Determine the values of equilibrium constant (Kc) and ΔG° for the following reaction : Ni(s) + 2Ag+ (aq) → Ni2+ (aq) + 2Ag(s), E° = 1.05 V (1F = 96500 C mol-1 -Chemistry

1 Answer

Answer :

According to the formula ΔG° = -nFE° = – 2 × 96500 ×1.05 or ΔG° = -202650 J mol-1 = -202.65 KJ mol-1 Now ΔG° ⇒ -202650 J Mol-1 R = 8.314 J/Mol/K, T = 298 K

Related questions

Description : Two half-reactions of an electrochemical cell are given below : MnO-4 (aq) + 8H+ (aq) + 5e- → Mn2+ (aq) + 4H2O (I), E° = 1.51 V Sn2+ (aq) → Sn4+ (aq) + 2e- ... the redox equation from the standard potential of the cell and predict if the reaction is reactant favoured or product favoured. -Chemistry

Last Answer : The reactions can be represented at anode and at cathode in the following ways : At anode (oxidation) : Sn2+ → = Sn4+ (aq) + 2e- ] 5 E° = + 0.15 V At cathode (reduction) : MnO-4(aq) + 8H+ ... = E°cathode - E°anode = 1.51 - 0.15 = + 1.36 V ∴ Positive value of E°cell favours formation of product.

Description : Two half-reactions of an electrochemical cell are given below : MnO-4 (aq) + 8H+ (aq) + 5e- → Mn2+ (aq) + 4H2O (I), E° = 1.51 V Sn2+ (aq) → Sn4+ (aq) + ... -reactions and calculate the cell potential from the standard potentials and predict if the reaction is reactant or product favoured. -Chemistry

Last Answer : The reactions can be represented at anode and at cathode in the following ways : At anode (oxidation) : Sn2+ → Sn4+ (aq) + 2e- ] 5 E° = + 0.15 V Af cathode (reduction) : MnO-4(aq) + 8H+ ( ... = E°cathode - E°anode = 1.51 - 0.15 = + 1.36 V ∴ Positive value of E°cell favours formation of product.

Description : The temperature at which the reaction : `Ag_(2)O(s)rarr 2Ag(s)+1//2O_(2)(g)` is at equilibrium is …….., Given `Delta H=30.5 KJ mol^(-1)` and `Delta S

Last Answer : The temperature at which the reaction : `Ag_(2)O(s)rarr 2Ag(s)+1//2O_(2)(g)` is at equilibrium is .., ... 362.12 K` C. `262.12 K` D. `562.12 K`

Description : (a) What are fuel cells? Explain the electrode reactions involved in the working of H2 – O2 fuel cell. (b) Represent the galvanic cell in which the reaction Zn (s) + Cu2+ (aq) → Zn2+ (aq) + Cu (s) takes place. -Chemistry

Last Answer : (a) Fuel cells : These cells are the devices which convert the energy produced during combustion of fuels like H2, CH4, etc. directly into electrical energy. The electrode reaction for H2 – O2 fuel cell : (b) The galvanic cell may be represented as Zn (s) | Zn2+ (1M) || Cu2+ (1M) | Cu (s)

Description : For the reaction `Ag_(2)O(s)rarr 2Ag(s)+1//2O_(2)(g)` the value of `Delta H=30.56 KJ mol^(_1)` and `Delta S = 66 JK^(-1)mol^(-1)`. The temperature at

Last Answer : For the reaction `Ag_(2)O(s)rarr 2Ag(s)+1//2O_(2)(g)` the value of `Delta H=30.56 KJ mol^(_1)` and `Delta ... :- A. 373 K B. 413 K C. 463 K D. 493 K

Description : (a) Write the essential condition for the following reaction to take place: 2AgBr--> 2Ag + Br2 Write one application of this reaction. (b) Complete the following chemical equation of a chemical ... science-5 (c) What happens when water is added to quick line. Write chemical equation. -Chemistry

Last Answer : Answer. This reaction is used in photography. (c) Slaked lime is formed with hissing sound and lot of heat is envolved.

Description : In which of the following reaction equilibrium, the value of equilibrium constant Kp will be more than is Kc? (A) 2HI ⇌ H2 + I2 (B) N2O4 ⇌ 2NO2 (C) 2SO2 + O2 ⇌ 2SO3 (D) None of these

Last Answer : (B) N2O4 ⇌ 2NO2

Description : For a heterogeneous catalytic reaction, A + B → C, with equimole feed of A and B, the initial rate - rA0 is invariant with total pressure. The rate controlling step is (A) Surface Kc /(1 + TS ) ... A and absorbed B (C) Surface reaction between A in the gas phase and absorbed B (D) Desorption of C

Last Answer : (D) Desorption of C

Description : Sodium reacts with water to form sodium hydroxide and hydrogen gas. The balanced equation which represents the above reaction is (a) Na(s) + 2H20(l) → 2NaOH(aq) + 2H2(g) (b) 2Na(s) + 2H2O(l) → 2NaOH(aq) +H2(g) (c) 2Na(s) + 2H20(l) → NaOH(aq) + 2H2(g) (d) 2Na(s) + H20(l) - 2NaOH(aq) + 2H2(g)

Last Answer : Answer: (b)

Description : What information do you get from the following chemical equation: Zn(s) + 2HCl (dil) → ZnCl2 (aq) + H2(g)

Last Answer : This gives zinc chloride and hydrogen. The word equation is: Zinc + Hydrochloric acid → Zinc chloride + Hydrogen Formulae for the products are ZnCl2 and H2

Description : The irreversible reaction, X → Y, is the special case of the reversible reaction, X ⇌ Y, in which the (A) Equilibrium constant is infinite (B) Fractional conversion of 'A' at equilibrium is unity (C) Concentration of 'A' at equilibrium is zero (D) All (A), (B) and (C)

Last Answer : (D) All (A), (B) and (C)

Description : For the reversible reaction A ⇌ 2B, if the equilibrium constant K is 0.05 mole/litre; starting from initially 2 moles of A and zero moles of B, how many moles will be formed at equilibrium? (A) 0.253 (B) 0.338 (C) 0.152 (D) 0.637

Last Answer : (B) 0.338

Description : The reaction A (l) → R(g) is allowed to reach equilibrium conditions in an autoclave. At equilibrium, there are two phases, one a pure liquid phase of A and the other a vapor phase of A, R and S. Initially A alone is present. The numbers of degrees of freedom are: (A) 1 (B) 2 (C) 3 (D) 0

Last Answer : (B) 2

Description : For the reaction `Ag_(2)O(s)rarr 2Ag(s)+1//2O_(2)(g)`, which one of the following is true :

Last Answer : For the reaction `Ag_(2)O(s)rarr 2Ag(s)+1//2O_(2)(g)`, which one of the following is true : A. ` ... . `Delta H lt Delta H` D. `Delta H gt Delta E`

Description : A second order liquid phase reaction, A → B, is carried out in a mixed flow reactor operated in semi batch mode (no exit stream). The reactant A at concentration CAF is fed to the reactor at a volumetric flow rate of F. The volume ... 2V (C) d(VCA )/dt = -FCA - kCA 2V (D) d(VCA )/dt = FCAF - kCA 2V

Last Answer : (D) d(VCA )/dt = FCAF - kCA 2V

Description : `Co^(2+)(aq.)+SCN^(-) (aq.) to "Complex"(X)` `Ni^(2+)(aq.) +"Dimethylglyoxime" overset(NH_(4)OH) to "Complex"(Y)` The coordination number of cobalt an

Last Answer : `Co^(2+)(aq.)+SCN^(-) (aq.) to "Complex"(X)` `Ni^(2+)(aq.) +"Dimethylglyoxime" overset(NH_ ... (Y) is diamagnetic D. (X) and (Y) both are diamagnetic.

Description : `Co^(2+)(aq.)+SCN^(-) (aq.) to "Complex"(X)` `Ni^(2+)(aq.) +"Dimethylglyoxime" overset(NH_(4)OH) to "Complex"(Y)` The coordination number of cobalt an

Last Answer : `Co^(2+)(aq.)+SCN^(-) (aq.) to "Complex"(X)` `Ni^(2+)(aq.) +" ... both tetrahedral C. square planar and tetrahedral D. both square planar.

Description : `Co^(2+)(aq.)+SCN^(-) (aq.) to "Complex"(X)` `Ni^(2+)(aq.) +"Dimethylglyoxime" overset(NH_(4)OH) to "Complex"(Y)` The coordination number of cobalt an

Last Answer : `Co^(2+)(aq.)+SCN^(-) (aq.) to "Complex"(X)` `Ni^(2+)(aq.) +" ... . tetrathiocyanoato-S-cobaltate(III) and bis(dimethylglyoximato) nickel (II).

Description : At absolute zero temperature, for any reaction involving condensed phases (A) Δ G° = 0 , Δ H° = 0 (B) Δ H° = 0 , Δ S° = 0 (C) Δ S° = 0 , Δ E° = 0 (D) Δ S° = 0 , Δ Cp° = 0

Last Answer : C) Δ S° = 0 , Δ E° = 0

Description : Given that the standard free energy change (∆G°) for the hydrolysis of ATP is -7.3 K cal/mol and that for the hydrolysis of Glucose 6-phosphate is -3.3 Kcal/mol, the ∆G° for the phosphorylation of glucose is Glucose + ATP → ... -10.6 Kcal/mol (B) -7.3 Kcal/mol (C) -4.0 Kcal/mol (D) +4.0 Kcal/mol

Last Answer : Answer : C

Description : Two substances, A and B were made to react to form a third substance, A2B according to the following reaction 2A + B → A2 B. Which of the following statements concerning this reaction are incorrect? -Chemistry 9th

Last Answer : (c) (i), (iii), (iv) Consider the example of H2O

Description : Can anyone help me with this? Chlorine and carbon monoxide gases are mixed in a 1.00L container and the following equilibrium is established: CO(g) + Cl2(g) COCl2(g).. Initially 1.5 mol of ... monoxide. At equilibrium, 0.8 mol of COCl2(g) was found. How do you calculate the percent reaction?

Last Answer : For a start, your equation isn't balanced; it should be Cl2 (Cl2, not 2Cl, because of HONClBrIF). Given this, if we assume the reaction goes to completion, 1.5 mol Cl2 will produce 1.5 mol ... .3% Incidentally, is that supposed to be CO or Co? It has no effect on the calculation, just curious.

Description : For a reaction `2X(s)+2Y(s)rarr 2Cl(l)+D(g)` The `q_(p)` at `27^(@)C` is -28 K Cal. `mol^(-1)`. The `q_(V)` is ___________ K. Cal. `mol^(-1)` :-

Last Answer : For a reaction `2X(s)+2Y(s)rarr 2Cl(l)+D(g)` The `q_(p)` at `27^(@)C` is -28 K Cal. `mol^(-1)`. The `q_( ... . `-27.4` B. `+27.4` C. `-28.6` D. `28.6`

Description : A proton moves at a speed `v = 2xx10^(6) m//s` in a region of constant magnetic field of magnitude B = 0.05 T. The direction of the proton when it ent

Last Answer : A proton moves at a speed `v = 2xx10^(6) m//s` in a region of constant magnetic field of magnitude B = 0.05 T. ... `0.209 m` C. `2.82 m` D. `2.41 m`

Description : The quantity of electricity requried to reduce 0.05 mol of `MnO_(4)^(-)` to `Mn^(2+)` in acidic medium would be

Last Answer : The quantity of electricity requried to reduce 0.05 mol of `MnO_(4)^(-)` to `Mn^(2+)` in acidic medium would be A. ... F B. 0.05 F C. 0.15 F D. 0.25 F

Description : Identify the substances that are oxidised and the substances which are reduced in the following reactions. (i) 4Na(s) + O2(g) → 2Na2O(s) (ii) CuO (s) + H2(g) → Cu (s) + H2O(l) -Chemistry-10

Last Answer : (i) Substances oxidised is Na as it gains oxygen and oxygen is reduced. (ii) Substances reduced is Cu as hydrogen is oxidised as it gains oxygen.

Description : Trace elements are a. Zn+2, Cu+2, Mn+2 b. MO6+, Ni2+, B3+ and CO2+ c. Both a and b d. None of these

Last Answer : Ans: D

Description : In the reaction `N_(2(g))+O_(2(g))rArr2NO_((g))`at equilibrium the concentrations of `N_(2),O_(2)andNO` are 0.25 , 0.05 and 1 M respectively . Calcula

Last Answer : In the reaction `N_(2(g))+O_(2(g))rArr2NO_((g))`at equilibrium the concentrations of `N_(2),O_(2)andNO` are 0.25 ... .75 M , 0.55 M D. 0.75 M , 0.45 M

Description : The correct values of ionization enthalpies(in KJ `"mol"^(-1)`) of Si, P, Cl, and S respectively are: a)`786, 1012, 999, 1256` b)`1012, 786, 999, 1256

Last Answer : The correct values of ionization enthalpies(in KJ `"mol"^(-1)`) of Si, P, Cl, and S respectively are: ... . `786,1012,1256,999` D. `786,999,1012,1256`

Description : A student measures time for 20 oscillations of a simple pendulum as 30 s. 32 s, 35 s and 31 s. 1f the minimum division in the measuring clock

Last Answer : A student measures time for 20 oscillations of a simple pendulum as 30 s. 32 s, 35 s and 31 s. 1f the minimum ... 1 (C) 32 2 (D) 32 5

Description : In an L-C circuit shown in figure C=1F, L=4H At time t=0, charge in the capacitor is 4C and it is decreasing at a rate of `sqrt5 C//s` Choose the corr

Last Answer : In an L-C circuit shown in figure C=1F, L=4H At time t=0, charge in the capacitor is 4C and it is ... a and b are correct D. Both a and b are wrong

Description : In the figure shown `C_(1)=1F, C_(2)=2F and L=5H`. Initially `C_(1)` is charged 50V and `C_(2)` to 10V. Switch S is closed at time t=D. Suppose at som

Last Answer : In the figure shown `C_(1)=1F, C_(2)=2F and L=5H`. Initially `C_(1)` is charged 50V and `C_(2)` to 10V. ... will A. 10 J B. 15 J C. 25 J D. 40 J

Description : In the figure shown `C_(1)=1F, C_(2)=2F and L=5H`. Initially `C_(1)` is charged 50V and `C_(2)` to 10V. Switch S is closed at time t=D. Suppose at som

Last Answer : In the figure shown `C_(1)=1F, C_(2)=2F and L=5H`. Initially `C_(1)` is charged 50V and `C_(2)` to 10V. ... (2) A` C. `20sqrt(3) A` D. `12sqrt(6) A`

Description : In the figure shown `C_(1)=1F, C_(2)=2F and L=5H`. Initially `C_(1)` is charged 50V and `C_(2)` to 10V. Switch S is closed at time t=D. Suppose at som

Last Answer : In the figure shown `C_(1)=1F, C_(2)=2F and L=5H`. Initially `C_(1)` is charged 50V and `C_(2)` to 10V. ... ` B. `15sqrt(2) A` C. `10 A` D. `20 A`

Description : The equilibrium, H2O(l) ⇌ H^+(aq) + OH^-(aq) is :

Last Answer : The equilibrium, H2O(l) ⇌ H+(aq) + OH-(aq) is : a. dynamic b. static c. physical d. mechanical

Description : If 96500 coulomb of electricity is passed through CuSo4 solution it will liberate?

Last Answer : Need answer

Description : A current of 4 amperes flowing for 45 minutes deposits 1.062 gm of metal at cathode. Calculate the equivalent weight of the metal. (Given 1 Faraday = 96500 C)

Last Answer : Given:  c : 4 amperes   t : 45 minutes : 45 x 60 = 2700 seconds   w : 1.062 gm   1 Faraday : 96500 C  To calculate: Eq. Weight (CE)  According to Faraday's first law:   w = z c t Therefore,  z = w / ct  ... g/c   Now, C.E. = 96500 x E.C.E.   C. E. = 96500 x 0.00009833  C.E. = 9.4888 gm

Description : Compare the following complexes’ with respect to structural shapes of units, magnetic behaviour and hybrid orbitals involved in units : (i) [Ni(CN)4]2- (ii) [NiCl4]2- (iii) [CoF6]3- [At. Nos. : Ni = 28; Co = 27] -Chemistry

Last Answer : (i) [Ni(CN)4]2- Shape : Octahedral outer orbital complex Hybridisation : sp3d2 Magnetic behaviour : Paramagnetic (4 unpaired electrons)

Description : Compare the following complexes with respect to structural shapes of units, magnetic behaviour and hybrid orbitals involved in units : [Co(NH3)6]+3, [Cr(NH3)6]3+, Ni(CO)4 (At. nos. : Co = 27, Cr = 24, Ni = 28) -Chemistry

Last Answer : (i) [Co(NH3)6]+3 → Octahedral shape, d2sp3 hybridisation, diamagnetic Formation of [Co(NH2)6]+3 → oxidation state of Co is +3.

Description : Compare the following complexes with respect to their shape, magnetic behaviour and the hybrid orbitals involved : (i) [CoF4]2- (ii) [Cr(H2O)2(C2O4)2]– (iii) [Ni(CO)4] (Atomic number : Co = 27, Cr = 24, Ni = 28) -Chemistry

Last Answer : (i) [COF4]2_ : Tetrafluorido cobalt (III) ion Coordination number = 4 Shape = Tetrahedral Hybridisation = sp3 Important Questions for Class 12 Chemistry Chapter 9 Coordination Compounds Class 12 Important Questions 7

Description : Explain why [Co(NH3)6]3+ is an inner orbital complex whereas [Ni(NH3)6]2+ is an outer orbital complex. (At. no. Co = 27, Ni = 28) -Chemistry

Last Answer : In [Co(NH3)6]3+, the d-electrons of Co3+ ([Ar]3d6 45°) get paired leaving behind two empty d-orbital and undergo d2sp3 hybridization and hence inner orbital complex, while in [Ni(NH3)6]2+ ... of Ni2+([Ar]3d8 45°) do not pair up and use outer 4d subshell hence outer orbital complex.

Description : Describe the shape and magnetic behaviour of following complexes : (i) [CO(NH3)6]3+ (ii) [Ni(CN)4]2- (At. No. Co = 27, Ni = 28) -Chemistry

Last Answer : (i) [CO(NH3)6]3+ : Orbitals of CO3+ ion : Hybridization : d2sp3 Shape : Octahedral Magnetic behaviour : Diamagnetic (absence of unpaired electrons) (ii) [Ni(CN)4]2-

Description : What is the IUPAC name of the complex [Ni(NH3)6]Cl2? -Chemistry

Last Answer : [Ni(NH3)6]Cl2 IUPAC name : Hexaamminenickel (II) chloride.

Description : Give IUPAC name of the ionization isomer of [Ni(NH3)3NO3]Cl. -Chemistry

Last Answer : IUPAC name : Triammine chlorido nickel (II) nitrate [Ni(NH3)3NO3]Cl

Description : Give IUPAC name of ionization isomer of [Ni(NH3)3NO3]Cl. -Chemistry

Last Answer : IUPAC name : Triammine nitrato nickel (III) chloride

Description : The relation between Kc and Kp for the reaction A(g) + B(g) ⇌ 2C(g) + D(g) is :

Last Answer : The relation between Kc and Kp for the reaction A(g) + B(g) ⇌ 2C(g) + D(g) is : a. Kc = Kp/RT b. Kp ... Kc = \(\frac{1}{\sqrt{Kp}}\) d. Kp/Kc = 1

Description : How value of Kc can help to predict the extent to which a chemical reaction can take place?

Last Answer : The extent of reaction depends upon the magnitude of Kc. i.e. (i) Very small value of Kc: when Kc is very small the forward reaction will not occur to an appreciable extent ... neither very large nor very small, the equilibrium mixture contains appreciable amounts of both reactant and products.

Description : How Kc can be applied to calculate direction of chemical reaction?

Last Answer : (i) If < Kc Then the reaction will proceed in the forward direction until the equilibrium is established. (ii) If > Kc Then the reaction will proceed in the backward direction until the equilibrium is established. If = kc Then the reaction is already in equilibrium.

Description : The dimensions of rate constant for reaction 3A → B are (l/gm mole)/min. Therefore the reaction order is (A) 0 (B) 1 (C) 2 (D) 3

Last Answer : (C) 2

Description : A batch adiabatic reactor at an initial temperature of 373°K is being used for the reaction, A → B. Assume the heat of reaction is - 1kJ/mole at 373°K and heat capacity of both A and B to be constant and equal ... rise after a conversion of 0.5 will be: (A) 5°C (B) 10°C (C) 20°C (D) 100°C

Last Answer : (B) 10°C