If 96500 coulomb of electricity is passed through CuSo4 solution it will liberate?

If 96500 coulomb of electricity is passed through CuSo4 solution it will liberate?
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A crystalline solid X reacts with dilute HCl to liberate a gas Y. The gas Y decolourises acidified `KMnO_(4)`. When a gas Z is slowly passed into aque

Description : A crystalline solid X reacts with dilute HCl to liberate a gas Y. The gas Y decolourises acidified `KMnO_(4)`. When a gas Z is slowly passed into aque

Last Answer : A crystalline solid X reacts with dilute HCl to liberate a gas Y. The gas Y decolourises acidified `KMnO_(4)`. When ... 2)S` D. `Na_(2)SO_(4),SO_(2)`

An aqueous solution of CuSO4 is acidic in nature because the salt undergoes (a) dialysis (b) hydrolysis (c) electrolysis (d) photolysis

Description : An aqueous solution of CuSO4 is acidic in nature because the salt undergoes (a) dialysis (b) hydrolysis (c) electrolysis (d) photolysis

Last Answer : Ans:(b)

FeSO4 solution mixed with (NH4 ) 2 SO4 solution in 1 : 1 molar ratio gives the test of Fe2+ ion but CuSO4 solution mixed with aqueous ammonia in 1 : 4 molar ratio does not give the test of Cu2+ ion. Explain why ?

Description : FeSO4 solution mixed with (NH4 ) 2 SO4 solution in 1 : 1 molar ratio gives the test of Fe2+ ion but CuSO4 solution mixed with aqueous ammonia in 1 : 4 molar ratio does not give the test of Cu2+ ion. Explain why ?

Last Answer : When FeSO4 and (NH4 ) 2 SO4 solution are mixed in 1 : 1 molar ratio, a double salt is formed. It has the formula FeSO4 (NH4 ) 2 SO4 . 6 H2O. In aqueous solution, the salt dissociates. When CuSO4 and NH3 are mixed in the molar ratio of 1 : 4 in solution, a complex [Cu (NH3 ) 4 ] SO4 is formed.

Why the blue colour of CuSO4 turns colourless during electrolysis of CuSO4 solution by platinum electrode.

Description : Why the blue colour of CuSO4 turns colourless during electrolysis of CuSO4 solution by platinum electrode.

Last Answer : The platinum electrodes are inert. Hence does not dissolve into the solution. The Cu++ ions (blue) present in the solution are discharged on the surface of cathode & OH - are ... a result of this electrolysis, blue coloured CuSO4 solution is slowly converted into colorless H2SO4 solution.

Determine the values of equilibrium constant (Kc) and ΔG° for the following reaction : Ni(s) + 2Ag+ (aq) → Ni2+ (aq) + 2Ag(s), E° = 1.05 V (1F = 96500 C mol-1 -Chemistry

Description : Determine the values of equilibrium constant (Kc) and ΔG° for the following reaction : Ni(s) + 2Ag+ (aq) → Ni2+ (aq) + 2Ag(s), E° = 1.05 V (1F = 96500 C mol-1 -Chemistry

Last Answer : According to the formula ΔG° = -nFE° = – 2 × 96500 ×1.05 or ΔG° = -202650 J mol-1 = -202.65 KJ mol-1 Now ΔG° ⇒ -202650 J Mol-1 R = 8.314 J/Mol/K, T = 298 K

A current of 4 amperes flowing for 45 minutes deposits 1.062 gm of metal at cathode. Calculate the equivalent weight of the metal. (Given 1 Faraday = 96500 C)

Description : A current of 4 amperes flowing for 45 minutes deposits 1.062 gm of metal at cathode. Calculate the equivalent weight of the metal. (Given 1 Faraday = 96500 C)

Last Answer : Given:  c : 4 amperes   t : 45 minutes : 45 x 60 = 2700 seconds   w : 1.062 gm   1 Faraday : 96500 C  To calculate: Eq. Weight (CE)  According to Faraday's first law:   w = z c t Therefore,  z = w / ct  ... g/c   Now, C.E. = 96500 x E.C.E.   C. E. = 96500 x 0.00009833  C.E. = 9.4888 gm

What product is formed when electricity is passed throughan aqueous solution of sodium chloride? (1) Sodium and water (2) Sodium oxide (3) Sodium and chlorine (4) Sodium hydroxide

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Allelochemicals liberate through volatiliza tion a). Terpinoid b). Alkaloids c). Tannins d). Lactones

Description : Allelochemicals liberate through volatiliza tion a). Terpinoid b). Alkaloids c). Tannins d). Lactones

Last Answer : a). Terpinoid

Electricity is passed through water in electrolysis and two gases are formed. If one gas has a boiling point of -183 degrees and other has a boiling point of -253 degrees what are the gasses?

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Last Answer : We know that the gas oxygen has a boiling point of about -183 degrees C. The gas hydrogen has a boiling point of about -253 degrees C.

The amount of different substances produced, when the same quantity of electricity is passed through different solutions are proportional to their (A) Equivalent weight (B) (Equivalent weight)2 (C) Molecular weight (D) (Molecular weight)2

Description : The amount of different substances produced, when the same quantity of electricity is passed through different solutions are proportional to their (A) Equivalent weight (B) (Equivalent weight)2 (C) Molecular weight (D) (Molecular weight)2

Last Answer : (A) Equivalent weight

How is electricity passed through a wire?

Description : How is electricity passed through a wire?

Last Answer : A  wire contains  mobile  electrons  as  majority  charge  carriers  and  holes  as minority  charge carriers when  an emf  or   potential  diffrence is  provided , electrons  flow  in opposite  direction  with  holes(convection current  flow)

Identify the type of reaction(s) in the following equations. (i)CH4 + 2O2 CO2 + 2 H2O (ii) Pb(NO3)2 + 2KI ——–>Pbl2 + 2KNOs (iii) CaO + H2O ——–> Ca(OH)2 (iv) CuSO4 + Zn ——–> ZnSO4 + Cu -Chemistry

Description : Identify the type of reaction(s) in the following equations. (i)CH4 + 2O2 CO2 + 2 H2O (ii) Pb(NO3)2 + 2KI ——–>Pbl2 + 2KNOs (iii) CaO + H2O ——–> Ca(OH)2 (iv) CuSO4 + Zn ——–> ZnSO4 + Cu -Chemistry

Last Answer : Answer. (i) Combustion reaction and oxidation reaction. (ii)Double displacement reaction and precipitation reaction. (iii) Combination reaction. (iv) Displacement reaction.

the number of Cu 's zeros in CuSO4 ?

Description : the number of Cu 's zeros in CuSO4 ?

Last Answer : CuSO4 - Cu 's zaron number +2

Why is CuSO4 more soluble in water than in organic solvent?

Description : Why is CuSO4 more soluble in water than in organic solvent?

Last Answer : CuSO4 is ionic and water is polar. The types of bonding allowwater to dissolve the salt much more easily than an organic solvent(e.g. alcohol, hexane) could.

Why is CuSO4 more soluble in water than in an organic solvent and why is the reverse true salicylic acid?

Description : Why is CuSO4 more soluble in water than in an organic solvent and why is the reverse true salicylic acid?

Last Answer : Water and copper sulfate are both polar compound; polar compounds are dissolved better in polar solvents. Salycilic acid is also polar but the solubility is lower because the benzene ring has a negative effect.

Why is cuso4 the reverse true salicylic acid?

Description : Why is cuso4 the reverse true salicylic acid?

Last Answer : Feel Free to Answer

How many atoms of sulphur are there in CuSO4?

Description : How many atoms of sulphur are there in CuSO4?

Last Answer : Feel Free to Answer

Why is salicylic acid the reverse of CuSO4?

Description : Why is salicylic acid the reverse of CuSO4?

Last Answer : Feel Free to Answer

Is CuSO4 an ionic bond or covalent bond?

Description : Is CuSO4 an ionic bond or covalent bond?

Last Answer : It is considered to be ionic.

What is the correct name for hydrate CuSO4.5H2O?

Description : What is the correct name for hydrate CuSO4.5H2O?

Last Answer : The correct name is copper(II) sulfate pentahydrate.

How many atoms are there in CuSO4?

Description : How many atoms are there in CuSO4?

Last Answer : The answer depends on how many formula units of CuSO4 you have.In one formula unit, there are 6 atoms (1 Cu, + 1 S + 4 O).

Copper substances when exposed to air gains a green coating due to the formation of: (1) CuO (2) CuCO3 Cu(OH)2 (3) CuSO4 (4) Cu(NO3)2

Description : Copper substances when exposed to air gains a green coating due to the formation of: (1) CuO (2) CuCO3 Cu(OH)2 (3) CuSO4 (4) Cu(NO3)2

Last Answer : (2) CuCO3 Cu(OH)2 Explanation: When copper is exposed to air, it reacts with moist carbon dioxide in the air and slowly loses its shiny brown surface and gains a green coat. This green substance is ... Cu(OH)2). The formation of this green coating on the surface of a copper object corrodes it.

How many hydrogen-bonded water molecule(s) are present in CuSO4.5H2O ? Draw its structure to show formation of hydrogen bond.

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Last Answer : Ans- one molecule of water is bonded by hydrogen bond and is deeply embedded in the lattice, While four molecules are bonded with coordinate bond. [ Cu(H2O)4] SO4.H2O

Predict,what would happen if CuSO4 is stored in a zinc vessel?

Description : Predict,what would happen if CuSO4 is stored in a zinc vessel?

Last Answer : Ans.No, as CuSO4 reacts with Zn.

The chemical formula for hydrated copper sulphate is – (a) CuSo4.2H 2 O (b) CuSo4.6H 2 O (c) CuSO 4 .4H 2 O (d) CuSO 4 .5H 2 O

Description : The chemical formula for hydrated copper sulphate is – (a) CuSo4.2H 2 O (b) CuSo4.6H 2 O (c) CuSO 4 .4H 2 O (d) CuSO 4 .5H 2 O

Last Answer : (d) CuSO 4 .5H 2 O

If America was invaded or infiltrated by an overwhelmingly superior foreign power, militarily speaking, would Americans resort to terrorism in a bid to liberate their homeland?

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Last Answer : The Americans practiced Guerilla warfare to get rid to the British..so I would say yes..

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Choose the reactions which would liberate nitrogen gas?

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Description : How many of the following liberate `O_(2)` on heating in a dry test tube ? `CaO, Fe_(2)O_(3), Fe_(3)O_(4), FeO, Cr_(2)O_(3), XeF_(4), Al_(2)O_(3), MgO

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Which of the following reacts with NaOH to liberate a gas ?

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Which of them liberate a gas which turns lime water milky .

Description : Which of them liberate a gas which turns lime water milky .

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Which of the following reaction does not liberate oxygen ?

Description : Which of the following reaction does not liberate oxygen ?

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Which of them liberate a gas which turns lime water milky .

Description : Which of them liberate a gas which turns lime water milky .

Last Answer : Which of them liberate a gas which turns lime water milky . A. B. `{:(CH_(3)-CH-COOH),(" |"),(" "COOH ... ))_(5)-COOH overset(Ca(OH)_(2)//Delta)to` D.

Which of the following reaction does not liberate oxygen ?

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One mole of acidified `K_(2)Cr_(2)O_(7)` on reaction with excess of KCl will liberate….., moles of `I_(2)`.

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Last Answer : One mole of acidified `K_(2)Cr_(2)O_(7)` on reaction with excess of KCl will liberate….., moles of `I_(2)`. A. 6 B. 1 C. 7 D. 3

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