If A cup as sugar has a volume of 237 ml what is the maa o the cup if the cup of sugar if the density is 1.59 g ml?

1 Answer

Answer :

Need answer

Related questions

Description : what is the density of CO GAS IF 0.196 g occupied a volume of 100 ml?

Last Answer : 100ml = 1 dm3 0.196g = 196x10-6kg Density = mass/volume Density of CO = 196x10-6 / 1 = 196x10-6 kg/dm3

Description : Mikä on maan suurin maa?

Last Answer : SUOMEA

Description : Who is the author of Hazar Churashir Maa ?

Last Answer : Mahasweta Devi is the author of the book 'Mother of Thousand and Eighty-Four' .

Description : What substance has a density of 1.79 g/mL?

Last Answer : My guess is tartaric acid

Description : The relation between molarity (M) and molarity (m) is given by : (`rho` = density of solution (g/mL), `M_(1)` = molecular weight of solute) :-

Last Answer : The relation between molarity (M) and molarity (m) is given by : (`rho` = density of solution (g/mL), `M_(1 ... ))` D. `m = (1000M)/(1000rho -MM_(1))`

Description : The actual density of a rock is 1.53 g/ml. You measured and calculated the density as 1.62 g/ml. How accurate was your answer?

Last Answer : (1.62 – 1.53)/1.53 * 100 = 5.89%

Description : If the total amount of a drug present in the body at a given moment is 2.0 g and its plasma concentration is 25 μg/ml, its volume of distribution is: A. 100 L B. 80 L C. 60 L D. 50 L

Last Answer : B. 80 L

Description : 2 If the total amount of a drug present in the body at a given moment is 2.0 g and its plasma concentration is 25 μg/ml, its volume of distribution is: A. 100 L B. 80 L C. 60 L D. 50 L

Last Answer : B. 80 L

Description : If the total amount of a drug present in the body at a given moment is 2.0 g and its plasma concentration is 25 μ g/ml, its volume of distribution is: A. 100 L B. 80 L C. 60 L D. 50 L

Last Answer : B. 80 L

Description : Match column I with column II and select the correct option from the given codes. `{:(,"Column I",,"Column II"),(A.,"Tidal volume",(i),2500-3000 mL "o

Last Answer : Match column I with column II and select the correct option from the given codes. `{:(,"Column I",,"Column II"),(A. ... (A,B,C,D,E),(iv,iii,ii,i,v):}`

Description : Potassium acid oxalate `K_(2)C_(2)O_(4).3H_(2)C_(2)O_(4).4H_(2)O` can be oxidized by `MnO_(4)^(-)` in acid medium. Calculate the volume of (in mL) 1 M

Last Answer : Potassium acid oxalate `K_(2)C_(2)O_(4).3H_(2)C_(2)O_(4).4H_(2)O` can be oxidized by ... reacting in acid solution with 5.08 gram of the acid oxalate.

Description : The volume (in `mL`) of `0.1M Ag NO_(3)` required for complete precipitation of chloride ions present in `30 mL` of `0.01M` solution of `[Cr(H_(2)O)_(

Last Answer : The volume (in `mL`) of `0.1M Ag NO_(3)` required for complete precipitation of chloride ions present ... Cl]Cl_(2)`, as silver chloride is close to:

Description : Co-ordination number of Cr in `CrCl_(3^.)5H_(2)O` is six. The volume of 0.1 N `AgNO_(3)` needed to ppt. the chorine in outer sphere in 200 ml of 0.01

Last Answer : Co-ordination number of Cr in `CrCl_(3^.)5H_(2)O` is six. The volume of 0.1 N `AgNO_(3)` ... of 0.01 M solution of he possible complex es is/are:

Description : The latest government regulation in the telecommunication which provides policy for the provision of local exchange carrier service. A. E.O. 546 B. E.O. 109 C. Act 3948 D. E.O. 59

Last Answer : B. E.O. 109

Description : A government regulation in telecommunication which provide policy to improve the provision of local exchange carrier service. A. E.O. 109 B. Act 3846 C. E.O. 59 D. E.O. 546

Last Answer : A. E.O. 109

Description : The temperature of O2 is changed from -48.03 °C to 235.59 °C. If its new volume is 29.164 L, what was its original volume in liters ______ L?

Last Answer : 12.90(Explanation): use charle's law for this one. V/T=V/T. we know the temperatures in both scenarios, and we're trying to solve for the volume in the beginning. Remember temperature in Kelvin! So, plug in ... Now, divide by 508.59 on both sides to get 12.90042093. Round to 4 sig figs, 12.90 DONE!

Description : The correct starting material and product of different disintegration series `"is"//"are"` a)`Th^(232), Pb^(208)` b)`Np^(237),Bi^(209)` c)`U^(235),Pb^

Last Answer : The correct starting material and product of different disintegration series `"is"//"are"` a)`Th^(232), Pb^(208)` ... )Pb` D. `.^(237)Np, .^(209)Bi`

Description : The correct starting material and product of different disintegration series `"is"//"are"` a)`Th^(232), Pb^(208)` b)`Np^(237),Bi^(209)` c)`U^(235),Pb^

Last Answer : The correct starting material and product of different disintegration series `"is"//"are"` a)`Th^(232), Pb^(208)` ... )Pb` D. `.^(237)Np, .^(209)Bi`

Description : Total number of amino acids in human chorionic gonadotropin is (A) 53 (B) 92 (C) 145 (D) 237

Last Answer : Answer : D

Description : Which type of Uranium is used in the fission process? A. Uranium – 234 B. Uranium - 235 C. Uranium - 236 D. Uranium - 237

Last Answer : ANSWER: B

Description : Which type of Uranium is used in the fission process? A. Uranium – 234 B. Uranium - 235 C. Uranium - 236 D. Uranium - 237

Last Answer : ANSWER: B

Description : Which type of Uranium is used in the fission process? A. Uranium – 234 B. Uranium - 235 C. Uranium - 236 D. Uranium - 237

Last Answer : ANSWER: B

Description : The atomic weight of uranium is (a) 237 (b) 238 (c) 226 (d) 242

Last Answer : Ans:(b)

Description : The isotope of Uranium used in atomic reactors is – (1) U^235 (2) (2) U^236 (3) U^237 (4) U^232

Last Answer : (1) U^235 Explanation: A nuclear reactor is a device to initiate and control a sustained nuclear chain reaction. Most commonly they are used for generating electricity and for the propulsion of ships ... fissile atomic nucleus such as U235 or U239 absorbs a neutron, it may undergo nuclear fission.

Description : When a voltage of 132 VDC is applied to the illustrated circuit with a resistance of 237 ohms the current will be ________. EL-0018 A. 1.236 amps B. 2.048 amps C. 0.557 amps D. 4.200 amps

Last Answer : Answer: C

Description : When a voltage of 124 VDC is applied to the illustrated circuit with a resistance of 237 ohms the current will be ________. EL-0018 A. 1.523 amps B. 1.911 amps C. 361 milliamps D. 523.2 milliamps

Last Answer : Answer: D

Description : When a voltage of 112 VDC is applied to the illustrated circuit with a resistance of 237 ohms the current will be ________. EL-0018 A. 1.47 amps B. 2.11 amps C. 347 milliamps D. 472.6 milliamps

Last Answer : Answer: D

Description : When a voltage of 110 VDC is applied to the illustrated circuit with a resistance of 237 ohms the current will be________. EL-0018 A. .464 amps B. 1.464 amps C. 2.154 amps D. 3.47 amps

Last Answer : Answer: A

Description : When a voltage of 95 VDC is applied to the circuit illustrated with a resistance of 237 ohms the current will be________. EL-0018 A. 1.40 amps B. 2.49 amps C. 332 milliamps D. 400.8 milliamps

Last Answer : Answer: D

Description : When a voltage of 115 VDC is applied to the illustrated circuit with a resistance of 237 ohms the current will be _______. EL-0018 A. 0.485 amps B. 1.485 amps C. 2.06 amps D. 0.352 amps

Last Answer : Answer: A

Description : When a voltage of 25 VDC is applied to the illustrated circuit with a resistance of 105.3 ohms the current will be _______. EL-0018 A. 130.3 amps B. 4.212 amps C. 1.237 amps D. 0.237 amps

Last Answer : Answer: D

Description : What is the effective radiated power of a repeater with 75 watts transmitter power output, 5 dB feedline loss, 4 dB duplexer and circulator loss, and 6 dB antenna gain? A. 37.6 W B. 237 W C. 150 W D. 23.7 W

Last Answer : A. 37.6 W

Description : An octal number 237 is equal to the binary number 1) 010 011 111 2) 010 111 011 3) 011 101 101 4) 011 000 001

Last Answer : 3) 011 101 101

Description : Buoynat density of DNA is increased by its (A) A and T content (B) G and C content (C) Sugar content (D) None of these

Last Answer : Answer : B

Description : A bottle of `H_(3)PO_(4)` solution contains 70% acid. If the density of the solution is `1.54 g cm^(-3)` , the volume of the `H_(3)PO_(4)` solution re

Last Answer : A bottle of `H_(3)PO_(4)` solution contains 70% acid. If the density of the solution is `1.54 g cm^(-3) ... is . A. 90 mL B. 45mL C. 30mL D. 23mL

Description : If a piece of rock has a volume of 0.73 L and a mass of 1524 g what is the density of the rock in gmL?

Last Answer : The density is 2,09 g/cm3.

Description : What is the density of a metal block that has a mass of g and a volume of cm?

Last Answer : Density = g / CmAssuming g is in a unit of mass, and Cm is in a unit of volume,If these are not the units of the quantities given then the resultwill not be density, instead it will be gibberish! The units of thequantities going into an equation are more important than thevalues.

Description : While Young's modulus ‘E’ relates to change in length and bulk modulus ‘K’ relates to change in volume, modulus of rigidity ‘G’ relates to change in: A. weight B. density C. shape D. temperature

Last Answer : . shape

Description : Which of the following fixes the volume of a batch reactor for a particular conversion and production rate? (A) Operating conditions (e.g. pressure and temperature) (B) Rate constant (C) Density of mixture (D) None of these

Last Answer : (C) Density of mixture

Description : A moist soil sample of volume 60 cc. weighs 108 g and its dried weight is 86.4 g. If its absolute density is 2.52, the degree of saturation is (A) 54 % (B) 64 % (C) 74 % (D) 84 %

Last Answer : (D) 84 %

Description : Laurie poured 4 cups of water into a bowl. Each cup contained 250 mL of water. Is it reasonable to say that the bowl contained 10 L?

Last Answer : A+LS No

Description : Normal fasting blood sugar level per 100 ml. of blood in man is - (1) 30 - 50 mg (2) 50 - 70 mg (3) 80 -100 mg (4) 120 -140 mg

Last Answer : (3) 80 -100 mg Explanation: The blood sugar concentration or blood glucose level is the amount of glucose (sugar) present in the blood of a human or animal. Glucose levels are usually lowest in the ... (termed the fasting level"), and rise after meals for an hour or two by a few millimolar.

Description : What is the normal blood sugar level of a human being? (1) Close to 10 mg/ml (2) 120 - 150 mg/dl (3) 80 - 90 mg/dl (4) 150 — 200 mg/dl

Last Answer : (2) 120 - 150 mg/dl Explanation: The blood sugar concentration or blood glucose level is the amount of glucose (sugar) present in the blood of a human or animal. The body naturally tightly regulates blood ... (termed "the fasting level"), and rise after meals for an hour or two by a few millimolar.

Description : Normal fasting blood sugar level per 100 ml. of blood in man is (1) 30 - 50 mg (2) 50 - 70 mg (3) 80 -100 mg (4) 120 -140 mg

Last Answer : 80 -100 mg

Description : What is the normal blood sugar level of a human being? (1) Close to 10 mg/ml (2) 120 – 150 mg/dl (3) 80 – 90 mg/dl (4) 150 – 200 mg/dl

Last Answer : 120 – 150 mg/dl 

Description : The density of air is `0.001293g//ml` at S.T.P. Its vapour density will be:

Last Answer : The density of air is `0.001293g//ml` at S.T.P. Its vapour density will be: A. 143 B. 14.53 C. 1.43 D. 0.143

Description : Hydrated density of HD lipoproteins is (A) 0.94 gm/ml (B) 0.94–1.006 gm/ml (C) 1.006–1.063 gm/ml (D) 1.063–1.21 gm/ml

Last Answer : Answer : D

Description : Hydrated density of (HD) lipoproteins is (A) 0.94 gm/ml (B) 0.94-1.006 gm/ml (C) 1.006-1.063 gm/ml (D) 1.063-1.21 gm/l

Last Answer : Answer : B

Description : a) 110 g of salt is present in 550g of solution. Calculate the concentration of solution. b) 10 ml of H2SO 4 is dissolved in 90 ml of H2O. Calculate the concentration of solution. -Chemistry

Last Answer : The concentration of salt is determined by the division of mass of the solute by the mass of the solution and the percentage is obtained by multiplying the value by 100. The quotient of the division of 110 by 550 is 0.2 here. So after multiplying it with 100, it is 20%. So the concentration is 20%.

Description : The solubility of `Ba_(3)(AsO_(4))_(2)`(formula mass=690) is `6.9xx10^(-2)` g//100 mL. What is the `K_(sp)`?

Last Answer : The solubility of `Ba_(3)(AsO_(4))_(2)`(formula mass=690) is `6.9xx10^(-2)` g//100 mL. What is the `K_(sp ... )` C. `1.0xx10^(-15)` D. `6.0xx10^(-13)`