If P:Q:R=2:3:4 and `P^(2)+Q^(2)+R^(2)=11600`, then find `(P+Q-R)`

If P:Q:R=2:3:4 and `P^(2)+Q^(2)+R^(2)=11600`, then find `(P+Q-R)`
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If P:Q:R=2:3:4 and `P^(2)+Q^(2)+R^(2)=11600`, then find `(P+Q-R)` A. 15 B. 16 C. 18 D. 20
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175 × 28 + 275 × 28 =? a) 11800 b) 12600 c) 12800 d) 11600 e) 12200

Description : 175 × 28 + 275 × 28 =? a) 11800 b) 12600 c) 12800 d) 11600 e) 12200

Last Answer : Answer: b)

In the diode equation, the voltage equivalent of temperature is a. 11600/T b. T/11600 c. T x 11600 d. 11600/T2

Description : In the diode equation, the voltage equivalent of temperature is a. 11600/T b. T/11600 c. T x 11600 d. 11600/T2

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If P,Q,R,S are respectively the mid - points of the sides of a parallelogram ABCD, if ar(||gm PQRS) = 32.5cm2 , then find ar(||gm ABCD). -Maths 9th

Description : If P,Q,R,S are respectively the mid - points of the sides of a parallelogram ABCD, if ar(||gm PQRS) = 32.5cm2 , then find ar(||gm ABCD). -Maths 9th

Last Answer : Join PR. ∵ △PSR and ||gm APRD are on the same base and between same parallel lines. ar(△PSR) = 1/2 ar(||gm APRD) Similarly, ar(△PQR) = 1/2 ar(||gm PBCR) ar(△PQRS) = ar(△PSR) + △(PQR) = 1/2 ar(||gm APRD) + 1 ... |gm PBCR) = 1/2 ar(||gm ABCD) ⇒ ar(||gm ABCD) = 2 ar(||gm PQRS) = 2 32.5 = 65cm2

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Description : If P(-l, 1), Q(3, -4), R(1, -1), S(-2, -3) and T(-4, 4) are plotted on the graph paper, then the point(s) in the fourth quadrant is/are -Maths 9th

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If P (5,1), Q (8, 0), R(0, 4), S(0, 5) and O(0, 0) are plotted on the graph paper, then the points on the X-axis is/are -Maths 9th

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If P,Q,R,S are respectively the mid - points of the sides of a parallelogram ABCD, if ar(||gm PQRS) = 32.5cm2 , then find ar(||gm ABCD). -Maths 9th

Description : If P,Q,R,S are respectively the mid - points of the sides of a parallelogram ABCD, if ar(||gm PQRS) = 32.5cm2 , then find ar(||gm ABCD). -Maths 9th

Last Answer : Join PR. ∵ △PSR and ||gm APRD are on the same base and between same parallel lines. ar(△PSR) = 1/2 ar(||gm APRD) Similarly, ar(△PQR) = 1/2 ar(||gm PBCR) ar(△PQRS) = ar(△PSR) + △(PQR) = 1/2 ar(||gm APRD) + 1 ... |gm PBCR) = 1/2 ar(||gm ABCD) ⇒ ar(||gm ABCD) = 2 ar(||gm PQRS) = 2 32.5 = 65cm2

If P(-l, 1), Q(3, -4), R(1, -1), S(-2, -3) and T(-4, 4) are plotted on the graph paper, then the point(s) in the fourth quadrant is/are -Maths 9th

Description : If P(-l, 1), Q(3, -4), R(1, -1), S(-2, -3) and T(-4, 4) are plotted on the graph paper, then the point(s) in the fourth quadrant is/are -Maths 9th

Last Answer : (b) In point P (-1, 1), x-coordinate is -1 unit and y-coordinate is 1 unit, so it lies in llnd quadrant. Similarly, we can plot all the points Q (3, -4), R (1, -1), S (-2, -3) and T (-4, 4), It is clear from the graph that points R and Q lie in fourth quadrant.

If P (5,1), Q (8, 0), R(0, 4), S(0, 5) and O(0, 0) are plotted on the graph paper, then the points on the X-axis is/are -Maths 9th

Description : If P (5,1), Q (8, 0), R(0, 4), S(0, 5) and O(0, 0) are plotted on the graph paper, then the points on the X-axis is/are -Maths 9th

Last Answer : (d) We know that, a point lies on X-axis, if its y-coordinate is zero. So, on plotting the given points on graph paper, we get Q and O lie on the X-axis.

If P, Q and R are the mid-points of the sides, BC, CA and AB of a triangle and AD is the perpendicular from A on BC, then prove that P, Q, R and D are concyclic. -Maths 9th

Description : If P, Q and R are the mid-points of the sides, BC, CA and AB of a triangle and AD is the perpendicular from A on BC, then prove that P, Q, R and D are concyclic. -Maths 9th

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Description : If P, Q and R are three points on a line and Q is between P and R,then prove that PR - QR= PQ. -Maths 9th

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If ABCD is a rectangle and P, Q, R and S are the mid-points of the sides AB, BC, CD and DA respectively, then quadrilateral PQRS is a rhombus. -Maths 9th

Description : If ABCD is a rectangle and P, Q, R and S are the mid-points of the sides AB, BC, CD and DA respectively, then quadrilateral PQRS is a rhombus. -Maths 9th

Last Answer : Here, we are joining A and C. In ΔABC P is the mid point of AB Q is the mid point of BC PQ∣∣AC [Line segments joining the mid points of two sides of a triangle is parallel to AC(third side) and ... RS=PS=RQ[All sides are equal] ∴ PQRS is a parallelogram with all sides equal ∴ So PQRS is a rhombus.

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Description : Let P(–3, 2), Q(–5, –5), R(2, –3) and S(4, 4) be four points in a plane. Then show that PQRS is a rhombus. Is it a square ? -Maths 9th

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The price of a refrigetor, P is 5 times that of a cooler Q. If then price of P increases by `40%.` then what is the change in the total price of the r

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If `(2p+5q)/(2r+5s) = (4p-3q)/(4r-3s)`, then find the relation between p, q, r and s.

Description : If `(2p+5q)/(2r+5s) = (4p-3q)/(4r-3s)`, then find the relation between p, q, r and s.

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A person walks from point P to point Q along a straight road ¡n 10 minutes, then turns back and returns to point R which is midway

Description : A person walks from point P to point Q along a straight road ¡n 10 minutes, then turns back and returns to point R which is midway

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The oxide of a metal (R ) can be reduced by the metal (P) and metal (R ) can reduce the oxide of metal (Q). Then the decreasing order of the reactivit

Description : The oxide of a metal (R ) can be reduced by the metal (P) and metal (R ) can reduce the oxide of metal (Q). Then the decreasing order of the reactivit

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P, Q and R can do a piece of work in 18,24 and 36 days on the second day and P on the third day, again R on the fourth day and so on. Then in how, many days will the work be completed? 1. 25 2. 24 3. 22 4. 20 5. 26

Description : P, Q and R can do a piece of work in 18,24 and 36 days on the second day and P on the third day, again R on the fourth day and so on. Then in how, many days will the work be completed? 1. 25 2. 24 3. 22 4. 20 5. 26

Last Answer : 2;

P, Q, R, S and T are placed in the order of 1 to 5. S is at one of the extreme ends. Q and R are neighbors and T is 3rd to the right of P If Q is in the third position then who will be in fifth position? a) Both S and T b) Either P or Q c) Either S or T d) Both P and Q

Description : P, Q, R, S and T are placed in the order of 1 to 5. S is at one of the extreme ends. Q and R are neighbors and T is 3rd to the right of P If Q is in the third position then who will be in fifth position? a) Both S and T b) Either P or Q c) Either S or T d) Both P and Q

Last Answer : c) Either S or T

P, Q, R, S and T are placed in the order of 1 to 5. S is at one of the extreme ends. Q and R are neighbors and T is 3rd to the right of P If R is in second position, then who will be in fourth position? a) T b) Q c) P d) S

Description : P, Q, R, S and T are placed in the order of 1 to 5. S is at one of the extreme ends. Q and R are neighbors and T is 3rd to the right of P If R is in second position, then who will be in fourth position? a) T b) Q c) P d) S

Last Answer : Ans: option (a)

P,Q, & R can complete a piece of job together in 20 days. All the 3 started working at it together and after 8 days P left. Then Q & R together completed a job in 20 more days. P alone could complete the work in. a) 60 b) 50 c) 40 d) 30

Description : P,Q, & R can complete a piece of job together in 20 days. All the 3 started working at it together and after 8 days P left. Then Q & R together completed a job in 20 more days. P alone could complete the work in. a) 60 b) 50 c) 40 d) 30

Last Answer : B Work done by P,Q & R in 8 days = 1/20 * 8 =2/5 Remaining work = (1 - 2/5) = 3/5 Now 3/5 work is done by Q & R in 20 days Whole work will be done by Q & R in(20*5/3) =100/3 days (P+Q+R ... (Q+R)'s 1 day work =1/20 - 3/100 =5-3/100 =2/100 =1/50 P alone could complete the work in 50 days..

P is thrice as fast as Q and Q is 4 times as fast as R. If the journey covered by R is 48 mins, then the time to be covered by Q. a) 12 b) 14 c) 10 d) 6

Description : P is thrice as fast as Q and Q is 4 times as fast as R. If the journey covered by R is 48 mins, then the time to be covered by Q. a) 12 b) 14 c) 10 d) 6 

Last Answer : A Let R's speed = x km/hr Then Q's speed = 4x km/hr P's speed = 12x km/hr Ratio of speeds of P<Q<R = 12x :4x:x =12:4:1 Ratio of time taken = 1/12: ¼:1 =1:3:12 If R ... mins, then Q takes 3 mins If R takes 48 mins, then Q takes =(3/12 *48)mins =(144/120mins =12mins

A race course is 250 m long. P and Q run a race and P wins by 4m. Q and R run over the same course and Q win by 3m. R and S run over it and S wins by 12m. If P and S run over it, then who would win and by how much? a) P by 4.82m b) S by 5.30m c) P by 7.25m d) Q by 6.54m

Description : A race course is 250 m long. P and Q run a race and P wins by 4m. Q and R run over the same course and Q win by 3m. R and S run over it and S wins by 12m. If P and S run over it, then who would win and by how much? a) P by 4.82m b) S by 5.30m c) P by 7.25m d) Q by 6.54m

Last Answer : B If P covers 250m, Q covers 246 m If Q covers 250m, R covers 247 m If S covers 250m, R covers 238m Now if Q covers 246 m, then R will cover =247/250*246=243.048 If R covers 243.048 m, then S will cover= ... 048=255.30 If P and S run over 250 m, then S win by =(255.30-250) S win by = 5.30 m

Two pumps P & Q can fill a tank in 12 mins and 15 mins respectively while a third pipe R can empty the full tank in 6 mins. P & Q kept open for 5 mins in the beginning and then R is also opened. In what time is tank emptied? A) 30mins B) 35mins C) 40mins D) 45 mins

Description : Two pumps P & Q can fill a tank in 12 mins and 15 mins respectively while a third pipe R can empty the full tank in 6 mins. P & Q kept open for 5 mins in the beginning and then R is also opened. In what time is tank emptied? A) 30mins B) 35mins C) 40mins D) 45 mins

Last Answer : D Part filled in 5 min = 5(1/12 +1/15) = 5*9/60 = ¾ Part emptied in 1 min when all the pumps are opened, = 1/6 – (1/12 + 1/15) = 1/6 – 3/20 = 1/60 Now 1/60 is part emptied in 1 min Therefore ¾ part will be emptied in 60 * ¾ = 45 mins

P,Q, R enter into a partnership.P initially invests Rs 54 lakh and withdraws Rs 18 lakhs after 4 years. Q initially Rs 72 lakh ans adds another Rs 18 lakhs after 6 years and R invests Rs 108 lakh and adds another Rs 18 lakh few years. At the end of 10 years profit Of R is equal to sum of profit of P and Q. Then for how many years did R invests Rs 126 lakh per annum A) 5 B) 7 C) 8 D) 11

Description : P,Q, R enter into a partnership.P initially invests Rs 54 lakh and withdraws Rs 18 lakhs after 4 years. Q initially Rs 72 lakh ans adds another Rs 18 lakhs after 6 years and R invests Rs 108 lakh and adds another ... Then for how many years did R invests Rs 126 lakh per annum A) 5 B) 7 C) 8 D) 11 

Last Answer : Answer: C) Ratio of their profit P, Q, R is 54*4+36*6:72*6+90*4:108*x+126*(10-x) =12:22:35 - 0.5x Profit of R=profit of P +profit of Q 35-0.5x=12+22 X=2 year The number of years for R invests Rs 126 lakh =10-2=8years

Among 3 persons, P, Q, R the profit of R is equal to two-fifth of the sum of one-third profit of P and onethird of Q. If at the end of the year total profit is Rs 12750, then find the average profit of P and Q? A) 4750 B) 5625 C) 7425 D) 6520

Description : Among 3 persons, P, Q, R the profit of R is equal to two-fifth of the sum of one-third profit of P and onethird of Q. If at the end of the year total profit is Rs 12750, then find the average profit of P and Q? A) 4750 B) 5625 C) 7425 D) 6520

Last Answer : Answer: B)  R=2/5(1/3 P+1/3 Q)  15R=2(P+Q)  R/(P+Q)= 2/15  Take R=2x, P+Q=15x  Total profit =15x+2x =12750  =>X=Rs.750  Average profit of P&Q =750/2 *15=5625

Among 3 Persons P,Q,R the profit Of Q is equal to one- third of the difference between the profit of R and triple of P. If at the end of the year, total profit is Rs 27000. Then find the profit of R? A) 13000 B) 17850 C) 14500 D) 20250

Description : Among 3 Persons P,Q,R the profit Of Q is equal to one- third of the difference between the profit of R and triple of P. If at the end of the year, total profit is Rs 27000. Then find the profit of R? A) 13000 B) 17850 C) 14500 D) 20250

Last Answer : Answer: D)  Q=1/3(R-3P)  3Q=R-3P R=3[P+Q]  R/(P+Q) =3/1  R/(P+Q+R)=3/4  R/27000 =3/4  R=Rs.20250

The amounts of P, Q and R in the ratio 3:4:5 and their spending are in the ratio 4:5:6. If P saves 1/6th of his income then then savings of P, Q, R are in the ratio A) 18:11:3. B) 12:13:4. C) 4:11:18. D) None

Description : The amounts of P, Q and R in the ratio 3:4:5 and their spending are in the ratio 4:5:6. If P saves 1/6th of his income then then savings of P, Q, R are in the ratio A) 18:11:3. B) 12:13:4. C) 4:11:18. D) None

Last Answer : Answer: C)  Income of P,Q,R = 3x:4x:5x Expense of 4:5:6=4y:5y:6y.  Savings [income –expenditure]  =3x-4y :4x-5y :5x-6y------->1  Given 3x-4y=x/6  y=17x/24  Sub if (1) is,  =3x-4(17x/24) :4x-5(17x/24) :5x-6(17x/24)  =8x:22x:36x  = 4:11:18

P, Q, R enter into a partnership. P initially invests Rs 15000 and withdrawn Rs. 7500 after 7 months. Q initially invests Rs 12500 and withdraws Rs 10000 after 5 months and R invests Rs 10000 and adds another Rs 5000 after few months. At the end of 1 year and 3 months profits of P and R is twice the profit of Q. Then after how many months did R invests Rs 10000? A) 2.5 B) 2.6 C) 2.7 D) None

Description : P, Q, R enter into a partnership. P initially invests Rs 15000 and withdrawn Rs. 7500 after 7 months. Q initially invests Rs 12500 and withdraws Rs 10000 after 5 months and R invests Rs 10000 and adds another Rs 5000 ... after how many months did R invests Rs 10000? A) 2.5 B) 2.6 C) 2.7 D) None

Last Answer : Answer: A)  Ratio of P, Q &R is , 15000*7+7500* 8:12500*5+2500* 10:10000*x+15000*(15-x)  P: Q: R=66:35:9-2x  Profit of Q = (profit of P + profit of R)/2  35 = (66 +9 -2x)/2  X=2.5 months

Rs.10500 is divided among P, Q and R. So that P receives half as much as Q and Q receives half as much as R. Then then total share of P and R is A) 4500 B) 3000 C) 5000 D) 7500

Description : Rs.10500 is divided among P, Q and R. So that P receives half as much as Q and Q receives half as much as R. Then then total share of P and R is A) 4500 B) 3000 C) 5000 D) 7500

Last Answer : Answer: D)  Let amount received by R is X  Amount received by Q is X/2  Amount received by P is X/4  Profit ratio of  P,Q &R =X/4:X/2:X  =1:2:4  Total share of P&R  =10500*5/7 =Rs 7500

If the mean of P, Q,R is A and PQ + QR + RP =0, then the mean of p^2,Q^2,R^2 is. A) 2A^2 B) 4A^2 C) A^2 D) 3A^2

Description : If the mean of P, Q,R is A and PQ + QR + RP =0, then the mean of p^2,Q^2,R^2 is. A) 2A^2 B) 4A^2 C) A^2 D) 3A^2

Last Answer : D) We have (P + Q + R)/3 = A P+Q+R = 3A (P+Q+R)^2 = 9A^2 P^2+Q^2+R^2 + 2 (PQ + QR + PR) = 9A^2 P^2+Q^2+R^2 = 9A^2 Required mean = (P^2+Q^2+R^2)/3 = 9A^2/3= 3A^2

I want to put "S.P.Q.R." on something. Any suggestions?

Description : I want to put "S.P.Q.R." on something. Any suggestions?

Last Answer : Put it in your profile.

Match the following: NC code DefinitionP. M05 1. Absolute coordinate system Q. G01 2. Dwell R. G04 3. Spindle stop S. G09 4. Linear interpolation a.P-2, Q-3, R-4, S-1 b.P-3, Q-4, R-1, S-2 c.P-3, Q-4, R-2, S-1 d.P-4, Q-3, R-2, S-1

Description : Match the following: NC code DefinitionP. M05 1. Absolute coordinate system Q. G01 2. Dwell R. G04 3. Spindle stop S. G09 4. Linear interpolation a.P-2, Q-3, R-4, S-1 b.P-3, Q-4, R-1, S-2 c.P-3, Q-4, R-2, S-1 d.P-4, Q-3, R-2, S-1

Last Answer : c.P-3, Q-4, R-2, S-1

Write the given sets in roster form: (a). P = {y: y is an integer and -4 < y < 6}. (b). Q = {y: y is a natural number which is <8} (c). R = {y: y is a 2 digit natural number in which the sum of its digits is 9} -Other

Description : Write the given sets in roster form: (a). P = {y: y is an integer and -4 < y < 6}. (b). Q = {y: y is a natural number which is

Last Answer : (i) A = {x: x is an integer and †3 < x < 7} The elements of this set are †2, †1, 0, 1, 2, 3, 4, 5, and 6 only. Therefore, the given set can be written in roster form as A = {†2, †... and 80 only. Therefore, this set can be written in roster form as C = {17, 26, 35, 44, 53, 62, 71, 80}}.

3. ABCD is a rectangle and P, Q, R and S are mid-points of the sides AB, BC, CD and DA respectively. Show that the quadrilateral PQRS is a rhombus. -Maths 9th

Description : 3. ABCD is a rectangle and P, Q, R and S are mid-points of the sides AB, BC, CD and DA respectively. Show that the quadrilateral PQRS is a rhombus. -Maths 9th

Last Answer : Solution: Given in the question, ABCD is a rectangle and P, Q, R and S are mid-points of the sides AB, BC, CD and DA respectively. Construction, Join AC and BD. To Prove, PQRS is a rhombus. Proof: In ΔABC P and Q ... (ii), (iii), (iv) and (v), PQ = QR = SR = PS So, PQRS is a rhombus. Hence Proved

2. ABCD is a rhombus and P, Q, R and S are the mid-points of the sides AB, BC, CD and DA respectively. Show that the quadrilateral PQRS is a rectangle. -Maths 9th

Description : 2. ABCD is a rhombus and P, Q, R and S are the mid-points of the sides AB, BC, CD and DA respectively. Show that the quadrilateral PQRS is a rectangle. -Maths 9th

Last Answer : Solution: Given in the question, ABCD is a rhombus and P, Q, R and S are the mid-points of the sides AB, BC, CD and DA respectively. To Prove, PQRS is a rectangle. Construction, Join AC and BD. Proof: In ΔDRS and ... , In PQRS, RS = PQ and RQ = SP from (i) and (ii) ∠Q = 90° , PQRS is a rectangle.

ABCD is a quadrilateral in which P, Q, R and S are mid-points of the sides AB, BC, CD and DA (see Fig 8.29). AC is a diagonal. Show that: (i) SR || AC and SR = 1/2 AC (ii) PQ = SR (iii) PQRS is a parallelogram. -Maths 9th

Description : ABCD is a quadrilateral in which P, Q, R and S are mid-points of the sides AB, BC, CD and DA (see Fig 8.29). AC is a diagonal. Show that: (i) SR || AC and SR = 1/2 AC (ii) PQ = SR (iii) PQRS is a parallelogram. -Maths 9th

Last Answer : . Solution: (i) In ΔDAC, R is the mid point of DC and S is the mid point of DA. Thus by mid point theorem, SR || AC and SR = ½ AC (ii) In ΔBAC, P is the mid point of AB and Q is the mid point of BC. ... ----- from question (ii) ⇒ SR || PQ - from (i) and (ii) also, PQ = SR , PQRS is a parallelogram.

P is the mid - point of side AB of a parallelogram ABCD. A line through B parallel to PD meets DC at Q and AD produced at R (see figure). -Maths 9th

Description : P is the mid - point of side AB of a parallelogram ABCD. A line through B parallel to PD meets DC at Q and AD produced at R (see figure). -Maths 9th

Last Answer : (i) In △ARB,P is the mid point of AB and PD || BR. ∴ D is a mid - point of AR [converse of mid - point theorem] ∴ AR = 2AD But BC = AD [opp sides of ||gm ABCD] Thus, AR = 2BC (ii) ∴ ABCD is a ... a mid - point of AR and DQ || AB ∴ Q is a mid point of BR [converse of mid - point theorem] ⇒ BR = 2BQ

Which of the points P(0, 3), Q(l, 0), R(0, – 1), S(-5, 0) and T(1, 2) do not lie on the X-axis ? -Maths 9th

Description : Which of the points P(0, 3), Q(l, 0), R(0, – 1), S(-5, 0) and T(1, 2) do not lie on the X-axis ? -Maths 9th

Last Answer : (c) We know that, if a point is of the form (x, 0)i.e., its y-coordinate is zero, then it will lie on X-axis otherwise not. Here, y-coordinates of points P(0, 3), R (0, -1) and T (1,2) are not zero, so these points do not lie on the X-axis.

Write the coordinates of each of the points P, Q, R, S, T and 0 from the figure . -Maths 9th

Description : Write the coordinates of each of the points P, Q, R, S, T and 0 from the figure . -Maths 9th

Last Answer : Here, points P and S lie in I quadrant so their both coordinates will be positive. Now, perpendicular distance of P from both axes is 1, so coordinates of P are (1, 1). Also, perpendicular distance of S ... 0 is the intersection of both axes, so it is the origin and its coordinates are O (0,0).

Plot the points P(1, 0), Q(4, 0) and 5(1, 3). Find the coordinates of the point R such that PQRS is a square. -Maths 9th

Description : Plot the points P(1, 0), Q(4, 0) and 5(1, 3). Find the coordinates of the point R such that PQRS is a square. -Maths 9th

Last Answer : see the below answer

P, Q, R and S are respectively the mid-points of the sides AB, BC, CD and DA of a quadrilateral ABCD in which AC = BD. -Maths 9th

Description : P, Q, R and S are respectively the mid-points of the sides AB, BC, CD and DA of a quadrilateral ABCD in which AC = BD. -Maths 9th

Last Answer : Given In a quadrilateral ABCD, P, Q, R and S are the mid-points of sides AB, BC, CD and DA, respectively. Also, AC = BD To prove PQRS is a rhombus.

P, Q, R and S are respectively the mid-points of sides AB, BC, CD and DA of quadrilateral ABCD in which AC = BD and AC ⊥ BD. Prove that PQRS is a square. -Maths 9th

Description : P, Q, R and S are respectively the mid-points of sides AB, BC, CD and DA of quadrilateral ABCD in which AC = BD and AC ⊥ BD. Prove that PQRS is a square. -Maths 9th

Last Answer : Given In quadrilateral ABCD, P, Q, R and S are the mid-points of the sides AB, BC, CD and DA, respectively. Also, AC = BD and AC ⊥ BD. To prove PQRS is a square. Proof Now, in ΔADC, S and R are the mid-points of the sides AD and DC respectively, then by mid-point theorem,

P is the mid - point of side AB of a parallelogram ABCD. A line through B parallel to PD meets DC at Q and AD produced at R (see figure). -Maths 9th

Description : P is the mid - point of side AB of a parallelogram ABCD. A line through B parallel to PD meets DC at Q and AD produced at R (see figure). -Maths 9th

Last Answer : (i) In △ARB,P is the mid point of AB and PD || BR. ∴ D is a mid - point of AR [converse of mid - point theorem] ∴ AR = 2AD But BC = AD [opp sides of ||gm ABCD] Thus, AR = 2BC (ii) ∴ ABCD is a ... a mid - point of AR and DQ || AB ∴ Q is a mid point of BR [converse of mid - point theorem] ⇒ BR = 2BQ

Which of the points P(0, 3), Q(l, 0), R(0, – 1), S(-5, 0) and T(1, 2) do not lie on the X-axis ? -Maths 9th

Description : Which of the points P(0, 3), Q(l, 0), R(0, – 1), S(-5, 0) and T(1, 2) do not lie on the X-axis ? -Maths 9th

Last Answer : (c) We know that, if a point is of the form (x, 0)i.e., its y-coordinate is zero, then it will lie on X-axis otherwise not. Here, y-coordinates of points P(0, 3), R (0, -1) and T (1,2) are not zero, so these points do not lie on the X-axis.

Write the coordinates of each of the points P, Q, R, S, T and 0 from the figure . -Maths 9th

Description : Write the coordinates of each of the points P, Q, R, S, T and 0 from the figure . -Maths 9th

Last Answer : Here, points P and S lie in I quadrant so their both coordinates will be positive. Now, perpendicular distance of P from both axes is 1, so coordinates of P are (1, 1). Also, perpendicular distance of S ... 0 is the intersection of both axes, so it is the origin and its coordinates are O (0,0).