In the diode equation, the voltage equivalent of temperature is a. 11600/T b. T/11600 c. T x 11600 d. 11600/T2

In the diode equation, the voltage equivalent of temperature is
a. 11600/T b. T/11600 c. T x 11600 d. 11600/T2
by

1 Answer

Answer :

b. T/11600
by

Related questions

When the diode is forward biased, it is equivalent to a. An off switch b. An On switch c. A high resistance d. None of the above

Description : When the diode is forward biased, it is equivalent to a. An off switch b. An On switch c. A high resistance d. None of the above

Last Answer : b. An On switch

The knee voltage (cut in voltage) of Si diode is a. 0.2 V b. 0.7 V c. 0.8 V d. 1.0 V

Description : The knee voltage (cut in voltage) of Si diode is a. 0.2 V b. 0.7 V c. 0.8 V d. 1.0 V

Last Answer : b. 0.7 V

When a reverse bias is applied to a diode, it will a. Raise the potential barrier b. Lower the potential barrier c. Increases the majority-carrier a current greatly d. None of these

Description : When a reverse bias is applied to a diode, it will a. Raise the potential barrier b. Lower the potential barrier c. Increases the majority-carrier a current greatly d. None of these

Last Answer : a. Raise the potential barrier

A forward potential of 10V is applied to a Si diode. A resistance of 1 KΩ is also in series with the diode. The current is a. 10 mA b. 9.3 mA c. 0.7 mA d. 0

Description : A forward potential of 10V is applied to a Si diode. A resistance of 1 KΩ is also in series with the diode. The current is a. 10 mA b. 9.3 mA c. 0.7 mA d. 0

Last Answer : b. 9.3 mA

Avalanche breakdown in a diode occurs when a. Potential barrier is reduced to zero. b. Forward current exceeds certain value. c. Reverse bias exceeds a certain value. d. None of these

Description : Avalanche breakdown in a diode occurs when a. Potential barrier is reduced to zero. b. Forward current exceeds certain value. c. Reverse bias exceeds a certain value. d. None of these

Last Answer : c. Reverse bias exceeds a certain value.

The arrow direction in the diode symbol indicates a. Direction of electron flow. b. Direction of hole flow (Direction of conventional current) c. Opposite to the direction of hole flow d. None of the above

Description : The arrow direction in the diode symbol indicates a. Direction of electron flow. b. Direction of hole flow (Direction of conventional current) c. Opposite to the direction of hole flow d. None of the above

Last Answer : b. Direction of hole flow (Direction of conventional current)

Equivalent bending moment in a shaft subjected to axial load P, torque T and bending moment M is (a) Meq = 0.5 [M + (M2 + T2)0.5]0.5 (b) Meq = 0.5 [M + (M2 + T2)0.5] (c) Meq = ( M2 + T2)0.5 (d) None

Description : Equivalent bending moment in a shaft subjected to axial load P, torque T and bending moment M is (a) Meq = 0.5 [M + (M2 + T2)0.5]0.5 (b) Meq = 0.5 [M + (M2 + T2)0.5] (c) Meq = ( M2 + T2)0.5 (d) None

Last Answer : (b) Meq = 0.5 [M + (M2 + T2)0.5]

Equivalent torque in a shaft subjected to axial load P, torque T and bending moment M is (a) Teq = (Pa2 + M2 + T2) (b) Teq = (Pa2 + M2 + T2)0.5 (c)Teq = ( M2 + T2)0.5 (d) None

Description : Equivalent torque in a shaft subjected to axial load P, torque T and bending moment M is (a) Teq = (Pa2 + M2 + T2) (b) Teq = (Pa2 + M2 + T2)0.5 (c)Teq = ( M2 + T2)0.5 (d) None

Last Answer : c)Teq = ( M2 + T2)0.5

Gibbs free energy (G) is represented by, G = H - TS, whereas Helmholtz free energy, (A) is given by, A = E - TS. Which of the following is the Gibbs Helmholtz equation? (A) [∂(G/T)/∂T] = - (H/T2) (B) [∂(A/T)/∂T]V = - E/T2 (C) Both (A) and (B) (D) Neither (A) nor (B)

Description : Gibbs free energy (G) is represented by, G = H - TS, whereas Helmholtz free energy, (A) is given by, A = E - TS. Which of the following is the Gibbs Helmholtz equation? (A) [∂(G/T)/∂T] = - (H/T2) (B) [∂(A/T)/∂T]V = - E/T2 (C) Both (A) and (B) (D) Neither (A) nor (B)

Last Answer : (C) Both (A) and (B)

Which of the following is the Ideal gas law (equation)?  A. V/T = K  B. V= k*(1/P)  C. P1/T1 = P2/T2  D. PV = nRT

Description : Which of the following is the Ideal gas law (equation)?  A. V/T = K  B. V= k*(1/P)  C. P1/T1 = P2/T2  D. PV = nRT

Last Answer : PV = nRT

To obtain integrated form of Clausius-Clapeyron equation, ln (P2/P1) = (∆HV/R) (1/T1- 1/T2) from the exact Clapeyron equation, it is assumed that the (A) Volume of the liquid phase is negligible compared to that of vapour phase (B) Vapour phase behaves as an ideal gas (C) Heat of vaporisation is independent of temperature (D) All (A), (B) & (C)

Description : To obtain integrated form of Clausius-Clapeyron equation, ln (P2/P1) = (∆HV/R) (1/T1- 1/T2) from the exact Clapeyron equation, it is assumed that the (A) Volume of the liquid phase is negligible compared to ... gas (C) Heat of vaporisation is independent of temperature (D) All (A), (B) & (C)

Last Answer : (D) All (A), (B) & (C)

What is the equation for the work done by a constant temperature system?  A. W = mRTln(V2-V1)  B. W = mR( T2-T1 ) ln( V2/V1)  C. W = mRTln (V2/V1)  D. W = RT ln (V2/V1) Formula : W=∫ pdV lim1,2 ∫ = mRT / V

Description : What is the equation for the work done by a constant temperature system?  A. W = mRTln(V2-V1)  B. W = mR( T2-T1 ) ln( V2/V1)  C. W = mRTln (V2/V1)  D. W = RT ln (V2/V1) Formula : W=∫ pdV lim1,2 ∫ = mRT / V

Last Answer : W = mRTln (V2/V1)

If P:Q:R=2:3:4 and `P^(2)+Q^(2)+R^(2)=11600`, then find `(P+Q-R)`

Description : If P:Q:R=2:3:4 and `P^(2)+Q^(2)+R^(2)=11600`, then find `(P+Q-R)`

Last Answer : If P:Q:R=2:3:4 and `P^(2)+Q^(2)+R^(2)=11600`, then find `(P+Q-R)` A. 15 B. 16 C. 18 D. 20

175 × 28 + 275 × 28 =? a) 11800 b) 12600 c) 12800 d) 11600 e) 12200

Description : 175 × 28 + 275 × 28 =? a) 11800 b) 12600 c) 12800 d) 11600 e) 12200

Last Answer : Answer: b)

Translational kinetic energy of molecules of an ideal gas is proportional to (where, T = absolute temperature of the gas) (A) T (B) √T (C) T2 (D) 1/√T

Description : Translational kinetic energy of molecules of an ideal gas is proportional to (where, T = absolute temperature of the gas) (A) T (B) √T (C) T2 (D) 1/√T

Last Answer : (A) T

The ratio of thermal & electrical conductivity is same for all the metals at the same temperature; and at around room temperature, this ratio is proportional to(where, T = absolute temperature, °K) (A) T (B) 1/T (C) T2 (D) 1/T2

Description : The ratio of thermal & electrical conductivity is same for all the metals at the same temperature; and at around room temperature, this ratio is proportional to(where, T = absolute temperature, °K) (A) T (B) 1/T (C) T2 (D) 1/T2

Last Answer : A) T

Pick up the correct statement from the following: (A) Mcg = M M 2 + r2 ) where letters carry their usual meanings (B) Tcp = m 2 + T2 )where letters carry their usual meanings (C) The torque which when acting alone would produce maximum shear stress equal to the maximum shear stress caused by the combined bending and torsion, is called equivalent torque (D) All the above

Description : Pick up the correct statement from the following:  (A) Mcg = M M 2  + r2 ) where letters carry their usual meanings  (B) Tcp = m 2  + T2 )where ... maximum shear stress caused by the combined bending and torsion, is called equivalent  torque  (D) All the above 

Last Answer : (D) All the above 

A particle starts from rest and moves in a straight line whose equation of motion is given by S = 2t3 - t2 - 1. The acceleration of the particle after one sec will be a.6 m/sec2 b.4 m/sec2 c.12 m/sec2 d.10 m/sec2 e.8 m/sec2

Description : A particle starts from rest and moves in a straight line whose equation of motion is given by S = 2t3 - t2 - 1. The acceleration of the particle after one sec will be a.6 m/sec2 b.4 m/sec2 c.12 m/sec2 d.10 m/sec2 e.8 m/sec2

Last Answer : d. 10 m/sec2

is the predominant form of Fast Ethernet, and runs over two pairs of category 5 or above cable. a. 100 BASE-T b. 100 BASE-TX c. 100 BASE-T4 d. 100 BASE-T2

Description : is the predominant form of Fast Ethernet, and runs over two pairs of category 5 or above cable. a. 100 BASE-T b. 100 BASE-TX c. 100 BASE-T4 d. 100 BASE-T2

Last Answer : b. 100 BASE-TX

S1 and S2 are the draw downs in an observation well at times t1 and t2 after pumping. For discharge Q and coefficient of transmissibility T, the relationship, is (A) S2 - S1 = (2.3Q/ ) log10 (t2/t1) (B) S2 - S1 = (2.3Q/4 ) log10 (t2/t1) (C) S2 - S1 = (2.3Q/4 ) loge (t2/t1) (D) S2 - S1 = (2.3Q/4 ) loge (t1/t2

Description : S1 and S2 are the draw downs in an observation well at times t1 and t2 after pumping. For  discharge Q and coefficient of transmissibility T, the relationship, is  (A) S2 - S1 = (2.3Q/ ) log10 (t2/t1)  (B) S2 - S1 ... - S1 = (2.3Q/4 ) loge (t2/t1)  (D) S2 - S1 = (2.3Q/4 ) loge (t1/t2

Last Answer : (B) S2 - S1 = (2.3Q/4 ) log10 (t2/t1) 

Efficiency of a Carnot engine working between temperatures T1 and T2(T1 < T) is (A) (T2- T1)/T2 (B) (T2- T1)/T1 (C) (T1- T2)/T2 (D) (T1- T2)/T1

Description : Efficiency of a Carnot engine working between temperatures T1 and T2(T1 < T) is (A) (T2- T1)/T2 (B) (T2- T1)/T1 (C) (T1- T2)/T2 (D) (T1- T2)/T1

Last Answer : (A) (T2- T1)/T2

The clock period is denoted by: a. T p b. T1+T2+T3-------+T n c. Pt d. None of these

Description : The clock period is denoted by: a. T p b. T1+T2+T3-------+T n c. Pt d. None of these

Last Answer : a. T p

s the predominant form of Fast Ethernet, and runs over two pairs of category 5 or above cable. A) 100 BASE-T B) 100 BASE-TX C) 100 BASE-T4 D) 100 BASE-T2

Description : s the predominant form of Fast Ethernet, and runs over two pairs of category 5 or above cable. A) 100 BASE-T B) 100 BASE-TX C) 100 BASE-T4 D) 100 BASE-T2

Last Answer : B) 100 BASE-TX

-For two shafts in parallel or for two concentric shafts a. T = T1 + T2 b. T = T1 = T2 c. T = T1 – T2 d. T = (T1.T2)^1/2

Description : -For two shafts in parallel or for two concentric shafts a. T = T1 + T2 b. T = T1 = T2 c. T = T1 – T2 d. T = (T1.T2)^1/2

Last Answer : a. T = T1 + T2

For two shafts in series or having different diameters for two parts of length a. T = T1 + T2 b. T = T1 = T2 c. T = T1 – T2 d. T = (T1.T2)^1/2

Description : For two shafts in series or having different diameters for two parts of length a. T = T1 + T2 b. T = T1 = T2 c. T = T1 – T2 d. T = (T1.T2)^1/2

Last Answer : b. T = T1 = T2

Let x1(t) and x2(t) be periodic with fundamental periods T1 and T2 respectively. Under what

Description : Let x1(t) and x2(t) be periodic with fundamental periods T1 and T2 respectively. Under what condition be the sum x(t) = x1(t) + x2(t) be periodic ? (A) Only for T1 = T2 (B) Always periodic (C) For T1/T2 equal to a rational number (D) Not periodic

Last Answer : Let x1(t) and x2(t) be periodic with fundamental periods T1 and T2 respectively. Under what condition be the sum x(t) = x1(t) + x2(t) be periodic ? (A) Only for T1 = T2 (B) Always periodic (C) For T1/T2 equal to a rational number (D) Not periodic

The most efficient heat engine that can operate between two temperature reservoirs T1 and T2 is: w) jet engine x) internal combustion engine y) Carnot engine (pron: car-no) z) steam engine

Description : The most efficient heat engine that can operate between two temperature reservoirs T1 and T2 is: w) jet engine x) internal combustion engine y) Carnot engine (pron: car-no) z) steam engine

Last Answer : ANSWER: Y -- CARNOT ENGINE

How does the temperature affect the Zener voltage of a Zener diode?

Description : How does the temperature affect the Zener voltage of a Zener diode?

Last Answer : The Zener voltage of a Zener diode is affected by temperature changes. The Zener voltage of a diode is directly proportional to the temperature. This means that as the temperature increases, the ... is given by the Zener voltage temperature coefficient, which is specified in the diode's datasheet.

In the illustration, the diode between terminals 16 and 17 is to _________. EL-0046 A. insure that the voltage across the governor coil (EG-3P) never exceeds .6 VDC B. compensate for the temperature difference of the governor oil heating up C. protect the electronic governor from counter EMF D. act as a filter to prevent hunting

Description : In the illustration, the diode between terminals 16 and 17 is to _________. EL-0046 A. insure that the voltage across the governor coil (EG-3P) never exceeds .6 VDC B. compensate for the ... heating up C. protect the electronic governor from counter EMF D. act as a filter to prevent hunting

Last Answer : Answer: C

Heat transfer by radiation between two bodies at T1 & T2 and in an ambient temperature of Ta °C depends on (A) T1 - T2 (B) T1 - Ta (C) T2 - Ta (D) None of these

Description : Heat transfer by radiation between two bodies at T1 & T2 and in an ambient temperature of Ta °C depends on (A) T1 - T2 (B) T1 - Ta (C) T2 - Ta (D) None of these

Last Answer : (D) None of these

What is the value of maximum COP in case of absorption refrigeration, if refrigeration provided is at temperature, TR (where, T1 and T2 are source & surrounding temperatures respectively.)? (A) TR/(T2 - TR) × (T1 - T2 )/T1 (B) TR/(T2 - TR) × T1 /(T1 - T2 ) (C) TR/(T1 - TR) × (T1 - T2 )/T1 (D) None of these

Description : What is the value of maximum COP in case of absorption refrigeration, if refrigeration provided is at temperature, TR (where, T1 and T2 are source & surrounding temperatures respectively.)? (A) TR/(T2 - TR) (T1 - T2 )/T1 (B) TR ... T1 /(T1 - T2 ) (C) TR/(T1 - TR) (T1 - T2 )/T1 (D) None of these

Last Answer : (A) TR/(T2 - TR) × (T1 - T2 )/T1

The expression for entropy change, ΔS = n Cp. ln (T2/T1), is valid for the __________ of a substance. (A) Simultaneous pressure & temperature change (B) Heating (C) Cooling (D) Both (B) and (C)

Description : The expression for entropy change, ΔS = n Cp. ln (T2/T1), is valid for the __________ of a substance. (A) Simultaneous pressure & temperature change (B) Heating (C) Cooling (D) Both (B) and (C)

Last Answer : (D) Both (B) and (C)

A gas having a volume of100 ft³ at 27ºC is expanded to 120 ft³by heated at constant pressure to what temperature has it been heated to have this new volume?  a. 87°C  b. 85°C  c. 76°C  d. 97°C t2= T2–T1

Description : A gas having a volume of100 ft³ at 27ºC is expanded to 120 ft³by heated at constant pressure to what temperature has it been heated to have this new volume?  a. 87°C  b. 85°C  c. 76°C  d. 97°C t2= T2–T1

Last Answer : 87°C

The heat supplied to the gaS at constant volume is (where m = Mass of gas, cv = Specific heat at constant volume, cp = Specific heat at constant pressure, T2 – T1 = Rise in temperature, and R = Gas constant)  A. mR(T2 – T1)  B. mcv(T2 – T1)  C. mcp(T2 – T1)  D. mcp(T2 + T1)

Description : The heat supplied to the gaS at constant volume is (where m = Mass of gas, cv = Specific heat at constant volume, cp = Specific heat at constant pressure, T2 – T1 = Rise in temperature, and R = Gas constant)  A. mR(T2 – T1)  B. mcv(T2 – T1)  C. mcp(T2 – T1)  D. mcp(T2 + T1)

Last Answer : Answer: B

Equation which measures alternating voltage is A. Vsin ω B. sin t C. Vo sinωt D. V=IR

Description : Equation which measures alternating voltage is A. Vsin ω B. sin t C. Vo sinωt D. V=IR

Last Answer : Vo sinωt

When the diode is forward biased, it is equivalent to

Description : When the diode is forward biased, it is equivalent to

Last Answer : When the diode is forward biased, it is equivalent to An On switch

The order of reaction is the number of moles whose concentrations determine the rate of a reaction at a given temperature Give the integrated equation for first order reaction. K = (2.303 / t) * log (a / a-x) Rate equation of first order reaction is. dx/dt = K * (a-x) where ‘a’ is the initial concentration of reactants ‘x’ is the amount reacted in time t seconds

Description : The order of reaction is the number of moles whose concentrations determine the rate of a reaction at a given temperature Give the integrated equation for first order reaction. K = (2.303 / t) * log (a ... a' is the initial concentration of reactants x' is the amount reacted in time t seconds

Last Answer : What is Threshold energy ?

How do you find the derivative for f(x) integral (1-t2)(1 plus t4) from sin2x to 1?

Description : How do you find the derivative for f(x) integral (1-t2)(1 plus t4) from sin2x to 1?

Last Answer : My suggestion is to multiply the binomials and do the integration directly, and then differentiate the result with respect to x. (If that doesn't work, feel free to send me a picture of the problem and I'll give it another try.)

Two infinitely long parallel conductors in vacuum any separated 1 metre between centers >then a current of 1 ampere flows the. uk each conductor, produce on each other a force of (a) 2 x 1(T2 N/m) (b) 2 x KT3 N/m (c) 2 x 10"5 N/m (d) 2x 1(T7 N/m)

Description : Two infinitely long parallel conductors in vacuum any separated 1 metre between centers >then a current of 1 ampere flows the. uk each conductor, produce on each other a force of (a) 2 x 1(T2 N/m) (b) 2 x KT3 N/m (c) 2 x 10"5 N/m (d) 2x 1(T7 N/m)

Last Answer : (d) 2x 1(T7 N/m)

One of the following is not a useful quantity for comparing the noise performance receivers. A. Input noise voltage B. Equivalent noise resistance C. Noise temperature D. Noise figure.

Description : One of the following is not a useful quantity for comparing the noise performance receivers. A. Input noise voltage B. Equivalent noise resistance C. Noise temperature D. Noise figure.

Last Answer : A. Input noise voltage

What equation is equivalent to 3[x + 3(4x – 5)] = 15x – 24?

Description : What equation is equivalent to 3[x + 3(4x – 5)] = 15x – 24?

Last Answer : 39x - 45 = 15x - 24

When the peak output voltage is 100 V the PIV for each diode in a center-tapped full-wave rectifier is (neglecting the diode drop)?

Description : When the peak output voltage is 100 V the PIV for each diode in a center-tapped full-wave rectifier is (neglecting the diode drop)?

Last Answer : Feel Free to Answer

Can the barrier voltage of a diode act as a voltage source?

Description : Can the barrier voltage of a diode act as a voltage source?

Last Answer : No, we don not consider the barrier voltage of a diode to beable to act as a voltage source. The barrier voltage arises duringconstruction of the p-n junction, and it results from ... as a voltage sourcebecause it cannot supply current the way we understand conventionalvoltage sources are able do.

Why can't the potential barrier of a diode be used as a voltage source?

Description : Why can't the potential barrier of a diode be used as a voltage source?

Last Answer : The potential barrier of a diode is caused by the movement ofelectrons to create holes. The electrons and holes create apotential barrier, but as this voltage will not supply current, itcannot be used as a voltage source.

What effect does an open diode have on the output voltage of a half wave rectifier and on a full wave rectifier?

Description : What effect does an open diode have on the output voltage of a half wave rectifier and on a full wave rectifier?

Last Answer : An open diode will result in no output from a half waverectifier, and an open diode will cut the output of a full waverectifier in half.

In the illustration, the component VR2 on the A1 AMPLIFIER MODULE is _________. EL-0060 A. a zener diode to regulate the +9 volt power supply from common B. a variable resistor diode to control the output to terminal 1 that controls the input to terminal 10 C. a zener diode that regulates the voltage to terminal 2 at 9.1 volts DC D. a tunnel diode with a breakdown voltage of 6.6 Volts DC

Description : In the illustration, the component VR2 on the A1 AMPLIFIER MODULE is _________. EL-0060 A. a zener diode to regulate the +9 volt power supply from common B. a variable resistor diode to control the output to terminal ... 2 at 9.1 volts DC D. a tunnel diode with a breakdown voltage of 6.6 Volts DC

Last Answer : Answer: C

In the illustration, the component VR1 on the A1 AMPLIFIER MODULE is _________. EL-0060 A. a zener diode to regulate the +9 volt power supply from common B. a variable resistor diode to control the output to terminal 9 that controls the input to terminal 10 C. a zener diode that regulates the voltage to terminal 9 at 6.6 volts DC D. a tunnel diode with a breakdown voltage of 6.6 Volts DC

Description : In the illustration, the component VR1 on the A1 AMPLIFIER MODULE is _________. EL-0060 A. a zener diode to regulate the +9 volt power supply from common B. a variable resistor diode to control the output to ... terminal 9 at 6.6 volts DC D. a tunnel diode with a breakdown voltage of 6.6 Volts DC

Last Answer : Answer: A

In the illustration, the component VR1 on the A1A1 PCB is _________. EL-0060 A. a zener diode to regulate the +9 volt power supply B. a variable resistor diode to control the output to terminal 9 that controls the input to terminal 10 C. a zener diode that regulates the voltage to terminal 9 at 6.6 volts DC D. a tunnel diode with a breakdown voltage of 6.6 Volts DC

Description : In the illustration, the component VR1 on the A1A1 PCB is _________. EL-0060 A. a zener diode to regulate the +9 volt power supply B. a variable resistor diode to control the output to terminal 9 that controls ... terminal 9 at 6.6 volts DC D. a tunnel diode with a breakdown voltage of 6.6 Volts DC

Last Answer : Answer: C

In the illustration, the diode between terminals 16 and 17 is to _________. EL-0046 A. act as a short circuit for the sensing coil when CEMF is applied B. insure that the voltage across the coil does not exceed 9 volts C. improve response time D. act as a filter to prevent hunting

Description : In the illustration, the diode between terminals 16 and 17 is to _________. EL-0046 A. act as a short circuit for the sensing coil when CEMF is applied B. insure that the voltage across the coil does not exceed 9 volts C. improve response time D. act as a filter to prevent hunting

Last Answer : Answer: A