Description : Some amount of "20V" `H_(2)O_(2)` is mixed with excess of acidified solution of Kl. The iodine so liberated required 200 mL of 0.1 N `Na_(2)S_(2)O_(3)
Last Answer : Some amount of "20V" `H_(2)O_(2)` is mixed with excess of acidified solution of Kl. The iodine so liberated ... 56 mL B. 112 mL C. 168 mL D. 224 mL
Last Answer : Some amount of "20V" `H_(2)O_(2)` is mixed with excess of acidified solution of Kl. The iodine so liberated required ... . 0.8 g C. 4.2 g D. 0.98 g
Last Answer : Some amount of "20V" `H_(2)O_(2)` is mixed with excess of acidified solution of Kl. The iodine so liberated required ... 37.2 mL C. 5.6 mL D. 22.4 mL
Description : 25 mL of household bleach solution was mixed with 30 mL of o.50 M Kl and 10 mL of 4N acetic acid. In the titration of the liberated iodine, 48 mL of 0
Last Answer : 25 mL of household bleach solution was mixed with 30 mL of o.50 M Kl and 10 mL of 4N acetic acid. In the titration ... B. 0.96 M C. 0.24 M D. 0.024 M
Description : A mixture containing `As_(2)O_(3)` and `As_(2)O_(5)` required 20 mL of 0.05 N iodine solution for titration. The resulting solution is then acidified
Last Answer : A mixture containing `As_(2)O_(3)` and `As_(2)O_(5)` required 20 mL of 0.05 N iodine solution for ... +2H_(2)O " " `(Atomic weight : As = 75)
Description : iodine is liberated from Kl solution when treated with:
Last Answer : iodine is liberated from Kl solution when treated with: A. (A) `ZnSO_4` B. (B) `CuSO_4 ` C. (C) `NiSO_4 ` D. (D) `FeSO_4`
Description : Hydrogen peroxide solution `(20 mL)` reacts quantitatively with a solution of `KMnO_(4) (20 mL)` acidified with dilute of `H_(2)SO_(4)`. The same volu
Last Answer : Hydrogen peroxide solution `(20 mL)` reacts quantitatively with a solution of `KMnO_(4) (20 mL)` ... calculate the molarity of `H_(2)O_(2)`.
Description : In the test for iodine, `I_(2)` is treated with sodium thiosulphate `(Na_(2)S_(2)O_(3))` : `Na_(2)S_(2)O_(3)+I_(2) to NaI +..`
Last Answer : In the test for iodine, `I_(2)` is treated with sodium thiosulphate `(Na_(2)S_(2)O_(3))` : `Na_(2)S_(2)O_(3 ... (4)` C. `Na_(2)S` D. `Na_(3)ISO_(4)`
Description : `25ml` of a `0.1(M)` solution of a stable cation of transition metal `z` reacts exactly with `25 ml` of `0.04(M)` acidified `KMnO_(4)` solution. Which
Last Answer : `25ml` of a `0.1(M)` solution of a stable cation of transition metal `z` reacts exactly with `25 ml` of `0.04 ... 3+)rarrZ^(4+)` D. `Z^(2+)rarrZ^(4+)`
Description : When equal weight of methyl alcohol and ehtyl alcohol react with excess of sodium metal, the volume of `H_(2)` liberated is more in the case of
Last Answer : When equal weight of methyl alcohol and ehtyl alcohol react with excess of sodium metal, the volume of `H_(2 ... in both D. `H_(2)` is not liberated
Description : The formula of product formed, when sodium thiosulphate solution is added to silver bromide is
Last Answer : The formula of product formed, when sodium thiosulphate solution is added to silver bromide is A. `Na_(3)[Ag(S_(2)O_ ... `Ag_(3)[Na(S_(2)O_(3))_(2)]`
Description : One mole of acidified `K_(2)Cr_(2)O_(7)` on reaction with excess of KCl will liberate….., moles of `I_(2)`.
Last Answer : One mole of acidified `K_(2)Cr_(2)O_(7)` on reaction with excess of KCl will liberate….., moles of `I_(2)`. A. 6 B. 1 C. 7 D. 3
Description : A compound 'X' of the formula `C_(3)H_(8)O` gives iodoform test. On oxidation with acidified `K_(2)Cr_(2)O_(7)X` gave Y. Y also gives iodogorm test. T
Last Answer : A compound 'X' of the formula `C_(3)H_(8)O` gives iodoform test. On oxidation with acidified `K_(2)Cr_(2) ... ` D. `CH_(3)COCH_(3), CH_(3)CHOHCH_(3)`
Description : I. `H_(2)S` reduces acidified `KMnO_(4)` to `MnSO_(4)` II. `H_(2)S` reduces acidified `K_(2)Cr_(2)O_(7)` to red colour `Cr_(2)(SO_(4))_(3)` III. `H_(2
Last Answer : I. `H_(2)S` reduces acidified `KMnO_(4)` to `MnSO_(4)` II. `H_(2)S` reduces acidified `K_(2)Cr_(2) ... and III C. only II and III D. I,II,III and IV
Description : Thiosulphate ion `(S_(2)O_(3)^(2-))` on acidification changes to `SO_(2)` along the precipitation of sulpur, `.^(35)S^(32) SO_(3)^(2-) + 2H^(+) to H_(
Last Answer : Thiosulphate ion `(S_(2)O_(3)^(2-))` on acidification changes to `SO_(2)` along the precipitation of sulpur, ` ... ` is in both D. `S^(35)` is in none
Description : If 1 mL of a `KMnO_(4)` solution react with 0.140g `Fe^(2+)` and if 1 mL of `KHV_(2)O_(4)`. `H_(2C_(2)O_(4)` solution react with o.1 mL of previous `K
Last Answer : If 1 mL of a `KMnO_(4)` solution react with 0.140g `Fe^(2+)` and if 1 mL of `KHV_(2)O_(4)`. `H_(2C_( ... 15/6 mL B. 13/16 C. `11/14` D. None of these
Description : In the redox reaction . `MnO_(4)^(-)+C^(2)O_(4)^(2-)+H^(+) rarr Mn^(2+)+CO_(2)+H_(2)O` (Unbalance equation) 20 mL of 0.1 M `KMnO_(4)` react quantitive
Last Answer : In the redox reaction . `MnO_(4)^(-)+C^(2)O_(4)^(2-)+H^(+) rarr Mn^(2+)+CO_(2)+H_(2)O` ( ... . 40 mL of 0.1 M oxalate D. 50 mL of 0.25 M oxalate
Description : Statement -1 : Sodium thiosulphate is not prepared by boiling `Na_(2)SO_(3)` with S in acidic medium. Statement -2 : `Na_(2)S_(2)O_(3)+H^(+) to 2Na++H
Last Answer : Statement -1 : Sodium thiosulphate is not prepared by boiling `Na_(2)SO_(3)` with S in acidic medium. Statement ... +H^(+) to 2Na++H_(2)SO_(3)+Sdarr`
Description : A gas turns lime water milky and acidified `K_(2)Cr_(2)O_(7)` solution green then gas is :
Last Answer : A gas turns lime water milky and acidified `K_(2)Cr_(2)O_(7)` solution green then gas is : A. `HCl` B. `H_(2)S` C. `SO_(2)` D. `CO_(2)`
Description : Componds `(A)` and `B` are treated with dilute `HCl` separately. The gases liberated are `Y` and `Z` respectively. `Y` turns acidified `K_2 Cr_2 O_7`
Last Answer : Componds `(A)` and `B` are treated with dilute `HCl` separately. The gases liberated are `Y` and `Z` ... )SO_(4)` D. `NaC1 and Na_(2)CO_(3)`
Description : 25 mL of a solution of `Fe^(2+)` ions was titrated with a solution of the oxidizing agent `Cr_(2)O_(7)^(2-)` . 50 mL of 0.01 M `K_(2)Cr_(2)O_(7)` solu
Last Answer : 25 mL of a solution of `Fe^(2+)` ions was titrated with a solution of the oxidizing agent `Cr_(2)O_ ... is the molarity of the `Fe^(2+)` solution ?
Description : When `SO_(2)` is passed through acidified solution of `H_(2)S`
Last Answer : When `SO_(2)` is passed through acidified solution of `H_(2)S` A. `H_(2)SO_(3)` is formed B. ... . Sulphur is precipitated D. `H_(2)SO_(5)` is formed
Description : Consider the given compounds : (a) `CH_(3)-CH_(2)-NH_(2)` (b) `CH_(3)-CH=NH` (c ) `CH_(3)-C=N` (d) `C_(2)H_(5)-NH-C_(2)H_(5)` Arrange basicity of thes
Last Answer : Consider the given compounds : (a) `CH_(3)-CH_(2)-NH_(2)` (b) `CH_(3)-CH=NH` (c ) `CH_(3)-C=N` (d) `C_(2 ... `a gt d gt b gt c` D. `d gt a gt c gt b`
Description : What numbers are from Least to greatest 8.200 ML 0.005 KL 8.1 L?
Last Answer : 0.005KL, 8.1 L, 8.200 ML (ML = megalitres).
Description : A solution containing `Na_(2)CO_(3)` and `NaOH` requires `300 ml` of `0.1 N HCl` using phenolphthalein as an indicator. Methyl orange is then added to
Last Answer : A solution containing `Na_(2)CO_(3)` and `NaOH` requires `300 ml` of `0.1 N HCl` using phenolphthalein ... solution is `(NaOH=40, Na_(2)CO_(3)=106)`
Description : Hydrazine `N_(2)H_(4)` acts as a reducing agent. To prepare 100 ml of 2 N hydrazine solution, the weight required will be
Last Answer : Hydrazine `N_(2)H_(4)` acts as a reducing agent. To prepare 100 ml of 2 N hydrazine solution, the weight required will ... B. 1.6 g C. 3.2 g D. 0.8 g
Description : A solution of sodium thiosulphate on addition of few drops of ferric chloride gives violet colour due to the formation of
Last Answer : A solution of sodium thiosulphate on addition of few drops of ferric chloride gives violet colour due to the formation of ... `Fe_(2)(S_(2)O_(3))_(2)`
Description : Doctor's solution used for sweetening of petroleum products is (A) Sodium plumbite (B) Sodium sulphite (C) Sodium thiosulphate (D) Lead sulphate
Last Answer : (A) Sodium plumbite
Description : 25 ml of the given HCl solution requires 30 mL of 0.1M sodium carbonate solution. What is the volume of this HCl solution required to titrate 30 mL of
Last Answer : 25 ml of the given HCl solution requires 30 mL of 0.1M sodium carbonate solution. What is the volume of this HCl ... 5 mL B. 75 mL C. 50 mL D. 25 mL
Description : `50 mL` of `0.1 M` solution of a salt reacted with `25 mL` of `0.1 M` solution of sodium sulphite. The half reaction for the oxidation of sulphite ion
Last Answer : `50 mL` of `0.1 M` solution of a salt reacted with `25 mL` of `0.1 M` solution of sodium ... was `3`, what would be the new oxidation number of metal:
Description : Which of the following is not formed in the below reaction `O_(3) + Kl + D_(2)O rarr`
Last Answer : Which of the following is not formed in the below reaction `O_(3) + Kl + D_(2)O rarr` A. KOH B. `O_(2)` C. `I_(2)` D. KOD
Description : `CH_(3)COOH overset((i) PCl_(3)+Cl_(2) ("excess"))underset((ii) O_(2))to (X) overset(SOCl_2) to (Y) overset(H_(2)//Pd//BaSO_(4))to(Z) overset(OH^(-))t
Last Answer : `CH_(3)COOH overset((i) PCl_(3)+Cl_(2) ("excess"))underset((ii) O_(2))to (X) overset(SOCl_2) to (Y) ... W+S ` Write the structure of X,Y,Z , W and S
Description : When thiosulphate ion is oxidised by iodine. which one of the following ion is produced ?
Last Answer : When thiosulphate ion is oxidised by iodine. which one of the following ion is produced ? A. (A) `SO_3^(2-)` B ... `S_4O_6^(2-)` D. (D) `S_2O_6^(2-)`
Description : In a constant pressure process steam is generated from 10 bar and 0.8 dry condition till it become dry and saturated. Determine amount of heat added per kg of steam. From steam table at 10 bar Tsat = 179.9°C hf = 762.6 kl/kg, hg = 2776.2 kJ/kg
Last Answer : Constant pressure process Final condition of steam is dry saturated Enthalpy of dry steam = hg= hf + hfg =2776.2 KJ/Kg .Given Latent heat of vaporization = hfg = hg - hf =2776.2-762.6 =2013.6 KJ/Kg Initial condition ... hfg = 762.6+0.8 X 2013.6 =2373.48 KJ/Kg Heat added = hg-hw = 402.72 KJ/kg
Description : Number of ml of 0.1 N KOH required to neutralize fatty acids from 5 gms of fat: (A) Iodine number (B) Polenske number (C) Reichert-Miessl number (D) None of these
Last Answer : Answer : B
Description : Ethyl alcohol on oxidation with acidified `K_(2)Ce_(2)O_(7)` gives
Last Answer : Ethyl alcohol on oxidation with acidified `K_(2)Ce_(2)O_(7)` gives A. `CH_(3)COCH_(3)` B. `HCOOH` C. `CH_(3)COOH` D. `HCHO
Description : `SO_(2)` reduces acidified `K_(2)Cr_(2)O_(7)` to
Last Answer : `SO_(2)` reduces acidified `K_(2)Cr_(2)O_(7)` to A. `Cr_(2)(SO_(2))_(3)` B. `CrO_(3)` C. `Cr_(2)O_(3)` D. chromium
Description : How many mL of 0.3M `K_(2)Cr_(2)O_(7)` (acidic) is required for complete oxidation of 5 mL of 0.2 M `SnC_(2)O_(4)` solution.
Last Answer : How many mL of 0.3M `K_(2)Cr_(2)O_(7)` (acidic) is required for complete oxidation of 5 mL of 0.2 M `SnC_(2)O_(4)` solution.
Description : A 100 mL sample of water was treated to convert any iron present to `Fe^(2+)`. Addition of 25 mL of 0.002 M `K_(2)Cr_(2)O_(7)` resulted in the reactio
Last Answer : A 100 mL sample of water was treated to convert any iron present to `Fe^(2+)`. Addition of 25 ... parts per million (ppm) of iron in the water sample.
Description : When `H_(2)O_(2)` is reacted with `K_(2)Cr_(2)O_(7)" in dilute "H_(2)SO_(4)` and then ether is added. The ether layer gets -colour
Last Answer : When `H_(2)O_(2)` is reacted with `K_(2)Cr_(2)O_(7)" in dilute "H_(2)SO_(4)` and then ether ... layer gets -colour A. Red B. Yellow C. Blue D. Green
Description : The volume (in ml) of 0.5 M NaOH required for the complete reaction with 150 ml of 1.5M `H_(3)PO_(3)` solution is
Last Answer : The volume (in ml) of 0.5 M NaOH required for the complete reaction with 150 ml of 1.5M `H_(3)PO_(3)` solution is A. 1350 B. 900 C. 1250 D. 1150
Description : The volume (in `mL`) of `0.1M Ag NO_(3)` required for complete precipitation of chloride ions present in `30 mL` of `0.01M` solution of `[Cr(H_(2)O)_(
Last Answer : The volume (in `mL`) of `0.1M Ag NO_(3)` required for complete precipitation of chloride ions present ... Cl]Cl_(2)`, as silver chloride is close to:
Description : What volume of water is requried to make `0.20 N` solution from `1600 mL` of `0.2050 N` solution?
Last Answer : What volume of water is requried to make `0.20 N` solution from `1600 mL` of `0.2050 N` solution? A. 40 mL B ... to `H_(3)AsO_(4)` C. 100 mL D. 20 mL
Description : `{:("column I","column II"),("(A)"4.1gH_(2)SO_(3),"(p) 200 mL of 0.5 N base is used for complete neutralization"),("(B)" 4.9 g H_(3)PO_(4),"(q) 200 mi
Last Answer : `{:("column I","column II"),("(A)"4.1gH_(2)SO_(3),"(p) 200 mL of 0.5 N base is used for ... Na_(2)CO_(3),"(s)May react with an oxidising agent"):}`
Description : One gram of `Na_(3)AsO_(4)` is boiled with excess of solid `KI` in presence of strong `HCl`. The iodine evolved is absorbed in `KI` solution and titra
Last Answer : One gram of `Na_(3)AsO_(4)` is boiled with excess of solid `KI` in presence of strong `HCl`. The iodine evolved ... B. 38.4 mL C. 24.7 mL D. 30.3 mL
Description : In the titration of `K_(2)Cr_(2)O_(7)` and ferrous sulphate, following data is obtained: `V_(1)` mL of `K_(2)Cr_(2)O_(7)` solution of molarity `M_(1)`
Last Answer : In the titration of `K_(2)Cr_(2)O_(7)` and ferrous sulphate, following data is obtained: `V_(1)` mL of `K_(2)Cr_ ... V_(2)` D. `M_(1)V_(1)=M_(2)V_(2)`
Description : A small iodine crystal is added to each of the following aq solutions: I. sodium sulphate II. Sodiumthiosulphate III. Sodium tetrathionate IV. Sulphur
Last Answer : A small iodine crystal is added to each of the following aq solutions: I. sodium sulphate II. Sodiumthiosulphate ... only in III and IV D. only in II