Description : The conversion of an amide by reaction `NaOH` and `Br_(2)` to primary amine that has one carbon than the strating amide is known as Hofmann-Bromoamide
Last Answer : The conversion of an amide by reaction `NaOH` and `Br_(2)` to primary amine that has one carbon than the ... ` Mechanism: A. B. C. D. all of these
Last Answer : The conversion of an amide by reaction `NaOH` and `Br_(2)` to primary amine that has one carbon than the strating ... : Find X and Y: A. B. C. D.
Description : In the hofmann-bromamide degradation reaction, the number of moles of NaOH and `Br_(2)` used per mole of amine produced are
Last Answer : In the hofmann-bromamide degradation reaction, the number of moles of NaOH and `Br_(2)` used per mole of ... moles of NaOH and one mole of `Br_(2)`
Description : Hofmann rearrangement In the Hofmann rearrangement an unsubstituted amide is treated with sodium hydroxide and bromide to give a primary amine that ha
Last Answer : Hofmann rearrangement In the Hofmann rearrangement an unsubstituted amide is treated with sodium hydroxide and bromide to ... . `II gt I gt IV gt III`
Last Answer : Hofmann rearrangement In the Hofmann rearrangement an unsubstituted amide is treated with sodium hydroxide and bromide to ... O)overset(||)(C)-NH_(2)`
Description : Which of the following will give Hofmann-Bromoamide reaction?
Last Answer : Which of the following will give Hofmann-Bromoamide reaction? A. B. C. D.
Description : Alkyl cyanide on reduction gives….. a. primary amine b. secondary amine c. amide d. carboxylic acid
Last Answer : a. primary amine
Description : Only one of the following amines will lose its nitrogen atom as trimethyl amine by repeated Hofmann elimination reactions:
Last Answer : Only one of the following amines will lose its nitrogen atom as trimethyl amine by repeated Hofmann elimination reactions: A. B. C. D.
Description : Why is amide more acidic than an amine ?
Last Answer : Ans.—In amide there is C=O group attached NH2 , electron withdrawing & increases acidic nature of amide whereas in amines there is alkyl group which is electron releasing and makes it more basic & hence less acidic.
Description : A primary amine can be identified by using (a) HCl (b) CHCl3 (c) NaOH (d) CHCl3 + KOH
Last Answer : CHCl3 + KOH
Description : Reduction of an imine will give an (a) Acid (b) Amide (c) Amine (d) Alcohol
Last Answer : Amine
Description : Consider a small aliphatic 1° amine, 1° alcohol, ester, carboxylic acid, and amide, all of similar molecular weight. Which one is most likely to have the highest boiling point? (a) The amide (b) The alcohol (c) The ester (d) The carboxylic acid
Last Answer : The amide
Description : Phenol reacts with methyl chloroformate in the presence of `NaOH` to form product A. A reacts with `Br_(2)` to form product B. A and B are respectivel
Last Answer : Phenol reacts with methyl chloroformate in the presence of `NaOH` to form product A. A reacts with `Br_(2)` ... A and B are respectively A. B. C. D.
Description : The product B of the following sequence of reactions is `C_(6)H_(5)CONH_(2) overset(Br_(2))underset(NaOH)toA overst(NaNO_(2)//HCl)underset(ul(" "0-5^(
Last Answer : The product B of the following sequence of reactions is `C_(6)H_(5)CONH_(2) overset(Br_(2))underset(NaOH)toA overst( ... 5^(@)C" "))toB` A. B. C. D.
Description : A nitrile can be made by dehydrating an amide. However, for this reaction to occur, the amide must be : (a) primary (b) secondary (c) tertiary (d) N-methylated
Last Answer : primary
Description : Preparation of a diazonium salt from a primary aromatic amine is known as : (a) Coupling reaction (b) Sandmeyer reaction (c) Diazotization (d) Corey-House synthesis
Last Answer : Diazotization
Description : Which of the following statements is False about acetamide? (a) reacts with Br2/NaOH to form tertiary amine (b) undergoes acid-hydrolysis to form acetic acid (c) undergoes dehydration with P2O5 to form a nitrile (d) is a white crystalline solid, soluble in water
Last Answer : reacts with Br2/NaOH to form tertiary amine
Description : When an primary aromatic amine is treated with `NaNO_(2)+HCI` at `0^(@)-5^(@)C`, a diazonium salt is formed and the reaction is called diazo reaction.
Last Answer : When an primary aromatic amine is treated with `NaNO_(2)+HCI` at `0^(@)-5^(@)C`, a diazonium salt is ... is formed which can be given as: A. B. C. D.
Last Answer : When an primary aromatic amine is treated with `NaNO_(2)+HCI` at `0^(@)-5^(@)C`, a diazonium salt ... reaction. The final product is A. B. C. D.
Last Answer : When an primary aromatic amine is treated with `NaNO_(2)+HCI` at `0^(@)-5^(@)C`, a diazonium salt is formed and ... gt R gt S` D. `S gt R gt Q gt P`
Description : The presence of primary amine can be confirmed by its reaction with:
Last Answer : The presence of primary amine can be confirmed by its reaction with: A. `HNO_(2)` B. `CHCI_(3) +NaOH` C. `CS_(2)` and `HgCI_(2)` D. `H_(2)SO_(4)`
Description : Which of the following is the correct ranking in decreasing order of relative Boiling Point of carbonyl containing compounds? (a) primary amide > carboxylic acid >> ester ~ acyl chloride ~ aldehyde ~ ketone ... chloride ~ amide (d) carboxylic acid > amide >> ester ~ acyl chloride ~ aldehyde ~ ketone
Last Answer : primary amide > carboxylic acid >> ester ~ acyl chloride ~ aldehyde ~ ketone
Description : Which of the following is Hofmann mustard oil reaction?
Last Answer : Which of the following is Hofmann mustard oil reaction? A. Reaction of primary amine with `CHCI_(3 ... 2)` D. Reaction of armoatic amine with iodoform
Description : The conversion of aldehyde having no alpha hydrogen to a mixture to a mixture of carboxylic acid and primary alcohol is known as cannizzaro reaction.
Last Answer : The conversion of aldehyde having no alpha hydrogen to a mixture to a mixture of carboxylic acid and primary ... final product is A. B. C. D.
Last Answer : The conversion of aldehyde having no alpha hydrogen to a mixture to a mixture of carboxylic acid and primary ... C. step III D. step I and II both
Description : Which reagent is used for conversion of benzaldehyde into toluene? a. KMnO4/NaOH b. NH2NH2/KOH c. HIO4 d. V2O5
Last Answer : b. NH2NH2/KOH
Description : Answer: b, c, d Eosinophils constitute 1% to 3% of the leukocyte population of the bloodstream. They also reside in tissues and they exhibit phagocytic capabilities. They are less ... the cycle of events that result in recruitment and activation of inflammatory cells at sites of inflammation
Last Answer : Cellular injury from oxidants may be manifest by which of the following? a. Cell membrane lipid peroxidation b. DNA strand breaks c. Cytoskeletal disassembly d. ATP depletion
Description : The substance that gives a primary amine on hydrolysis is
Last Answer : The substance that gives a primary amine on hydrolysis is A. nitroparaffin B. alkyl cyanide C. oxime D. alkyl isocyanide
Description : Give 3 methods to distinguish primary amine from secondary and tertiary.
Last Answer : Give 3 methods to distinguish primary amine from secondary and tertiary.
Description : Which of the following statements is false about aniline? (a) It is a primary aromatic amine. (b) It is a weak base which forms salts with acids. (c) It liberates nitrogen on treatment with ice-cold nitrous acid. (d) It can be prepared by the reduction of nitrobenzene with tin and HCl
Last Answer : It liberates nitrogen on treatment with ice-cold nitrous acid
Description : Which type of amine produces N2 when treated with HONO? (a) Primary (b) Secondary (c) Tertiary (d) Quaternary
Last Answer : Primary
Description : Carbylamine test involves heating a mixture of (a) alcoholic KOH, methyl iodide, and sodium metal (b) alcoholic KOH, methyl iodide, and primary amine (c) alcoholic KOH, chloroform, and primary amine (d) alcoholic KOH, methyl alcohol, and primary amine
Last Answer : alcoholic KOH, chloroform, and primary amine
Description : Calculate the entropy of `Br_(2)(g)` in the reaction `H_(2)(g)+Br_(2)(g)rarr2HBr(g), Delta S^(@)=20.1 JK^(-1)` given, entropy of `H_(2)` and HBr is 13
Last Answer : Calculate the entropy of `Br_(2)(g)` in the reaction `H_(2)(g)+Br_(2)(g)rarr2HBr(g), Delta S^(@)=20.1 JK^(-1 ... ` C. `24.63 JK^(-1)` D. `20 KJK^(-1)`
Description : The enthalpy and entropy change for the reaction, `Br_(2)(l)+Cl_(2)(g)rarr2BrCl(g)` are `30KJmol^(-1)` and `105JK^(-1)mol^(-1)` respectively. The temp
Last Answer : The enthalpy and entropy change for the reaction, `Br_(2)(l)+Cl_(2)(g)rarr2BrCl(g)` are `30KJmol^(-1)` and ` ... 285.7 K B. 273 K C. 450 K D. 300 K
Description : Which is the best description of the behaviour of bromine in the reaction given below `H_(2)O+Br_(2) rarr HOBr+HBr`
Last Answer : Which is the best description of the behaviour of bromine in the reaction given below `H_(2)O+ ... . Oxidized C. Reduced only D. Proton acceptor only
Description : The reaction `RCH_(2)CH_(2)COOH overset(Red P)underset(Br_(2))toRCH_(2)-underset(Br)underset(|)(C)HCOOH` is called as
Last Answer : The reaction `RCH_(2)CH_(2)COOH overset(Red P)underset(Br_(2))toRCH_(2)-underset(Br) ... reaction C. Reimer Teimann reaction D. Sandmeyer reaction
Description : `CH_(3)CH_(2)-CH_(2)-COOH overset("Red + P" +Br_(2))toCH_(3)-CH_(2)-underset(Br)underset(|)(CH)-COOH` This reaction is called
Last Answer : `CH_(3)CH_(2)-CH_(2)-COOH overset("Red + P" +Br_(2))toCH_(3)-CH_(2)-underset(Br)underset(|)(CH)-COOH` This reaction is called
Description : Consider the following reaction and statements: `[Co(NH_(3))_(4)Br_(2)]^(+)+Br^(-) to [Co(NH_(3))_(3)Br_(3)]+NH_(3)` Two isomers are produced if the r
Last Answer : Consider the following reaction and statements: `[Co(NH_(3))_(4)Br_(2)]^(+)+Br^(-) to [Co(NH_(3))_(3) ... II B. III and IV C. I and IV D. II and III
Description : Reaction I `Ph-overset(O)overset(||)(C)-NH_(2) overset(overset(Theta)(OD),Br_(2))rarrA` Reaction II `Ph-overset(O)overset(||)(C)-ND_(2) overset(overse
Last Answer : Reaction I `Ph-overset(O)overset(||)(C)-NH_(2) overset(overset(Theta)(OD),Br_(2))rarrA` Reaction II `Ph- ... Both `Ph-NH_(2)` D. Both `Ph-ND_(2)`
Description : `overset(1.Br_(2)^(-)+KOH, Delta)underset(2.H_(3)O^(o+))rarr` The product of above reaction is:
Last Answer : `overset(1.Br_(2)^(-)+KOH, Delta)underset(2.H_(3)O^(o+))rarr` The product of above reaction is: A. B. C. D.
Description : Reaction of `RCONH_(2)` with a mixture of `Br_(2)` and `KOH` gives `RNH_(2)` as the main product. The intermediates involved in the reaction are:
Last Answer : Reaction of `RCONH_(2)` with a mixture of `Br_(2)` and `KOH` gives `RNH_(2)` as the main product. The intermediates ... ` B. `R-NHBr` C. `R-N=C=O` D.
Description : under Hofmann conditions will give :
Last Answer : under Hofmann conditions will give : A. B. C. D.
Description : In the Hofmann-Bromamide rearrangement intermediate compounds are:
Last Answer : In the Hofmann-Bromamide rearrangement intermediate compounds are: A. `R -CONHBr` B. `[R-overset(O)overset(||)(C)- ... ` C. `R -N=C=O` D. all of these
Description : Is Hans hofmann a modern artist?
Last Answer : Need answer
Description : Which of the following drugs undergoes ‘Hofmann’ elimination: A. Succinylcholine B. Pancuronium C. Vecuronium
Last Answer : D. Atracurium
Description : Quartenry ammonium salt after Hofmann elimination gives--- a. Alcohol b. Alkene c. Alkyne d. Ammmonia
Last Answer : b. Alkene
Description : ----rearrangement involves alpha diketone. a. Wolf b. Schmidt c. Hofmann d. Curtius
Last Answer : a. Wolf