is 76.975 rounded to the nearest hundreth?

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What is 76.975 rounded to the nearest tenth?

Description : What is 76.975 rounded to the nearest tenth?

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What is the annual rock salt production in tonnes in Pakistan? A. 1375 Thousand B. 1298 Thousand C. 975 Thousand D. 610 Thousand 75

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When a voltage of 124 VDC is applied to the illustrated circuit with a resistance of 470 ohms the current will be________. EL-0018 A. 0.263 amps B. 3.79 amps C. 594 milliamps D. 1.7814 amps

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A sand mixture was screened through a standard 10-mesh screen. The mass fraction of the oversize material in feed, overflow and underflow were found to be 0.38, 0.79 and 0.22 respectively. The screen effectiveness based on the oversize is (A) 0.50 (B) 0.58 (C) 0.68 (D) 0.62

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Volumetric ratio of N2 to O2 in dry atmospheric air is (A) 0.21 (B) 3.76 (C) 4.76 (D) 0.79

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