The oxide of a metal (R ) can be reduced by the metal (P) and metal (R ) can reduce the oxide of metal (Q). Then the decreasing order of the reactivit

The oxide of a metal (R ) can be reduced by the metal (P) and metal (R ) can reduce the oxide of metal (Q). Then the decreasing order of the reactivit
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The oxide of a metal (R ) can be reduced by the metal (P) and metal (R ) can reduce the oxide of metal (Q). Then ... C. `R gt P gt Q` D. `Q gt P gt R`
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P, Q, R, S and T are placed in the order of 1 to 5. S is at one of the extreme ends. Q and R are neighbors and T is 3rd to the right of P If Q is in the third position then who will be in fifth position? a) Both S and T b) Either P or Q c) Either S or T d) Both P and Q

Description : P, Q, R, S and T are placed in the order of 1 to 5. S is at one of the extreme ends. Q and R are neighbors and T is 3rd to the right of P If Q is in the third position then who will be in fifth position? a) Both S and T b) Either P or Q c) Either S or T d) Both P and Q

Last Answer : c) Either S or T

P, Q, R, S and T are placed in the order of 1 to 5. S is at one of the extreme ends. Q and R are neighbors and T is 3rd to the right of P If R is in second position, then who will be in fourth position? a) T b) Q c) P d) S

Description : P, Q, R, S and T are placed in the order of 1 to 5. S is at one of the extreme ends. Q and R are neighbors and T is 3rd to the right of P If R is in second position, then who will be in fourth position? a) T b) Q c) P d) S

Last Answer : Ans: option (a)

Electrometallurgical methods of metal extraction is normally used for those metals (A) Whose oxide/ore is not reduced by carbon (B) Which fall in the category of alkali & alkaline earth metals (C) Which stands higher in the electrochemical series of the metal (D) All (A), (B) & (C)

Description : Electrometallurgical methods of metal extraction is normally used for those metals (A) Whose oxide/ore is not reduced by carbon (B) Which fall in the category of alkali & alkaline earth metals (C) Which stands higher in the electrochemical series of the metal (D) All (A), (B) & (C)

Last Answer : (D) All (A), (B) & (C)

Consider the follwing complexes ion `P,Q` and `R` `P =[FeF_(6)]^(3-), Q=[V(H_(2)O)_(6)]^(2+)` and `R=[Fe(H_(2)O)_(6)]^(2+)` The correct order of the c

Description : Consider the follwing complexes ion `P,Q` and `R` `P =[FeF_(6)]^(3-), Q=[V(H_(2)O)_(6)]^(2+)` and `R=[Fe(H_(2)O)_(6)]^(2+)` The correct order of the c

Last Answer : Consider the follwing complexes ion `P,Q` and `R` `P =[FeF_(6)]^(3-), Q=[V(H_(2)O)_(6)]^(2+)` and `R=[Fe( ... lt P` C. `R lt P lt Q` D. `Q lt P lt R`

Points P,Q,R(in this order) divide the line joining the points A(-2,2) and B(2,8) into four equal parts. The coordinates of the point Q are: (a) (-1,7/2) (b) (1,13/2) (c) (0,5) (d) (5,1/2)

Description : Points P,Q,R(in this order) divide the line joining the points A(-2,2) and B(2,8) into four equal parts. The coordinates of the point Q are: (a) (-1,7/2) (b) (1,13/2) (c) (0,5) (d) (5,1/2)

Last Answer : (c) (0,5)

(A): At 1200K iron can be reduce cuprous oxide (R )L: At 1200K, `Fe+Cu_(2)O to FeO+2Cu` `DeltaG=-300kj//"mole"`

Description : (A): At 1200K iron can be reduce cuprous oxide (R )L: At 1200K, `Fe+Cu_(2)O to FeO+2Cu` `DeltaG=-300kj//"mole"`

Last Answer : (A): At 1200K iron can be reduce cuprous oxide (R )L: At 1200K, `Fe+Cu_(2)O to FeO+2Cu` ` ... incorrect D. If (A) is incorrect but (R ) is correct

Reduced glutathione functions in R.B.Cs to (A) Produce NADPH (B) Reduce methemoglobin to hemoglobin (C) Produce NADH (D) Reduce oxidizing agents such as H2O2

Description : Reduced glutathione functions in R.B.Cs to (A) Produce NADPH (B) Reduce methemoglobin to hemoglobin (C) Produce NADH (D) Reduce oxidizing agents such as H2O2

Last Answer : D

If P,Q,R,S are respectively the mid - points of the sides of a parallelogram ABCD, if ar(||gm PQRS) = 32.5cm2 , then find ar(||gm ABCD). -Maths 9th

Description : If P,Q,R,S are respectively the mid - points of the sides of a parallelogram ABCD, if ar(||gm PQRS) = 32.5cm2 , then find ar(||gm ABCD). -Maths 9th

Last Answer : Join PR. ∵ △PSR and ||gm APRD are on the same base and between same parallel lines. ar(△PSR) = 1/2 ar(||gm APRD) Similarly, ar(△PQR) = 1/2 ar(||gm PBCR) ar(△PQRS) = ar(△PSR) + △(PQR) = 1/2 ar(||gm APRD) + 1 ... |gm PBCR) = 1/2 ar(||gm ABCD) ⇒ ar(||gm ABCD) = 2 ar(||gm PQRS) = 2 32.5 = 65cm2

If P(-l, 1), Q(3, -4), R(1, -1), S(-2, -3) and T(-4, 4) are plotted on the graph paper, then the point(s) in the fourth quadrant is/are -Maths 9th

Description : If P(-l, 1), Q(3, -4), R(1, -1), S(-2, -3) and T(-4, 4) are plotted on the graph paper, then the point(s) in the fourth quadrant is/are -Maths 9th

Last Answer : (b) In point P (-1, 1), x-coordinate is -1 unit and y-coordinate is 1 unit, so it lies in llnd quadrant. Similarly, we can plot all the points Q (3, -4), R (1, -1), S (-2, -3) and T (-4, 4), It is clear from the graph that points R and Q lie in fourth quadrant.

If P (5,1), Q (8, 0), R(0, 4), S(0, 5) and O(0, 0) are plotted on the graph paper, then the points on the X-axis is/are -Maths 9th

Description : If P (5,1), Q (8, 0), R(0, 4), S(0, 5) and O(0, 0) are plotted on the graph paper, then the points on the X-axis is/are -Maths 9th

Last Answer : (d) We know that, a point lies on X-axis, if its y-coordinate is zero. So, on plotting the given points on graph paper, we get Q and O lie on the X-axis.

If P, Q and R are the mid-points of the sides, BC, CA and AB of a triangle and AD is the perpendicular from A on BC, then prove that P, Q, R and D are concyclic. -Maths 9th

Description : If P, Q and R are the mid-points of the sides, BC, CA and AB of a triangle and AD is the perpendicular from A on BC, then prove that P, Q, R and D are concyclic. -Maths 9th

Last Answer : According to question prove that P, Q, R and D are concyclic.

If P,Q,R,S are respectively the mid - points of the sides of a parallelogram ABCD, if ar(||gm PQRS) = 32.5cm2 , then find ar(||gm ABCD). -Maths 9th

Description : If P,Q,R,S are respectively the mid - points of the sides of a parallelogram ABCD, if ar(||gm PQRS) = 32.5cm2 , then find ar(||gm ABCD). -Maths 9th

Last Answer : Join PR. ∵ △PSR and ||gm APRD are on the same base and between same parallel lines. ar(△PSR) = 1/2 ar(||gm APRD) Similarly, ar(△PQR) = 1/2 ar(||gm PBCR) ar(△PQRS) = ar(△PSR) + △(PQR) = 1/2 ar(||gm APRD) + 1 ... |gm PBCR) = 1/2 ar(||gm ABCD) ⇒ ar(||gm ABCD) = 2 ar(||gm PQRS) = 2 32.5 = 65cm2

If P(-l, 1), Q(3, -4), R(1, -1), S(-2, -3) and T(-4, 4) are plotted on the graph paper, then the point(s) in the fourth quadrant is/are -Maths 9th

Description : If P(-l, 1), Q(3, -4), R(1, -1), S(-2, -3) and T(-4, 4) are plotted on the graph paper, then the point(s) in the fourth quadrant is/are -Maths 9th

Last Answer : (b) In point P (-1, 1), x-coordinate is -1 unit and y-coordinate is 1 unit, so it lies in llnd quadrant. Similarly, we can plot all the points Q (3, -4), R (1, -1), S (-2, -3) and T (-4, 4), It is clear from the graph that points R and Q lie in fourth quadrant.

If P (5,1), Q (8, 0), R(0, 4), S(0, 5) and O(0, 0) are plotted on the graph paper, then the points on the X-axis is/are -Maths 9th

Description : If P (5,1), Q (8, 0), R(0, 4), S(0, 5) and O(0, 0) are plotted on the graph paper, then the points on the X-axis is/are -Maths 9th

Last Answer : (d) We know that, a point lies on X-axis, if its y-coordinate is zero. So, on plotting the given points on graph paper, we get Q and O lie on the X-axis.

If P, Q and R are the mid-points of the sides, BC, CA and AB of a triangle and AD is the perpendicular from A on BC, then prove that P, Q, R and D are concyclic. -Maths 9th

Description : If P, Q and R are the mid-points of the sides, BC, CA and AB of a triangle and AD is the perpendicular from A on BC, then prove that P, Q, R and D are concyclic. -Maths 9th

Last Answer : According to question prove that P, Q, R and D are concyclic.

If P, Q and R are three points on a line and Q is between P and R,then prove that PR - QR= PQ. -Maths 9th

Description : If P, Q and R are three points on a line and Q is between P and R,then prove that PR - QR= PQ. -Maths 9th

Last Answer : Solution :-

If a, b, c be the p^th, q^th, r^th terms of a GP, then the value of (q – r) log a + (r – p) -Maths 9th

Description : If a, b, c be the p^th, q^th, r^th terms of a GP, then the value of (q – r) log a + (r – p) -Maths 9th

Last Answer : (a) 0Let h be the first term and k be the common ratio of a GP, then a = hkp - 1, b = hkq - 1, c = hkr - 1∴ (q - r) log a + (r - p) log b + (p - q) log c = log [hkp -1]q - r + log [hkq -1]r - p + log[hkr -1]p - ... r + r - p + p - q) (kp - 1)q - r (kq -1)r - p (kr -1)p - q = log(ho ko) = log 1 = 0.

For three distinct positive numbers p, q and r, if p + q + r = a, then -Maths 9th

Description : For three distinct positive numbers p, q and r, if p + q + r = a, then -Maths 9th

Last Answer : answer:

If ABCD is a rectangle and P, Q, R and S are the mid-points of the sides AB, BC, CD and DA respectively, then quadrilateral PQRS is a rhombus. -Maths 9th

Description : If ABCD is a rectangle and P, Q, R and S are the mid-points of the sides AB, BC, CD and DA respectively, then quadrilateral PQRS is a rhombus. -Maths 9th

Last Answer : Here, we are joining A and C. In ΔABC P is the mid point of AB Q is the mid point of BC PQ∣∣AC [Line segments joining the mid points of two sides of a triangle is parallel to AC(third side) and ... RS=PS=RQ[All sides are equal] ∴ PQRS is a parallelogram with all sides equal ∴ So PQRS is a rhombus.

ABCD is a trapezium in which AB || DC and AD = BC. If P, Q, R and S be respectively the mid-points of BA, BD, CD and CA, then PQRS is a -Maths 9th

Description : ABCD is a trapezium in which AB || DC and AD = BC. If P, Q, R and S be respectively the mid-points of BA, BD, CD and CA, then PQRS is a -Maths 9th

Last Answer : Here is your First of all we will draw a quadrilateral ABCD with AD = BC and join AC, BD, P,Q,R,S are the mid points of AB, AC, CD and BD respectively. In the triangle ABC, P and Q are mid points of AB and AC respectively. All sides are equal so PQRS is a Rhombus.

Let P(–3, 2), Q(–5, –5), R(2, –3) and S(4, 4) be four points in a plane. Then show that PQRS is a rhombus. Is it a square ? -Maths 9th

Description : Let P(–3, 2), Q(–5, –5), R(2, –3) and S(4, 4) be four points in a plane. Then show that PQRS is a rhombus. Is it a square ? -Maths 9th

Last Answer : Let P(1, -1), Q \(\big(rac{-1}{2},rac{1}{2}\big)\) and R(1,2) be the vertices of the ΔPQR.Then, PQ = \(\sqrt{\big(rac{-1}{2}-1\big)^2+\big(rac{1}{2}+1\big)^2}\) = \(\sqrt{rac{9}{4}+rac{9}{4}} ... {3\sqrt2}{2}\)PR = \(\sqrt{(1-1)^2+(2+1)^2}\) = \(\sqrt9\) = 3∵ PQ = QR, the triangle PQR is isosceles.

The price of a refrigetor, P is 5 times that of a cooler Q. If then price of P increases by `40%.` then what is the change in the total price of the r

Description : The price of a refrigetor, P is 5 times that of a cooler Q. If then price of P increases by `40%.` then what is the change in the total price of the r

Last Answer : The price of a refrigetor, P is 5 times that of a cooler Q. If then price of P ... total price of the refrigerator and cooler put together ?

If `(p)/(q)=(r)/(s)=(t)/(u)` then `(p^(2)+r^(2)+t^(2))/(q^(2)+s^(2)+u^(2))=`

Description : If `(p)/(q)=(r)/(s)=(t)/(u)` then `(p^(2)+r^(2)+t^(2))/(q^(2)+s^(2)+u^(2))=`

Last Answer : If `(p)/(q)=(r)/(s)=(t)/(u)` then `(p^(2)+r^(2)+t^(2))/(q^(2)+s^(2)+u^(2))=` A. `(prt)/(qsu)` B. `1 ... q^(3)+s^(3)+u^(3))` D. `((p+r+t)/(q+s+u))^(2)`

If P:Q:R=2:3:4 and `P^(2)+Q^(2)+R^(2)=11600`, then find `(P+Q-R)`

Description : If P:Q:R=2:3:4 and `P^(2)+Q^(2)+R^(2)=11600`, then find `(P+Q-R)`

Last Answer : If P:Q:R=2:3:4 and `P^(2)+Q^(2)+R^(2)=11600`, then find `(P+Q-R)` A. 15 B. 16 C. 18 D. 20

If `(2p+5q)/(2r+5s) = (4p-3q)/(4r-3s)`, then find the relation between p, q, r and s.

Description : If `(2p+5q)/(2r+5s) = (4p-3q)/(4r-3s)`, then find the relation between p, q, r and s.

Last Answer : If `(2p+5q)/(2r+5s) = (4p-3q)/(4r-3s)`, then find the relation between p, q, r and s.

A person walks from point P to point Q along a straight road ¡n 10 minutes, then turns back and returns to point R which is midway

Description : A person walks from point P to point Q along a straight road ¡n 10 minutes, then turns back and returns to point R which is midway

Last Answer : A person walks from point P to point Q along a straight road n 10 minutes, then turns back and ... velocity of the person in going from P to R.

P, Q and R can do a piece of work in 18,24 and 36 days on the second day and P on the third day, again R on the fourth day and so on. Then in how, many days will the work be completed? 1. 25 2. 24 3. 22 4. 20 5. 26

Description : P, Q and R can do a piece of work in 18,24 and 36 days on the second day and P on the third day, again R on the fourth day and so on. Then in how, many days will the work be completed? 1. 25 2. 24 3. 22 4. 20 5. 26

Last Answer : 2;

P,Q, & R can complete a piece of job together in 20 days. All the 3 started working at it together and after 8 days P left. Then Q & R together completed a job in 20 more days. P alone could complete the work in. a) 60 b) 50 c) 40 d) 30

Description : P,Q, & R can complete a piece of job together in 20 days. All the 3 started working at it together and after 8 days P left. Then Q & R together completed a job in 20 more days. P alone could complete the work in. a) 60 b) 50 c) 40 d) 30

Last Answer : B Work done by P,Q & R in 8 days = 1/20 * 8 =2/5 Remaining work = (1 - 2/5) = 3/5 Now 3/5 work is done by Q & R in 20 days Whole work will be done by Q & R in(20*5/3) =100/3 days (P+Q+R ... (Q+R)'s 1 day work =1/20 - 3/100 =5-3/100 =2/100 =1/50 P alone could complete the work in 50 days..

P is thrice as fast as Q and Q is 4 times as fast as R. If the journey covered by R is 48 mins, then the time to be covered by Q. a) 12 b) 14 c) 10 d) 6

Description : P is thrice as fast as Q and Q is 4 times as fast as R. If the journey covered by R is 48 mins, then the time to be covered by Q. a) 12 b) 14 c) 10 d) 6 

Last Answer : A Let R's speed = x km/hr Then Q's speed = 4x km/hr P's speed = 12x km/hr Ratio of speeds of P<Q<R = 12x :4x:x =12:4:1 Ratio of time taken = 1/12: ¼:1 =1:3:12 If R ... mins, then Q takes 3 mins If R takes 48 mins, then Q takes =(3/12 *48)mins =(144/120mins =12mins

A race course is 250 m long. P and Q run a race and P wins by 4m. Q and R run over the same course and Q win by 3m. R and S run over it and S wins by 12m. If P and S run over it, then who would win and by how much? a) P by 4.82m b) S by 5.30m c) P by 7.25m d) Q by 6.54m

Description : A race course is 250 m long. P and Q run a race and P wins by 4m. Q and R run over the same course and Q win by 3m. R and S run over it and S wins by 12m. If P and S run over it, then who would win and by how much? a) P by 4.82m b) S by 5.30m c) P by 7.25m d) Q by 6.54m

Last Answer : B If P covers 250m, Q covers 246 m If Q covers 250m, R covers 247 m If S covers 250m, R covers 238m Now if Q covers 246 m, then R will cover =247/250*246=243.048 If R covers 243.048 m, then S will cover= ... 048=255.30 If P and S run over 250 m, then S win by =(255.30-250) S win by = 5.30 m

Two pumps P & Q can fill a tank in 12 mins and 15 mins respectively while a third pipe R can empty the full tank in 6 mins. P & Q kept open for 5 mins in the beginning and then R is also opened. In what time is tank emptied? A) 30mins B) 35mins C) 40mins D) 45 mins

Description : Two pumps P & Q can fill a tank in 12 mins and 15 mins respectively while a third pipe R can empty the full tank in 6 mins. P & Q kept open for 5 mins in the beginning and then R is also opened. In what time is tank emptied? A) 30mins B) 35mins C) 40mins D) 45 mins

Last Answer : D Part filled in 5 min = 5(1/12 +1/15) = 5*9/60 = ¾ Part emptied in 1 min when all the pumps are opened, = 1/6 – (1/12 + 1/15) = 1/6 – 3/20 = 1/60 Now 1/60 is part emptied in 1 min Therefore ¾ part will be emptied in 60 * ¾ = 45 mins

P,Q, R enter into a partnership.P initially invests Rs 54 lakh and withdraws Rs 18 lakhs after 4 years. Q initially Rs 72 lakh ans adds another Rs 18 lakhs after 6 years and R invests Rs 108 lakh and adds another Rs 18 lakh few years. At the end of 10 years profit Of R is equal to sum of profit of P and Q. Then for how many years did R invests Rs 126 lakh per annum A) 5 B) 7 C) 8 D) 11

Description : P,Q, R enter into a partnership.P initially invests Rs 54 lakh and withdraws Rs 18 lakhs after 4 years. Q initially Rs 72 lakh ans adds another Rs 18 lakhs after 6 years and R invests Rs 108 lakh and adds another ... Then for how many years did R invests Rs 126 lakh per annum A) 5 B) 7 C) 8 D) 11 

Last Answer : Answer: C) Ratio of their profit P, Q, R is 54*4+36*6:72*6+90*4:108*x+126*(10-x) =12:22:35 - 0.5x Profit of R=profit of P +profit of Q 35-0.5x=12+22 X=2 year The number of years for R invests Rs 126 lakh =10-2=8years

Among 3 persons, P, Q, R the profit of R is equal to two-fifth of the sum of one-third profit of P and onethird of Q. If at the end of the year total profit is Rs 12750, then find the average profit of P and Q? A) 4750 B) 5625 C) 7425 D) 6520

Description : Among 3 persons, P, Q, R the profit of R is equal to two-fifth of the sum of one-third profit of P and onethird of Q. If at the end of the year total profit is Rs 12750, then find the average profit of P and Q? A) 4750 B) 5625 C) 7425 D) 6520

Last Answer : Answer: B)  R=2/5(1/3 P+1/3 Q)  15R=2(P+Q)  R/(P+Q)= 2/15  Take R=2x, P+Q=15x  Total profit =15x+2x =12750  =>X=Rs.750  Average profit of P&Q =750/2 *15=5625

Among 3 Persons P,Q,R the profit Of Q is equal to one- third of the difference between the profit of R and triple of P. If at the end of the year, total profit is Rs 27000. Then find the profit of R? A) 13000 B) 17850 C) 14500 D) 20250

Description : Among 3 Persons P,Q,R the profit Of Q is equal to one- third of the difference between the profit of R and triple of P. If at the end of the year, total profit is Rs 27000. Then find the profit of R? A) 13000 B) 17850 C) 14500 D) 20250

Last Answer : Answer: D)  Q=1/3(R-3P)  3Q=R-3P R=3[P+Q]  R/(P+Q) =3/1  R/(P+Q+R)=3/4  R/27000 =3/4  R=Rs.20250

The amounts of P, Q and R in the ratio 3:4:5 and their spending are in the ratio 4:5:6. If P saves 1/6th of his income then then savings of P, Q, R are in the ratio A) 18:11:3. B) 12:13:4. C) 4:11:18. D) None

Description : The amounts of P, Q and R in the ratio 3:4:5 and their spending are in the ratio 4:5:6. If P saves 1/6th of his income then then savings of P, Q, R are in the ratio A) 18:11:3. B) 12:13:4. C) 4:11:18. D) None

Last Answer : Answer: C)  Income of P,Q,R = 3x:4x:5x Expense of 4:5:6=4y:5y:6y.  Savings [income –expenditure]  =3x-4y :4x-5y :5x-6y------->1  Given 3x-4y=x/6  y=17x/24  Sub if (1) is,  =3x-4(17x/24) :4x-5(17x/24) :5x-6(17x/24)  =8x:22x:36x  = 4:11:18

P, Q, R enter into a partnership. P initially invests Rs 15000 and withdrawn Rs. 7500 after 7 months. Q initially invests Rs 12500 and withdraws Rs 10000 after 5 months and R invests Rs 10000 and adds another Rs 5000 after few months. At the end of 1 year and 3 months profits of P and R is twice the profit of Q. Then after how many months did R invests Rs 10000? A) 2.5 B) 2.6 C) 2.7 D) None

Description : P, Q, R enter into a partnership. P initially invests Rs 15000 and withdrawn Rs. 7500 after 7 months. Q initially invests Rs 12500 and withdraws Rs 10000 after 5 months and R invests Rs 10000 and adds another Rs 5000 ... after how many months did R invests Rs 10000? A) 2.5 B) 2.6 C) 2.7 D) None

Last Answer : Answer: A)  Ratio of P, Q &R is , 15000*7+7500* 8:12500*5+2500* 10:10000*x+15000*(15-x)  P: Q: R=66:35:9-2x  Profit of Q = (profit of P + profit of R)/2  35 = (66 +9 -2x)/2  X=2.5 months

Rs.10500 is divided among P, Q and R. So that P receives half as much as Q and Q receives half as much as R. Then then total share of P and R is A) 4500 B) 3000 C) 5000 D) 7500

Description : Rs.10500 is divided among P, Q and R. So that P receives half as much as Q and Q receives half as much as R. Then then total share of P and R is A) 4500 B) 3000 C) 5000 D) 7500

Last Answer : Answer: D)  Let amount received by R is X  Amount received by Q is X/2  Amount received by P is X/4  Profit ratio of  P,Q &R =X/4:X/2:X  =1:2:4  Total share of P&R  =10500*5/7 =Rs 7500

If the mean of P, Q,R is A and PQ + QR + RP =0, then the mean of p^2,Q^2,R^2 is. A) 2A^2 B) 4A^2 C) A^2 D) 3A^2

Description : If the mean of P, Q,R is A and PQ + QR + RP =0, then the mean of p^2,Q^2,R^2 is. A) 2A^2 B) 4A^2 C) A^2 D) 3A^2

Last Answer : D) We have (P + Q + R)/3 = A P+Q+R = 3A (P+Q+R)^2 = 9A^2 P^2+Q^2+R^2 + 2 (PQ + QR + PR) = 9A^2 P^2+Q^2+R^2 = 9A^2 Required mean = (P^2+Q^2+R^2)/3 = 9A^2/3= 3A^2

(A) Auto reduction of ore is used for the extraction of copper (R ) The sulphide ore of copper reacts with its oxide to the give the metal

Description : (A) Auto reduction of ore is used for the extraction of copper (R ) The sulphide ore of copper reacts with its oxide to the give the metal

Last Answer : (A) Auto reduction of ore is used for the extraction of copper (R ) The sulphide ore of copper reacts ... . If (A) is incorrect but (R ) is correct

In the illustrated amplifier, the base of the transistor is what type of material? EL-0022 A. N type B. P type C. metal oxide insulator D. alloy junction material

Description : In the illustrated amplifier, the base of the transistor is what type of material? EL-0022 A. N type B. P type C. metal oxide insulator D. alloy junction material

Last Answer : Answer: A

NMOS stands for: a. N-channel metal-oxide-semiconductor b. P-channel metal-oxide-semiconductor c. N-channel memory-oxide-semiconductor d. All the above

Description : NMOS stands for: a. N-channel metal-oxide-semiconductor b. P-channel metal-oxide-semiconductor c. N-channel memory-oxide-semiconductor d. All the above

Last Answer : a. N-channel metal-oxide-semiconductor

PMOS stands for: a. P-channel metal-oxide-semiconductor b. P-channel memory –oxide-semiconductor c. Both A and B d. None of these

Description : PMOS stands for: a. P-channel metal-oxide-semiconductor b. P-channel memory –oxide-semiconductor c. Both A and B d. None of these

Last Answer : a. P-channel metal-oxide-semiconductor

What is sensible cooling of air? A. the cooling in which sensible heat of air is removed in order to reduce temperature B. the cooling in which temperature of air is reduced without changing in its moisture content C. both a. and b. D. none of the above

Description : What is sensible cooling of air? A. the cooling in which sensible heat of air is removed in order to reduce temperature B. the cooling in which temperature of air is reduced without changing in its moisture content C. both a. and b. D. none of the above

Last Answer : ANSWER : C

The load stress of a section can be reduced by (A) Decreasing the lever arm (B) Increasing the total perimeter of bars (C) Replacing larger bars by greater number of small bars (D) Replacing smaller bars by greater number of greater bars

Description : The load stress of a section can be reduced by (A) Decreasing the lever arm (B) Increasing the total perimeter of bars (C) Replacing larger bars by greater number of small bars (D) Replacing smaller bars by greater number of greater bars

Last Answer : Answer: Option C

How can the R&D cycle time be reduced? a. Increasing automation levels b. Budgeting money to quality initiatives c. Increasing R&D budget d. Decreasing product portfolio e. Decreasing capacity

Description : How can the R&D cycle time be reduced? a. Increasing automation levels b. Budgeting money to quality initiatives c. Increasing R&D budget d. Decreasing product portfolio e. Decreasing capacity

Last Answer : b. Budgeting money to quality initiatives

Exposure of the patient to ionising radiation when taking a radiograph is NOT REDUCED by: A. The use of fast film B. The addition of filtration C. Collimation of the beam D. The use of an open and lead lined cone E. Decreasing the kilovoltage KvP

Description : Exposure of the patient to ionising radiation when taking a radiograph is NOT REDUCED by: A. The use of fast film B. The addition of filtration C. Collimation of the beam D. The use of an open and lead lined cone E. Decreasing the kilovoltage KvP

Last Answer : E. Decreasing the kilovoltage KvP

Quantization noise can be reduced by ________ the number of levels. a) Decreasing b) Increasing c) Doubling d) Squaring

Description : Quantization noise can be reduced by ________ the number of levels. a) Decreasing b) Increasing c) Doubling d) Squaring

Last Answer : b) Increasing

The “Primaquin sensitivity types of haemolytic anaemia has been found to relate to reduced R.B.C activity of which enzyme? (A) Pyruvate kinase deficiency (B) Glucose-6-phosphatase deficiency (C) Glucose-6-p dehydrogenase deficiency (D) Hexokinase deficiency

Description : The “Primaquin sensitivity types of haemolytic anaemia has been found to relate to reduced R.B.C activity of which enzyme? (A) Pyruvate kinase deficiency (B) Glucose-6-phosphatase deficiency (C) Glucose-6-p dehydrogenase deficiency (D) Hexokinase deficiency

Last Answer : C

If a CSD overheat warning is shown: a. The CSD can be disconnected and the pilot must control the alternator himself b. The pilot must throttle back to reduce the load on the alternator c. The CSD can be disconnected then reconnected later when the temperature has reduced d. The CSD can be disconnected but not used for the rest of the flight

Description : If a CSD overheat warning is shown: a. The CSD can be disconnected and the pilot must control the alternator himself b. The pilot must throttle back to reduce the load on the alternator c. The ... temperature has reduced d. The CSD can be disconnected but not used for the rest of the flight

Last Answer : d. The CSD can be disconnected but not used for the rest of the flight

If a CSD overheat warning is shown: a. The CSD can be disconnected and the pilot must control the alternator himself b. The pilot must throttle back to reduce the load on the alternator c. The CSD can be disconnected then reconnected later when the temperature has reduced d. The CSD can be disconnected but not used for the rest of the flight

Description : If a CSD overheat warning is shown: a. The CSD can be disconnected and the pilot must control the alternator himself b. The pilot must throttle back to reduce the load on the alternator c. The ... temperature has reduced d. The CSD can be disconnected but not used for the rest of the flight

Last Answer : d. The CSD can be disconnected but not used for the rest of the flight