What are the 2 factors of 28 add up to 9 what are they?

What are the 2 factors of 28 add up to 9 what are they?
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What two factors multiply to equal 196 and add up to equal -28?

Description : What two factors multiply to equal 196 and add up to equal -28?

Last Answer : -14 and -14 Add them together to get -28 Multiply them to get 196

what two numbers add up to 28 and once multiplied equals 160?

Description : what two numbers add up to 28 and once multiplied equals 160?

Last Answer : need answer

What is the length of the 3rd side of a triangle having sides of 17.1cm and 28.8cm whose opposite angles add up to 72 degrees?

Description : What is the length of the 3rd side of a triangle having sides of 17.1cm and 28.8cm whose opposite angles add up to 72 degrees?

Last Answer : The largest angle then is 108 degrees that is opposite the 3rdside which is the longest side and by using the cosine rule intrigonometry it is 37.77cm in length rounded to two decimalplaces

If you add anything other than 60 to 28, it will be 8 ?

Description : If you add anything other than 60 to 28, it will be 8 ?

Last Answer : If you add "e" without 60 to 28, it will be 8.

what are the common factors and factors of 21 and 28.?

Description : what are the common factors and factors of 21 and 28.?

Last Answer : the greatest common factor is 7, because 21 divided by 7 is 3, 28 divided by 7 is 4 and 56 divided by 7 is 8.

Two filling tap can fill a dumper in 14 and 28 min. respectively and when the waste tap is open, they can together fill it in 35 min. The waste pipe can empty the full dumper in – A) 152/9 hrs. B) 137/7 hrs. C) 60/9 hrs. D) 140/11 hrs.

Description : Two filling tap can fill a dumper in 14 and 28 min. respectively and when the waste tap is open, they can together fill it in 35 min. The waste pipe can empty the full dumper in – A) 152/9 hrs. B) 137/7 hrs. C) 60/9 hrs. D) 140/11 hrs.

Last Answer :  D 1/14 + 1/28 – 1/35 =>10 + 5 – 4/140 =>11/140 =>140/11 => hence answer is 140/11 hours.

A floral design on a floor is made up of 16 tiles which are triangular, the sides of the triangle being 9 cm, 28 cm and 35 cm (see figure). -Maths 9th

Description : A floral design on a floor is made up of 16 tiles which are triangular, the sides of the triangle being 9 cm, 28 cm and 35 cm (see figure). -Maths 9th

Last Answer : NCERT Solutions for Class 9 Maths Chapter 12 Heron's Formula NCERT Solutions for Class 9 Maths Chapter 12 Heron's Formula Ex 12.1 are part of NCERT Solutions for Class 9 Maths. Here we have given NCERT Solutions for Class 9 Maths ... = 48 m Sides ∆ABC are a = AB = 30m, b = AD = 30m, c = BD = 48m S

What two factors of 20 add up to 14?

Description : What two factors of 20 add up to 14?

Last Answer : 34

What are the factors of -180 that would add up to 57?

Description : What are the factors of -180 that would add up to 57?

Last Answer : -123

1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16, 17, 18, 19, 20, 21, 23, 24, 25, 26, 27, 28, 29, 30, 31, 32, 33, 34, 35, 36, 37, 38, 39, 40, 41, 42, 43, 44, 45, 46, 47, 48, 49, 50'. What number is missing? -Riddles

Description : 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16, 17, 18, 19, 20, 21, 23, 24, 25, 26, 27, 28, 29, 30, 31, 32, 33, 34, 35, 36, 37, 38, 39, 40, 41, 42, 43, 44, 45, 46, 47, 48, 49, 50'. What number is missing? -Riddles

Last Answer : 22

What is the sum of a number times 9 and 28 is at least -20 as an equation?

Description : What is the sum of a number times 9 and 28 is at least -20 as an equation?

Last Answer : 9*n + 28 >= -20.

Are there the same number of days between January 7 and February 22 as there are between February 22 and April 9 - with February having 28 days?

Description : Are there the same number of days between January 7 and February 22 as there are between February 22 and April 9 - with February having 28 days?

Last Answer : Yes. In a standard year, there are 46 days between the 7th ofJanuary and the 22nd of February and 46 days between the 22nd ofFebruary and the 9th of April.

How can you divide 28 cans of soda into two groups so the ratio is 9 to 5?

Description : How can you divide 28 cans of soda into two groups so the ratio is 9 to 5?

Last Answer : The ratio then will be 18 to 10

Current SIMMs have either or connectors (pins) A) 9 or 32 B) 30 or 70 C) 28 or 72 D) 30 or 72

Description : Current SIMMs have either or connectors (pins) A) 9 or 32 B) 30 or 70 C) 28 or 72 D) 30 or 72

Last Answer : Answer : D

A 15-year-old girl was seen by her family physician because of increasing lethargy. She had a recent history of the "flu". Biochemistry tests show that she has renal impairement. serum sodium 140 mmol/L (137 - 144) serum potassium 4.2 mmol/L (3.5 - 4.9) serum urea 28 mol/L (2.5 - 7.5) serum creatinine 280 µmol/L (60 - 110) Her condition does not improve after several weeks on corticosteroid therapy, so a renal biopsy is performed. The biopsy demonstrates the presence of segmental sclerosis of 3 of 10 glomeruli identified in the biopsy specimen. Immunofluorescence studies and electron microscopy do not reveal evidence for immune deposits. What is the most appropriate advice to give regarding her condition? 1) She has an underlying malignancy 2) She may require a renal transplant in 10 years

Description : A 15-year-old girl was seen by her family physician because of increasing lethargy. She had a recent history of the "flu". Biochemistry tests show that she has renal impairement. ... will likely develop a restrictive lung disease 5) She will probably improve with additional corticosteroid therapy

Last Answer : Answers-2 The findings point to focal segmental glomerulosclerosis (FSGS), which leads to chronic renal failure in half of cases. The lack of resolution with corticosteroid therapy and the progression to chronic renal failure is what sets FSGS apart from minimal change disease.

When a voltage of 112 VDC is applied to the illustrated circuit with a resistance of 12 ohms the current will be ________. EL-0018 A. .107 amps B. 1.28 amps C. 9.33 amps D. 124 milliamps

Description : When a voltage of 112 VDC is applied to the illustrated circuit with a resistance of 12 ohms the current will be ________. EL-0018 A. .107 amps B. 1.28 amps C. 9.33 amps D. 124 milliamps

Last Answer : Answer: C

According to the Fenske equation, what will be the minimum number of plates required in a distillation column to separate an equimolar binary mixture of components A and B into an overhead fraction containing 99 mol% A and a bottom fraction containing 98 mol% B ? Assume that relative volatility (αAB = 2) does not change appreciably in the column. (A) 5 (B) 9 (C) 12 (D) 28

Description : According to the Fenske equation, what will be the minimum number of plates required in a distillation column to separate an equimolar binary mixture of components A and B into an overhead fraction containing 99 mol% A and a ... in the column. (A) 5 (B) 9 (C) 12 (D) 28

Last Answer : (C) 12

A system has a mass of 0.5 kg and spring stiffness of 2452 N/m. Find the natural frequency of the system. A. 5.14 Hz B. 9.14 Hz C. 11.14 Hz D. 28.14 Hz

Description : A system has a mass of 0.5 kg and spring stiffness of 2452 N/m. Find the natural frequency of the system. A. 5.14 Hz B. 9.14 Hz C. 11.14 Hz D. 28.14 Hz

Last Answer : C. 11.14 Hz

A system has a mass of 0.5 kg and spring stiffness of 2452 N/m. Find the natural frequency of the system. (A) 5.14 Hz (B) 9.14 Hz (C) 11.14 Hz (D) 28.14 Hz

Description : A system has a mass of 0.5 kg and spring stiffness of 2452 N/m. Find the natural frequency of the system. (A) 5.14 Hz (B) 9.14 Hz (C) 11.14 Hz (D) 28.14 Hz

Last Answer : (C) 11.14 Hz

Deuterium oxide and inulin are injected into a normal 30-year-old man. The volume of distribution of deuterium oxide is found to be 42 L and that of inulin 14 L. a. The man’s intracellular fluid volume is about 14 L. b. The man’s intracellular fluid volume is about 28 L. c. The man’s plasma volume is about 7 L. d. The man’s interstitial fluid volume is about 9 L. e. The man’s total body water cannot be calculated from these data

Description : Deuterium oxide and inulin are injected into a normal 30-year-old man. The volume of distribution of deuterium oxide is found to be 42 L and that of inulin 14 L. a. The man's intracellular fluid ... fluid volume is about 9 L. e. The man's total body water cannot be calculated from these data

Last Answer : The man’s intracellular fluid volume is about 28 L.

Current SIMMs have either “ or “ connectors (pins) a. 9 or 32 b. 30 or 70 c. 28 or 72 d. 30 or 72

Description : Current SIMMs have either “ or “ connectors (pins) a. 9 or 32 b. 30 or 70 c. 28 or 72 d. 30 or 72

Last Answer : 30 or 72

Current SIMMs have either “ or “ connectors (pins) a. 9 or 32 b. 30 or 70 c. 28 or 72 d. 30 or 72

Description : Current SIMMs have either “ or “ connectors (pins) a. 9 or 32 b. 30 or 70 c. 28 or 72 d. 30 or 72

Last Answer : 30 or 72

For water at 300°C, it has a vapour pressure 8592.7 kPa and fugacity 6738.9 kPa Under these conditions, one mole of water in liquid phase has a volume of 25.28 cm3 and that in vapour phase in 391.1 cm3.Fugacity of water (in kPa) at 9000 kPa will be (A) 6738.9 (B) 6753.5 (C) 7058.3 (D) 9000

Description : For water at 300°C, it has a vapour pressure 8592.7 kPa and fugacity 6738.9 kPa Under these conditions, one mole of water in liquid phase has a volume of 25.28 cm3 and that in vapour phase in 391.1 cm3.Fugacity of water (in kPa) at 9000 kPa will be (A) 6738.9 (B) 6753.5 (C) 7058.3 (D) 9000

Last Answer : (B) 6753.5

A water tank contains 1.3 m deep water. The pressure exerted by the water per metre length of the tank is (A) 2.89 kN (B) 8.29 kN (C) 9.28 kN (D) 28.9 kN

Description : A water tank contains 1.3 m deep water. The pressure exerted by the water per metre length of the tank is (A) 2.89 kN (B) 8.29 kN (C) 9.28 kN (D) 28.9 kN

Last Answer : Answer: Option B

3 7 6 28 9 112 12 ? a) 112 b) 448 c) 28 d) 38 e) None of these

Description : 3 7 6 28 9 112 12 ? a) 112 b) 448 c) 28 d) 38 e) None of these

Last Answer : First series: 3, 6, 9 (increased by 3) Second Series: 7, 28, 112, 448 (multiplied by 4) Answer: d)

Evaluate: (0.625 × 0.0729 × 28.9)/(0.0081 × 0.025 × 1.7) a) 382.5 b) 3725 c) 3625 d) 3825 e) None of these

Description : Evaluate: (0.625 × 0.0729 × 28.9)/(0.0081 × 0.025 × 1.7) a) 382.5 b) 3725 c) 3625 d) 3825 e) None of these

Last Answer : (0.625×0.0729×28.9) / (0.0081×0.025×1.7) = (625/25) × (729/81) × (289/17) = 25×9× 17 = 3825. Answer: d)

1/9, 4/9, 1 7/9, 7 1/9, 28 4/9, ? a) 112(1/9) b) 113(7/9) c) 115(4/9) d) 140(5/9) e) 142(2/9)

Description : 1/9, 4/9, 1 7/9, 7 1/9, 28 4/9, ? a) 112(1/9) b) 113(7/9) c) 115(4/9) d) 140(5/9) e) 142(2/9)

Last Answer : The pattern is 1/9,4/9,16/9,64/9,256/9,1024/9. 1024/9 = 113 7/9 Answer: b)

Two trains starting at the same time from two stations 200 km apart and going in opposite directions cross each other at a distance of 110 km from one of the stations. What is the ratio of their speeds? A.9 : 28 B.11 : 9 C.11 : 8 D.9 : 22 E.None of these

Description : Two trains starting at the same time from two stations 200 km apart and going in opposite directions cross each other at a distance of 110 km from one of the stations. What is the ratio of their speeds? A.9 : 28 B.11 : 9 C.11 : 8 D.9 : 22 E.None of these

Last Answer : Answer – B (11 : 9) Explanation – In the same time, they cover 110 km and 90 km respectively.Ratio of their speeds = 110 : 90 = 11 : 9 

Two trains are running at 40 km/hr and 20 km/hr respectively in the same direction. Fast train completely passes a man sitting in the slower train in 5 seconds. What is the length of the fast train? A.27 7/9 m B.28 m C.29 m D.30 2/7 m E.None of these

Description : Two trains are running at 40 km/hr and 20 km/hr respectively in the same direction. Fast train completely passes a man sitting in the slower train in 5 seconds. What is the length of the fast train? A.27 7/9 m B.28 m C.29 m D.30 2/7 m E.None of these 

Last Answer : Answer – A (27 7/9 m) Explanation – When SAME direction- MINUS Relative speed = (40-20) km/hr = [20 x 5/18] m/sec = [50/9] m/sec. Length of faster train = sxt=[50/9 x 5] m = 250/9 m = 27 7/9 m.

Present ages of Simmi and Anu are in the ratio of 5 : 4 respectively. Three years hence, the ratio of their ages will become 11 : 9 respectively, What is Anu’s present age in years? A.20 B.24 C.28 D.35 E.None of these

Description : Present ages of Simmi and Anu are in the ratio of 5 : 4 respectively. Three years hence, the ratio of their ages will become 11 : 9 respectively, What is Anu’s present age in years? A.20 B.24 C.28 D.35 E.None of these

Last Answer : Answer – B (24) Explanation – Let the present ages of Simmi and Anu be 5x years and 4x years respectively Then, [5X + 3] / [4X + 3] =11/9 x=6 Anu’s present age = 4X = 24 years

The external length, breadth and height of a closed box are 10cm, 9cm and 7cm respectively. The total inner surface area of the box is 262 sq.cm. If the walls of the box are of uniform thickness “t” cm, then “t” equals a) 1cm b) 23/3 cm c) 28/9 cm d) 42.5 cm

Description : The external length, breadth and height of a closed box are 10cm, 9cm and 7cm respectively. The total inner surface area of the box is 262 sq.cm. If the walls of the box are of uniform thickness “t” cm, then “t” equals a) 1cm b) 23/3 cm c) 28/9 cm d) 42.5 cm

Last Answer : a) 1cm

BIRMINGHAM EGBB/BHX SA0850 280850 18014kt 9999 SCT024 BKN030 BKN045 12/08 Q1011 = FC0600 280600Z 280816 190015G27kt 9999 BKN025 TEMPO 0812 5000 – DZ BKN012 BECMG 1214 19022G37 = FT0400 280434Z 281212 19022G37 9999 BKN025 TEMPO 1902 5000 RA BKN010 BECMG 2201 25007kt Refer to weather information for Birmingham above. What is the total time for which the weather is forecast? a. 9 hours b. 18 hours c. 24 hours d. 28 hours

Description : BIRMINGHAM EGBB/BHX SA0850 280850 18014kt 9999 SCT024 BKN030 BKN045 12/08 Q1011 = FC0600 280600Z 280816 190015G27kt 9999 BKN025 TEMPO 0812 5000 - DZ BKN012 BECMG 1214 19022G37 = FT0400 280434Z 281212 19022G37 9999 ... weather is forecast? a. 9 hours b. 18 hours c. 24 hours d. 28 hours

Last Answer : d. 28 hours

Current SIMMs have either … or … connectors (pins) a. 9 or 32 b. 30 or 70 c. 28 or 72 d. 30 or 72

Description : Current SIMMs have either … or … connectors (pins) a. 9 or 32 b. 30 or 70 c. 28 or 72 d. 30 or 72

Last Answer : d. 30 or 72

Current SIMMs have either … or … connectors (pins) a. 9 or 32 b. 30 or 70 c. 28 or 72 d. 30 or 72

Description : Current SIMMs have either … or … connectors (pins) a. 9 or 32 b. 30 or 70 c. 28 or 72 d. 30 or 72

Last Answer : d. 30 or 72

After finishing the work by Aswin for 9 days, Ajay finds that only 1/4 of the work has been done. He employs Ajay who is 80% as efficient as Aswin. How many days more would Ajay take to complete the work? a) 32 b) 28 c) 34 d) 26

Description : After finishing the work by Aswin for 9 days, Ajay finds that only 1/4 of the work has been done. He employs Ajay who is 80% as efficient as Aswin. How many days more would Ajay take to complete the work? a) 32 b) 28 c) 34 d) 26

Last Answer : C Aswin has completed 1/4 of the work in 9 days Then he can complete the total work in 1/4 ---- 9 1 ---- ? = 36 days But given Ajay is only 80% as efficient as Aswin Ajay = 1/36*80/100=1/45 Ajay can ... work can be completed in 1 ------ 45 3/4 ------ ? =3/4*45 =33.75=34 days (approx.)